Technical Sciences Grade 10 P1 Eastern Cape November 2018 Memo

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE / NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 10 NOVEMBER 2018 TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 MARKING GUIDELINE/NASIENRIGLYN MARKS/PUNTE: 150 This marking guideline consists of 7 pages./ Hierdie nasienrglyn bestaan uit 7 bladsye.

Downloaded from hlayiso.com 2 TECHNICAL SCIENCES P1 (EC/NOVEMBER 2018) QUESTION/VRAAG 1 1.1 D 99 1.2 D 99 1.3 A 99 1.4 A 99 1.5 C 99 1.6 B 99 1.7 D 99 1.8 C 99 1.9 C 99 1.10 A 99 (10 x 2) [20] QUESTION/VRAAG 2 2.1 Scalar is a quantity that has magnitude only 99 Skalaar is ʼn hoeveelheid wat slegs grootte het.99 Vector is a quantity with both magnitude and direction 99 Vektor is ʼn hoeveelheid met beide grootte en rigting. 99 (4) 2.2 2.2.1 2,23 99 (kg) (2) 2.2.2 2 900 99 (m) (2) 2.2.3 2,23 x 103 99 (2) 2.3 Shortest distance between two points in a particular direction OR Straight line distance from the starting point to the finishing point with direction 99 Kortste afstand tussen twee punte in ʼn spesifieke rigting OF Die reguitlyn tussen die beginpunt en eindpunt met rigting 99 (2) 2.4 2.4.1 2,9 km 9 (or 2 900 m) (1) 2.4.2 2 km 9 (or 2 000 m) to the RIGHT / na REGS 9 (2) 2.5 v = displacement/time v = verplasing/tyd 9 = 2 000 9 /1 800 9 =1,11 m.s-1 9 (4) 2.6 9 9 Resultant displacement/Resultante verplasing = 0 N 9 (3) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2018) TEGNIESE WETENSKAPPE V1 3 2.7.1 No / Nee 9 There are equal changes in displacement in equal time intervals 9 Therefore velocity is constant 9 Daar is gelyke veranderings in verplasing in gelyke tydintervalle 9 Dus is die snelheid constant 9 (3) 2.7.2 T= 1/F= 1/50 9 = 0,02s 9 Time/tyd = 5 x 0,02 9 = 0,1 s 9 (4) 2.7.3 v = displacement /time= 5 9 x (20/100) 9/0,19 = 2 m.s-19 v = verplasing/tyd = 5 9 x (20/100) 9/ 0,1 9 = 2 m.s-1 9 OR ஽௜௦௣௟௔௖௘௠௘௡௧Ȁ௏௘௥௣௟௔௦௜௡௚ v= ்௜௠௘Ȁ்௬ௗ 9 ଶ଴௖௠ =  99 ଴ǡଵ ଴ǡଶ௠ =  ଴ǡଵ = 2 m.s-1 9 (4) [33] QUESTION/VRAAG 3 3.1 Single force which can produce the same effect as two or more forces 99 ʼn Enkel krag wat dieselfde effek het as twee of meer kragte 99 (2) 3.2 3.2.1 F1 Normal/Normaal 9 (1) 3.2.2 F2 Applied force/Toegepaste krag 9 (1) 3.2.3 F3 Weight or Force of gravity/Gewig of Swaartekrag 9 (1) 3.2.4 F4 Friction/Wrywing 9 (1) 3.3 Weight/Gewig 9 or/of Force of gravity/Swaartekrag 9 (1) 3.4 Fg = mg 9= 60 x 9,8 9 = 588 N 9 (3) 3.5 Take right as positive/Neem regs as positief Fresultant = 50 + (-15) = 35 N99 to the right/na regs 9 (3) OR/OF Take left as positive/Neem links as positief Fresultant = 15 + (-50) = -35 N = 35 N 99 to the right/na regs 9 Kopiereg voorbehou Blaai om asseblief

Downloaded from hlayiso.com 4 TECHNICAL SCIENCES P1 (EC/NOVEMBER 2018) 3.6 3.6.1 Fresultant = 0 N9 (1) 3.6.2 Equilibrant /Ekwilibrant 9 (1) 3.6.3 F = 35N 9 to the LEFT/na LINKS 9 (2) [17] QUESTION/VRAAG 4 4.1 4.1.1 Moment 9 (of a force/van ʼn krag)/Wringkrag (1) 4.1.2 Cantilever / Cantilever 9 (1) 4.1.3 Mechanical advantage / Meganiese voordeel9 (1) 4.2 4.2.1 Sum of moments clockwise/ Som van momente kloksgewys = F1 x d1 + F2 x d29 = 3 000 x 2 9+ 4 000 x 4 9 = 22 000 N.m 9 or (22 kN) (4) 4.2.2 MACW = MCW 9 (Law of moments/Wet van momente) RB x 6 = 22 0009 RB = 3 670 N RA + RB = F1 + F2 9 (Beam is in equilibrium/Balk is in ewewig) RA + 3 6709 = 3 000 + 4 0009 RA = 3 330 N9 (6) 4.3 Load/Vrag 99 Effort/Las 9 Fulcrum/Draaipunt 99 (6) 4.4 4.4.1 Class ONE/Klas EEN 9 Load is between effort and fulcrum/Vrag is tussen las en fulkrum 9 (2) 4.4.2 FL/FE = dE/dL 9 200/50 9 = (20/100) 9/dL dL= 0,05 m 9 (4) [25] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2018) TEGNIESE WETENSKAPPE V1 5 QUESTION/VRAAG 5 5.1.1 Energy a body has due to its position above the ground. 99 (2) Energie van ʼn liggaam as gevolg van sy posisie bokant die grond 99 5.1.2 Sum of kinetic energy and potential energy 99 (2) Som van die kinetiese en potensiële energie 99 5.2.1 Ek at P = ½ mv2 9 = ½ x 60 x 42 9 (3) = 480 J 9 5.2.2 U at Q = mgh 9 = 60 x 9,8 x 3 9 (3) = 1 764 J 9 5.3 U at P = mgh 2 469 9 = 60 x 9,8 x h 9 4,2 m 9 = h Accept/Aanvaar 4,199 m (3) 5.4 Ek at Q = ½ mv2 705,6 9 = ½ (60) 9 v2 v = 4,85 m.s-19 (3) [16] QUESTION/VRAAG 6 6.1 REMOVED /VERWYDER 9 (1) 6.2 ne = ΔQ/e 9 = 6 x 10-6/1,6 x 10-19 9 = 3,75 x10-199 e- (3) 6.3 To prevent charge from leaking 99 (2) Om te verhoed dat lading uitlek 99 6.4 6.4.1 Total charge of an isolated system remains constant 99 (2) Totale lading van ʼn geïsoleerde system bly constant. 99 6.4.2 From R to P / Van R na P 9 (1) 6.4.3 Qtotal before / Qtotaal voor= (+6 x 10-6 + 0) Qtotal after = Qtotal before / Qtotaal na = Qtotaal voor QR = +6 x 10-6 /2 99= +3 x 10-6 C 9 (3) [12] Kopiereg voorbehou Blaai om asseblief

Downloaded from hlayiso.com 6 TECHNICAL SCIENCES P1 (EC/NOVEMBER 2018) QUESTION/VRAAG 7 7.1 Rate of flow of charge/ Tempo van vloei van lading 99 (2) 7.2 7.2.1 CIRCUIT/STROOMBAAN 2 9 (1) 7.2.2 CIRCUIT/STROOMBAAN 1 9 (1) 7.3 Y to/na X 9 (1) 7.4 7.4.1 EMF = 12 V 9 (1) 7.4.2 Rp= R1R2/R1+R2 9 = 12 x 12 /(12 + 12) 9 = 6 Ω9 (3) 7.5 Voltmeter V Cells /Selle Ammeter A Bulbs/Gloelampe Marking criteria/Merk kriteria Three cells / Drie selle 9 Voltmeter 9 Ammeter 9 Bulbs in parallel/Gloeilampe in parallel 9 Switch/Skakelaar 9 (5) [14] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/NOVEMBER 2018) TEGNIESE WETENSKAPPE V1 7 QUESTION/VRAAG 8 8.1 8.1.1 Opposition to flow of electric current 99 (2) Opposisie teen die vloei van elektriese stroom 99 8.1.2 Length of conductor/Lengte van die geleier 9 (1) 8.1.3 Temperature/Temperatuur 9 Thickness (Cross sectional area)/ Dikte (Deursnit-area) 9 (3) Type of conductor/Tipe geleier 9 8.2 8.2.1 The longer the conductor the higher the resistance OR The shorter the conductor the lower the resistance OR Resistance is directly proportional to the length of the conductor 99 Hoe langer die geleier, hoe hoër is die weerstand OF Hoe korter die geleier, hoe laer is die weerstand OF (2) Weerstand is direk eweredig aan die lengte van die geleier 99 8.2.2 9 √√ (Ω) (2) 8.2.3 Gradient/Gradiënt = (18 – 9) √/(7 – 3) √ = 2,25 √ (3) [13] TOTAL/TOTAAL: 150 Kopiereg voorbehou Blaai om asseblief