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SENIOR CERTIFICATE EXAMINATIONS/
NATIONAL SENIOR CERTIFICATE EXAMINATIONS
SENIORSERTIFIKAAT-EKSAMEN/
NASIONALE SENIORSERTIFIKAAT-EKSAMEN
PHYSICAL SCIENCES: CHEMISTRY (P2)
FISIESE WETENSKAPPE: CHEMIE (V2)
2021
MARKING GUIDELINES/NASIENRIGLYNE
MARKS/PUNTE: 150
These marking guidelines consist of 19 pages./
Hierdie nasienriglyne bestaan uit 19 bladsye.
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Physical Sciences Grade 12 Paper 2 NSC June 2021 Memo
Grade 12 Physical Sciences Paper 2 memorandum from the NSC June Exam 2021, 19 pages. Read online or download the free PDF.
Physical Sciences · Grade 12 · NSC June Exam · 2021. Memorandum. Read online or download the PDF.
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- 2021
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Physical Sciences/P2/Fisiese Wetenskappe/V2 2 DBE/2021
SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne
QUESTION 1/VRAAG 1
1.1 C (2)
1.2 D (2)
1.3 C (2)
1.4 B (2)
1.5 D (2)
1.6 C (2)
1.7 B (2)
1.8 B (2)
1.9 A (2)
1.10 B (2)
[20]
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Physical Sciences P2/Fisiese Wetenskappe V2 3 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
QUESTION 2/VRAAG 2
2.1
2.1.1 F (1)
2.1.2 B&F (1)
2.1.3 C (1)
2.2
2.2.1 Haloalkane / alkyl halide
Haloalkaan/alkielhalied (1)
2.2.2 3,5-dibromooctane
3,5-dibroomoktaan
Marking criteria/Nasienkriteria:
Octane/Oktaan
Dibromo/Dibroom
Substituents (dibromo) correctly numbered, hyphens, commas correctly used./
Substituente (dibroom) korrek genommer, koppeltekens en kommas korrek
gebruik. (3)
2.3
2.3.1 Pentan-3-one Marking criteria/Nasienkriteria:
Pentan-3-oon Pentanone/pentanoon
OR/OF Correct position of functional group.
3-pentanone Korrekte posisie van funksionele groep.
3-pentanoon (2)
2.3.2 3-methylbutan-2-one/3-metielbutan-2-oon
OR/OF
3-methylbutanone/3-metielbutanoon
OR/OF
methylbutanone/metielbutanoon
OR/OF
3-methyl- 2-butanone/3-metiel-2-butanoon (2)
2.4
2.4.1 Hexyl methanoate
Heksielmetanoaat (2)
2.4.2 O O
OR/OF
C O C R C O R
(1)
2.5
2.5.1 Cracking/Elimination
Kraking/eliminasie (1)
2.5.2 C7H16 (2)
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Physical Sciences P2/Fisiese Wetenskappe V2 4 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
2.5.3 H H Notes/Aantekeninge
Functional group/Funksionele
H C C C H groep:
Whole structure correct/Hele
H H struktuur korrek: (2)
[19]
QUESTION 3/VRAAG 3
3.1 Marking guidelines/Nasienkriteria:
If any one of the underlined key phrases in the correct context is omitted, deduct 1
mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is,
trek 1 punt af.
The pressure exerted by a vapour at equilibrium with its liquid in a closed
system.
Die druk uitgeoefen deur 'n damp in ewewig met sy vloeistoffase in 'n geslote
sisteem. (2)
3.2 Functional group/Type of intermolecular forces/Homologous series
Funksionele groep/Tipe intermolekulêre kragte/Homoloë reeks (1)
3.3 B (1)
3.4 Marking criteria/Nasienkriteria
State hydrogen bonding in A./Noem waterstofbinding in A.
State dipole-dipole forces in B./Noem dipool-dipoolkragte in B.
Compare strengths of IMFs./Vergelyk sterktes van IMKe.
Compare energies required./Vergelyk energieë benodig.
Compound A/butan-1-ol has hydrogen bonding (dipole-dipole and
London forces) between molecules.
Compound B/butan-2-one has dipole-dipole forces (and London forces)
between molecules.
Intermolecular forces in compound A/butan-1-ol are stronger than
intermolecular forces in compound B/butan-2-one.
OR
Intermolecular forces in compound B/butan-2-one are weaker than
intermolecular forces in compound A/butan-1-ol.
More energy is needed to overcome/break intermolecular forces in
compound A/butan-ol than in compound B/butan-2-one.
Verbinding A/butan-1-ol het waterstofbindings (dipool-dipoolkragte en
Londonkragte) tussen molekule.
Verbinding B/butan-2-oon het dipool-dipoolkragte (en London kragte)
tussen molekule.
Intermolekulêre kragte in verbinding A/butan-1-ol is sterker as
intermolekulêre kragte in verbinding B/butan-2-oon.
OF
Intermolekulêre kragte in verbinding B/butan-2-oon is swakker as
intermolekulêre kragte in verbinding A/butan-1-ol.
Meer energie is nodig om intermolekulêre kragte te oorkom/breek in
verbinding A/butan-1-ol as in verbinding B/butan-2-oon. (4)
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Physical Sciences/P2/Fisiese Wetenskappe/V2 5 DBE/2021
SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne
3.5
3.5.1 Boiling point (of compound A/butan-1-ol)
Kookpunt (van verbinding A/butan-1-ol) (1)
3.5.2 Gas (1)
3.5.3 Marking criteria/Nasienkriteria:
A Curve C starts below curve
A/Kurwe C begin onder
Vapour pressure (kPa)
C kurwe A.
Curve C remains below
curve A/ Kurwe C bly onder
101,3 kurwe A.
Accept/Aanvaar
Dampdruk (kPa)
If C is labelled as B / Indien
C as B benoem is
If graph below graph A is
unlabelled /Indien grafiek
Temperature/Temperatuur (°C) onder grafiek A nie
benoemis nie
Note/Let Wel
If both graphs unlabelled / Indien
beide grafiek nie benoem is nie:
0 marks / 0 punte (2)
[12]
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Physical Sciences P2/Fisiese Wetenskappe V2 6 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
QUESTION 4/VRAAG 4
4.1
4.1.1 Heat/sunlight/ultraviolet light/radiation/light
Hitte/sonlig/ultravioletlig/straling/lig (1)
4.1.2 HBr/hydrogen bromide/waterstofbromied (1)
4.1.3 Hydrolysis/hidrolise (1)
4.1.4 H2O/water
Accept/Aanvaar
hydrogen oxide/waterstofoksied
OR/OF
NaOH/KOH/LiOH/sodium hydroxide/potassium hydroxide/lithium hydroxide
NaOH/KOH/LiOH/Natriumhidroksied/kaliumhidroksied/litiumhidroksied (1)
4.1.5 2-bromopropane
2-bromopropaan (2)
4.2 Marking criteria/Nasienkriteria:
(Mark bullets independently. / Sien kolpunte onafhanklik na.)
React chloroethane with (conc) NaOH or NaOH in ethanol.
Indicate heat/Δ (on the arrow) or as a reactant in the reaction of chloroethane.
Correct condensed formula for ethene as product.
Product NaCℓ in the reaction of chloroethane.
Product H2O in the reaction of chloroethane.
React ethene with H2.
Indicate Pt on the arrow of / at the reaction of ethene with H2.
Correct condensed formula of ethane as product.
.
Reageer chloroetaan met (gekons) NaOH of NaOH in etanol.
Dui hitte/Δ (op die pyl) of as ‘n reaktant in die reaksie van chloroetaan.
Korrekte gekondenseerde formule vir eteen as produk.
Produk NaCℓ in die reaksie van chloroetaan.
Produk H2O in die reaksie van chloroetaan.
Reageer eteen met H2
Dui Pt aan op die pyl / by die reaksie van eteen met H2.
Korrekte gekondenseerde formule vir etaan as produk.
+ NaOH (in ethanol/etanol)
CH3CH2Cℓ + (conc/gekons) NaOH ∆ CH2CH2 + NaCℓ + H2O
Pt
CH2CH2 + H2 CH3CH3
Note/Let wel
Any additional reactants or products: Deduct one mark per reaction
Enige addisionele reaktanse of produkte: Trek een punt af per reaksie (8)
[14]
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Physical Sciences/P2/Fisiese Wetenskappe/V2 7 DBE/2021
SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne
QUESTION 5/VRAAG 5
5.1 NOTE/LET WEL
Give the mark for per unit time only if in context of reaction rate.
Gee die punt vir per eenheidtyd slegs indien in konteks met reaksietempo.
ANY ONE/ENIGE EEN
Change in concentration of products/reactants per (unit) time.
Verandering in konsentrasie van produkte/reaktanse per (eenheid)tyd.
Change in amount/number of moles/volume/mass of products or reactants
per (unit) time.
Verandering in hoeveelheid/getal mol/volume/massa van produkte of
reaktanse per (eenheid)tyd.
Amount/number of moles/volume/mass of products formed/reactants used
per (unit) time.
Hoeveelheid/getal mol/volume/massa van produkte gevorm/reaktanse
gebruik per (eenheid)tyd.
Rate of change in concentration/amount/number of moles/volume/mass.
Tempo van verandering in konsentrasie/ hoeveelheid/getal mol/ volume/
massa. (2 or/of 0) (2)
5.2 Time/tyd
Volume of gas/CO2/carbon dioxide (in gas syringe)
Volume gas/CO2/koolstofdioksied (in gasspuit)
OR/OF
Time taken for Aℓ2(CO3)3 to be used up.
Tyd geneem vir die Aℓ2(CO3)3 om opgebruik te word.
Accept/Aanvaar
Measure volume of gas/CO2 at regular time intervals.
Meet volume van gas/CO2 met gereelde tydintervalle. (2)
5.3 Experiment II/Eksperiment II:
More (HCℓ) particles per unit volume./More particles with correct
orientation.
More effective collisions per unit time./Higher frequency of effective
collisions.
Higher reaction rate.
Meer (HCℓ)-deeltjies per eenheid volume./Meer deeltjies met korrekte
oriëntasie.
Meer effektiewe botsings per eenheid tyd./Hoër frekwensie van effektiewe
botsings.
Hoër reaksietempo. (3)
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Physical Sciences P2/Fisiese Wetenskappe V2 8 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
OR/OF
Experiment I/Eksperiment I:
Less (HCℓ) particles per unit volume.
Less effective collisions per unit time./Lower frequency of effective
collisions.
Lower reaction rate.
Minder (HCℓ) deeltjies per eenheidvolume.
Minder effektiewe botsings per eenheidtyd./ Laer frekwensie van
effektiewe botsings.
Laer reaksietempo.
5.4 OPTION 1/OPSIE 1 Marking criteria/Nasienkriteria
n Substitute average rate and ∆t./
ave rate/gem tempo = - Vervang gemiddelde tempo en ∆t.
t
Substitute/Vervang ∆n.
n 0,016
4,4 x 10-3 = - f Final answer/Finale antwoord:
2,5 ( 0) 0,005 (mol)
n[Aℓ2(CO3)3] = 0,005 (mol) NOTE/LET WEL
OPTION 2/OPSIE 2 Accept negative answers when the
n negative sign in front of the formula is
ave rate/gem tempo = omitted./Aanvaar negatiewe antwoord
t wanneer die negatiewe teken voor die
-3 n formule uitgelaat is.
4,4 x 10 =
2,5 Do not penalise if initial and final mole
values or time values are swopped. /
Δn[Aℓ2(CO3)3] = 0,016 – 0,011 Moenie penaliseer indien aanvanklike
= 0,005 mol en finale molwaardes omgeruil is nie.
OPTION 3/OPSIE 3
With reference to CO2/Met verwysing na CO2
n
ave. rate/gem tempo =
t
n
4,4 x 10-3 =
2,5
Δn(CO2) = 0,011 mol
n(CO2) : n(Aℓ2(CO3)3
3 : 1
0,011 : 3,67 x 10-3 mol
n(Aℓ2(CO3)3 left/oor = 0,016 - 3,67 x 10-3 = 1,23 x 10-2 mol
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Physical Sciences P2/Fisiese Wetenskappe V2 9 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
OPTION 4/OPSIE 4
With reference to HCℓ/Met verwysing na HCℓ
n
ave. rate/gem tempo =
t
n
4,4 x 10-3 =
2,5
Δn(HCℓ) = 0,011 mol
0,011
n[Aℓ2(CO3)3] = = 0,0018 mol
6
n[Aℓ2(CO3)3] left/oor = 0,016 – 0,0018 = 0,0142 mol
OPTION 5/OPSIE 5
With reference to AℓCℓ3/Met verwysing na AℓCℓ3
n
ave. rate/gem tempo =
t
n
4,4 x 10-3 =
2,5
Δn(AℓCℓ3) = 0,011 mol
n[Aℓ2(CO3)3] = 0,0055 mol
n[Aℓ2(CO3)3] left/oor = 0,016 – 0,0055 = 0,0105 mol (3)
5.5 Marking criteria/Nasienkriteria:
Use mol ratio/Gebruik molverhouding: n(CO2) : n(Aℓ2(CO3)3) = 3 : 1
3 -1 3 -1 V
Substitute 24 000 cm ∙mol /24 dm ∙mol in n = or in ratio.
VM
V
Vervang 24 000 cm3∙mol-1/24 dm3∙mol-1 in n = of in verhouding.
VM
Final answer/Finale antwoord: 1 152 cm3 / 1,152 dm3
OPTION 1/OPSIE 1 OPTION 2/OPSIE 2
n(CO2) = 3n[Aℓ2(CO3)3] n(CO2) = 3n[Aℓ2(CO3)3]
= 3(0,016) = 3(0,016)
= 0,048 mol = 0,048 mol
V
n(CO2) = 1 mol ……………….24 000 cm3
VM
0,048 mol ………….V
V
0,048 = 0,048 24000
24000 V(CO2) =
3 3 1
V(CO2) = 1 152 cm (1,152 dm )
= 1 152 cm3 (1,152 dm3) (3)
[13]
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Physical Sciences P2/Fisiese Wetenskappe V2 10 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
QUESTION 6/VRAAG 6
6.1 (The stage in a chemical reaction when the) rate of forward reaction equals
the rate of reverse reaction.
(Die stadium in 'n chemiese reaksie wanneer die) tempo van die voorwaartse
reaksie gelyk is aan die tempo van die terugwaartse reaksie. (2 or/of 0)
OR/OF
(The stage in a chemical reaction when the) concentrations of reactants and
products remain constant.
(Die stadium in 'n chemiese reaksie wanneer die) konsentrasies van
reaktanse en produkte konstant bly. (2 or/of 0) (2)
6.2
6.2.1 X
- ANY ONE/ENIGE EEN
The concentration of products increases (from 0 – 6 min.).
Die konsentrasie van die produkte neem toe (van 0 - 6 min.).
The concentration of reactants decreases (from 0 – 6 min.).
Die konsentrasie van die reaktanse neem af (van 0 – 6 min.).
No products were present initially.
Geen produkte was aanvanklik teenwoordig nie.
The curve begins at zero./Die kurwe begin by nul. (2)
6.2.2 Higher than/Hoër as (1)
6.3 CALCULATIONS USING NUMBER OF MOLES
BEREKENINGE WAT AANTAL MOL GEBRUIK
Marking criteria/Nasienkriteria
Calculate/Bereken mol HI: n(HI)ini/aanv. = 1(0,5).
Use mol ratio/Gebruik molverhouding: 2:1:1 / n(HI) = 2n(H2) = 2n(I2).
n(H2)equilibrium/ewewig = n(H2)formed/gevorm
n(I2)equilibrium/ewewig = n(I2)formed/gevorm
Note: If Δn not shown award mark for equal nequilibrium
Let wel: Indien Δn nie aangedui is nie, ken punt toe vir gelyke newewig
n((HI)equilibrium/ewewig = n(HI)initial/aanvanklik - n(HI)change/verandering.
Divide n(HI)equil & n(H2)equil & n(H2)equil by 0,5 dm3.
Deel n(HI)ewewig & n(H2)ewewig & n(H2)ewewig deur 0,5 dm3.
Correct Kc expression (formulae in square brackets).
Korrekte Kc-uitdrukking (formules in vierkanthakies).
Substitute 0,04 into Kc expression.
Vervang 0,04 in Kc-uitdrukking.
Substitute equilibrium concentrations in Kc expression.
Vervang ewewigskonsentrasies in Kc-uitdrukking.
Final answer/Finale antwoord: 0,07 mol
Range/Gebied: 0,07 – 0,072 mol
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Physical Sciences P2/Fisiese Wetenskappe V2 11 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
OPTION 1/OPSIE 1
n(HI) = 1(0,5) = 0,5 mol
HI H2 I2
Initial quantity (mol)
0,5 0 0
Aanvangshoeveelheid (mol)
Change (mol) ratio
2x x x
Verandering (mol) verhouding
Quantity at equilibrium (mol)/
0,5-2x x x
Hoeveelheid by ewewig (mol)
Equilibrium concentration (mol∙dm-3) 0,5 - 2x x x divide by 0,5
Ewewigskonsentrasie (mol∙dm-3) 0,5 0,5 0,5 deel deur 0,5
[H2 ][I2 ] No KC expression, correct substitution/Geen Kc-
Kc =
[HI] 2 8
uitdrukking, korrekte substitusie: Max./Maks.
x x 9
( )( )
0,5 0,5 Wrong KC expression /Verkeerde Kc-uitdrukking:
0,04 = 6
0,5 - 2x 2 Max./Maks.
( ) 9
0,5
x = 0,071 mol
CALCULATIONS USING CONCENTRATION
BEREKENINGE WAT KONSENTRASIE GEBRUIK
Marking criteria/Nasienkriteria:
Use initial/Gebruik aanvanklike c(HI) = 1 mol∙dm-3.
Use mol ratio/Gebruik molverhouding: 2 : 1: 1 / n(HI) = 2n(H2) = 2n(I2).
c(H2)equilibrium/ewewig = c(H2)formed/gevorm
c(I2)equilibrium/ewewig = c(I2)formed/gevorm
Note: If Δc not shown award mark for equal cequilibrium
Let wel: Indien Δc nie aangedui is nie, ken punt toe vir gelyke cewewig
c(HI)equilibrium/ewewig = c(HI)initial - c(HI)change.
Correct Kc expression (formulae in square brackets).
Korrekte Kc-uitdrukking (formules in vierkanthakies).
Substitution of 0,04 into Kc expression.
Vervang 0,04 in Kc-uitdrukking.
Substitution of equilibrium concentrations into Kc expression.
Vervanging van ewewigskonsentrasies in Kc-uitdrukking.
Multiply concentration by 0,5 dm3.
Vermenigvuldig konsentrasie met 0,5 dm3.
Final answer/Finale antwoord: 0,07 mol
Range/Gebied: 0,07 to/tot 0,072 mol
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Physical Sciences P2/Fisiese Wetenskappe V2 12 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
OPTION 2/OPSIE 2
HI H2 I2
-3
Initial concentration (mol∙dm )
1 0 0
Aanvangskonsentrasie (mol∙dm-3)
Change (mol∙dm-3)
2x x x
Verandering (mol∙dm-3)
Equilibrium concentration (mol∙dm-3)
Ewewigskonsentrasie (mol∙dm-3) 1-2x x x
[H2 ][I2 ]
Kc = No KC expression, correct substitution/Geen Kc-
[HI] 2 8
uitdrukking, korrekte substitusie: Max./Maks.
( x )( x ) 9
0,04 =
(1 2x )2
Wrong KC expression /Verkeerde Kc-uitdrukking:
x = 0,143 mol∙dm-3 6
Max./Maks.
9
n(I2) = cV
= 0,143 x 0,5
= 0,072 mol (9)
6.4
6.4.1 Both forward and reverse/Beide voorwaartse en terugwaartse (1)
6.4.2 Positive/Positief
The forward reaction is favoured.
Die voorwaartse reaksie word bevoordeel.
An increase in temperature favours the endothermic reaction.
'n Toename in temperatuur bevoordeel die endotermiese reaksie.
The forward reaction is endothermic.
Die voorwaartse reaksie is endotermies. (4)
[19]
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Physical Sciences P2/Fisiese Wetenskappe V2 13 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
QUESTION 7/VRAAG 7
7.1 Standard solution/Standaardoplossing (1)
7.2
7.2.1 Marking criteria/Nasienkriteria:
m m n
Any one of the formulae/Enige een van die formules: c /n /c
MV M V
Substitution of 40 g∙mol-1 into correct formula.
Vervanging van 40 g∙mol-1 in korrekte formule.
Substitution of 0,25 dm3 into correct formula.
Vervanging van 0,25 dm3 in korrekte formule.
Final answer/Finale antwoord: 0,2 mol∙dm-3
OPTION 1/OPSIE 1 OPTION 2/OPSIE 2
m m
c n
MV M
2
2
40 0,25
40 Any one formula/
= 0,20 mol∙dm-3
= 0,05 mol enige formule
n
c
V
0,05
0,25
= 0,20 mol∙dm-3 (4)
7.2.2 POSITIVE MARKING FROM 7.2.1./POSITIEWE NASIEN VAN 7.2.1.
OPTION 1/OPSIE 1 OPTION 2/OPSIE 2
[H3O+][OH-] = 1 x 10-14 pOH = -log[OH-]
[H3O+](0,2) = 1 x 10-14 = -log(0,2)
[H3O+] = 5 x 10-14 mol∙dm-3 = 0,6989 (0,7)
pH = -log[H3O+] pH + pOH = 14
= -log(5 x 10-14) pH = 14 – 0,6989
= 13,30 = 13,30 (4)
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Physical Sciences P2/Fisiese Wetenskappe V2 14 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
7.3 POSITIVE MARKING FROM QUESTION 7.2.
POSITIEWE NASIEN VANAF VRAAG 7.2.
Marking criteria/Nasienkriteria:
Substitution to calculate n(NaOH)./Vervanging om n(NaOH) te bereken.
Use mol ratio/Gebruik molverhouding: n(HCℓ)excess/oormaat : n(NaOH) = 1 : 1.
m
Substitute/Vervang 100 g·mol-1 in n =
M
Use mol ratio Gebruik molverhouding: n(HCℓ)reacted/oormaat : n(CaCO3) = 2 : 1.
n(HCℓ)initial/aanvanklik = n(HCℓ) excess/oormaat + n(HCℓ) reacted/reageer
Substitute 0,05 dm3 to calculate either c(HCℓ)initial or c(HCℓ) reacted
Vervang 0,05 dm3 om c(HCℓ)aanvanklik of c(HCℓ)reageer te bereken.
Final answer/Finale antwoord: 0,7 mol∙dm-3
Range/Gebied: 0,70 to/tot 0,90 mol∙dm-3
OPTION 1/OPSIE 1 OPTION 2/OPSIE 2
n(NaOH)used/gebruik = cbVb 25 2
n(NaOH)used/gebruik =
= 0,2 x 0,025 250 40
= 5 x 10-3 mol = 5 x 10-3 mol
n(HCℓ)excess/oormaat = n(NaOH) = 5 x 10-3 mol
m
n(CaCO3) =
M
1,5
=
100
= 0,015 mol (0,02 mol)
n(HCℓ)reacted/reageer = 2n(CaCO3) = 0,03 mol (0,04 mol)
n(HCℓ)ini/aanv. = 5 x 10-3 + 0,03
= 0,035 mol (0,045 mol)
n
c(HCℓ)ini/aanv =
V
0,035
=
0,05
= 0,70 mol∙dm-3 (0,90 mol∙dm-3)
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Physical Sciences P2/Fisiese Wetenskappe V2 15 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
OPTION 3/OPSIE 3 OPTION/OPSIE 4
c a Va na (NaOH)used/gebruik = cbVb
= (0,2)(0,025)
c b Vb nb
= 0,005 mol
c a (0,05) 1
(0,2)(0,025) 1 n(HCℓ)excess/oormaat = n(NaOH)
= 0,005 mol
ca = c(HCℓ)excess/oormaat
0,005
= 0,1 mol·dm-3 c(HCℓ)excess/oormaat =
0,05
= 0,1 mol·dm-3
m
n(CaCO3) =
M
1,5
=
100
= 0,015 mol
n(CaCO3) : n(HCℓ) = 1 : 2
n(HCℓ)reacted/reageer = 2(0,015)
= 0,03 mol
n
c(HCℓ)reacted/reageer =
V
0,03
=
0,05
= 0,6 mol·dm-3
c(HCℓ)initial/aanvanklik = c(HCℓ)reacted/reageer + c(HCℓ)excess/oormaat
= 0,6 + 0,1
= 0,7 mol·dm-3
(8)
[17]
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Physical Sciences P2/Fisiese Wetenskappe V2 16 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
QUESTION 8/VRAAG 8
8.1
8.1.1 Gain of electrons./Opneem van elektrone. (2 or/of 0) (2)
8.1.2 2H2O(ℓ) + 2e─ H2(g) + 2OH─(aq)
Ignore phases/Ignoreer fases.
Marking criteria /Nasienkriteria:
H2(g) + 2OH─(aq) ← 2H2O(ℓ) + 2e─ (2 )
2
2H2O(ℓ) + 2e ⇌ H2(g) + 2OH (aq)
─ ─
( 1 )
2
H2(g) + 2OH─(aq) ⇌ 2H2O(ℓ) + 2e─ (0 )
2
─ ─ 0
2H2O(ℓ) + 2e ← H2(g) + 2OH (aq) ( )
2
Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op
elektron.
If charge (-) omitted on OH─/Indien lading (-) weggelaat op OH─:
Example/Voorbeeld: 2H2O(ℓ) + 2e─ H2(g) + 2OH(aq) Max./Maks: 1
2 (2)
8.1.3 2Na(s) + 2H2O(ℓ) H2(g) + 2OH-(aq) + 2Na+(aq) Bal
OR/OF
2Na(s) + 2H2O(ℓ) H2(g) + 2NaOH(aq) Bal
Ignore phases/Ignoreer fases.
Marking criteria/Nasienkriteria:
Reactants Products Balancing
Reaktanse Produkte Balansering
Ignore double arrows./Ignoreer dubbelpyle.
Ignore phases/Ignoreer fases.
Marking rule 6.3.10./Nasienreël 6.3.10. (3)
8.1.4 Formation of hydroxide ions / OH- / sodium hydroxide/base/ alkaline/ pH > 7
Vorming van hidroksied / OH- / natriumhidroksied / basis / alkalies / pH > 7 (1)
─
8.1.5 Cu is a weaker reducing agent than H2 (and OH─) and H2O will not be
reduced (to H2 and OH─).
Cu is 'n swakker reduseermiddel as H2 (and OH─) en H2O sal nie gereduseer
word nie na H2 (en OH─).
─
OR/OF
H2 (and OH-) are stronger reducing agent than Cu and H2O will not be
reduced(to H2 and OH-).
H2 (en OH-) is 'n sterker reduseermiddel as Cu en H2O sal nie gereduseer
word (na H2 en OH-). (3)
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Physical Sciences P2/Fisiese Wetenskappe V2 17 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
8.2
8.2.1 Phase separator/boundary/difference
Fase skeiding/grens/verskil (1)
8.2.2 Chemical (energy) to electrical (energy)
Chemiese (energie) na elektriese (energie) (1)
8.2.3 OPTION/OPSIE 1 Notes/Aantekeninge
E cell
E reduction
E oxidation Accept any other correct formula from the data
sheet./Aanvaar enige ander korrekte formule
= 0,77 - (-0,13) vanaf gegewensblad.
E cell = 0,90 V Any other formula using unconventional
abbreviations, e.g. Eθcell = EθOA - EθRA followed by
correct substitutions:/Enige ander formule wat
onkonvensionele afkortings gebruik bv.
Eθsel = EθOM - EθRM gevolg deur korrekte
vervangings: Max/Maks: 3
4
OPTION/OPSIE 2
Pb(s) Pb2+(aq) + 2e- 0,13 (V)
2Fe3+(aq) + 2e- 2Fe2+(aq) 0,77 (V)
2+ 3+ 2+
Pb (aq) + 2Fe (aq) Pb(s) + 2Fe (aq) 0,90 V (4)
[17]
QUESTION 9/VRAAG 9
9.1 Electrolytic (cell)/Elektrolitiese (sel)
-
Cells have a battery/DC power source/ /Electrical energy is converted to
chemical energy.
Selle het batterye/GS kragbron/ Elektriese energie is omgeskakel na
chemiese energie. (2)
9.2
9.2.1 2Cℓ─ Cℓ2 + 2e─
Notes/Aantekeninge
2Cℓ─ ⇌ Cℓ2 + 2e─ ( 1 ) Cℓ2 + 2e─ ← 2Cℓ─ ( 2 )
2 2
─ ─ 0 ─ ─ 0
Cℓ2 + 2e ⇌ 2Cℓ ( ) 2Cℓ ← Cℓ2 + 2e ( )
2 2
Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op elektron.
If charge (-) omitted on Cℓ─/Indien lading (-) weggelaat op Cℓ─:
Example/Voorbeeld: 2Cℓ(aq) Cℓ2(g) + 2e─ Max./Maks: 1
2 (2)
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Physical Sciences P2/Fisiese Wetenskappe V2 18 DBE/2021
SCE/NSC/SSE/NSS – Marking Guidelines/Nasienriglyne
9.2.2 Aℓ3+ + 3e─ Aℓ
Notes/Aantekeninge
Aℓ3+ + 3e─ ⇌ Aℓ ( 1 ) Aℓ ← Aℓ3+ + 3e─ ( 2 )
2 2
─ 0 0
Aℓ ⇌ Aℓ + 3e
3+
( ) 3+
Aℓ + 3e ← Aℓ ( )
2 2
Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op elektron.
If charge (+) omitted on Aℓ3+ /Indien lading (+) weggelaat op Aℓ3+:
Example/Voorbeeld: Aℓ3(aq) + 3e─ Aℓ(s) Max./Maks: 1
2 (2)
9.2.3 Cu/copper/koper (1)
9.3 ANY ONE/ENIGE EEN
The electrode/carbon/C reacts with oxygen.
Die elektrode/koolstof/C reageer met suurstof.
C + O2 CO2
Oxidation takes place./Electrons are lost.
Oksidasie vind plaas./Elektrone word verloor.
Oxygen corrodes the carbon electrode.
Suurstof roes die koolstof elektrode. (1)
[8]
QUESTION 10/VRAAG 10
10.1
10.1.1 Sulphur dioxide/SO2/swaweldioksied (1)
10.1.2 Sulphur trioxide/SO3/swaweltrioksied (1)
10.1.3 Vanadium pentoxide/V2O5/ Vanadium(V) oxide
Vanadiumpentoksied/Vanadium(V) oksied (1)
10.1.4 H2SO4 + 2NH3 (NH4)2SO4 bal
Marking guidelines/Nasienkriteria:
Reactants Products Balancing
Reaktanse Produkte Balansering
Ignore/Ignoreer → and phases / en fases
Marking rule 6.3.10/Nasienreël 6.3.10 (3)
10.2
10.2.1 The ratio of nitrogen (N), phosphorous (P) and potassium (K) in a
fertiliser./The ratio of the primary nutrients
Die verhouding van stikstof (N), fosfor (P) en kalium (K) in die kunsmis. / Die
verhouding van primêre nutriënte. (1)
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SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne
10.2.2 OPTION 1/OPSIE 1
Mass N in 4 kg NH4NO3 / Massa N in 4 kg NH4NO3
28
m(N) = x4
80
= 1,4 kg
m(K) = 2m(N)
= 2,8 kg
m(P) = 3m(N)
= 4,2 kg
m(fertiliser/kunsmis) = 1,4 + 2,8 + 4,2
= 8,4 kg
OPTION 2/OPSIE 2
Mass N in 4 kg NH4NO3/Massa N in 4 kg NH4NO3:
28
m(N) = x4
80
= 1,4 kg
N:P:K
1:3 :2
∴ m(fertiliser/kunsmis) = (6)(1,4)
= 8,4 kg
OPTION 3/OPSIE 3
(2)(14)
%N= x 100 = 35%
80
Nitrogen in 4 kg = 35% of/van 4 = 1,4 kg
N : P : K
1 : 3 : 2
1,4 : 4,2 : 2,8
Total mass of fertiliser /Totale massa kunsmis = 1,4 + 4,2 + 2,8
= 8,4 kg (4)
[11]
TOTAL/TOTAAL: 150
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