Technical Sciences Grade 10 North West June 2019 Memo

Downloaded from hlayiso.com PROVINCIAL ASSESSMENT GRADE 10 TECHNICAL SCIENCES P1 JUNE 2019 MEMORANDUM MARKS: 100 This memorandum consists of 4 pages. Demo NW/JUNE/TEC-SCNE/ EMIS/6*******

Downloaded from hlayiso.com Technical Sciences/P1 2 NW/JUNE 2019 Memorandum – Grade 10 QUESTION 1 1.1 A  (2) 1.2 D  (2) 1.3 C  (2) 1.4 A (2) 1.5 A  (2) 1.6 D  (2) 1.7 B  (2) 1.8 C  (2) 1.9 B  (2) 1.10 B  (2) [20] QUESTION 2 2.1 2.1.2 F=  =1.8(83) + 32 = 181.40 F (3) 2.1.2 500/1000  = 0.5 kg (2) 2.1.3 65× 60  = 3900 s (2) 2.1.3 0.00000165 m = 1.65×10-6 m (2) 2. 2s=  2.52 =  time = 500/2.52 time = 198.41 s (4) 2.3 a=  a= a= a = 0.1 m/s2  (5) [18] QUESTION 3 3.1 A substance which consists of one type of atoms or particles (that has chemical and physical properties that does not change).  (2) 3.2 3.2.1 C (1) 3.2.2 Aand B (2) Demo NW/JUNE/TEC-SCNE/ EMIS/6*******

Downloaded from hlayiso.com Technical Sciences/P1 3 NW/JUNE 2019 Memorandum – Grade 10 3.3 3.3.1 Potassium , zinc, sodium (3) 3.3.2 Fluorine, bromine,Sulphur  (3) 3.3.3 Boron, silicon (2) 3.4 3.4.1 Carbon chloride , CCl4  (2) 3.4.2 Magnesium oxide , MgO (2) 3.4.3 Lead sulphide  , PbS  (2) [19] QUESTION 4 4.1 Gravitational potential energy is the energy of an object due to its position above the surface of the earth and kinetic energy is the energy an object due to its motion . (4) 4.2 Is the sum of gravitational potential energy and kinetic energy of an object.  (2) 4.3 4.3.1 Ep = mgh = (8.5)(9.8)(1)  = 83.3 J (3) 4.3.2 Ep = mgh =(8.5)(9.8)(1.4)  = 116.62 J (3) 4.3.3 Ek = mv2 = 0.5(8.5) (2)2 = 17 J (3) 4.3.4 ME = Ep + Ek  ANY ONE = mgh + mv2 = (8.5)(9.8)(0.9)  + 17 = 91.97 J (4) [20] Demo NW/JUNE/TEC-SCNE/ EMIS/6*******

Downloaded from hlayiso.com Technical Sciences/P1 4 NW/JUNE 2019 Memorandum – Grade 10 QUESTION 5 5.1. It states that for a body in equilibrium the sum of the clockwise moments about a point must be equal to sum of the anticlockwise moments about a point.  (2) 5.2.1 moment = F × d  = 200× (2/100)  = 40 N.m anticlockwise (4) 5.2.2 It is going to up (clockwise)  Moment = F × d  = 300 × 0.02 = 6 N. m clockwise The moment of this block is greater than the moment on the first block, the 200 N block will move up or clockwise as it has smaller moment.  (5) 5.3 MCW = MACW  400 x 3 = F x 2  F = 1200/2 F = 600 N  (4) 5.4 Mechanical advantage is the ratio of load to effort.   (2) 5.5 MA =  =  = 0.5 (3) 5.6 MA =  1.5 = 800/E E = 800/1.5 E = 533.33 N (3) [23] GRAND TOTAL: 100 Demo NW/JUNE/TEC-SCNE/ EMIS/6*******