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PROVINCIAL EXAMINATION/
PROVINSIALE EKSAMEN
JUNE/JUNIE 2022
GRADE/GRAAD 10
MARKING GUIDELINES/NASIENRIGLYNE
MATHEMATICS/WISKUNDE
(PAPER/VRAESTEL 1)
5 pages/bladsye
NOTE/LET WEL
• If a candidate answers a question TWICE, mark only the FIRST attempt./As 'n kandidaat 'n vraag TWEE
KEER beantwoord het, merk slegs die EERSTE poging.
• If a candidate crossed out an answer and did not redo it, mark the crossed-out answer./As 'n kandidaat 'n
antwoord deurgehaal het en dit nie oorgedoen het nie, merk die deurgehaalde antwoord.
• Consistent accuracy applies to ALL aspects of the marking guidelines./Konsekwente akkuraatheid is van
toepassing op ALLE aspekte van die nasienriglyne.
• Assuming values/answers in order to solve a problem is unacceptable./Om waardes/antwoorde te aanvaar om
'n probleem op te los, is onaanvaarbaar.
1
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Gr10 MATH P1 (ENG _ AFR) June 2022 Possible Answers_hlayiso.com_.pdf
Mathematics · Grade 10 · Gauteng June · 2022. Memorandum, 5 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 10
- Document type
- Memorandum
- Year
- 2022
- Exam period
- Gauteng June
- Paper
- 1
- Pages
- 5
- File size
- 193.8 KB
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MARKING GUIDELINES MATHEMATICS/WISKUNDE
NASIENRIGLYNE (Paper/Vraestel 1) GRADE/GRAAD 10
QUESTION/VRAAG 1
Q./VR. Suggested solution/voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
1.1 x=1 ✓1 (1)
1.2 1.2.1 2 x 2 − 32
= 2( x 2 − 16) ✓factorise/faktoriseer
✓factorise/faktoriseer
= 2( x + 4)( x − 4) (2)
1.2.2 6a 2 − b + a ( 2 − 3b )
✓simplify/vereenvoudig
= 6a 2 − b + 2a − 3ab ✓grouping/groepering
= 2a(3a + 1) − b(3a + 1) OR/OF ✓factorise/faktoriseer
= (3a + 1)(2a − b)
= 3a(2a − b) + (2a − b)
= (2a − b)(3a + 1) (3)
1.3 1.3.1 ( x − 1)( x 2 + x + 1) If they multiply everything out and ✓𝑥 3
answer is incorrect then no marks. ✓–1
= x3 − 1 As hulle alles vermenigvuldig en
antwoord is verkeerd, dan geen
punte nie. (2)
1.3.2 x+7 3 2
− +
x − x − 6 x − 3 2x + 4
2
x+7 3 2 ✓factorise trinomial and/
= − + faktoriseer drieterm en
( x − 3)( x + 2) x − 3 2( x + 2)
2x + 4
x+7 3 1
= − +
( x − 3)( x + 2) x − 3 x + 2
x + 7 − 3( x + 2) + x − 3
= ✓common denominator
( x − 3)( x + 2) gemeenskaplike noemer
x + 7 − 3x − 6 + x − 3
=
( x − 3)( x + 2) ✓numerator/teller
−x − 2
=
( x − 3)( x + 2)
−( x + 2) ✓simplify numerator/
=
( x − 3)( x + 2) vereenvoudig die teller
−1
=
x−3 ✓factorise and simplify
faktoriseer en
vereenvoudig (5)
2
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MARKING GUIDELINES MATHEMATICS/WISKUNDE
NASIENRIGLYNE (Paper/Vraestel 1) GRADE/GRAAD 10
1.3.3 4 x +1.9 x
62 x −1
22( x +1).32 x
=
(3.2) 2 x −1
22 x + 2.32 x ✓numerator/teller
=
32 x −1.22 x −1 ✓denominator/noemer
= 23.3 ✓answer/antwoord
= 24 (3)
1.4 −2 x , 2− x , 2 x ,2 x , 2 x
0 2
✓✓ all correct/alles reg
✓one error/een fout (2)
[18]
QUESTION/VRAAG 2
Q./VR. Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
2.1 2.1.1 ax = b
𝑎𝑥 = 𝑏 2 ✓square/vierkant
𝑏2 ✓divide/deel
𝑥 = 𝑎 ; a≠0 (2)
2.1.2 3x + 3x−1 = 36
3x (1 + 3−1 ) = 36 ✓factorise/faktoriseer
4
3x = 36
3
3 = 27
x ✓simplify isolate/
vereenvoudig isoleer 3𝑥
3x = 33
x=3 ✓answer/antwoord (3)
2.2 2.2.1 x x
+1
3 2
2 x 3x + 6 ✓LCD/KGV
−x 6 ✓answer/antwoord
x −6 (2)
2.2.2 x = −10 ✓answer/antwoord (1)
3
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MARKING GUIDELINES MATHEMATICS/WISKUNDE
NASIENRIGLYNE (Paper/Vraestel 1) GRADE/GRAAD 10
2.3 2 x + y = 4 and/en
and 3x − y = 11
y = 4 − 2x
✓equation/vergelyking 1
2x + y = 4 ✓subs./vervang
3 x − (4 − 2 x) = 11 ✓x value/x-waarde
3 x − y = 11
3 x − 4 + 2 x = 11 ✓y value/y-waarde
5x = 15
5 x = 15 OR/OF
x=3
x=3
y = −2
y = 4 − 2(3)
y = −2
ALTERNATIVE/ALTERNATIEF
Eq1 + Eq2 Adding the two equations:
5𝑥 = 15 Optel van 2 vergelykings:
𝑥=3 ✓5𝑥
✓15
𝑦 = −2 ✓x value/x-waarde
✓y value/y-waarde (4)
[12]
QUESTION/VRAAG 3
Q./VR. Suggested solution/Voorgestelde oplossing Explanation/Verduideliking Marks/Punte
3.1 3; 5; 7; 9; 11 9✓
11 ✓ (2)
3.2 2n + 1 ✓✓ correct answer/korrekte
antwoord (2)
3.3 4(131) +1 ✓ substitute/vervang 131
524 +1 ✓ 525
525 (2)
[6]
4
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MARKING GUIDELINES MATHEMATICS/WISKUNDE
NASIENRIGLYNE (Paper/Vraestel 1) GRADE/GRAAD 10
QUESTION/VRAAG 4
Q.VR. Suggested solution/Voorgestelde oplossing Explanation/Verduideliking Marks/Punte
4.1 B(0;4) Answers must be in coordinate form (see ✓ B(0;4)
D(0;2) question)./ Antwoorde moet in koördinaatvorm ✓ D(0;2)
wees (sien vraag). (2)
4.2 𝑦≤4 ✓
OR/OF
𝑦𝜖(−∞; 4] (1)
4.3 −𝑥 2 + 4 = 0 ✓ equation/vergelyking = 0
(2 − 𝑥)(2 + 𝑥) = 0 ✓factors/faktore
𝑥=2 𝑥 = −2 ✓Both values of x/albei
waardes van x
AE = 2 – (-2)
AE = 4 ✓Answer/Antwoord (4)
4.4 Using values for A/Gebruik waardes vir A ✓sub./vervang
0 = 𝑚(−2) + 2 ✓𝑚 = 1
2𝑚 = 2
𝑚=1 (2)
4.5 𝑓(𝑥) = 𝑔(𝑥) ✓𝑓(𝑥) = 𝑔(𝑥)
−𝑥 2 + 4 = 𝑥 + 2
𝑥2 + 𝑥 − 2 = 0
(𝑥 + 2)(𝑥 − 1) ✓Correct x values/Korrekte
𝑥 = −2 𝑥 = +1 x-waardes
A(-2;0)
Sub/vervang 𝑥 = 1 into/in 𝑔(𝑥)
𝑦 = 1(1) + 2
y=3 ✓ C(1;3)
C(1;3) (3)
4.6 Using the reflection of the points of intersection CA from 4.5/CA van 4.5
in Q.4.5/Gebruik die reflekse van die snypunte in
Vr. 4.5. ✓correct x values/korrekte x-
waardes
−1 ≤ 𝑥 ≤ 2 ✓inequality/ongelykheid (2)
[14]
TOTAL/TOTAAL: 50
5
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