Physical Sciences Grade 10 P1 KZN November 2024 Paper & Memo

Downloaded from Stanmorephysics.com KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 10 MARKS: 100 DURATION: 2 hours This question paper consists of 11 pages and a data sheet.

Physical Sciences P1 NSC — Grade 10 November 2024 Test Downloaded from Stanmorephysics.com INSTRUCTIONS AND INFORMATION 1; eo oe NP 11. Copyright reserved This question paper consists of EIGHT questions. Answer ALL the questions in the ANSWER BOOK. Start EACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. Leave ONE line between two sub-questions, for example between QUESTION 2.1 and QUESTION 2.2. You may use a non-programmable calculator. You may use appropriate mathematical instruments. You are advised to use the attached DATA SHEET. Show ALL formulae and substitutions in ALL calculations. Round off your final numerical answers to a minimum of TWO decimal places. Give brief motivations, discussions et cetera where required. Write neatly and legibly. Please turn over

Physical Sciences P1 NSC — Grade 10 November 2024 Test Downloaded from Stanmorephysics.com QUESTION 1: MULTIPLE-CHOICE QUESTIONS Four options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the answer and write only the letter (A-D) next to the question number (1.1—1.5) in the ANSWER BOOK, for example 1.6 E. 1.1 Which of the following indicates the number of wave pulses per second? A Wave speed B_ Period C Frequency D Wavelength 1.2 The velocity-time graph for a car travelling along a straight horizontal surface is shown below. North is taken as positive. Which of the following 'T for the motion of the car after 20 seconds Acceleration Direction of motion A_ | Positive North B_ | Positive South C_ | Negative North D_ | Negative South Copyright reserved Please turn over (2) (2)

Physical Sci Pt NSC — Grade 10 ber 2024 Test howhloaded from Stanmorepaysics.com Novem ONS 1.3 Which statement explains why a glass rod becomes positively charged when rubbed with a woollen cloth? A Protons are transferred from the glass rod to the woollen cloth. B-_Protons are transferred from the woollen cloth to the glass rod. C~_ Electrons are transferred from the glass rod to the woollen cloth. D Electrons are transferred from the woollen cloth to the glass rod. (2) 14 An object is thrown from the top of a building with velocity V and kinetic energy E. It reaches the ground with a velocity of 2V. Which ONE of the following is the objects kinetic energy just before it strikes the ground? A 2E B 4E Cc 0,5E DE (2) 15 A battery is connected to three identical resistors in different combinations. Which combination, represented in the circuit diagrams below, will result in the ammeter having the largest reading? HA A we Ra Cc ee Ri Ri Re Re Rs Rs (2) [2X 5= 10] Copyright reserved Please turn over

Physical Sciences P1 ‘ade NSC - Ne ber 2024 Ti wnloaded from Stanmorephysics.com _—ses QUESTION 2 (Start on a new page.) The propagation of Radiation X in air is represented by the transverse wave pattern below. 2.1 Calculate the frequency of the wave. (3) 29 Write down the speed of the wave. (1) 2.3 The table below shows the data for different types of radiation in order of decreasing wavelength. TYPE OF RADIATION WAVELENGTH RANGE (m) Radio waves Greater than 0,1 m Microwaves 0,1 to 10° Infrared (IR) —_ 103 107 Visible light ee 4x 107 Ultraviolet (UV) light 2 10° X-rays 1 i Gamma rays 1 fae morep ES 23:1 By means-OF d , identify the type of radiation (4) represented by Radiation X. 2.3.2 Determine the energy of a photon of Radiation X. (3) [11] Copyright reserved Please turn over

Physicak.Sciences P1 NSC — Grade 10 Ni ber 2024 Test Lisivfiloaded from Stanmorepbysics.com _ QUESTION 3_ (Start on a new page.) 3.1 S and T are two points on a longitudinal wave pattern travelling at 2 m-s* WL LUTE T The distance between FOUR consecutive compressions is 1,2 m. a | Define the term longitudinal wave in words. (2) 3.1.2 Calculate the frequency of the wave. (4) 3:13 Determine the time taken for the wave to move from point S to (3) point T. 3.2 The alarm of a stationary ambulance emits a sound wave which is detected by both Sam and James. Sam stands at an unknown distance, X metres, due east of the ambulance and hears the sound after 0,6 seconds. James stands 50 m due east of Sam and hears the sound after 0,75 seconds. “Xm 50m 3.2.1 Calculate the speed of the sound wave. (4) 3.2.2 Determine X, the distance between Sam and the ambulance. (2) [15] Copyright reserved Please turn over

Physical Sciences P14 NSC — Grade 10 November 2024 Test Downloaded from Stanmorephysics.com QUESTION 4 (Start on anew Page.) A metal sphere, P, which was initially neutral, is given a charge of 8 x 10°C 4.1 Were electrons ADDED TO or REMOVED FROM sphere P? (1) 4.2 Determine the number of electrons that were added or removed. (4) Sphere P is now suspended from a wooden beam by means of a light insulated string. An identical sphere, R, carrying an initial charge of — 12 x10° C is first brought into contact with sphere P and then placed on an insulated stand next to Sphere P, as shown in the diagram below. 4.3 Determine the charge on sphere R after it touches and separates from sphere P. (3) 4.4 Will the spheres ATTRACT or REPEL each other when they are placed as shown in the diagram? Give a reason for the answer. (2) [10] Copyright reserved Please turn over

Prysicssiitoaded from StannidvepEysies.com SE QUESTION 5 (Start on a new page) A battery with an EMF of 22 V is connected to three resistors and an electrical device, as shown in the circuit diagram below. The connecting wires and the battery have negligible resistance. 22V (2)——|! | The voltmeter reads 8 V. 5.1 Define the term current in words. (2) 5.2 Calculate the reading on ammeter A1. (3) 3000 J of energy is transferred in the electrical device in 1 minute 5.3 Determine the: 5.3.1 Charge travelling through the electrical device in 1 minute (5) 53:2 Reading on Ammeter Az (3) The switch is now opened. 5.4 Will the current through the device INCREASE, DECREASE or REMAIN THE SAME? (2) Give a reason for the answer. [15] Copyright reserved Please turn over

Pusch Sunloaded from StannisvepHysies.com QUESTION 6 (Start on a new page) November 2024 Test Peter and Jim are both on the final lap of an 800 m race, in a swimming pool of length 50 metres. When Jim is at pool wall 1, Peter is 20 metres ahead of him. Both swimmers are moving eastwards to finish the race at pool wall 2. nL N z8 al Sc tlt o£ 2< s 50m 6.1 Write down the position of Peter relative to the finish line, when Jim is at pool wall 1. Peter swims at an average velocity of 1,2 m-s* east. 6.2 Calculate the time taken for Peter to reach the finish line from his current position. 6.3 Calculate the average speed at which Jim needs to swim in order to finish the race 0,5s ahead of Peter. Copyright reserved Please turn over (2) (3) (4) [9]

Physical Bismmidaded from Stantrephysits.com aes QUESTION 7 (Start on a new page) Car X, starting from rest at Point A, accelerates at 4 m-s? for 5 seconds along a straight horizontal road, travelling eastwards. After 5 seconds it continues further at a constant velocity. At the same instant that Car X starts to move, Car Y moves past Point B on the same road in a westerly direction at an unknown CONSTANT velocity. Points A and B are 490 metres apart. N E Ss 7A Define the term acceleration in words. -- (2) 7.2 Calculate the velocity that Car X reaches after 5 seconds. (4) Both cars pass each other after 12 seconds. 7.3 Determine the: 7.3.1 Distance covered by Car X in 12 seconds. (5) 7.32 Velocity of Car Y. (4) 7A On the same set of axis sketch the Velocity — Time graph for BOTH Car X and Car Y until they pass each other. Label each graph. Show the following on the graph: e The maximum velocity reached by Car X e The velocity of Car Y e The time they pass each other (5) [20] Copyright reserved Please turn over

Physical Sci P41 NSC — 4 Ne ber 2024 Test *“bownloaded from Stanmbrephysics.com — QUESTION 8 (Start on a new page) A boy skates along the frictionless ramp shown below. The boy starts at Point X, 2 metres above the ground, at a velocity of 1 m-s™. The combined mass of the boy and skateboard is 60 kg. 8.1 Calculate the mechanical energy of the boy and his skateboard at Point X. (4) 8.2 Determine the speed of the boy and his skateboard at Point Y. (3) 8.3 Use relevant calculations to show that the skateboard will not be able to reach Point Z, when starting at 1 m-s* at Point X. (3) [10] TOTAL: 100 Copyright reserved Please turn over

November 2024 Test Pr eiMTBaded from StanmdPepeysies.com DATA FOR PHYSICAL SCIENCES GRADE 10 PAPER 1 (PHYSICS) TABLE 1; PHYSICAL CONSTANTS NAME SYMBOL VALUE Acceleration due to gravity g 9,8 m.s? Speed of light in a vacuum c 3,0 x 108 m-s Planck's constant h 6,63 x 104 Js Charge on electron qe -1,6 x 10°79 C Electron mass Me 9,11 x 10°" kg TABLE 2: FORMULAE WAVES, SOUND AND LIGHT 1 v=fa or c=fa T=-+ f f 7 he E=hf elec J a ELECTROSTATICS Q1+Q2 Q=n XG Q= ; ELECTRIC CIRCUITS 1oijiy Q=!1x At i” s Ry Ww R, = Ry +R2+° ia) V=IR MOTION 1 Vp = Vi + at AX = vit + Saat? Ve + V; v2 = vi? + 2aAx xz ( S ‘Yat WORK, ENERGY AND POWER U=mgh or E,= mgh = yy, mv? or Ey = 1/, a? Copyright reserved

KWAZULU-NATAL PROVINCE EDUCATION REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE GRADE 10 MARKS: 100 DURATION: 2 hours Copyright reserved

Downloaded from Stanmorephysics.com QUESTION 1: 11. Cv (2) 12. ByYy (2) 13° Cvy (2) 14. BYv (2) 15 Aulolyv (2) [10] QUESTION 2 OPTION 2 3,57 x10" = v 35 = 1,428x 10? s find 7 1 1,428 x 1071? = ; v f=7x 10" Hzv (3) 2.2 3x10°m-s* v (1) 23.1 POSITIVE MARKING FROM QUESTION 2.1 c=f xiv 3x108=7x10!!xA v N=4,29x 104m v Radiation X is Infrared ¥ (4) 2.3.2 OPTION 1 (POSITIVE MARKING | OPTION 2 (POSITIVE MARKING FROM QUESTION 2.1) FROM QUESTION 2.3.1) E=hxf ¥. he =— v i a = 6,63 x 10x 7x10" v. _ 6,63 x 1074 x 3 x 108 v 7 4,29 x 10-4 =4,64x107 J v. 4,64x 10 J v. (3) [11] Copyright reserved

Dyraieaded from Stanmorephysics.com 3.1.1. A wave in which the particles of the medium vibrate parallelv to the direction of motion of the wave. 9.132 A ig v =04m vefxA Vv 2=f x04Vv f=5HzvY 3.1.3 OSITIVE ING FROM QUESTION 3.1.2 OPTION 1 OPTION 2 _1 5 waves > 1 second v T= - 2 waves > x seconds = iv x= - v =0,2s time =0,4sv time = 0,2 x 2v =0,4sv OPTION 1 OPTION 2 dist i 3.2.1 saeeit= es ance |, time _ 50v ~ 0,75 - 0,6% = 333,33 m-s' v speed = 333,33 ms! v 3.2.2 | POSITIVE MARKING FROM POSITIVE MARKING FROM QUESTION 3.2.1 QUESTION 3.2.1 distance x X+50 = = = speed ime 333,33 06 OR 333,33 0.75 x 333,33 = oe” X=200mv X= 200 mv Copyright reserved (2) (4) (3) (4) (2) [15]

Duymemerded from Stanmorephysics.com 4.1 Removed from “ 4.2 Q=nxq, ¥ 8x10°V =n x 1,6x10°° v n=5x10°v os Q1+Q2 v Qe 2 8x10° + (-12x10°) v q= ee 2 =-2x10°Cv 4.4 Repelv. The spheres have the same charges after contact / Like charges repel ¥ QUESTION 5 5.1 The rate of flow of charge Vv V=IRV QUESTION 5.2 OR =2x4+2x2v =12V Voevice = 22 - 12 ¥ =10V 5.3.2 POSITIVE MARKING FROM QUESTION 5.3.1 OPTION 1 OPTION 2 Q=IlAtv W =VIAt ¥ 300 =|x60v 3000 = 10x 1x 60 ¥ l=5Av l=5AV 5.4 Decrease. Y The total resistance increases. ¥ Copyright reserved (1) (4) (3) (2) [10] (2) (3) (5) (3) (2) [15]

Downloaded from Stanmorephysics.com QUESTION 6 6.1 30m.v westY (2) (3) (4) [9] QUESTION 7 Ta Rate of change of velocity v v (2 or 0) (2) 72 vy = vi + adtyv 0+4(5)¥ = 20 m:s" V east ¥ (4) 7.3 POSITIVE MARKING FROM QUESTION 7.2 73.1 Start — 5 seconds: Ax = viAt + %adt? Vv v2 = v;2 + 2adx Y (0)5 + % (4)(5*) ¥ OR (20)? = 0? + 2(4)ax ¥ = 50m Ax =50m 5 seconds — 12 seconds: Ax = viAt + %adt? Ax = vAt = (20)7 + %(0)(7%) ¥ OR (20)7 ¥ =140m =140m Distance = 140 + 50 ¥ =190mv (5) 7.3.2 Ax=490-190v = 300m of v" it 300 if ve" = 25 m-s" west ¥ (4) Copyright reserved

5 3 “a iS 2 207 y ‘ 1 CarX 8 s 0) t i 5 12 Time (s) - 25 - CarY Marking Criteria 41 Mark — Car X maximum velocity 1 Mark — Car Y velocity 1 Mark — Both graphs stop at time = 12 seconds 1 Mark — Car X Shape( straight line from t = 0 s tot = 5s AND horizontal line from t = 5 s to t= 12 s) and labelled. 1 Mark — Car Y Shape (horizontal lines from t = 0 s tot = 12 s) and labelled. (5) [20] QUESTION 8 8.1 Ey = mgh + “mv? ¥ = 60x98x2V+%x 60x (1 v = 1206 J ¥ (4) 8.2 POSITIVE MARKING FROM 8.1 Ey = mgh + Ymv? (3) a e to reach Point Z since), the gravitational potential energy a Z is greater than the total mechanical energy v. (3) [10] TOTAL: 100 Copyright reserved