Physical Sciences Grade 10 P1 Gauteng November 2020 Memo

Downloaded from hlayiso.com GAUTENG DEPARTMENT OF EDUCATION PROVINCIAL EXAMINATION NOVEMBER 2020 GRADE 10 PHYSICAL SCIENCES (PHYSICS) PAPER 1 MEMORANDUM 6 pages 1

Downloaded from hlayiso.com PHYSICAL SCIENCES MEMORANDUM (PAPER 1) GRADE 10 QUESTION 1: MULTIPLE CHOICE QUESTIONS 1.1 C   1.2 D   1.3 B   1.4 C   1.5 C   [10] QUESTION 2 2.1 NEGATIVE MARKING TRANSVERSE  The disturbance of the particles of the medium are perpendicular to the direction of propagation.   (3) 2.2 P (1) 2.3 2.3.1 Wavelength = 100 mm = 10 cm = 0,1 m (1) 2.3.2 T = 1,5 s (1) 2.3.3 f = 1 / T = 1 / 1,5 = 0,67 Hz v = f x wavelength  v = (0,67) (0,1) v = 0,067 m·s-1 (3) [9] QUESTION 3 3.1 150 m + 25 m = 175 m (1) 3.2 ∆x = 125 m east  (1) 3.3 3.3.1 Displacement is the change in position of the object   (2) 3.3.2 Physical quantity that has magnitude and direction  (2) 3.4 Marking grid for scale drawing 5 cm  1 cm  Criteria Mark Correct measurements for  Displacement = 125 m  due east  50 m and 25 m Correct measurement for  displacement (4) [10] 2

Downloaded from hlayiso.com PHYSICAL SCIENCES MEMORANDUM (PAPER 1) GRADE 10 QUESTION 4 Δx 6 4.1.1 VAB    3 m.s 1   Δt 2 (3) 4.1.2 ΔX 18 VCD    9 m.s1   Δt 2 (2) Δv  9  3  4.2 a   1,5 m.s-2  Δt 5 1  OR    = 1,5 m.s-2  (4) 4.3 The change (increase) in displacement in each (consecutive) interval is constant (6 m)  (2) 4.4.1 The car is moving with constant/uniform velocity/ acceleration is zero  (1) Δv  4,8  0  2 4.4.2 gradient     0,192 m.s  (3) Δt  25  0  4.4.3 Time interval: 0 to 25 s and 450 s to 510 s   (2) [17] 3

Downloaded from hlayiso.com PHYSICAL SCIENCES MEMORANDUM (PAPER 1) GRADE 10 QUESTION 5 5.1 The energy that an object has due to its vertical height above the surface of the earth.   (2) 5.2 Ep = mgh Ep = 1 (9,8) 35 Ep = 343 J (3) 5.3 In a closed/isolated system, the total mechanical energy remains constant/ is conserved   (2) 5.4 Emec (x) = Emec (y) (Ep + Ek) x = (Ep + Ek) y  (mgh + ½ mv2) x = (mgh + ½ mv2) y 343 + 0  = 0 + ½ (1) v2 v = 26,19 m.s-1 (4) [11] 4

Downloaded from hlayiso.com PHYSICAL SCIENCES MEMORANDUM (PAPER 1) GRADE 10 QUESTION 6 6.1 NEGATIVE MARKING Removed  It has a positive charge.  (3) 6.2 6.2.1 Every charge in the universe is an integer multiple of the elementary charge.   (2) 6.2.2 Qnew = 𝑄𝑛𝑒𝑡  2 Qnew = (9 x 10-9 + 0) / 2  Qnew = 4,5 x 10-9 C  (3) 6.2.3 n = ∆𝑄  𝑒 n = (4,5 x 10-9 - 0)  / 1,6 x 10-19  n = 2,8125 x 1010 electrons  OR ∆𝑄 n= 𝑒  n = (4,5 x 10-9 - 9 x 10-9)  / -1,6 x 10-19  n = 2,8125 x 1010 electrons  (4) [12] 5

Downloaded from hlayiso.com PHYSICAL SCIENCES MEMORANDUM (PAPER 1) GRADE 10 QUESTION 7 7.1 A charge of 5 C passes through a point per unit time or in one second.  (2) 7.2 1 1 1 = 𝑅1 + 𝑅2  𝑅𝑝 1 1 1 =4+6 𝑅𝑝 1 12 = 5 𝑅𝑝 Rp = 2,4 Ω  (3) 7.3 IT = I 2 + I 3  5 = 3 – I3  I3 = 2 A  (3) 7.4 𝑊 V= 𝑄  12 = W / 1  W = 12 J  (3) [11] TOTAL: 80 6