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PROVINCIAL EXAMINATION/
PROVINSIALE EKSAMEN
JUNE/JUNIE 2022
GRADE/GRAAD 10
MARKING GUIDELINES/
NASIENRIGLYNE
MATHEMATICS/WISKUNDE
(PAPER 2)/(VRAESTEL 2)
5 pages/bladsye
1
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Mathematics Grade 10 Paper 2 Gauteng June 2022 Memo
Grade 10 Mathematics Paper 2 memorandum from the Gauteng June 2022, 5 pages. Read online or get the free PDF download, question paper linked when available.
Mathematics · Grade 10 · Gauteng June · 2022. Memorandum, 5 pages. Read online or download the PDF.
- Subject
- Mathematics
- Grade
- Grade 10
- Document type
- Memorandum
- Year
- 2022
- Exam period
- Gauteng June
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 5
- File size
- 238.1 KB
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This exam
Gauteng June 2022
Questions in this paper
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MARKING GUIDELINES MATHEMATICS/WISKUNDE
NASIENRIGLYNE (Paper/Vraestel 2) GRADE/GRAAD 10
Q./Vr. 1 Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
1.1 𝑟 2 = (−3)2 + (−4)2 Using Pythagoras
𝑟 2 = 25 correctly/Gebruik
𝑟=5 Pythagoras korrek
3 ✓𝑟 = 5
∴ sin 𝜃 = − ✓Answer/Antwoord (3)
5
5cos(90° − 𝜃) + 3 cot 𝜃 −3
1.2 5( 5 )✓
−4
−3 −4 3 (−3)✓
5( 5 ) +3 (−3)
= −3 + 4 Answer/Antwoord ✓
=1 (3)
[6]
Q./Vr. 2 Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
2.1 sin( 𝛽 − 17.8°) = 0,215
𝛽 − 17,8° = 12,41554° ✓ 12,41554°
𝛽 = 30,22° ✓ 30,22° (2)
2.2 tan 3𝛽 = √3
3𝛽 =60° ✓ 3𝛽 =60°
𝛽 =20° ✓ Answer/Antwoord (2)
2.3 𝛽
3 sin = 2,012
2 ✓ 0,6706666
𝛽
sin = 0,6706666
2
𝛽
= 37,42097785° ✓ 37,4209778°
2
𝛽 = 74,84° ✓ 74,84°
(3)
Q./Vr. 3 Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
3.1 𝑡𝑎𝑛 30°°. 𝑐𝑜𝑠𝑒𝑐 60°
𝑐𝑜𝑠 45°. 𝑠𝑖𝑛 45° ✓ 3
√3
√3 √2 √2
✓
3 × 3 3
√2 √2 √2
2
×
2 ✓
2
√6 √2
= 2
3
✓ Answer/Antwoord (4)
[4]
2
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MARKING GUIDELINES MATHEMATICS/WISKUNDE
NASIENRIGLYNE (Paper/Vraestel 2) GRADE/GRAAD 10
Q./Vr 4 Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
4.1 𝑎 = −2 ; 𝑏 = 1 ✓𝑎 = −2
✓𝑏=1 (2)
4.2 0° ≤ 𝑥 ≤ 180° ✓ IneQ /Ongelykhede
✓ critical values/ kritieke
waardes (2)
4.3 2 ✓ Answer/Antwoord (1)
4.4 −1 ≤ 𝑦 ≤ 1 OR [-1;1] ✓Inequalities/
Ongelykhede
✓ critical values/kritieke
waardes (2)
4.5 𝑥 = 270° ✓ Answer/Antwoord (1)
[8]
Q./Vr. 5 Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
5.1 Square and Rhombus/Vierkant en Ruit ✓ Answer/ Antwoord (1)
5.2 Square and Rectangle/Vierkant en Reghoek ✓ Answer/ Antwoord (1)
5.3 Square; Rectangle; Parallelogram; Rhombus ✓✓ Answer/ Antwoord
Vierkant; Reghoek; Parallelogram; Ruit (2)
[4]
3
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MARKING GUIDELINES MATHEMATICS/WISKUNDE
NASIENRIGLYNE (Paper/Vraestel 2) GRADE/GRAAD 10
Q./Vr. 6 Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
6.1 M̂1 = x [alternate s PS// QR] / [verwiss e ; PS // QR] ✓ S ✓R
✓ S ✓R
Q̂1 = x [angles opp = sides] /[e teenoor gelyke sye ] (4)
6.2 Sˆ = Qˆ1 + Qˆ 2 [opp s of //gm] /[oorst e van ||m ] ✓ S/R
Sˆ = 2 x
Mˆ 3 = 2 x [ s opp = sides] /[e teenoor gelyke sye ] ✓S/R
OR/OF
OR/OF
Pˆ = 180 − (Qˆ1 + Qˆ 2 ) [co - interior s PS//QR/
ko - binnee ; PS // QR]
✓ S/R
Pˆ = 180 − 2 x
Pˆ + Sˆ = 180 [co - interior s SR//PQ /
✓ S/R
ko - binnee ; SR // PQ]
Sˆ = 2 x
Mˆ = 2 x
3 [ s opp = sides / e teenoor gelyke sye ] (2)
6.3 ̂1 + M
M ̂2 + M̂ 3 = 180° [sum of interior < s of Δ ✓ S/R
som binnehoeke van ]
𝑥 + 90° + 2𝑥 = 180°
3𝑥 = 90° ✓
𝑥 = 30° Answer/Antwoo
rd (2)
[8]
Q./Vr. 7 Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
BD = BD [common / gemeenskaplik ] ✓S
✓ S/R
Dˆ = Bˆ [alternate s AD// BC/
1 2
✓S
verwissele nde binnee ; AD // BC ]
Bˆ1 = Dˆ 2 [alternate s AB // DC/ ✓S ✓R
verwissele nde binnee ; B // DC ]
ABC CBD [ AAS ] / S
AD = BC and / en AB = DC (5)
[5]
4
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MARKING GUIDELINES MATHEMATICS/WISKUNDE
NASIENRIGLYNE (Paper/Vraestel 2) GRADE/GRAAD 10
Q./Vr. 8 Suggested solution/Voorgestelde oplossing Explanation/ Marks/
Verduideliking Punte
8.1 AO = OC [diagonals of//gm bisect/ ✓S ✓R
✓S
hoeklyne van ||m halveer ]
✓R
DO = OB [diagonals of//gm bisect /
hoeklyne van ||m halveer ]
BOAF is a / 'n // gm [opp sides of a quad equal/
oorst sye van vierhoek is gelyk ] (4)
8.2 EA // BC given / gegee ✓S
BF // AC proven / bewys ✓S
✓R
EBCA is a / 'n // gm [ two pairs of opp sides || / ✓S
twee pare teenoorst sye ||]
EA = BC
EA = AD (4)
[8]
TOTAL/TOTAAL: 50
5
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