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NATIONAL
SENIOR CERTIFICATE
GRADE 12
MECHANICAL TECHNOLOGY: FITTING AND MACHINING
NOVEMBER 2018
MARKING GUIDELINES
MARKS: 200
These marking guidelines consist of 21 pages.
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Mechanical Technology Grade 12 NSC November 2018 Memo (Eng)
Grade 12 Mechanical Technology memorandum from the NSC November Exam 2018 (English), 21 pages. Read online or download the free PDF.
Mechanical Technology · Grade 12 · NSC November Exam · 2018. Memorandum, 21 pages. Read online or download the PDF.
- Subject
- Mechanical Technology
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2018
- Exam period
- NSC November Exam
- Curriculum
- CAPS
- Pages
- 21
- File size
- 672.9 KB
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Mechanical Technology: Fitting and Machining 2 DBE/November 2018
NSC – Marking Guidelines
QUESTION 1: MULTIPLE-CHOICE QUESTIONS (GENERIC)
1.1 A (1)
1.2 C (1)
1.3 A (1)
1.4 B (1)
1.5 D (1)
1.6 A (1)
TOTAL QUESTION 1: [6]
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Mechanical Technology: Fitting and Machining 3 DBE/November 2018
NSC – Marking Guidelines
QUESTION 2: SAFETY (GENERIC)
2.1 Angle grinder: (Before using)
• The safety guard must be in place before starting.
• Protective shields must be placed around the object being grinded
to protect the people around.
• Use the correct grinding disc for the job.
• Make sure that there are no cracks in the disc before you start.
• Protective clothing and eye protection are essential.
• Check electrical outlets and cord/plugs for any damages.
• Ensure that lockable switch is disengaged.
• Ensure that the disc and the nut are well secured.
• Ensure that the removable handle is secured.
(Any 2 x 1) (2)
2.2 Welding goggles:
• To protect your eyes against sparks
• To protect your eyes against heat
• To be able to see where to weld
• To protect your eyes from UV rays
(Any 2 x 1) (2)
2.3 PPE for Hydraulic Press:
• Overall
• Safety shoes / boots
• Safety goggle
• Leather gloves
• Face shield
(Any 2 x 1) (2)
2.4 Workshop layouts:
• Process layout
• Product layout (2)
2.5 Employer’s responsibility regarding first-aid:
• Provision of first-aid equipment
• First aid training
• First-aid services by qualified personnel
• Any first aid procedures / treatment
• Display first aid safety signs
• First aid personnel must be identified by means of arm bands or
relevant personal signage
(Any 2 x 1) (2)
TOTAL QUESTION 2: [10]
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Mechanical Technology: Fitting and Machining 4 DBE/November 2018
NSC – Marking Guidelines
QUESTION 3: MATERIALS (GENERIC)
3.1 Bending test:
• Ductility
• Malleability
• Brittleness
• Flexibility
(Any 1 x 2) (2)
3.2 Heat-treatment:
3.2.1 Annealing:
• To relieve internal stresses
• To soften the steel
• To make the steel ductile
• To refine the grain structure of the steel
• To reduce the brittleness of the steel
(Any 2 x 1) (2)
3.2.2 Case hardening:
• To require a wear resistant surface and it must be
tough enough internally at the core to withstand the
applied loads.
• Hard case and tough core.
(Any 1 x 2) (2)
3.3 Tempering process:
• To reduce the brittleness caused by the hardening process.
• Relieve strain caused during hardening process.
• Increase the toughness of the steel.
(Any 1 x 2) (2)
3.4 Factors for heat-treatment processes:
• Heating temperature / Carbon content
• Soaking (Time period at temperature) / Size of the work piece
• Cooling rate / Quenching rate (3)
3.5 Hardening of steel:
• Steel is heated to 30 – 50°C above the higher critical temperature.
(AC 3 )
• It is then kept at that temperature to ensure (soaking) that the whole
structure is Austenite.
• The steel is then rapidly cooled by quenching it in clean water, brine
or oil. (3)
TOTAL QUESTION 3: [14]
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Mechanical Technology: Fitting and Machining 5 DBE/November 2018
NSC – Marking Guidelines
QUESTION 4: MULTIPLE-CHOICE QUESTIONS (SPECIFIC)
4.1 C (1)
4.2 A (1)
4.3 D (1)
4.4 A (1)
4.5 B (1)
4.6 A (1)
4.7 B (1)
4.8 B (1)
4.9 D (1)
4.10 C (1)
4.11 B (1)
4.12 D (1)
4.13 D (1)
4.14 C (1)
TOTAL QUESTION 4: [14]
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Mechanical Technology: Fitting and Machining 6 DBE/November 2018
NSC – Marking Guidelines
QUESTION 5: TERMINOLOGY (LATHE AND MILLING MACHINE) (SPECIFIC)
5.1 Advantages of using the tailstock to cut an external taper:
• Long an accurate taper can be cut.
• The automatic feed can be used which result in a good finish. (2)
5.2 Calculate the compound slide set-over:
θ D−d
Tan =
2 2L
θ 60 - 28
Tan =
2 2 × 85
= 0,188
θ
= 10,66 °
2
OR
28 60
Ɵ
2 X
85
D−d
X=
2 θ 16
Tan =
60 - 28 2 85
=
2 θ
= 10,66 °
= 16 mm 2 (5)
5.3 Centre gauge:
• To measure the form and angle of the screw cutting tool angle while
grinding the tool
• To set the screw cutting tool square/perpendicular to the axis of the
work piece (2)
5.4 Parallel key:
Length:
Length = 1,5 × diameter
= 1,5 × 42
= 63 mm (3)
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Mechanical Technology: Fitting and Machining 7 DBE/November 2018
NSC – Marking Guidelines
5.5 Advantages of up-cut milling:
• Deeper cuts can be made as the cutting pressure on the cutter is
lower than down cut milling.
• The process enables hard steel to be cut, because the total cutting
pressure is absorbed by the material at the back of the edge.
• Metal with hard scale, such as castings or forgings, the cut is started
under the scale where the material is softer which extends the life of
the cutter.
• A quicker/course feed can be used.
• The strain on the cutter and arbour will be less.
• Vibration is limited
• Good finish
• Low noise level
(Any 2 x 1) (2)
5.6 Disadvantage of down-cut milling:
• Vibration in the arbour is unavoidable.
• A fine feed must be used.
• When milling a material with hard scale the milling cutter will be
damaged.
• Process takes time because of slower feed.
• Noisy process.
• Bad finish because of vibration.
(Any 2 x 1) (2)
5.7 Methods of centring a milling cutter:
• Square and ruler method.
• Set-over method by milling machine dial.
• Dial indicator method
• Using reference points on digital read out equipment
(Any 2 x 1) (2)
TOTAL QUESTION 5: [18]
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Mechanical Technology: Fitting and Machining 8 DBE/November 2018
NSC – Marking Guidelines
QUESTION 6: TERMINOLOGY (INDEXING) (SPECIFIC)
6.1 Spur gear:
Chordal tooth thickness:
90° 90°
t c = Tmsin t c = PCDsin
T T
90° 90°
= 50 × 3sin or = 150sin
50 50
= 50 × 3(0,03141) = 150 × 0,03141
= 4,71 mm = 4,71 mm
(4)
6.2 Calculate simple indexing:
40
Simple Indexing =
N
40
=
13
1
=3
13
1 3
=3 ×
13 3
3
=3
39
3 full turns and 3 holes in a 39 hole circle (4)
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Mechanical Technology: Fitting and Machining 9 DBE/November 2018
NSC – Marking Guidelines
6.3 Differential indexing:
6.3.1 Indexing required:
40 40
Indexing = =
n 127
40 40 5
= = ÷
A 125 5
8
=
25
Indexing = 8 holes on the 25 hole circle (3)
6.3.2 Change gears required:
Dr A - n 40
= ×
Dn A 1
125 - 127 40
= ×
125 1
2 40
= ×
125 1
- 80 5
= ÷
125 5
- 16 4
= ×
25 4
- 64
=
100 (5)
6.3.3 Direction of rotation of index plate:
The index plate will turn the opposite direction as the index
crank handle. (1)
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Mechanical Technology: Fitting and Machining 10 DBE/November 2018
NSC – Marking Guidelines
6.4 Calculate distance “x” between rollers:
" x" = 150 + 2(AB ) − 2(CD) − 2r
B A
θ = BC
tan
AB 60°
BC
AB = θ
tan
35
=
tan 60° 35
= 20,207 mm
= 20,21 mm
C
θ = DE
tan
CD E
15
CD = θ 15
tan
15 30°
= C
tan30° D
= 25,98 mm
" x" = 150 + 2(AB ) − 2(CD) − 2r
= 150 + 2(20,21) − 2(25,98 ) − 2(15 )
= 150 + 40,42 − 51,96 − 30
= 108,454 mm
= 108, 45 mm
(9)
6.5 Reasons for balancing work piece on a centre lathe:
• Prevent unnecessary bearing loads
• Prevent excessive vibration
• To obtain a good finish
• To prevent clatter on the gear teeth
• To prevent the spindle from bending
(Any 2 x 1) (2)
TOTAL QUESTION 6: [28]
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Mechanical Technology: Fitting and Machining 11 DBE/November 2018
NSC – Marking Guidelines
QUESTION 7: TOOLS AND EQUIPMENT (SPECIFIC)
7.1 Hardness testers:
• Brinell-hardness tester
• Rockwell-hardness tester
• Vickers
(Any 2 x 1) (2)
7.2 Moment tester:
To determine the reactions on either side of a simply loaded beam. (2)
7.3 Tensile test:
A piece of material is subjected to an increasing axial load while
measuring the corresponding elongation of the material. (3)
7.4 Depth micro-meter:
Reading = 100 + 11,00 + 0,50 + 0,09
= 111,59 mm (5)
7.5 Measure depth:
Vernier calliper (1)
TOTAL QUESTION 7: [13]
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Mechanical Technology: Fitting and Machining 12 DBE/November 2018
NSC – Marking Guidelines
QUESTION 8: FORCES (SPECIFIC)
8.1 Forces:
(15)
Horizontal Vertical
Magnitudes Magnitudes
Components Components
1150cos0° 1150N 1150sin0° 0N
800cos150° -692,82N 800sin150° 400N
650cos200° -610,80N 650sin200° -222,31N
550cos270° 0N 550sin270° -550N
TOTAL: -153,62N TOTAL: -372,31N
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Mechanical Technology: Fitting and Machining 13 DBE/November 2018
NSC – Marking Guidelines
8.2 Moments:
2800 N 700 N
“x”
O
1m 5m
Calculate “x”:
Take moments about O.
∑ RHM = ∑ LHM
700 × " x" = 2800 × 1
700 × " x" = 2800
2800
" x" =
700
" x" = 4 m (4)
8.3 Stress and Strain:
8.3.1 Type of stress:
Compressive stress (1)
8.3.2 Stress:
A=
(
π D2 - d2 )
4
(
π 0,04 2 − 0,03 2
=
)
4
A = 0,55 × 10 -3 m2
σ =F
A
50 × 10 3
=
0,55 × 10 −3
σ = 90,91× 10 6 Pa
σ = 90,91 MPa
(NO UNIT – NO MARK) (5)
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Mechanical Technology: Fitting and Machining 14 DBE/November 2018
NSC – Marking Guidelines
8.3.3 Change in length:
σ
Eε=
σ
ε =
E
90,91× 10 6
=
90 × 10 9
= 1,01× 10 −3
(IF ANY UNIT IS GIVEN – NO MARK)
Δ
ε =L
L
Δ ε= ×L
L
( )
= 1,01× 10 −3 × (80 )
= 0,08 mm (5)
8.3.4 Safety factor:
Break stress
Safety factor =
Safe working stress
Break stress
Safe working stress =
Safety factor
600 × 10 6
=
4
= 150 × 10 6 Pa
= 150 MPa (3)
TOTAL QUESTION 8: [33]
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Mechanical Technology: Fitting and Machining 15 DBE/November 2018
NSC – Marking Guidelines
QUESTION 9: MAINTENANCE (SPECIFIC)
9.1 Lack of preventative maintenance:
• Risk of injury or death.
• Financial loss due to damage suffered as a result of part failure and
the waste of material.
• Loss of valuable production time. (3)
9.2 Causes for the malfunctioning of chain drive systems:
• Lack of or incorrect lubrication
• Lack of maintenance
• Overloading
• Misalignment of sprockets
• Incorrect chain tension
• Contamination of chain drive system such as dust or sand
(Any 2 x 1) (2)
9.3 Procedures to reduce the physical wear on a belt drive system:
• Check the belt alignment.
• Checking the belt tension.
• Prevent overloading of the system.
• Keep the pulleys and belt clean.
• Check that all covers are secure.
(Any 2 x 1) (2)
9.4 Procedures to replace the belt on a belt drive system:
• Ensure that the machine is switched off
• Release the tension on the belt
• Remove the belt from the pulleys
• Fit the correct size replacement belt onto the pulleys
• Check the pulley alignment
• Apply adequate tension according to specification and lock the
system
(Any 5 x 1) (5)
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Mechanical Technology: Fitting and Machining 16 DBE/November 2018
NSC – Marking Guidelines
9.5 Properties of materials:
9.5.1 Poly vinyl chloride (PVC):
• Flexible
• Rubber-like substance
• Makes a dull sound when dropped
• Tough
• Act as an insulator
• It is durable
• Highly resistant to oxidative material
• Oil, water and chemical resistant
(Any 1 x 1) (1)
9.5.2 Carbon fibre:
• Strong
• Tough
• Light weight
• Good electrical conductor
(Any 1 x 1) (1)
9.6 Difference between “Thermoplastic” and “Thermo hardened
(thermosetting)” composites:
Thermoplastics can be reheated and deformed. / Recyclable
Thermo hardened cannot be reheated. / Non-recyclable (2)
9.7 Examples of thermo hardened composites:
• Carbon fibre or (Any application)
• Glass fibre or (Any application)
• Bakelite or (Any application)
• Teflon or (Any application)
(Any 2 x 1) (2)
TOTAL QUESTION 9: [18]
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Mechanical Technology: Fitting and Machining 17 DBE/November 2018
NSC – Marking Guidelines
QUESTION 10: JOINING METHODS (SPECIFIC)
10.1 Square thread:
10.1.1 The lead of the thread:
Lead = pitch × no of starts
= 5×2
= 10 mm (2)
10.1.2 The helix angle of the thread:
θ = lead
Helix angle tan
pitch cercumfrence
10
=
π × outside dia − 1 pitch
2
10
=
π × (82 − 2,5)
= 0,0400
θ = 2,29° / 2°17'24"
OR
θ = lead
Helix angle tan
pitch diameter
10
=
82 − 2,5
θ = 7,17° / 7°10'12" (5)
10.1.3 The leading tool angle:
Leading tool angle = 90° − (helix angle + clearance angle )
= 90° − (2,29° + 3°)
= 84,71° / 84°42'36"
OR
Leading tool angle = 90° − (helix angle + clearance angle )
= 90° − (7,17° + 3°)
= 79,83° / 79°49'48" (2)
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Mechanical Technology: Fitting and Machining 18 DBE/November 2018
NSC – Marking Guidelines
10.1.4 The following tool angle:
Following tool angle = 90° + (helix angle − clearance angle )
= 90° + (2,29° − 3°)
= 89,29° / 89°17'24"
OR
Following tool angle = 90° + (helix angle − clearance angle )
= 90° + (7,17° − 3°)
= 94,17° / 94°10'12" (2)
10.2 Measurements of a screw thread :
10.2.1 Metric screw thread (1)
10.2.2 Crest / Major / External / Basic / Nominal / Outside diameter (1)
10.2.3 Pitch (1)
10.3 Angles of a square thread cutting tool:
A – Helix angle
B – Clearance angle
C – Leading tool angle
D – Following tool angle (4)
TOTAL QUESTION 10: [18]
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Mechanical Technology: Fitting and Machining 19 DBE/November 2018
NSC – Marking Guidelines
QUESTION 11: SYSTEMS AND CONTROL (DRIVE SYSTEMS) (SPECIFIC)
11.1 Advantages of a belt drive system compared to a chain drive system:
• Silent operation
• Less expensive
• Drive can take place over a longer distance
• No lubrication needed
(Any 2 x 1) (2)
11.2 Hydraulics:
11.2.1 Fluid pressure:
π 2
AA = d
4
π (0,032)2
=
4
= 0,8 × 10 −3 m2
FA
p=
AA
120
=
0,8 × 10 −3
= 0,1492 × 10 6 Pa
= 0,15 MPa or 149207,76 Pa
(NO UNIT – NO MARK) (4)
11.2.2 Diameter of the ram:
F FB F
p= A = A
AA AB A A
F A A × FB
AB = B AB =
p OR FA
=
18 × 10 3 =
(0,8 × 10 )× (18 × 10 )
−3 3
0,15 × 10 6 120
2
= 0,12 m 2
= 0,12 m
π 2
AB = d
4
4A
d =π
4 × 0,12
= π
= 0,39088 m
= 390,88 mm (6)
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Mechanical Technology: Fitting and Machining 20 DBE/November 2018
NSC – Marking Guidelines
11.3 Hydraulic symbols: One-way valve
(1)
11.4 Belt drives:
Rotation frequency of the drive pulley:
NDRD DR = NDND DN
N × D DN
NDR = DN
D DR
80 × 240
=
75
= 256 r/min (4)
11.5 Gear drives:
11.5.1 Rotation frequency of the output:
N A Product of Driven gears
=
ND Product of Driver gears
ND TA × TC
=
N A TB × TD
T × TC × N A
ND = A
TB × TD
20 × 25 × 3000
=
35 × 30
1428,57 r/min
ND =
60
= 23,81 r/sec
OR
NB = NC = 1714,29 r/min
NB × TB = NA × TA
NA × TA ND × TD = NC × TC
NB =
TB NC × TC
ND =
3000 × 20 TD
=
35 1714,29 × 25
=
= 1714,29 r/min 30
1428,57 r/min
=
60
= 23,81r/sec (6)
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Mechanical Technology: Fitting and Machining 21 DBE/November 2018
NSC – Marking Guidelines
11.5.2 Gear ratio:
Product of the number of teeth on driven gears
Gear ratio =
Product of the number of teeth on driver gears
35 30
= ×
20 25
= 2,1 : 1 (3)
11.6 Work done:
Work done = F × s
= 250 × 15
= 3750 Joule or N.m (2)
TOTAL QUESTION 11: [28]
TOTAL: 200
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