Technical Sciences Grade 10 P1 2026 Memo (Eng)

Mock hlayiso mock exams Practice Series: Grade 10 Exam Preparation WWW.HLAYISO.COM NATIONAL SENIOR CERTIFICATE GRADE 10 TECHNICAL SCIENCES P1 NOVEMBER EXAMINATION 2026 (MOCK) MARKING GUIDELINES MARKS: 150 These marking guidelines consist of 11 pages. Copyright reserved Please turn over

Technical Sciences/P1 2 Hlayiso/Mock 2026 NSC – Marking Guidelines GENERAL MARKING GUIDELINES 1. Calculations: Marks are awarded for the correct formula, correct substitution and the correct final answer WITH the correct unit, as indicated by the ticks (✓). No mark is awarded for a formula that is not followed by a substitution. If an incorrect formula is used, no further marks are awarded for that calculation. 2. Units: The final-answer mark is only awarded if the correct unit is given. Penalise an omitted or incorrect unit only ONCE per question. 3. Rounding: Accept final answers rounded to a minimum of TWO decimal places. Small differences caused by rounding of intermediate values are accepted. 4. Positive marking: Where an incorrect answer from a previous question is used correctly in a later calculation, full marks are awarded for the later calculation. 5. Negative marking: If a candidate must explain or motivate a choice and the choice is incorrect, no marks are awarded for the explanation. 6. Definitions: Where key words are underlined, deduct 1 mark for EACH key word or phrase that is omitted. Accept equivalent wording that conveys the same meaning. 7. Free-body diagrams: ONE mark for each force represented by an arrow with a correct label. Penalise ONCE for: no arrows, gaps between the arrows and the dot, dotted lines, or additional (non-applicable) forces. 8. Vectors: Where a direction is asked for (displacement, velocity, acceleration, resultant force), the final mark is only awarded if the direction is given. Copyright reserved Please turn over

Technical Sciences/P1 3 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 1 1.1 A ✓✓ (2) 1.2 B ✓✓ (2) 1.3 D ✓✓ (2) 1.4 C ✓✓ (2) 1.5 A ✓✓ (2) 1.6 C ✓✓ (2) 1.7 B ✓✓ (2) 1.8 D ✓✓ (2) 1.9 A ✓✓ (2) 1.10 C ✓✓ (2) [20] Copyright reserved Please turn over

Technical Sciences/P1 4 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 2 2.1.1 2,5 × 60 × 60 ✓ = 9 000 s ✓ (2) 750 2.1.2 ✓ = 0,75 m ✓ 1 000 (2) 2.1.3 4,8 × 107 ✓ m ✓ (1 mark for 4,8; 1 mark for the correct power of ten) (2) 2.2.1 Scalar ✓ (1) 2.2.2 Vector ✓ (1) 2.3.1 1 200 + 1 800 ✓ = 3 000 m ✓ (3 km without conversion: 1/2) (2) 2.3.2 North positive: ∆x = 1,2 + (–1,8) ✓ ∆x = –0,6 km ∆x = 0,6 km (600 m) ✓ south ✓ (3) 2.3.3 1,8 km S 1,2 km N resultant: 0,6 km S Criteria: 1,2 km vector north and 1,8 km vector south, labelled, drawn head-to-tail ✓; resultant drawn from tail of first to head of last vector ✓; resultant labelled 0,6 km (600 m) south ✓. (3) 2.3.4 POSITIVE MARKING FROM QUESTION 2.3.1 distance speed = ✓ ∆t 3 000 speed = ✓ 15 × 60 speed = 3,33 m·s–1 ✓ If 15 is used for ∆t (200 m·s–1 ): max 1/3. (3) 2.3.5 POSITIVE MARKING FROM QUESTION 2.3.2 ∆x 600 v= = ✓ ∆t 900 v = 0,67 m·s–1 ✓ south ✓ 0,6 Accept other units: = 2,4 km·h–1 south, or 0,04 km·min–1 (40 m·min–1 ) south. 0,25 (3) 2.4.1 YES ✓ The distance between successive dots increases (in equal time intervals). ✓ (2) Copyright reserved Please turn over

Technical Sciences/P1 5 Hlayiso/Mock 2026 NSC – Marking Guidelines 1 2.4.2 ∆t = 5 × ✓ (5 spaces between 6 dots) 50 ∆t = 0,1 s ✓ (2) 2.4.3 POSITIVE MARKING FROM QUESTION 2.4.2 ∆x = 1 + 2 + 3 + 4 + 5 = 15 cm = 0,15 m ✓ ∆x 0,15 v= = ✓ ∆t 0,1 v = 1,5 m·s–1 ✓ (magnitude only asked: direction not required) (3) 108 36 2.5 vi = = 30 m·s–1 and vf = = 10 m·s–1 ✓ 3,6 3,6 ∆v a= ✓ ∆t 10 – 30 a= ✓ 5 a = –4 m·s–2 , i.e. a = 4 m·s–2 west ✓ Accept: 4 m·s–2 opposite to the motion / deceleration of 4 m·s–2 . No conversion (a = –14,4): max 2/4. (4) [33] Copyright reserved Please turn over

Technical Sciences/P1 6 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 3 3.1 The single force that has the same effect as all the forces acting on an object together. ✓✓ Accept: the vector sum of all the forces acting on an object. (2) 3.2.1 Fg = mg ✓ Fg = (12)(9,8) ✓ Fg = 117,6 N (downwards) ✓ (3) 3.2.2 POSITIVE MARKING FROM QUESTION 3.2.1 117,6 N ✓ The toolbox is at rest (in equilibrium), so the resultant force is zero / the upward tension balances the weight. ✓ (2) 3.3 N / FN / normal force ✓ T2 / 40 N ✓ T1 / 90 N / applied force ✓ f / friction ✓ Fg / w / weight ✓ The 40 N pull and the friction both act to the west: two separate westward arrows are preferred; accept arrows drawn on top of each other provided BOTH are labelled. Do not penalise for relative lengths of arrows. Accept a box drawn instead of a dot. (5) 3.4 East positive: Fres = 90 + (–40) + (–15) ✓ Fres = 35 N ✓ east ✓ Friction omitted (50 N east): max 2/3. (3) [15] Copyright reserved Please turn over

Technical Sciences/P1 7 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 4 4.1.1 Fulcrum / pivot ✓ (1) 4.1.2 Moment (of a force) / torque ✓ (1) 4.1.3 Effort (force) ✓ (1) 4.2 τ = F × r⊥ ✓ τ = (300)(0,17) ✓ τ = 51 N·m ✓ (3) 4.3.1 Take moments about A: Σ clockwise moments = Σ anticlockwise moments ✓ (1 200)(1,5) + (900)(4) + (600)(6) ✓ = RB (5) ✓ 9 000 = 5RB RB = 1 800 N ✓ (4) 4.3.2 POSITIVE MARKING FROM QUESTION 4.3.1 Upward forces = downward forces: RA + 1 800 = 1 200 + 900 + 600 ✓✓ RA = 900 N ✓ OR moments about B: RA (5) + (600)(1) ✓ = (1 200)(3,5) + (900)(1) ✓ ⇒ RA = 900 N ✓ (3) 4.3.3 POSITIVE MARKING FROM QUESTIONS 4.3.1 AND 4.3.2 Upward forces: 900 + 1 800 = 2 700 N ✓ Downward forces: 1 200 + 900 + 600 = 2 700 N ✓ ∴ upward forces = downward forces (2) 4.4.1 Second-class lever (class 2) ✓ (1) 4.4.2 Σ clockwise moments = Σ anticlockwise moments (about the fulcrum) ✓ L(0,02) = (20)(0,10) ✓ (accept cm throughout: L(2) = (20)(10)) L = 100 N ✓ (3) 4.4.3 POSITIVE MARKING FROM QUESTION 4.4.2 load MA = ✓ effort 100 MA = ✓ 20 MA = 5 ✓ (no unit) (3) Copyright reserved Please turn over

Technical Sciences/P1 8 Hlayiso/Mock 2026 NSC – Marking Guidelines 4.5 effort load fulcrum Criteria: fulcrum between the effort and the load ✓; effort at one end ✓; load at the other end, with all three labelled ✓. Accept a labelled sketch of a real object (e.g. see-saw, crowbar, scissors, pliers) if the three positions are correctly labelled. (3) [25] QUESTION 5 5.1 Ek = 12 mv2 ✓ 60 000 = 12 (1 200)v2 ✓ v = 10 m·s–1 ✓ (3) 5.2 Ep = mgh ✓ 19 110 = (65)(9,8)h ✓ h = 30 m ✓ (3) 5.3.1 The sum of the gravitational potential energy and the kinetic energy of an object. ✓✓ (2) 5.3.2 EM = Ep + Ek ✓ EM = (0,5)(9,8)(2,4) ✓ + 21 (0,5)(8)2 ✓ EM = 11,76 + 16 = 27,76 J ✓ (4) 5.3.3 0 J (zero) ✓ The ball is (momentarily) at rest / its velocity is zero at Y. ✓ (2) 5.3.4 POSITIVE MARKING FROM QUESTION 5.3.2 EM(Y) = EM(X) : (0,5)(9,8)h + 0 = 27,76 ✓ h = 5,67 m ✓ 82 Accept h = 2,4 + = 5,67 m. 2(9,8) (2) [16] Copyright reserved Please turn over

Technical Sciences/P1 9 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 6 6.1.1 GAIN ✓ (1) 6.1.2 POSITIVE ✓ (1) Q 6.2.1 n= ✓ e –12 × 10–9 n= ✓ –1,6 × 10–19 n = 7,5 × 1010 electrons ✓ (3) 6.2.2 To prevent the charge from flowing (leaking) away (to the support / ground / earth). ✓✓ Accept: insulators do not conduct, so the spheres keep their charge. (2) 6.2.3 The net (total) charge in an isolated (closed) system remains constant (is conserved). ✓✓ (2) Q1 + Q2 6.2.4 Q= ✓ 2 (–12 × 10–9 ) + (+4 × 10–9 ) Q= ✓ 2 Q = –4 × 10–9 C (on each sphere) ✓ (3) 6.2.5 FROM X TO Y ✓ (1) [13] Copyright reserved Please turn over

Technical Sciences/P1 10 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 7 7.1 The rate of flow of charge. ✓✓ Accept: the amount of charge that passes a point in a conductor per second. (2) Q 7.2.1 I= ✓ ∆t Q 0,25 = ✓ 2 × 60 Q = 30 C ✓ If 2 is used for ∆t (0,5 C): max 1/3. (3) 7.2.2 POSITIVE MARKING FROM QUESTION 7.2.1 Q 30 n= = ✓ e 1,6 × 10–19 n = 1,88 × 1020 electrons ✓ (accept 1,875 × 1020 ) (2) 7.3 S (closed) A 2 cells V Criteria: battery of TWO cells, closed switch and ammeter in series ✓; two bulbs in parallel with each other ✓; voltmeter in parallel across the battery ✓; correct symbols used and circuit complete ✓. (4) 7.4.1 Length of the (nichrome) wire ✓ (1) 7.4.2 Any ONE ✓: Thickness (cross-sectional area) of the wire / type of material / temperature (1) [13] Copyright reserved Please turn over

Technical Sciences/P1 11 Hlayiso/Mock 2026 NSC – Marking Guidelines QUESTION 8 8.1 The work done (energy transferred) per unit (coulomb) of charge between two points in a circuit. ✓✓ (2) 8.2 R12 = R1 + R2 = 4 + 8 = 12 Ω ✓ 1 1 1 = + ✓ Rp R12 R3 1 1 1 = + ✓ Rp 12 6 Rp = 4 Ω ✓ (4) 8.3 POSITIVE MARKING FROM QUESTION 8.2 RT = R4 + Rp = 2 + 4 ✓ RT = 6 Ω ✓ (2) 8.4 POSITIVE MARKING FROM QUESTION 8.3 V R= ✓ I 18 6= ✓ I I=3A✓ (3) 8.5 POSITIVE MARKING FROM QUESTIONS 8.2 AND 8.4 V = IRp = (3)(4) ✓ V = 12 V ✓ OR: VR4 = (3)(2) = 6 V; V = 18 – 6 = 12 V (2) 8.6 POSITIVE MARKING FROM QUESTION 8.5 V 12 I= = ✓ R 6 I=2A✓ (2) [15] TOTAL: 150 Copyright reserved