Bouectoscientesrom Stanm&sepR42E/ CS. COPRITAMBO INLAND - MARCH 2023
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Physical Sciences Grade 12 EC March 2023 Paper & Memo
Grade 12 Physical Sciences question paper and memo from the EC March 2023, 21 pages. Read online or get the free PDF download.
Physical Sciences · Grade 12 · EC March · 2023. Question paper and memorandum, 21 pages. Read online or download the PDF.
- Subject
- Physical Sciences
- Grade
- Grade 12
- Document type
- Question paper and memo
- Year
- 2023
- Exam period
- EC March
- Curriculum
- CAPS
- Pages
- 21
- File size
- 4.4 MB
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Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023
INSTRUCTIONS AND INFORMATION
1.
10.
11
This question paper consists of TEN questions. Answer ALL the questions in
the ANSWER BOOK.
StartiEACH question on a NEW page in the ANSWER BOOK.
Number the answers correctly according to the numbering system used in this
question paper.
Leave ONE line between two sub questions, for example between QUESTION
2.2. and 2.3.
You may use a non-programmable calculator.
You may use appropriate mathematical instruments.
You are advised to use the attached DATA SHEETS.
Show ALL formulae and substitutions in ALL calculations.
Round off your final numerical answers to a minimum of TWO decimal places.
Give brief motivations, discussions et cetera where required.
Write neatly and legibly.
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023
QUESTION 1 (Start on a new page)
Various options are provided as possible answers to the following questions. Choose
the correct answer and write only the letter (A-D) next to the question number (1.1 -
1.7) on th er sheet e.g.; 1.8 A.
1.1 A boxis at rest on a horizontal desk. The name of the force that will form
an action reaction pair with gravitational force is.......
A The force that the earth exerts on the box
B The force that the box exerts on the earth.
Cc The normal force acting on the box
D The force that the desk exerts on the box (2)
1.2. Aball of mass 2 kg is projected vertically upwards. At the highest point of
its motion... ignore air friction.
i. Acceleration of the ball is zero
ii. | Net force acting on the ball is 19.6 N
iii. Velocity of the ball is zero
iv. Net force acting on the ball is zero
Which of the above statement(s) is/are CORRECT?
A (i) and (iii) only
B (iii), (iv) and (i) only
Cc (iv) only
D (ii) and (iii) only (2)
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023
1.3
1.4
1.5
An object is dropped from rest and after falling a distance d, its momentum
is p. Ignore the effect of air friction.
The momentum of the object after it has fallen a distance of 5d is.....
A
B P
5
Cc Pp
D — V5p (2)
Which ONE of the following compounds is UNSATURATED
A Chloroethane
B Propan—1-ol
Cc Ethene
D Ethane (2)
The name of the functional group of an ALCOHOL is...
A Carboxyl group
B Carbonyl group
Cc Hydroxyl group
D Formyl group (2)
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023
1.6
1.7
1.8
The type of intermolecular force that is responsible for the difference in
boiling point of butan-1-ol and its CHAIN isomer is..
A London forces.
B a rogen bonds.
Cc n-dipole force.
D Dipole-dipole force (2)
Dilute solution of a strong base and mild heat are reaction conditions
for...
A Hydrolysis reaction
B Hydration reaction
Cc Dehydrohalogenation reaction
D Hydrohalogenation reaction (2)
Which ONE of the following compounds has the LOWEST melting point?
A Hexanal
B Ethanal
Cc Butanal
D Octanal
[16]
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023
QUESTION 2 (Start on a new page)
A 5 kg block is connected to a 3 kg block by a light inextensible string through a
frictionless pulley as shown in the diagram below. A force, F of magnitude 80 N force
is applied on_the 5 kg block at an angle of 30° to the horizontal and the system
accelerates-to-the left at 2,2 m.s on a rough horizontal surface.
2.1
2.2
2.3
80 N
5 kg q
3 kg
Draw a labelled free body diagram indicating all the HORIZONTAL forces
acting on the 5 kg block. (3)
Calculate the:
2.2.1 magnitude of the tension in the string. (3)
2.2.2 coefficient of kinetic friction acting on the 5 kg block. (5)
How will each of the following be affected if the angle between the surface
and the force F increases? Choose from INCREASE, DECREASE or
REMAIN THE SAME. Give a reason for your answer.
2.3.1 Kinetic frictional force (2)
2.3.2 Coefficient of kinetic friction (2)
[15]
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023
QUESTION 3 (start each question on a new page)
Ball A of mass 200 g is thrown vertically down with velocity of 10 m.s* from a cliff of 13
m above the ground.
When ball Alhits the ground, it is in contact with the ground for 0.3 s and it then bounces
back with a Velocity of 24 m.s* until it reaches a MAXIMUM height of 30m after the first
bounce. See Til diagram below. Ignore the effects of air friction.
AT,
fel Zz
agm fae
2m
ES |
3.1 Define the term projectile. (2)
3.2 Calculate the....
3.2.1 The velocity at which the Ball A hits the ground. (3)
3.2.2 Magnitude of the average net force exerted by the ground on the
ball while it is in contact with it. (4)
At the same instant that Ball A is at its maximum height after the first bounce,
a similar Ball B is projected vertically upwards from a point of 2m above the ground
with a velocity of 15 m.s*.
3.3 Calculate the time it takes for Ball A and Ball B to pass each other (5)
3.4 Draw a velocity vs time graph for Ball A from the moment it is projected
down until it reaches maximum height after first bounce. (2)
[16]
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023
QUESTION 4 (start on a new page)
A 1500 kg cars travelling west at 20 m.s* on a horizontal frictionless track. It collides
ruck travelling at 16 m.s* east. After the collision, the car travels at
ee the diagram below.
— ims’
4.1 State the principle of conservation of linear momentum in words. (2)
4.2 Calculate the velocity of the truck immediately after the collision. (4)
4.3 Determine by means of relevant calculations whether the collision is
ELASTIC or INELASTIC. (5)
4.4 Which ONE of the vehicles (CAR or TRUCK) that will experience a greater (2)
amount of damage during collision? Explain your answer.
[13]
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023
QUESTION 5 (Start on a new page)
Molecules containing carbon atoms are listed in the table below.
5.1
5.2
5.3
5.4
5.5
=>
A [aHs0H B | CH2CH2
c4 H D HHH oO
| Hes a0 oo "
re H-C-C-C-C
H
abeae HHH H
Ee face
H | H H H
H—C—H
i
E | Propyl Methanoate F HH! ce 0
| el ae
H—C—C—C—C—0O-H
Ee
H H H
Give one word for the underlined phrase.
Write
5.2.1
5.2.2
5.2.3
5.2.4
5.2.5
Cons
5.3.1
5.3.2
Write
down the LETTER that represents the following:
A haloalkane
A carboxylic acid
A compound with a general formula CnHen.
A compound which has the formyl group as its functional group
Functional isomer of F.
ider compound E, Write down the:
Structural formula of its functional group.
IUPAC name of the alcohol used to prepare this compound.
down the IUPAC name of compound C.
Is compound a PRIMARY, SECONDARY or TERTIARY alcohol? Give a reason
for your answer.
(1)
(1)
(1)
(1)
(1)
(1)
(2)
(1)
(2)
(3)
(2)
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023
Compound G is formed when compound B undergoes HYDROGENATION reaction in the
presence of nickel (Ni).
5.6 Use MOLECULAR FORMULAE and write down a balanced equation for the
comp combustion of compound G. (3)
[18]
10
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023
QUESTION 6 (start on a new page)
Two groups of compounds were investigated viz: Alkanes and alcohols
The graph below is obtained after learners conducted an investigation on the
factors affecting boiling point.
Variation of Boiling Points of straight chained Alcohols and Alkanes
—
with Number of Carbon
150
z00) Alcohols
50
hd
a)
‘Oo
2
2 Alkanes
= -50
S
a
-100
-150
200 : ‘ A
1 2 3 4
Number of Carbon Atoms
Experiment 1 is for straight chain alkanes while experiment 2 is for
straight chain alcohols.
6.1 Define the term boiling point. (2)
6.2 For experiment 1, write down the:
6.2.1 Independent variable. (1)
6.2.2 Investigative question (2)
6.2.3. Conclusion that can be drawn from graph of alkanes only (2)
6.3 Explain why the boiling points of alkanes differ from those of alcohols. Refer (4)
to the (TYPE OF INTERMOLECULAR FORCES,STRENGTH OF
INTERMOLECULAR FORCES AND ENERGY )
[11]
11
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023
QUESTION 7 (start on a new page)
Some of the reactions of Pentan-1-ol are represented in the flow diagram below. P, Q
and R represent the organic products formed.
=
pa P
| concentrated H2SO,
Pentan-1-ol
HBr Ethanoic acid
Q | R
7.1 Product P is formed when Pentan-1-ol is heated in the presence of
concentrated sulphuric acid.
Write down the:
7.1.1 Name of the type of reaction that takes place. (1)
7.1.2 Balanced equation for the reaction that takes place using
STRUCTURAL FORMULAE. (5)
7.2 Product R is formed when Pentan-1-ol reacts with ethanoic acid in the
presence of an acid catalyst.
7.2.1 Name of the type of reaction that takes place. (1)
7.2.2 Structural formula of the organic product formed (2)
7.3. When HBr reacts with Pentan-1-ol, compound Q, a haloalkane is formed.
Write down the:
7.3.1 Name of the type of reaction that takes place. (1)
7.3.2. IUPAC name of the haloalkane formed. (2)
7.4 Draw the structural formulae of two positional isomers of pentan-1-ol. (2)
[14]
TOTAL [100]
12
TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES
Dopwioacientesrom Stanm&SeEPRA2EICS . COPA TAMBO INLAND - MARCH 2023
NAME/VAAM SYMBOL/SIMBOOL VALUE/WAARDE
TABLE 2: FORMULAE/TABEL 2: FORMULES
MOTION/BEWEGING
vVp=vtadt Ax =v, At +4adt? or/of Ay =v,At +4aat?
Vv, +V Vv, +V
Vv, =v, +2adx orof v,7 =v, +2ady | Ax = (“5 as or/of Ay “(5 \a
FORCE/KRAG
Fret =ma p=mv
f°" =p.N f, =H,N
F,,At=Ap
Ap=mvy,- my, w=mg
M M
F-oue orlof Fone g=Gy oof, 9 g= GG
13
Seecnl camiesy cOwnRo1..S tan cRApe TD NyRIOS EMONELINES
QUESTION 1
11
1.2
1.3
1.4
15
1.6
17
18
Bvv
Dv
D v
C vv
C vv
AVY
A vv
Bvv
ORTI DISTRICT MARCH 2023
(2)
(2)
(2)
(2)
(2)
(2)
(2)
[14]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES
ORTI DISTRICT MARCH 2023
QUESTION 2
2.1
2.2
2.3
2.2.2
2.31
2.3.2
Tv
On 3 kg block
Fret = ma v
T-W= an
T — (3)(9.8) = (3)(2.2) ¥
T= 36 NY
On 5 kg block
Fnet = ma +
Fx -T — fk = ma.
v
v
80cos 30° — 36 — pk(5x9.8 + 80sin 30°) = 5(2.2) ¥
Uk = 0.25Y
Increase Vv
According to (fx = uxN), at a constant coefficient of kinetic friction,
kinetic frictional force increases as normal forces increases. ~
OR
Increase Vv
Normal force is directly proportional to kinetic frictional force. ¥
Remain the same. ¥
Coefficient of kinetic friction depend on the nature of the surface
only. ¥
(3)
(3)
(5)
(2)
(2)
[15]
Saicnloamierd cOwRo.iS fai GRAPE NWRIOGG EWNALINES
QUESTION 3
ORTI DISTRICT MARCH 2023
3.1 An object which has been given an initial velocity and then it moves under
the influence of gravitational force only. vv (2)
3.3
i _
upwards as positive
Vit= V2 + 2adyv
= (-10)2 + 2(-9,8)(-13) ¥
= 18,84 m.s? downwardsY
OPTION 2
downwards as positive
Vi? = Vi? + ZaAyY
= (10)? + 2(9,8)(13) V
= 18,84 m.s*? downwardsY¥ (3)
POSITIVE MARKING FROM QUESTION 3.2.1
OPTION 1
downwards as positive
Fnet At = Ap
Fret At = m(vs- we ¥
v,
Fnet(0,3)= 200x10°(-24 - 18,84) ¥
Fnet = -28,56 N
Fnet = 28,56 N ¥
OPTION 1
upwards as positive
For ball A
Ay = ViAt +aAt”
Ay=0+5(—9,8)At¥ — .... (1)
For ball B
Ay = ViAt +aAt?
v i”
-[(30-2)- Ay] = -15At + 5 (—9,8) At?
.. (2)
(1) Into (2)
t=1,87s v
OPTION 2
upwards as positive
Fnet At = Ap
Fnet At = m(vi - we v
A
Fnet(0,3)= 200x10°9(24 - (- (4)
18,84)) v
Fret = 28,56 N ¥
OPTION 2
downwards as positive
For ball A
Ay = Vidt + at”
~Ay = OF5{+(9,8)At® —... (1)
For ball B
(5)
y = ViAt +aAt?
v
[(30-2)- Ayf = 15at + +,8)at2
(2)
(1) Into (2)
t=1,87s v
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES
ORTI DISTRICT MARCH 2023
3.4 OPTION 1
upwards as positive
shape : ¥
label both axis: ¥
OPTION 2
Downwards as positive
---=p,
(2)
shape : ¥
label both axis: ¥
[16]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES
ORTI DISTRICT MARCH 2023
QUESTION 4
4.1 The total linear momentum of an isolated system remains constant. Vv ¥
4.2 Zpi=
McVic it = McVtc + Mwvit v
(15 0) + (2600)(16) Y = (1500)(5,2) + (2600) vaw
4.3
4.4
vi = 1,46 m.s? easwards. ¥
Inealstic ¥
POSITIVE MARKING FROM QUESTION 4.2
LEKbefore = ; McV2ic + ; mvt ¥
= =(1500)(20)? + {2600)(16)? ¥
= 622800 J
ZEkafter = smevte 4 mvt
= 3(1500)(5,2)? + $(2600)(1,46)? v
= 23051 J
ZEKbefore # ZEkatter VW
Car v
It experiences a greater acceleration OR It has a greater change in
velocity ¥
(2)
(4)
(5)
(2)
[13]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES
QUESTION 5
ORTI DISTRICT MARCH 2023
5.1 Organic molecules. ~
5.2
5.2.1
5.2.
5.2.3
5.2.4
5.2.5
5.3.1
5.3.2
5.4
BY
Dv
Ev
Oo vv
lI |
Propanol vv
v v v
4 — bromo-2,2 — dimethyl pentane
5.5 Primary alcohol. ¥
The carbon atom bonded to the hydroxyl (-OH) group is directly bonded to
only one other carbon atom. “
5.6 2C2He + 702v¥
———» 4CO2 + 6H20 VY YY balancing.
(1)
(1)
(a)
(1)
(1)
(1)
(2)
(2)
(3)
(2)
(3)
[18]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES
ORTI DISTRICT MARCH 2023
QUESTION 6
6.1 The te mpe pressure Y of a substance equals the
spheric pressure. ¥ (2)
rature at which the vapour
atmo:
6.2
6.2.1. Number of carbons/ chain length. (1)
6.2.2 Whatis the relationship between the number of carbon atoms/ (2)
chain length and the boiling point? vv
6.2.3. As the number of carbon atoms / chain length increases, the boiling (2)
point also increases. Vv ¥
6.3 e Alkanes have London forces. ¥
e Alcohols have London forces Dipole-dipole forces and hydrogen
bonds. v (4)
e The intermolecular forces of alcohols are stronger than those of
alkanes. ¥
e More energy needed to overcome the intermolecular forces of
alcohols. ¥
[11]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES
ORTI DISTRICT MARCH 2023
QUESTION 7
7.1
7.1.1 Elimination v (1)
7.1.2 HoH H H yy H HH H
Ae ea a ae v
ns le —c—o—H —— > H-C—C—C—C=C *+H-O
| | | ee, |
H oH H oH H oH H
Functional group: / Functional group: /
Whole structure correct: / Whole structure: / (5)
Water v
7.2
7.2.1 Esterificationy (1)
7.2.2
eg ee
H H H H H H (2)
Y¥ functional group Y structure
7.3
7.3.1 Substitution ¥ (1)
7.3.2 1-bromopentane Vv (2)
7.4 H H H OHH
I | to to
nn ne
ee
H H H H H v
H H ran H
| || |
“TTT ito
H H H H H v (2)
[14]
TOTAL [100]
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