Confidential
GRAAD 12
NATIONAL
SENIOR CERTIFICATE
GRADE 12
LIFE SCIENCES P2
NOVEMBER 2025
MARKS: 150
TIME: 2½ hours
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Life Sciences Grade 12 P2 NSC November 2025 QP (Eng)
Grade 12 Life Sciences Paper 2 question paper from the NSC November Exam 2025 (English), 17 pages. Read online or download the free PDF.
Life Sciences · Grade 12 · NSC November Exam · 2025. Question paper, 17 pages. Read online or download the PDF.
- Subject
- Life Sciences
- Grade
- Grade 12
- Document type
- Question paper
- Year
- 2025
- Exam period
- NSC November Exam
- Paper
- 2
- Curriculum
- CAPS
- Pages
- 17
- File size
- 1.1 MB
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This exam
NSC November Exam 2025
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Life Sciences/P2 2 DBE/November 2025
NSC Confidential
INSTRUCTIONS AND INFORMATION
Read the following instructions carefully before answering the questions.
1. Answer ALL the questions.
2. Write ALL the answers in the ANSWER BOOK.
3. Start the answers to EACH question at the top of a NEW page.
4. Number the answers correctly according to the numbering system used in this
question paper.
5. Present your answers according to the instructions of each question.
6. Do ALL drawings in pencil and label them in blue or black ink.
7. Draw diagrams, tables or flow charts only when asked to do so.
8. The diagrams in this question paper are NOT necessarily drawn to scale.
9. Do NOT use graph paper.
10. You must use a non-programmable calculator, protractor and a compass,
where necessary.
11. Write neatly and legibly.
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Life Sciences/P2 3 DBE/November 2025
NSC Confidential
SECTION A 2025
QUESTION 1
1.1 Various options are provided as possible answers to the following questions.
Choose the answer and write only the letter (A–D) next to the question numbers
(1.1.1 to 1.1.10) in the ANSWER BOOK, e.g. 1.1.11 D.
1.1.1 A gene is …
A the complete set of chromosomes of an organism.
B a segment on a chromosome, coding for a characteristic.
C the haploid number of chromosomes in a cell.
D a triplet of bases that codes for an amino acid.
1.1.2 The significance of DNA replication is that the cells formed at the
end of mitosis will …
A be genetically identical.
B contain half the number of chromosomes.
C be genetically different.
D have double the number of chromosomes.
1.1.3 Which ONE of the following statements is a feature of punctuated
equilibrium?
A Individual organisms adapt to changes in the environment.
B The inheritance of acquired characteristics
C There are long periods of little or no change in a population.
D The more a structure is used, the more it develops.
1.1.4 Haemophilia is …
A characterised by the inability to distinguish between red and
green.
B caused by a mutation of an allele on the X-chromosome.
C caused by non-disjunction of chromosomes during meiosis.
D caused by an allele carried on an autosome.
1.1.5 Which ONE of the following is an example of a heterozygous
genotype?
A XrXr
B BB
C RW
D aa
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Life Sciences/P2 4 DBE/November 2025
NSC Confidential
QUESTIONS 1.1.6 AND 1.1.7 REFER TO THE DIAGRAM BELOW THAT
REPRESENTS DNA REPLICATION.
1
5
G
A
T
T
1.1.6 Which ONE of the following combinations CORRECTLY identifies
molecules 1, 4 and 5?
Molecule 1 Molecule 4 Molecule 5
A Nucleotide Deoxyribose Phosphate
B Nitrogenous base Phosphate Deoxyribose
C Nucleotide Phosphate Deoxyribose
D Nitrogenous base Deoxyribose Phosphate
1.1.7 Which ONE of the following combinations is CORRECT for
molecules 2 and 3?
Molecule 2 Molecule 3
A T A
B A A
C T G
D A C
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Life Sciences/P2 5 DBE/November 2025
NSC Confidential
QUESTIONS 1.1.8 AND 1.1.9 REFER TO THE INFORMATION IN THE
DIHYBRID CROSS BELOW.
In a certain plant species, one gene controls stem colour and another controls
plant height. The stem colour can be brown (B) or red (b), while the plant height
can be tall (T) or short (t).
STEM COLOUR PLANT HEIGHT
Plant 1 Brown Short
Plant 2 Red Tall
When plant 1 was crossed with plant 2, some of their offspring were red and
short.
1.1.8 Which ONE of the following represents the genotypes of plant 1 and
plant 2?
PLANT 1 PLANT 2
A bbtt BbTt
B Bbtt bbTt
C BbTt bbtt
D bbTt Bbtt
1.1.9 The number of possible different genotypes expected in the
offspring from this cross is …
A 4.
B 8.
C 9.
D 16.
1.1.10 A rare form of rickets is caused by a dominant allele on the
X-chromosome.
Which ONE of the following statements is TRUE about the
inheritance of this form of rickets?
A If the father is affected, all his sons will be affected.
B It will be expressed more frequently in males than in females,
since males have only one X-chromosome.
C If the father is affected, all his daughters will be affected.
D It will only be expressed in females, since they have two
X-chromosomes. (10 x 2) (20)
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Life Sciences/P2 6 DBE/November 2025
NSC Confidential
1.2 Give the correct biological term for EACH of the following descriptions.
Write only the term next to the question numbers (1.2.1 to 1.2.9) in the
ANSWER BOOK.
1.2.1 The bond formed between two amino acids during protein synthesis
1.2.2 An organelle that contains DNA which is used in tracing female
ancestry
1.2.3 Undifferentiated cells in animals that have the potential to become
any type of tissue
1.2.4 A change in the sequence of nitrogenous bases resulting in the
formation of a different protein
1.2.5 The natural shape of a DNA molecule
1.2.6 The permanent disappearance of a species from Earth
1.2.7 A type of variation with a range of intermediate phenotypes
1.2.8 An allele that is expressed in a phenotype in the heterozygous
condition
1.2.9 The position of an allele on a chromosome (9 x 1) (9)
1.3 Indicate whether each of the descriptions in COLUMN I apply to A ONLY,
B ONLY, BOTH A AND B or NONE of the items in COLUMN II. Write A only,
B only, both A and B or none next to the question numbers (1.3.1 to 1.3.3) in
the ANSWER BOOK.
COLUMN I COLUMN II
1.3.1 The phase of meiosis during A: Anaphase I
which non-disjunction can occur B: Anaphase II
1.3.2 A representation of the number, A: Phylogenetic tree
shape and arrangement of all the B: Karyotype
chromosomes in the nucleus
1.3.3 The alleles of a gene separate A: Law of independent
into different gametes during assortment
meiosis B: Law of segregation
(3 x 2) (6)
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Life Sciences/P2 7 DBE/November 2025
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1.4 The diagrams below represent cells from the same organism during different
phases of mitosis and meiosis.
V W X
A
B
C
Y Z
1.4.1 Identify part:
(a) A (1)
(b) B (1)
(c) C (1)
1.4.2 Which diagram (V, W, X, Y or Z) represents a cell during:
(a) Prophase of mitosis (1)
(b) Metaphase I (1)
(c) Prophase I (1)
1.4.3 How many chromosomes will there be in each cell at the end of:
(a) Mitosis (1)
(b) Meiosis I (1)
(8)
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1.5 The diagram below represents a stage of protein synthesis. Each amino acid
(P, Q, R and S) is coded for by a different codon on this mRNA molecule.
1
2 3 4 5
U A C G C A C G A
Z
1.5.1 Identify:
(a) The stage of protein synthesis represented (1)
(b) Molecule 1 (1)
(c) Organelle Z (1)
1.5.2 State the sequence of nitrogenous bases on the DNA molecule for
codon:
(a) 3 (1)
(b) 4 (2)
1.5.3 Which amino acid (P, Q, R or S) is coded for by codon 5? (1)
(7)
TOTAL SECTION A: 50
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SECTION B
QUESTION 2
2.1 The diagram below represents the sex chromosomes in a female.
X X
A
P
2.1.1 Identify structure A. (1)
2.1.2 Give the biological term for the sex chromosomes. (1)
2.1.3 Describe how these chromosomes would differ in the somatic cells
of a male. (1)
2.1.4 An exchange of genetic material takes place at region P.
(a) Name the process above. (1)
(b) Identify the phase during which the process named in
QUESTION 2.1.4(a) takes place. (1)
(c) Give ONE reason why the process named in
QUESTION 2.1.4(a) is important. (1)
2.1.5 Explain how the structure of the chromosomes would differ at the
end of meiosis II. (2)
2.1.6 Non-disjunction of these chromosomes occurred during meiosis and
a gamete with an extra chromosome is formed. If this gamete is
fertilised by normal gametes, the resulting zygotes will not be
normal.
Explain the genetic composition of these zygotes. (3)
(11)
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Life Sciences/P2 10 DBE/November 2025
NSC Confidential
2.2 The diagram below shows the DNA analysis of a sample obtained at a crime
scene, a sample from the victim and samples from two suspects. In their
investigation, police conducted a comparison of the DNA to identify the criminal.
Sample from
crime scene
Sample from
the victim
Sample from
suspect 1
Sample from
suspect 2
2.2.1 Name the technique used in this criminal investigation. (1)
2.2.2 Which ONE of the suspects (1 or 2) was at the crime scene? (1)
2.2.3 Give ONE observable reason for your answer to QUESTION 2.2.2. (1)
2.2.4 Give TWO possible reasons why the suspect identified in
QUESTION 2.2.2 might NOT be convicted if only this evidence is
used. (2)
2.2.5 Explain how the technique named in QUESTION 2.2.1 is used in
paternity testing. (4)
(9)
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2.3 CADASIL is an autosomal genetic disorder caused by a dominant allele (D).
It results in the thickening of the walls of blood vessels.
The diagram below shows the inheritance of CADASIL in a family.
1 2 3 4
5 6 7 8
KEY:
Female with CADASIL
Male with CADASIL
Female without CADASIL 9 10 11
Male without CADASIL
2.3.1 Name the type of diagram represented above. (1)
2.3.2 How many offspring do parents 3 and 4 have? (1)
2.3.3 Give the:
(a) Phenotype of individual 10 (1)
(b) Genotype of individual 5 (1)
2.3.4 Using evidence from the diagram, explain why individuals 1 and 2
are both heterozygous. (4)
2.3.5 What is the percentage chance of parents 7 and 8 having another
child with CADASIL? (1)
(9)
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2.4 The graph below shows the distribution of blood groups for two ethnic groups
(1 and 2) in a certain country during 2021.
Percentage of people with each blood group
60
51
Percentage of people
50 45
40
40
30 26
19
20
11
10 4 4
0
A B AB O
Blood groups
Ethnic group 1 Ethnic group 2
2.4.1 Which blood group:
(a) Is most common in both ethnic groups (1)
(b) Has a higher percentage in ethnic group 1 than in ethnic
group 2 (1)
2.4.2 State ALL the possible genotypes of 11% of the people in ethnic
group 1. (2)
2.4.3 Ethnic group 1 had a population of 360 000 people in 2021.
Which blood group (A, B, AB or O) had 39 600 people? (2)
2.4.4 Explain the inheritance of blood group AB. (3)
(9)
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2.5 Palomino horses are bred by horse breeders for their coat colour. A palomino
has a golden-coloured coat. It is the offspring of a horse with a cream-coloured
coat (A) and a horse with a chestnut-coloured coat (G).
2.5.1 Name the type of dominance displayed in the inheritance of coat
colour in palomino horses. (1)
2.5.2 Explain your answer to QUESTION 2.5.1. (2)
2.5.3 The breeding of horses with desired characteristics is a type of
biotechnology.
(a) Name this type of biotechnology. (1)
(b) Name the TWO phenotypes of the horses that must be
interbred for a 100% chance of palomino offspring. (2)
2.5.4 A horse with a cream-coloured coat was crossed with a palomino
horse.
Use a genetic cross to show the expected phenotypic ratio of the
offspring. (6)
(12)
[50]
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QUESTION 3
3.1 Theories of human evolution are based on the similarities between humans and
African apes and also on the anatomical differences between them.
3.1.1 State TWO characteristics related to vision that humans share with
African apes. (2)
3.1.2 Describe TWO differences between the jaws of humans and African
apes. (4)
3.1.3 Explain the significance of the position of the foramen magnum, the
shape of the spine and the size of the pelvis in bipedalism. (6)
(12)
3.2 The table below shows the average brain volume of different hominid species.
SPECIES AVERAGE BRAIN VOLUME
(mℓ)
Ardipithecus ramidus 350
Australopithecus africanus 461
Homo habilis 609
Homo erectus 959
Homo sapiens 1 330
3.2.1 How many genera are represented in the table? (1)
3.2.2 Give TWO examples of fossils of Australopithecus africanus found
in South Africa. (2)
3.2.3 Give the average brain volume (mℓ) of the species that was the first
to use tools. (1)
3.2.4 Calculate the percentage increase in the average brain volume
between Homo habilis and Homo sapiens. Show ALL working and
round off the answer to TWO decimal places. (3)
3.2.5 The brain decomposes after the organism dies.
Explain how scientists are able to determine the brain volume of
fossils. (3)
3.2.6 Explain the relationship between average brain volume and cultural
evidence for human evolution. (3)
(13)
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3.3 The extract and diagram below are based on ratites.
BREEDING MONTHS IN RATITES
Ratites are egg-laying flightless birds. The egg-laying months are influenced by
many factors such as the temperature, length of the day and availability of food.
Ostriches normally lay their eggs in September, rheas between October and
March, while emus lay their eggs from November to April.
Ostrich
Rhea
Emu
The present-day distribution of ratite species
3.3.1 The ratites shown in the map are classified as different biological
species.
(a) State what is meant by a biological species. (2)
(b) Using the information in the extract, explain why the ostrich and
emu are considered different species. (2)
(c) Name TWO other reproductive isolation mechanisms that
would have prevented the rhea and ostrich from interbreeding
if they were in the same habitat. (2)
3.3.2 Identify the evidence for evolution represented in the diagram. (1)
3.3.3 Describe how the evidence identified in QUESTION 3.3.2 supports
the theory of evolution. (5)
(12)
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3.4 Starvation resistance refers to the period for which an organism can go without
food before it dies.
An investigation was conducted to determine the effect of the availability of food
on the starvation resistance in fruit flies.
The procedure was as follows:
• 5 000 fruit flies of the same age were used.
• They were all placed in a container suitable for the growth of fruit flies and
were given a maltose-based food source.
• The food source was removed after an hour.
• The time it took for 80% of the fruit flies to die from starvation was recorded.
• The dead flies were removed from the container.
• The food source was then returned to the container.
• The remaining fruit flies were allowed to interbreed.
• Their eggs were collected and transferred to a new container with a food
source where they were allowed to hatch.
• These fruit flies were allowed to grow to the same age as the
1st generation.
• The food source was then removed again.
• The time it took for 80% of the fruit flies to die from starvation was recorded
again.
• This procedure was repeated until the 60th generation of fruit flies was
reached.
Food removed
Food returned
New generation
3.4.1 State the independent variable for this investigation. (1)
3.4.2 Describe how the dependent variable was measured. (1)
3.4.3 State ONE controlled variable that was considered when selecting
the fruit flies at the beginning of the investigation. (1)
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3.4.4 Explain why the investigator gave the fruit flies the same type of food
throughout the investigation. (2)
The graphs below show the results obtained for the 1st generation and the
60th generation.
300
Chart Title 300 Chagert Title
GENERATION 1 GENERATION 60
Number of flies
Number of flies
200 ORIGINAL POPULATION
200
100
100
0
0 40 80 120 160 200 0
0 40 80 120 160 200
Hours until death from starvation
Hours until death from starvation
3.4.5 Describe the results obtained in this investigation. (2)
3.4.6 Using Darwin's theory of natural selection, explain the increase in
starvation resistance in fruit flies. (6)
(13)
[50]
TOTAL SECTION B: 100
GRAND TOTAL: 150
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