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Physical Sciences Grade 12 EC March 2023 Paper & Memo

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Grade 12 Physical Sciences question paper and memo from the EC March 2023, 21 pages. Read online or get the free PDF download.

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Bouectoscientesrom Stanm&sepR42E/ CS. COPRITAMBO INLAND - MARCH 2023 Province of the EASTERN CAPE EDUCATION This question paper consists of 13 pages including cover page.
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023 INSTRUCTIONS AND INFORMATION 1. 10. 11 This question paper consists of TEN questions. Answer ALL the questions in the ANSWER BOOK. StartiEACH question on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. Leave ONE line between two sub questions, for example between QUESTION 2.2. and 2.3. You may use a non-programmable calculator. You may use appropriate mathematical instruments. You are advised to use the attached DATA SHEETS. Show ALL formulae and substitutions in ALL calculations. Round off your final numerical answers to a minimum of TWO decimal places. Give brief motivations, discussions et cetera where required. Write neatly and legibly.
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023 QUESTION 1 (Start on a new page) Various options are provided as possible answers to the following questions. Choose the correct answer and write only the letter (A-D) next to the question number (1.1 - 1.7) on th er sheet e.g.; 1.8 A. 1.1 A boxis at rest on a horizontal desk. The name of the force that will form an action reaction pair with gravitational force is....... A The force that the earth exerts on the box B The force that the box exerts on the earth. Cc The normal force acting on the box D The force that the desk exerts on the box (2) 1.2. Aball of mass 2 kg is projected vertically upwards. At the highest point of its motion... ignore air friction. i. Acceleration of the ball is zero ii. | Net force acting on the ball is 19.6 N iii. Velocity of the ball is zero iv. Net force acting on the ball is zero Which of the above statement(s) is/are CORRECT? A (i) and (iii) only B (iii), (iv) and (i) only Cc (iv) only D (ii) and (iii) only (2)
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023 1.3 1.4 1.5 An object is dropped from rest and after falling a distance d, its momentum is p. Ignore the effect of air friction. The momentum of the object after it has fallen a distance of 5d is..... A B P 5 Cc Pp D — V5p (2) Which ONE of the following compounds is UNSATURATED A Chloroethane B Propan—1-ol Cc Ethene D Ethane (2) The name of the functional group of an ALCOHOL is... A Carboxyl group B Carbonyl group Cc Hydroxyl group D Formyl group (2)
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023 1.6 1.7 1.8 The type of intermolecular force that is responsible for the difference in boiling point of butan-1-ol and its CHAIN isomer is.. A London forces. B a rogen bonds. Cc n-dipole force. D Dipole-dipole force (2) Dilute solution of a strong base and mild heat are reaction conditions for... A Hydrolysis reaction B Hydration reaction Cc Dehydrohalogenation reaction D Hydrohalogenation reaction (2) Which ONE of the following compounds has the LOWEST melting point? A Hexanal B Ethanal Cc Butanal D Octanal [16]
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023 QUESTION 2 (Start on a new page) A 5 kg block is connected to a 3 kg block by a light inextensible string through a frictionless pulley as shown in the diagram below. A force, F of magnitude 80 N force is applied on_the 5 kg block at an angle of 30° to the horizontal and the system accelerates-to-the left at 2,2 m.s on a rough horizontal surface. 2.1 2.2 2.3 80 N 5 kg q 3 kg Draw a labelled free body diagram indicating all the HORIZONTAL forces acting on the 5 kg block. (3) Calculate the: 2.2.1 magnitude of the tension in the string. (3) 2.2.2 coefficient of kinetic friction acting on the 5 kg block. (5) How will each of the following be affected if the angle between the surface and the force F increases? Choose from INCREASE, DECREASE or REMAIN THE SAME. Give a reason for your answer. 2.3.1 Kinetic frictional force (2) 2.3.2 Coefficient of kinetic friction (2) [15]
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023 QUESTION 3 (start each question on a new page) Ball A of mass 200 g is thrown vertically down with velocity of 10 m.s* from a cliff of 13 m above the ground. When ball Alhits the ground, it is in contact with the ground for 0.3 s and it then bounces back with a Velocity of 24 m.s* until it reaches a MAXIMUM height of 30m after the first bounce. See Til diagram below. Ignore the effects of air friction. AT, fel Zz agm fae 2m ES | 3.1 Define the term projectile. (2) 3.2 Calculate the.... 3.2.1 The velocity at which the Ball A hits the ground. (3) 3.2.2 Magnitude of the average net force exerted by the ground on the ball while it is in contact with it. (4) At the same instant that Ball A is at its maximum height after the first bounce, a similar Ball B is projected vertically upwards from a point of 2m above the ground with a velocity of 15 m.s*. 3.3 Calculate the time it takes for Ball A and Ball B to pass each other (5) 3.4 Draw a velocity vs time graph for Ball A from the moment it is projected down until it reaches maximum height after first bounce. (2) [16]
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023 QUESTION 4 (start on a new page) A 1500 kg cars travelling west at 20 m.s* on a horizontal frictionless track. It collides ruck travelling at 16 m.s* east. After the collision, the car travels at ee the diagram below. — ims’ 4.1 State the principle of conservation of linear momentum in words. (2) 4.2 Calculate the velocity of the truck immediately after the collision. (4) 4.3 Determine by means of relevant calculations whether the collision is ELASTIC or INELASTIC. (5) 4.4 Which ONE of the vehicles (CAR or TRUCK) that will experience a greater (2) amount of damage during collision? Explain your answer. [13]
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023 QUESTION 5 (Start on a new page) Molecules containing carbon atoms are listed in the table below. 5.1 5.2 5.3 5.4 5.5 => A [aHs0H B | CH2CH2 c4 H D HHH oO | Hes a0 oo " re H-C-C-C-C H abeae HHH H Ee face H | H H H H—C—H i E | Propyl Methanoate F HH! ce 0 | el ae H—C—C—C—C—0O-H Ee H H H Give one word for the underlined phrase. Write 5.2.1 5.2.2 5.2.3 5.2.4 5.2.5 Cons 5.3.1 5.3.2 Write down the LETTER that represents the following: A haloalkane A carboxylic acid A compound with a general formula CnHen. A compound which has the formyl group as its functional group Functional isomer of F. ider compound E, Write down the: Structural formula of its functional group. IUPAC name of the alcohol used to prepare this compound. down the IUPAC name of compound C. Is compound a PRIMARY, SECONDARY or TERTIARY alcohol? Give a reason for your answer. (1) (1) (1) (1) (1) (1) (2) (1) (2) (3) (2)
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023 Compound G is formed when compound B undergoes HYDROGENATION reaction in the presence of nickel (Ni). 5.6 Use MOLECULAR FORMULAE and write down a balanced equation for the comp combustion of compound G. (3) [18] 10
Bouectoscientesrom Stanm&sePR42E/ CS. COR TAMBO INLAND - MARCH 2023 QUESTION 6 (start on a new page) Two groups of compounds were investigated viz: Alkanes and alcohols The graph below is obtained after learners conducted an investigation on the factors affecting boiling point. Variation of Boiling Points of straight chained Alcohols and Alkanes — with Number of Carbon 150 z00) Alcohols 50 hd a) ‘Oo 2 2 Alkanes = -50 S a -100 -150 200 : ‘ A 1 2 3 4 Number of Carbon Atoms Experiment 1 is for straight chain alkanes while experiment 2 is for straight chain alcohols. 6.1 Define the term boiling point. (2) 6.2 For experiment 1, write down the: 6.2.1 Independent variable. (1) 6.2.2 Investigative question (2) 6.2.3. Conclusion that can be drawn from graph of alkanes only (2) 6.3 Explain why the boiling points of alkanes differ from those of alcohols. Refer (4) to the (TYPE OF INTERMOLECULAR FORCES,STRENGTH OF INTERMOLECULAR FORCES AND ENERGY ) [11] 11
Bouectoscientesrom Stanm&sePR42E/0S. COPA TAMBO INLAND - MARCH 2023 QUESTION 7 (start on a new page) Some of the reactions of Pentan-1-ol are represented in the flow diagram below. P, Q and R represent the organic products formed. = pa P | concentrated H2SO, Pentan-1-ol HBr Ethanoic acid Q | R 7.1 Product P is formed when Pentan-1-ol is heated in the presence of concentrated sulphuric acid. Write down the: 7.1.1 Name of the type of reaction that takes place. (1) 7.1.2 Balanced equation for the reaction that takes place using STRUCTURAL FORMULAE. (5) 7.2 Product R is formed when Pentan-1-ol reacts with ethanoic acid in the presence of an acid catalyst. 7.2.1 Name of the type of reaction that takes place. (1) 7.2.2 Structural formula of the organic product formed (2) 7.3. When HBr reacts with Pentan-1-ol, compound Q, a haloalkane is formed. Write down the: 7.3.1 Name of the type of reaction that takes place. (1) 7.3.2. IUPAC name of the haloalkane formed. (2) 7.4 Draw the structural formulae of two positional isomers of pentan-1-ol. (2) [14] TOTAL [100] 12
TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES Dopwioacientesrom Stanm&SeEPRA2EICS . COPA TAMBO INLAND - MARCH 2023 NAME/VAAM SYMBOL/SIMBOOL VALUE/WAARDE TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING vVp=vtadt Ax =v, At +4adt? or/of Ay =v,At +4aat? Vv, +V Vv, +V Vv, =v, +2adx orof v,7 =v, +2ady | Ax = (“5 as or/of Ay “(5 \a FORCE/KRAG Fret =ma p=mv f°" =p.N f, =H,N F,,At=Ap Ap=mvy,- my, w=mg M M F-oue orlof Fone g=Gy oof, 9 g= GG 13
Seecnl camiesy cOwnRo1..S tan cRApe TD NyRIOS EMONELINES QUESTION 1 11 1.2 1.3 1.4 15 1.6 17 18 Bvv Dv D v C vv C vv AVY A vv Bvv ORTI DISTRICT MARCH 2023 (2) (2) (2) (2) (2) (2) (2) [14]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES ORTI DISTRICT MARCH 2023 QUESTION 2 2.1 2.2 2.3 2.2.2 2.31 2.3.2 Tv On 3 kg block Fret = ma v T-W= an T — (3)(9.8) = (3)(2.2) ¥ T= 36 NY On 5 kg block Fnet = ma + Fx -T — fk = ma. v v 80cos 30° — 36 — pk(5x9.8 + 80sin 30°) = 5(2.2) ¥ Uk = 0.25Y Increase Vv According to (fx = uxN), at a constant coefficient of kinetic friction, kinetic frictional force increases as normal forces increases. ~ OR Increase Vv Normal force is directly proportional to kinetic frictional force. ¥ Remain the same. ¥ Coefficient of kinetic friction depend on the nature of the surface only. ¥ (3) (3) (5) (2) (2) [15]
Saicnloamierd cOwRo.iS fai GRAPE NWRIOGG EWNALINES QUESTION 3 ORTI DISTRICT MARCH 2023 3.1 An object which has been given an initial velocity and then it moves under the influence of gravitational force only. vv (2) 3.3 i _ upwards as positive Vit= V2 + 2adyv = (-10)2 + 2(-9,8)(-13) ¥ = 18,84 m.s? downwardsY OPTION 2 downwards as positive Vi? = Vi? + ZaAyY = (10)? + 2(9,8)(13) V = 18,84 m.s*? downwardsY¥ (3) POSITIVE MARKING FROM QUESTION 3.2.1 OPTION 1 downwards as positive Fnet At = Ap Fret At = m(vs- we ¥ v, Fnet(0,3)= 200x10°(-24 - 18,84) ¥ Fnet = -28,56 N Fnet = 28,56 N ¥ OPTION 1 upwards as positive For ball A Ay = ViAt +aAt” Ay=0+5(—9,8)At¥ — .... (1) For ball B Ay = ViAt +aAt? v i” -[(30-2)- Ay] = -15At + 5 (—9,8) At? .. (2) (1) Into (2) t=1,87s v OPTION 2 upwards as positive Fnet At = Ap Fnet At = m(vi - we v A Fnet(0,3)= 200x10°9(24 - (- (4) 18,84)) v Fret = 28,56 N ¥ OPTION 2 downwards as positive For ball A Ay = Vidt + at” ~Ay = OF5{+(9,8)At® —... (1) For ball B (5) y = ViAt +aAt? v [(30-2)- Ayf = 15at + +,8)at2 (2) (1) Into (2) t=1,87s v
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES ORTI DISTRICT MARCH 2023 3.4 OPTION 1 upwards as positive shape : ¥ label both axis: ¥ OPTION 2 Downwards as positive ---=p, (2) shape : ¥ label both axis: ¥ [16]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES ORTI DISTRICT MARCH 2023 QUESTION 4 4.1 The total linear momentum of an isolated system remains constant. Vv ¥ 4.2 Zpi= McVic it = McVtc + Mwvit v (15 0) + (2600)(16) Y = (1500)(5,2) + (2600) vaw 4.3 4.4 vi = 1,46 m.s? easwards. ¥ Inealstic ¥ POSITIVE MARKING FROM QUESTION 4.2 LEKbefore = ; McV2ic + ; mvt ¥ = =(1500)(20)? + {2600)(16)? ¥ = 622800 J ZEkafter = smevte 4 mvt = 3(1500)(5,2)? + $(2600)(1,46)? v = 23051 J ZEKbefore # ZEkatter VW Car v It experiences a greater acceleration OR It has a greater change in velocity ¥ (2) (4) (5) (2) [13]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES QUESTION 5 ORTI DISTRICT MARCH 2023 5.1 Organic molecules. ~ 5.2 5.2.1 5.2. 5.2.3 5.2.4 5.2.5 5.3.1 5.3.2 5.4 BY Dv Ev Oo vv lI | Propanol vv v v v 4 — bromo-2,2 — dimethyl pentane 5.5 Primary alcohol. ¥ The carbon atom bonded to the hydroxyl (-OH) group is directly bonded to only one other carbon atom. “ 5.6 2C2He + 702v¥ ———» 4CO2 + 6H20 VY YY balancing. (1) (1) (a) (1) (1) (1) (2) (2) (3) (2) (3) [18]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES ORTI DISTRICT MARCH 2023 QUESTION 6 6.1 The te mpe pressure Y of a substance equals the spheric pressure. ¥ (2) rature at which the vapour atmo: 6.2 6.2.1. Number of carbons/ chain length. (1) 6.2.2 Whatis the relationship between the number of carbon atoms/ (2) chain length and the boiling point? vv 6.2.3. As the number of carbon atoms / chain length increases, the boiling (2) point also increases. Vv ¥ 6.3 e Alkanes have London forces. ¥ e Alcohols have London forces Dipole-dipole forces and hydrogen bonds. v (4) e The intermolecular forces of alcohols are stronger than those of alkanes. ¥ e More energy needed to overcome the intermolecular forces of alcohols. ¥ [11]
Sean camer’ cOWROLLS fe GRADIETA NYRKING EWNELINES ORTI DISTRICT MARCH 2023 QUESTION 7 7.1 7.1.1 Elimination v (1) 7.1.2 HoH H H yy H HH H Ae ea a ae v ns le —c—o—H —— > H-C—C—C—C=C *+H-O | | | ee, | H oH H oH H oH H Functional group: / Functional group: / Whole structure correct: / Whole structure: / (5) Water v 7.2 7.2.1 Esterificationy (1) 7.2.2 eg ee H H H H H H (2) Y¥ functional group Y structure 7.3 7.3.1 Substitution ¥ (1) 7.3.2 1-bromopentane Vv (2) 7.4 H H H OHH I | to to nn ne ee H H H H H v H H ran H | || | “TTT ito H H H H H v (2) [14] TOTAL [100]

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