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Mechanical Technology Grade 12 NSC November 2018 Memo (Eng)

MemorandumMechanical TechnologyGrade 12201821 pages

Grade 12 Mechanical Technology memorandum from the NSC November Exam 2018 (English), 21 pages. Read online or download the free PDF.

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Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 MECHANICAL TECHNOLOGY: FITTING AND MACHINING NOVEMBER 2018 MARKING GUIDELINES MARKS: 200 These marking guidelines consist of 21 pages. Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 2 DBE/November 2018 NSC – Marking Guidelines QUESTION 1: MULTIPLE-CHOICE QUESTIONS (GENERIC) 1.1 A (1) 1.2 C (1) 1.3 A (1) 1.4 B (1) 1.5 D (1) 1.6 A (1) TOTAL QUESTION 1: [6] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 3 DBE/November 2018 NSC – Marking Guidelines QUESTION 2: SAFETY (GENERIC) 2.1 Angle grinder: (Before using) • The safety guard must be in place before starting.  • Protective shields must be placed around the object being grinded to protect the people around.  • Use the correct grinding disc for the job.  • Make sure that there are no cracks in the disc before you start.  • Protective clothing and eye protection are essential.  • Check electrical outlets and cord/plugs for any damages.  • Ensure that lockable switch is disengaged.  • Ensure that the disc and the nut are well secured.  • Ensure that the removable handle is secured.  (Any 2 x 1) (2) 2.2 Welding goggles: • To protect your eyes against sparks  • To protect your eyes against heat  • To be able to see where to weld  • To protect your eyes from UV rays  (Any 2 x 1) (2) 2.3 PPE for Hydraulic Press: • Overall  • Safety shoes / boots • Safety goggle  • Leather gloves  • Face shield  (Any 2 x 1) (2) 2.4 Workshop layouts: • Process layout  • Product layout  (2) 2.5 Employer’s responsibility regarding first-aid: • Provision of first-aid equipment  • First aid training  • First-aid services by qualified personnel  • Any first aid procedures / treatment  • Display first aid safety signs  • First aid personnel must be identified by means of arm bands or relevant personal signage  (Any 2 x 1) (2) TOTAL QUESTION 2: [10] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 4 DBE/November 2018 NSC – Marking Guidelines QUESTION 3: MATERIALS (GENERIC) 3.1 Bending test: • Ductility  • Malleability  • Brittleness  • Flexibility  (Any 1 x 2) (2) 3.2 Heat-treatment: 3.2.1 Annealing: • To relieve internal stresses  • To soften the steel  • To make the steel ductile  • To refine the grain structure of the steel  • To reduce the brittleness of the steel  (Any 2 x 1) (2) 3.2.2 Case hardening: • To require a wear resistant surface  and it must be tough enough internally  at the core to withstand the applied loads. • Hard case  and tough core.  (Any 1 x 2) (2) 3.3 Tempering process: • To reduce  the brittleness  caused by the hardening process. • Relieve  strain  caused during hardening process. • Increase  the toughness of the steel.  (Any 1 x 2) (2) 3.4 Factors for heat-treatment processes: • Heating temperature / Carbon content  • Soaking (Time period at temperature) / Size of the work piece  • Cooling rate / Quenching rate  (3) 3.5 Hardening of steel: • Steel is heated to 30 – 50°C above the higher critical temperature. (AC 3 )  • It is then kept at that temperature to ensure (soaking) that the whole structure is Austenite.  • The steel is then rapidly cooled by quenching it in clean water, brine or oil.  (3) TOTAL QUESTION 3: [14] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 5 DBE/November 2018 NSC – Marking Guidelines QUESTION 4: MULTIPLE-CHOICE QUESTIONS (SPECIFIC) 4.1 C (1) 4.2 A (1) 4.3 D (1) 4.4 A (1) 4.5 B (1) 4.6 A (1) 4.7 B (1) 4.8 B (1) 4.9 D (1) 4.10 C (1) 4.11 B (1) 4.12 D (1) 4.13 D (1) 4.14 C (1) TOTAL QUESTION 4: [14] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 6 DBE/November 2018 NSC – Marking Guidelines QUESTION 5: TERMINOLOGY (LATHE AND MILLING MACHINE) (SPECIFIC) 5.1 Advantages of using the tailstock to cut an external taper: • Long an accurate taper can be cut.  • The automatic feed can be used which result in a good finish.  (2) 5.2 Calculate the compound slide set-over: θ D−d  Tan = 2 2L θ 60 - 28 Tan =  2 2 × 85  = 0,188 θ = 10,66 °  2 OR 28 60 Ɵ 2 X 85 D−d X=   2 θ 16 Tan = 60 - 28  2 85 =  2 θ  = 10,66 ° = 16 mm 2 (5) 5.3 Centre gauge: • To measure the form and angle of the screw cutting tool angle while grinding the tool  • To set the screw cutting tool square/perpendicular to the axis of the work piece  (2) 5.4 Parallel key: Length: Length = 1,5 × diameter  = 1,5 × 42  = 63 mm  (3) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 7 DBE/November 2018 NSC – Marking Guidelines 5.5 Advantages of up-cut milling: • Deeper cuts can be made as the cutting pressure on the cutter is lower than down cut milling.  • The process enables hard steel to be cut, because the total cutting pressure is absorbed by the material at the back of the edge.  • Metal with hard scale, such as castings or forgings, the cut is started under the scale where the material is softer which extends the life of the cutter.  • A quicker/course feed can be used.  • The strain on the cutter and arbour will be less.  • Vibration is limited  • Good finish  • Low noise level  (Any 2 x 1) (2) 5.6 Disadvantage of down-cut milling: • Vibration in the arbour is unavoidable.  • A fine feed must be used.  • When milling a material with hard scale the milling cutter will be damaged.  • Process takes time because of slower feed.  • Noisy process.  • Bad finish because of vibration.  (Any 2 x 1) (2) 5.7 Methods of centring a milling cutter: • Square and ruler method.  • Set-over method by milling machine dial.  • Dial indicator method  • Using reference points on digital read out equipment  (Any 2 x 1) (2) TOTAL QUESTION 5: [18] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 8 DBE/November 2018 NSC – Marking Guidelines QUESTION 6: TERMINOLOGY (INDEXING) (SPECIFIC) 6.1 Spur gear: Chordal tooth thickness: 90° 90° t c = Tmsin  t c = PCDsin  T T 90°  90°  = 50 × 3sin or = 150sin 50 50 = 50 × 3(0,03141)  = 150 × 0,03141  = 4,71 mm  = 4,71 mm  (4) 6.2 Calculate simple indexing: 40 Simple Indexing = N 40 =  13 1  =3 13 1 3 =3 × 13 3 3  =3 39  3 full turns and 3 holes in a 39 hole circle (4) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 9 DBE/November 2018 NSC – Marking Guidelines 6.3 Differential indexing: 6.3.1 Indexing required: 40 40 Indexing = = n 127 40 40 5  = = ÷ A 125 5 8  = 25 Indexing = 8 holes on the 25 hole circle  (3) 6.3.2 Change gears required: Dr A - n 40  = × Dn A 1 125 - 127 40  = × 125 1 2 40 = × 125 1 - 80 5  = ÷ 125 5 - 16 4 = × 25 4 - 64 =  100  (5) 6.3.3 Direction of rotation of index plate: The index plate will turn the opposite  direction as the index crank handle. (1) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 10 DBE/November 2018 NSC – Marking Guidelines 6.4 Calculate distance “x” between rollers: " x" = 150 + 2(AB ) − 2(CD) − 2r B A θ = BC tan  AB 60° BC AB = θ tan 35 =  tan 60° 35 = 20,207 mm  = 20,21 mm C θ = DE tan CD  E 15 CD = θ 15 tan  15 30° = C tan30° D = 25,98 mm  " x" = 150 + 2(AB ) − 2(CD) − 2r  = 150 + 2(20,21) − 2(25,98 ) − 2(15 ) = 150 + 40,42 − 51,96 − 30  = 108,454 mm = 108, 45 mm  (9) 6.5 Reasons for balancing work piece on a centre lathe: • Prevent unnecessary bearing loads  • Prevent excessive vibration  • To obtain a good finish  • To prevent clatter on the gear teeth  • To prevent the spindle from bending  (Any 2 x 1) (2) TOTAL QUESTION 6: [28] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 11 DBE/November 2018 NSC – Marking Guidelines QUESTION 7: TOOLS AND EQUIPMENT (SPECIFIC) 7.1 Hardness testers: • Brinell-hardness tester  • Rockwell-hardness tester  • Vickers  (Any 2 x 1) (2) 7.2 Moment tester: To determine the reactions  on either side of a simply loaded beam.  (2) 7.3 Tensile test: A piece of material is subjected to an increasing axial load  while measuring  the corresponding elongation  of the material. (3) 7.4 Depth micro-meter:     Reading = 100 + 11,00 + 0,50 + 0,09  = 111,59 mm (5) 7.5 Measure depth: Vernier calliper  (1) TOTAL QUESTION 7: [13] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 12 DBE/November 2018 NSC – Marking Guidelines QUESTION 8: FORCES (SPECIFIC) 8.1 Forces: (15) Horizontal Vertical Magnitudes Magnitudes Components  Components  1150cos0° 1150N  1150sin0° 0N 800cos150° -692,82N  800sin150° 400N  650cos200° -610,80N  650sin200° -222,31N  550cos270° 0N 550sin270° -550N  TOTAL: -153,62N  TOTAL: -372,31N  Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 13 DBE/November 2018 NSC – Marking Guidelines 8.2 Moments: 2800 N 700 N “x” O 1m 5m Calculate “x”: Take moments about O. ∑ RHM = ∑ LHM  700 × " x" = 2800 × 1 700 × " x" = 2800  2800  " x" = 700 " x" = 4 m  (4) 8.3 Stress and Strain: 8.3.1 Type of stress: Compressive stress  (1) 8.3.2 Stress: A= ( π D2 - d2 )  4 ( π 0,04 2 − 0,03 2 = ) 4 A = 0,55 × 10 -3 m2  σ =F  A 50 × 10 3 = 0,55 × 10 −3  σ = 90,91× 10 6 Pa σ = 90,91 MPa  (NO UNIT – NO MARK) (5) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 14 DBE/November 2018 NSC – Marking Guidelines 8.3.3 Change in length: σ Eε=  σ ε = E 90,91× 10 6 = 90 × 10 9 = 1,01× 10 −3  (IF ANY UNIT IS GIVEN – NO MARK) Δ ε =L  L Δ ε= ×L L  ( ) = 1,01× 10 −3 × (80 ) = 0,08 mm  (5) 8.3.4 Safety factor: Break stress Safety factor =  Safe working stress Break stress Safe working stress = Safety factor 600 × 10 6 =  4 = 150 × 10 6 Pa = 150 MPa  (3) TOTAL QUESTION 8: [33] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 15 DBE/November 2018 NSC – Marking Guidelines QUESTION 9: MAINTENANCE (SPECIFIC) 9.1 Lack of preventative maintenance: • Risk of injury or death.  • Financial loss due to damage suffered as a result of part failure and the waste of material.  • Loss of valuable production time.  (3) 9.2 Causes for the malfunctioning of chain drive systems: • Lack of or incorrect lubrication  • Lack of maintenance  • Overloading  • Misalignment of sprockets  • Incorrect chain tension  • Contamination of chain drive system such as dust or sand  (Any 2 x 1) (2) 9.3 Procedures to reduce the physical wear on a belt drive system: • Check the belt alignment.  • Checking the belt tension.  • Prevent overloading of the system.  • Keep the pulleys and belt clean.  • Check that all covers are secure.  (Any 2 x 1) (2) 9.4 Procedures to replace the belt on a belt drive system: • Ensure that the machine is switched off  • Release the tension on the belt  • Remove the belt from the pulleys  • Fit the correct size replacement belt onto the pulleys  • Check the pulley alignment  • Apply adequate tension according to specification and lock the system  (Any 5 x 1) (5) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 16 DBE/November 2018 NSC – Marking Guidelines 9.5 Properties of materials: 9.5.1 Poly vinyl chloride (PVC): • Flexible  • Rubber-like substance  • Makes a dull sound when dropped  • Tough  • Act as an insulator  • It is durable  • Highly resistant to oxidative material  • Oil, water and chemical resistant  (Any 1 x 1) (1) 9.5.2 Carbon fibre: • Strong  • Tough  • Light weight  • Good electrical conductor  (Any 1 x 1) (1) 9.6 Difference between “Thermoplastic” and “Thermo hardened (thermosetting)” composites: Thermoplastics can be reheated and deformed. / Recyclable  Thermo hardened cannot be reheated. / Non-recyclable  (2) 9.7 Examples of thermo hardened composites: • Carbon fibre or (Any application)  • Glass fibre or (Any application)  • Bakelite or (Any application)  • Teflon or (Any application)  (Any 2 x 1) (2) TOTAL QUESTION 9: [18] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 17 DBE/November 2018 NSC – Marking Guidelines QUESTION 10: JOINING METHODS (SPECIFIC) 10.1 Square thread: 10.1.1 The lead of the thread: Lead = pitch × no of starts  = 5×2 = 10 mm  (2) 10.1.2 The helix angle of the thread: θ = lead Helix angle tan  pitch cercumfrence 10  = π ×  outside dia − 1 pitch    2  10 = π × (82 − 2,5)  = 0,0400 θ = 2,29° / 2°17'24"  OR θ = lead Helix angle tan  pitch diameter 10  =  82 − 2,5 θ = 7,17° / 7°10'12"  (5) 10.1.3 The leading tool angle: Leading tool angle = 90° − (helix angle + clearance angle )  = 90° − (2,29° + 3°)  = 84,71° / 84°42'36" OR Leading tool angle = 90° − (helix angle + clearance angle )  = 90° − (7,17° + 3°) = 79,83° / 79°49'48"  (2) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 18 DBE/November 2018 NSC – Marking Guidelines 10.1.4 The following tool angle: Following tool angle = 90° + (helix angle − clearance angle )  = 90° + (2,29° − 3°) = 89,29° / 89°17'24"  OR Following tool angle = 90° + (helix angle − clearance angle )  = 90° + (7,17° − 3°) = 94,17° / 94°10'12"  (2) 10.2 Measurements of a screw thread : 10.2.1 Metric screw thread  (1) 10.2.2 Crest / Major / External / Basic / Nominal / Outside diameter  (1) 10.2.3 Pitch  (1) 10.3 Angles of a square thread cutting tool: A – Helix angle  B – Clearance angle  C – Leading tool angle  D – Following tool angle  (4) TOTAL QUESTION 10: [18] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 19 DBE/November 2018 NSC – Marking Guidelines QUESTION 11: SYSTEMS AND CONTROL (DRIVE SYSTEMS) (SPECIFIC) 11.1 Advantages of a belt drive system compared to a chain drive system: • Silent operation  • Less expensive  • Drive can take place over a longer distance  • No lubrication needed  (Any 2 x 1) (2) 11.2 Hydraulics: 11.2.1 Fluid pressure: π 2 AA = d  4 π (0,032)2 = 4 = 0,8 × 10 −3 m2  FA p=  AA 120 = 0,8 × 10 −3 = 0,1492 × 10 6 Pa = 0,15 MPa or 149207,76 Pa  (NO UNIT – NO MARK) (4) 11.2.2 Diameter of the ram: F FB F p= A  = A  AA AB A A F A A × FB AB = B AB = p OR FA = 18 × 10 3  = (0,8 × 10 )× (18 × 10 )  −3 3 0,15 × 10 6 120 2 = 0,12 m 2  = 0,12 m  π 2 AB = d  4 4A d =π 4 × 0,12  = π = 0,39088 m  = 390,88 mm (6) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 20 DBE/November 2018 NSC – Marking Guidelines 11.3 Hydraulic symbols: One-way valve  (1) 11.4 Belt drives: Rotation frequency of the drive pulley: NDRD DR = NDND DN  N × D DN NDR = DN  D DR 80 × 240  = 75 = 256 r/min  (4) 11.5 Gear drives: 11.5.1 Rotation frequency of the output: N A Product of Driven gears = ND Product of Driver gears ND TA × TC  = N A TB × TD T × TC × N A  ND = A TB × TD 20 × 25 × 3000  =  35 × 30 1428,57 r/min ND =  60 = 23,81 r/sec  OR NB = NC = 1714,29 r/min NB × TB = NA × TA  NA × TA ND × TD = NC × TC  NB = TB NC × TC ND = 3000 × 20 TD = 35 1714,29 × 25  = = 1714,29 r/min  30 1428,57 r/min  = 60  = 23,81r/sec (6) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology: Fitting and Machining 21 DBE/November 2018 NSC – Marking Guidelines 11.5.2 Gear ratio: Product of the number of teeth on driven gears  Gear ratio = Product of the number of teeth on driver gears 35 30 = ×  20 25 = 2,1 : 1  (3) 11.6 Work done: Work done = F × s  = 250 × 15 = 3750 Joule or N.m  (2) TOTAL QUESTION 11: [28] TOTAL: 200 Copyright reserved Please turn over

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