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NATIONAL
SENIOR CERTIFICATE
NASIONALE
SENIOR SERTIFIKAAT
GRADE/GRAAD 12
PHYSICAL SCIENCES: CHEMISTRY (P2)
FISIESE WETENSKAPPE: CHEMIE (V2)
FEBRUARY/MARCH/FEBRUARIE/MAART 2013
MEMORANDUM
MARKS/PUNTE: 150
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Physical Sciences Grade 12 P2 NSC Supplementary 2013 Memo
Grade 12 Physical Sciences Paper 2 memorandum from the NSC Supplementary 2013, 16 pages. Read online or download the free PDF.
Physical Sciences · Grade 12 · NSC Supplementary · 2013. Memorandum, 16 pages. Read online or download the PDF.
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- Physical Sciences
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- Memorandum
- Year
- 2013
- Exam period
- NSC Supplementary
- Paper
- 2
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- CAPS
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1 of 16
This exam
NSC Supplementary 2013
- Paper 1Question paperMemo
- Paper 2Question paperMemo
Questions in this paper
- Question 1Organic Compounds and Macromolecules5 marks
- Question 2Organic Compounds and Macromolecules20 marks
- Question 3Organic Compounds and Macromolecules13 marks
- Question 4Organic Compounds and Macromolecules14 marks
- Question 5Organic Compounds and Macromolecules13 marks
- Question 6The Fertiliser Industry14 marks
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Physical Sciences P1/Fisiese Wetenskappe V2 2 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
SECTION A/AFDELING A
QUESTION 1/VRAAG 1
1.1 Alcohols/Alkanols
Alkohole/Alkanole (1)
1.2 Cracking/Elimination
Kraking/Eliminasie (1)
1.3 (Reaction) rate/Rate (of reaction)
(Reaksie-)tempo/Tempo (van reaksie) (1)
1.4 Electrolysis/Elektrolise (1)
1.5 Haber (process)/Haber(-proses) (1)
[5]
QUESTION 2/VRAAG 2
2.1 D (2)
2.2 B (2)
2.3 A (2)
2.4 A (2)
2.5 C (2)
2.6 C (2)
2.7 D (2)
2.8 B (2)
2.9 D (2)
2.10 C (2)
[20]
TOTAL SECTION/TOTAAL AFDELING A: 25
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Physical Sciences P1/Fisiese Wetenskappe V2 3 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
SECTION B/AFDELING B
QUESTION 3/VRAAG 3
3.1
3.1.1 E (1)
3.1.2 A (1)
3.1.3 A (1)
3.1.4 F (1)
3.1.5 A OR/OF D (1)
3.1.6 C (1)
3.2
3.2.1 H H H
Notes/Aantekeninge
H C C C C C H Functional group:
Whole structure correct:
H H H H H
Funksionele groep:
Hele struktuur korrek:
Notes/Aantekeninge:
• Condensed or semistructural formula: 1
2
Gekondenseerde of semistruktuurformule: 1
2
• Molecular formula/Molekulêre formule: 0
(2)
2
3.2.2 H
H C H
H H H H H H
H C C C C C C C H
H H H H H H
H C H
H
Notes/Aantekeninge:
• Condensed or semistructural formula:/Gekondenseerde of semistruktuurformule: 1
2
• All bonds shown, one or more H atoms omitted: Max. 1
2
Alle bindings aangetoon, een of meer H-atome uitgelaat: Maks. 1
2
• Wrong number of bonds e.g. C atoms not forming 4 bonds: 0
2
Verkeerde aantal bindings bv. C-atome vorm nie 4 bindings nie: 0 (2)
2
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Physical Sciences P1/Fisiese Wetenskappe V2 4 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
3.3
3.3.1 Carbonyl (group)/Karboniel(groep) (1)
3.3.2 2-methylpropan-1-ol Notes/Aantekeninge:
2-metielpropan-1-ol IF/INDIEN:
2 methyl 1 propanol/2 metiel 1 propanol 1
OR/OF 2
2-methyl-1-propanol 2 methylpropan 1 ol/2 metielpropan 1 ol 1
2
2-metiel-1-propanol (2)
[13]
QUESTION 4/VRAAG 4
4.1
4.1.1 Gas (1)
4.1.2 Lower than
- Isomers of A:
More branching/Molecules more compact./Smaller surface area (over which
the intermolecular forces act.)
Weaker/less intermolecular forces.
Less energy needed to overcome intermolecular forces.
Laer as
- Isomere van A:
Meer vertak/Molekule meer kompak./Kleiner oppervlakte (waaroor
intermolekulêre kragte werk.)
Swakker/minder intermolekulêre kragte.
Minder energie benodig om intermolekulêre kragte te oorkom.
OR/OF
Lower than
- A is less branched./has less compact molecules./has larger surface area
(over which intermolecular forces act).
Stronger/more intermolecular forces.
More energy needed to overcome intermolecular forces.
Laer as
- A en B is minder vertak./het minder kompakte molekule./ het groter
oppervlakte (waaroor intermolekulêre kragte werk).
Sterker/meer intermolekulêre kragte.
Meer energie benodig om intermolekulêre kragte te oorkom. (4)
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Physical Sciences P1/Fisiese Wetenskappe V2 5 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
4.1.3 2C 4 H 10 + 13O 2 → 8CO 2 + 10H 2 O bal.
Notes/Aantekeninge
• Reactants Products Balancing
Reaktanse Produkte Balansering
• Ignore/Ignoreer ⇌
• Marking rule 3.9/Nasienreël 3.9 (3)
4.1.4 Compound B contains a carbonyl group/O atom (bonded to C atom)
and is a polar (molecule)/dipole.
Verbinding B bevat 'n karbonielgroep/O-atoom (gebind aan 'n C-atoom)
en is 'n polêre (molekuul)/dipool. (2)
4.2
4.2.1 Compound D: Two sites for hydrogen bonding/forms dimers
Compound C: One site for hydrogen bonding
Verbinding D: Twee punte vir waterstofbindings/vorm dimere
Verbinding C: Een punt vir waterstofbinding
Both compounds have hydrogen bonding (between molecules).
Compound D has two sites for/stronger/more hydrogen bonding./
Beide verbindings het waterstofbindings (tussen molecule).
Verbinding D het twee punte vir/sterker/meer waterstofbinding. (2)
4.2.2 - (Compound/Verbinding) C
Lowest boiling point/Laagste kookpunt (2)
[14]
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Physical Sciences P1/Fisiese Wetenskappe V2 6 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
QUESTION 5/VRAAG 5
5.1 Primary/Primêr (1)
5.2
5.2.1 Elimination/dehydration
Eliminasie/dehidrering/dehidrasie (1)
5.2.2 H H H H H H
H
H C C C C O H H C C C C + O H
H H H H H H H H H
Functional group/Funksionele groep:
Whole structure correct/Hele struktuur korrek:
Notes/Aantekeninge:
• Accept -OH as condensed in structural formula.
Aanvaar -OH as gekondenseerd in struktuurformule.
• Accept H 2 O as condensed or any shape.
Aanvaar H 2 O as gekondenseerd of enige vorm.
• Condensed/semistructural formulae or mixture of both: Max. 4
5
Gekondenseerde/semistruktuurformules of mengsel van beide: Maks. 4
5
• Molecular formula for all structures, e.g. C 4 H 10 O: Max. 1
5
Molekulêre formules vir alle strukture, bv. C 4 H 10 O: Maks. 1
5
• Any additional reactants or products: Max. 4
5
Enige addisionele reaktanse of produkte: Maks. 4
5
• Everything correct, wrong balancing: Max. 4
5
Alles korrek, verkeerde balansering: Maks. 4
5 (5)
5.3
5.3.1 Esterification/(Acid catalysed) condensation
Verestering/(Suurgekataliseerde) kondensasie/Esterifikasie (1)
5.3.2 Notes/Aantekeninge
H H H H O H Functional group:
Whole structure correct:
H C C C C O C C H
Funksionele groep:
H H H H H Hele struktuur korrek: (2)
Notes/Aantekeninge:
• Condensed or semistructural formula: 1
2
Gekondenseerde of semistruktuurformule: 1
2
• Molecular formula/Molekulêre formule: 2
0
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Physical Sciences P1/Fisiese Wetenskappe V2 7 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
5.4
5.4.1 Substitution
Substitusie (1)
5.4.2 1-bromobutane
1-bromobutaan (2)
[13]
QUESTION 6/VRAAG 6
6.1 Conical (flask)/Koniese (fles)
OR/OF
Erlenmeyer (flask/fles) (1)
6.2 Collect gas produced./Measure volume of gas produced.
Vang bereide gas op./Meet volume gas berei. (1)
6.3
6.3.1 Concentration/Konsentrasie (1)
6.3.2 ANY ONE/ENIGE EEN:
Temperature
Surface area/State of division
Temperatuur
Reaksieoppervlak/Toestand van verdeeldheid (1)
6.4 P
- Higher (acid) concentration in experiment 2.
Steeper slope/Greater gradient
Hoër (suur)konsentrasie in eksperiment 2.
Steiler helling/Groter gradiënt.
OR/OF
Higher (acid) concentration in experiment 2.
Same volume of gas produced/collected in a shorter time/faster.
Hoër (suur)konsentrasie in eksperiment 2.
Dieselfde volume gas berei/opgevang in 'n korter tyd/vinniger. (3)
6.5 Concentration of acid decreases as reaction proceeds.
Konsentrasie van suur verminder soos wat die reaksie verloop.
OR/OF
Surface area of Zn decreases.
Reaksieoppervlak van Zn verminder. (1)
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Physical Sciences P1/Fisiese Wetenskappe V2 8 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
6.6 V Mark Allocation/Puntetoekenning
n(H 2 ) =
Vm
• Substitute volume.
0,24
= Vervang volume.
24,04 • Substitute molar volume.
= 0,01 mol Vervang molêre volume.
n(Zn) =
m • n(H 2 ) = 0,01 mol
M • n(Zn) = n(H 2 )
m • Substitute/Vervang 65 g·mol-1.
∴ 0,01 =
65 • Answer/Antwoord
∴m = 0,65 g
OR/OF
1 mole/mol H 2 gas = 24,04 dm3
0,01 mol/mol H 2 gas = 0,24 dm3
65 g Zn = 1 mole/mol
0,65 g = 0,01 mole/mol (6)
[14]
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Physical Sciences P1/Fisiese Wetenskappe V2 9 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
QUESTION 7/VRAAG 7
7.1 - Exothermic
∆H is negative./less than zero.
- Eksotermies
∆H is negatief./kleiner as nul.
OR/OF
- Exothermic/Eksotermies
Energy is released./Energie word vrygestel. (2)
7.2
7.2.1
- Greater than/Greater at t 1 than at t 2 .
Larger/Steeper gradients/slopes.
- Groter as/Groter by t 1 as t 2 .
Groter/steiler gradiënte/hellings.
OR/OF
at t 2 than at t 1 .
- Smaller
Smaller/less steep gradients/slopes.
- Kleiner by t 2 as by t 1 .
Kleiner/minder steil gradiënte/hellings. (2)
7.2.2 Equal to/Gelyk aan (1)
7.2.3 CALCULATIONS USING NUMBER OF MOLES
BEREKENINGE WAT AANTAL MOL GEBRUIK
Mark allocation/Puntetoekenning
• Initial amount of reactants: n(HCℓ) = 1 mol & n(O 2 ) = 0,3 mol
Aanvanklike hoeveelheid reaktanse: n(HCℓ) = 1 mol & n(O 2 ) = 0,3 mol
• Equilibrium/Ewewig: n(O 2 ) = 0,1 mol
• USING ratio/GEBRUIK verhouding: 4 : 1 : 2 : 2
• Equilibrium: n(HCℓ) = 0,2 mol (initial – change)
Ewewig: n(HCℓ) = 0,2 mol (aanvanklik – verandering)
• Equilibrium: n(H 2 O) = n(Cℓ 2 ) = 0,4 mol (initial + change)
Ewewig: n(H 2 O) = n(Cℓ 2 ) = 0,4 mol (aanvanklik – verandering)
• Divide by volume/Gedeel deur volume (5 dm3)
• Correct K c expression (formulae in square brackets)
Korrekte K c -uitdrukking (formules tussen vierkanthakies)
• Substitution of concentrations/Vervanging van konsentrasies
• Final answer/Finale antwoord: 800
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Physical Sciences P1/Fisiese Wetenskappe V2 10 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
Option 1/Opsie 1:
From graph/Uit grafiek:
Initially/Aanvanklik n(HCℓ) = 1 mol & n(O 2 ) = 0,3 mol
At equilibrium/By ewewig n(O 2 ) = 0,1 mol
Ratio/verhouding:
n(HCℓ) reacted/gereageer = 4n(O 2 ) reacted/gereageer
n(H 2 O) formed/gevorm = n(Cℓ 2 ) formed/gevorm = 2n(O 2 ) reacted/gereageer
= 2(0,2) = 0,4 mol
At equilibrium/By ewewig:
n(HCℓ) = 0,2 mol/(initial/aanvanklik – change/verandering)
n(H 2 O) = n(Cℓ 2 ) = 0,4 mol (initial/aanvanklik + change/verandering)
Equilibrium concentration/Ewewigskonsentrasies:
n 0,2
c(HCℓ) = = = 0,04 mol∙dm-3
V 5
n 0,1
c(O 2 ) = = = 0,02 mol∙dm-3
V 5
Divide by 5
n 0,4 -3 Deel deur 5
c(H 2 O) = = = 0,08 mol∙dm
V 5
n 0,4
c(Cℓ 2 ) = = = 0,08 mol∙dm-3
V 5
[H O] [C 2 ]2
2
(0,08)2 (0,08)2
KC = 2 ∴ = 800
[HC]4 [O2 ] (0,04 )4 (0,02)
No KC expression, correct substitution/Geen Kc -uitdrukking, korrekte substitusie:
Max./Maks. 8
9
Wrong KC expression/Verkeerde Kc-uitdrukking:
Max./Maks. 6
9
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Physical Sciences P1/Fisiese Wetenskappe V2 11 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
Option 2/Opsie 2
HCℓ O2 H2O Cℓ 2
Initial quantity (mol)
1 0,3 0 0
Aanvangshoeveelheid (mol)
Change (mol)
Verandering (mol) -0,8 -0,2 + 0,4 + 0,4 ratio
verhouding
Quantity at equilibrium (mol)/
0,2 0,1 0,4 0,4
Hoeveelheid by ewewig(mol)
0,2 0,1 0,4 0,4
Equilibrium concentration (mol∙dm-3) Divide by 5
Ewewigskonsentrasie (mol∙dm-3) 5 5 5 5
(0,04) (0,02) (0,08) (0,08) Deel deur 5
[H2O]2 [C 2 ]2 (0,08)2 (0,08)2
KC = ∴ = 800
[HC]4 [O2 ] (0,04 )4 (0,02)
No KC expression, correct substitution/Geen Kc-uitdrukking, korrekte substitusie:
Max./Maks. 8
9
Wrong KC expression/Verkeerde Kc-uitdrukking:
Max./Maks. 6
9
CALCULATIONS USING CONCENTRATIONS
BEREKENINGE WAT KONSENTRASIES GEBRUIK
Mark allocation/Puntetoekenning
• Initial concentration of reactants/Aanvanklike konsentrasie van reaktanse:
c(HCℓ) = 0,2 & c(O 2 ) = 0,06 mol∙dm-3
• Equilibrium/Ewewig:c(O 2 ) = 0,02 mol∙dm-3
• USING ratio/GEBRUIK verhouding: 4 : 1 : 2 : 2
• Equilibrium: c(HCℓ) = 0,04 mol (initial – change)
Ewewig: c(HCℓ) = 0,04 mol (aanvanklik – verandering)
• Equilibrium/Ewewig: c(H 2 O) = c(Cℓ 2 ) = 0,08 mol (initial + change)
Ewewig: c(H 2 O) = c(Cℓ 2 ) = 0,08 mol (aanvanklik + verandering)
• Correct K c expression (formulae in square brackets).
Korrekte K c -uitdrukking (formules tussen vierkanthakies).
• Substitution of concentrations/Vervanging van konsentrasies.
• Final answer/Finale antwoord: 800
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Physical Sciences P1/Fisiese Wetenskappe V2 12 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
Option 3/Opsie 3
HCℓ O2 H2O Cℓ 2
Initial concentration (mol∙dm )
-3
1 3 Divide by 5
Aanvangshoeveelheid (mol∙dm-3) = 0,2 = 0,06 0 0
5 5
Change (mol∙dm-3) ratio
-0,16 -0,04 +0,08 +0,08
Verandering (mol∙dm-3)
Equilibrium concentration (mol∙dm-3)
0,04 0,02 0,08 0,08
Ewewigskonsentrasie (mol∙dm-3)
[H 2 O] 2 [C 2 ] 2
(0,08) 2 (0,08) 2
KC = ∴ = 800
[HC] 4 [O 2 ] (0,04 )4 (0,02)
No KC expression, correct substitution/Geen Kc uitdrukking, korrekte substitusie:
Max./Maks. 8
9
Wrong KC expression/Verkeerde Kc-uitdrukking: Max./Maks. 6
9
(9)
7.3 Decreases
- Higher temperature favours the endothermic reaction.
The reverse reaction is favoured.
Less products/more reactants.
Verminder
- Hoër temperatuur bevoordeel die endotermiese reaksie.
Die terugwaartse reaksie word bevoordeel.
Minder produkte/meer reaktanse. (4)
7.4
7.4.1 Decreases/Verminder (1)
7.4.2 Remains the same/Bly dieselfde (1)
7.4.3 Decreases/Verminder (1)
[21]
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Physical Sciences P1/Fisiese Wetenskappe V2 13 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
QUESTION 8/VRAAG 8
8.1 Pressure/Druk: 101,3 kPa (1,013 x 105 Pa)
Temperature/Temperatuur: 25 °C (298 K) (2)
8.2 Salt bridge/Soutbrug (1)
8.3 Anode
- It/ Mg is a stronger reducing agent than H2
and (Mg) will be oxidised.
Dit/Mg is 'n sterker reduseermiddelas H 2
en (Mg) sal geoksideer word.
OR/OF
- Anode
H 2 is a weaker reducing agent than Mg/ it.
and Mg will be oxidised.
H 2 .is 'n swakker reduseermiddel as Mg/dit
en Mg sal geoksideer word. (4)
8.4
Mg(s) | Mg2+(1 mol∙dm-3) || H+(1 mol∙dm-3) | H 2 (g) | Pt(s)
OR/OF
Mg(s) | Mg2+(aq) || H+(aq) | H 2 (g)|Pt(s)
OR/OF
Mg | Mg2+ || H+ | H 2 | Pt
Accept/Aanvaar:
Mg | Mg2+ || H+ | H 2 , Pt (3)
8.5 Option 1/Opsie 1 Notes/Aantekeninge
Eθ cell = Eθ cathode - Eθ anode Accept any other correct formula from the
2,36 = 0,00 – (Eθ anode ) data sheet.
Eθ anode = -2,36 V Aanvaar enige ander korrekte formule
vanaf gegewensblad.
Option 2/Opsie 2 Any other formula using unconventional
abbreviations, e.g. E° cell = E° OA - E° RA
Mg → Mg 2+
+ 2e -
E° = +2,36
2H+ + 2e- → H 2 E° = 0,00 followed by correct substitutions: 3
4
E° = 2,36 V Enige ander formule wat
Mg (red. pot.) = -2,36 V onkonvensionele afkortings gebruik bv.
E° sel = E° OM - E° RM (4)
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Physical Sciences P1/Fisiese Wetenskappe V2 14 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
8.6 Mg(s) + 2H+(aq) → Mg2+(aq) + H 2 (g) Bal.
Notes/Aantekeninge
• Reactants Products Balancing
Reaktanse Produkte Balansering
• Ignore if phases are omitted./Ignoreer indien fases uitgelaat word.
• Ignore/Ignoreer ⇌
• Marking rule 3.9/Nasienreël 3.9
• Marking rule 3.4: One mark is forfeited when the charge of an ion is omitted per
equation (not for the charge on an electron).
Nasienreël 3.4: Een punt word verbeur per vergelyking indien die lading op 'n ioon
uitgelaat word (nie vir die lading op 'n elektron nie.) (3)
[17]
QUESTION 9/VRAAG 9
9.1 Electrolytic/Elektrolities (1)
9.2
9.2.1 A (1)
9.2.2 B (1)
9.3
9.3.1 Remains the same
- The rate of oxidation of copper at the anode is equal
to the rate of reduction of copper(II) ions at the cathode.
Bly dieselfde
- Die tempo van oksidasie van koper by die anode is gelyk aan
Die tempo van reduksie van koper(II)-ione by die katode. (3)
9.3.2 Cu → Cu2+ + 2e- Notes/Aantekeninge
Cu ⇌ Cu2+ + 2e- (1 )
2
Cu + 2e → Cu
2+ -
(0 )
2
Cu2+ + 2e- ← Cu ( 2 )
2
Cu2+ + 2e- ⇌ Cu (0 )
2 (2)
9.4
9.4.1 It contains precious metals/valuable/expensive metals.
Dit bevat edelmetale/waardevole/duur metale. (1)
9.4.2 Consumes large amount of electricity/energy.
Depletes coal resources. OR Contributes to global warming. OR Habitats
destroyed in mining of coal. OR Contributes to acid rain.
Verbruik groot hoeveelhede elektrisiteit/energie.
Put steenkoolbronne uit. OF Dra by tot aardverwarming. OF Habitatte word
vernietig. OF Dra by tot suurreën. (2)
[11]
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Physical Sciences P1/Fisiese Wetenskappe V2 15 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
QUESTION 10/VRAAG 10
10.1 Secondary (cells)/Sekondêre (selle) (1)
10.2 Zn(s) + NiO 2 (s) + 2H 2 O(ℓ) → Zn2+(aq) + Ni(OH) 2 (s) + 2OH-(aq) bal
Notes/Aantekeninge:
• Reactants Products Balancing
Reaktanse Produkte Balansering
• Ignore if phases are omitted / Ignoreer indien fases uitgelaat word
• Ignore/Ignoreer ⇌
• Marking rule/Nasienreël 3.9 (3)
10.3
10.3.1 The ability (of a cell) to store/deliver charge.
Die vermoë (van 'n sel) om lading te stoor/lewer. (2)
10.3.2 OPTION 1/OPSIE 1
W = Vq
= (1,65)(1 500 x 10-3 x 3600)
= 8 910 J
OPTION 2/OPSIE 2
q = I∆t
= (1 500 x 10-3)(3 600)
∴ q = 5 400 C
W = Vq
W = (1,65)(5 400)
= 8 910 J (4)
[10]
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Physical Sciences P1/Fisiese Wetenskappe V2 16 DBE/Feb.–Mar./Feb.–Mrt. 2013
NSC/NSS – Memorandum
QUESTION 11/VRAAG 11
11.1
11.1.1 Nitrogen/Stikstof/N 2 (1)
11.1.2 Hydrogen/Waterstof/H 2 (1)
11.1.3 Ammonium nitrate/Ammoniumnitraat/NH 4 NO 3 (1)
11.2
11.2.1 Contact process/Kontakproses (1)
11.2.2 2NH 3 + H 2 SO 4 → (NH 4 ) 2 SO 4 Bal.
Notes/Aantekeninge:
• Reactants Products Balancing
Reaktanse Produkte Balansering
• Ignore/Ignoreer ⇌
• Marking rule/Nasienreël 3.9 (3)
11.3
11.3.1 Catalytic oxidation of ammonia
Katilitiese oksidasie van ammoniak (1)
11.3.2 4NH 3 + 5O 2 → 4NO + 6H 2 O Balancing/Balansering
Notes/Aantekeninge:
• Reactants Products Balancing
Reaktanse Produkte Balansering
• Ignore/Ignoreer ⇌
• Marking rule/Nasienreël 3.9 (3)
11.3.3 NO 2/ Nitrogen dioxide Notes/Aantekeninge
NO 2/ Stikstofdioksied Accept: Nitrogen(IV) oxide
Aanvaar: Stikstof(IV)oksied (1)
[12]
TOTAL SECTION B/TOTAAL AFDELING B: 125
GRAND TOTAL/GROOTTOTAAL: 150
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