Physical Sciences Grade 12 P1 North West Mock 2023 QP & Memo

tanmorephysics.com education Department: Education North West Provincial Government REPUBLIC OF SOUTH AFRICA 12841E X10 This question paper consists of 15 pages and 3 data sheets. INSTRUCTIONS AND INFORMATION Copyright reserved Please turn over—...

Downloaded from Stanmorephysics.com Physical Sciences/P1 NW/September 2023 10. 11. 12. NSC Write your name on the ANSWER BOOK. This ques paper consists of TEN questions. Answer ALL the questions in BOOK. uestion on a NEW page in the ANSWER BOOK. Number the answers correctly according to the numbering system used in this question paper. Leave ONE line open between two sub questions, e.g. between QUESTION 2.1 and QUESTION 2.2. You may use a non-programmable calculator. You may use appropriate mathematical instruments. You are advised to use the attached DATA SHEETS. Show ALL formulae and substitutions in ALL calculations. Round off your FINAL numerical answers to a minimum of TWO decimal places. Give brief motivations, discussions, etc. where required. Write neatly and legibly. Copyright reserved Please turn over

Prmnteudted from Stanmorepkysics.com NwiSeptember 2023 QUESTION 1: MULTIPLE-CHOICE QUESTIONS Various options are provided as possible answers to the following questions. Each question has only ONE correct answer. Choose the answer and write only the letter (A-D) next to the=question numbers (1.1 to 1.10) in the ANSWER BOOK, e.g.1.11 E. Inna? 1.1 If the distance of an object above the surface of the Earth is increased, the weight of thi ject vee — A _ increases, B_ decreases. C remains same. D __ increase then suddenly decrease. (2) 1.2 A constant,'resultant force acts on a body which is moving freely in a straight line. Which PHYSICAL QUANTITY will remain constant? A Velocity B = Momentum C Acceleration . D Kinetic energy (2) 1.3 Which one of the following DOES NOT represent the units of a vector? A N B N-C*t Cc Cs DD J-m* (2) Copyright reserved Please tur over--~-

14 1.5 16 Downloaded from Sta je Physical Sciences/P1 nmorephysics. com NW/September 2023 NSC A car is moving on a straight, frictionless and horizontal road at CONSTANT velocity. When the car enters on to a rough surface Q, the speed decreases and the car comes to rest. Which of the following statements about the car, after passing point Q is true? A inetic energy of the car remains constant. B The mechanical energy of the car is conserved. C The potential energy of the car is converted to kinetic energy. D__ The kinetic energy of the car is used to do work against friction. (2) Light of wavelength 680 nm coming from a receding distant galaxy is observed by an astronomer on the Earth. The wavelength observed by the astronomer will most likely be ... A 700nm. B 680nm. Cc 600 nm. D 630nm. (2) A positive test charge is placed in the electric field of two identical positively charged objects Q1 and Qz2as shown in the diagram below. ~ The net force experienced by the test charge will be: A zero 400 B upwards jaa C downwards D to the left (2) Copyright reserved Please turn over

PriaATereed from Stanmorepkysics.com NW/September 2023 1.7 Power may be defined as: A force per unit displacement B gy exchange c of transfer of energy D uct of work done and time 1.8 In the circuit shown below, the battery lights up all four identical bulbs °) P, Q, Rand S. Which one of the statements correctly describes the comparative brightness of bulbs P, Q, R and S? | HHH ] P Q 6) R s at eae A P and Q glow equally bright and are brighter than R and S. B P,R and S are of equal brightness and glow brighter than Q. Cc P and R are of equal brightness and glow brighter than Q and S. D P glows the brightest followed by Q and then by R and S, which are of the same brightness. oo (2) ry Copyright reserved Please turn over

oh Downloaded from Stanmorephysics.com 1.9 NW/September 2023 NSC One difference between a DC generator and an AC generator is that a DC generator ... A gppprates a lower current than an AC generator. nn B “a sto ting and an AC generator has split ring commutator. Cc rm split ring commutator and an AC generator has slip rings. D generates electrical energy where the AC generator generates mechanical energy. (2) An absorption spectrum is the result of the ... A material's absorption of red light. B___ emission of specific frequencies of light when a gas is heated. C atoms of a cold, dilute gas absorbing photons of certain frequencies of white light. D radiation of distinct lines of different frequencies when a low-density gas is electrolysed. (2) [20] Copyright reserved Please turn over

PiDpserreaded from Stanmorephiysics.com NW/September 2023 QUESTION 2 (Start on a new page.) A tow truck attempts to tow a broken down car of mass 400 kg. The coefficient of Static friction is 0,60 and the coefficient of kinetic (dynamic) friction is 0,4. A tow chain connectsifhe tow truck to the car as shown in the diagram below. Janay ft 400 kg Towchain 2.1 Calculate the force required to: 2.1.1 Just move the car if the rope is parallel to the road (3) 2.1.2 Keep the car moving at CONSTANT speed (2) 2.2 A rocket of mass of 20 000 kg moves vertically upwards with a uniform acceleration from rest to a velocity of 40 m-s*in 1.6 s. Ignore the effects of friction. 40 m-s* 2.2.1 State Newton’s Third Law of Motion in words. (2) 2.2.2 Drawa labelled free-body diagram of all the forces acting on the rocket. ay (2) 2.2.3 What is the magnitude and direction of the total forcejexerted on the rocket during first 1,6 s? Lonny (4) inant 2.2.4 An astronaut of mass 80 kg is carried in the space le. Determine the resultant force acting on him during the-first 1,6 s? (2) [15] Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/P1 NW/September 2023 NSC QUESTION 3 (Start on a new page.) A helicopter moves vertically upwards at a constant velocity, releases a package. It takes 6 s forthe package to reach the ground. The package strikes the ground with a velocity-6#/49,8 m:s*. Ignore effects of air friction. 3.1 Define the term free fall. (2) 3.2 Why does the package rise before falling to the ground? (1) 3.3 If the time taken for the package to reach the maximum height is 0,8 s, calculate the velocity of the helicopter. (3) 3.4 Calculate the height of the package above the ground at the moment it is released from the helicopter. (3) 3.5 Draw a velocity-time graph that represents the motion of the package until it reaches the ground. Indicate the initial velocity, final velocity and times for entire motion on the graph. (3) 3.6 Use the graph, drawn for question 3.5, to determine the maximum height reached by the package above its point of release. (2) 3.7 After releasing the package, the helicopter continue to move vertically upwards with the same constant velocity. Calculate how much higher the helicopter moves, from the time it releases the package until the time that the package reaches the ground. (2) [16] Copyright reserved Please turn over

PiewAforeed from Stanmorephysics.com NWiSeptember 2023 QUESTION 4 (Start on a new page.) Two trolleys are placed on a frictionless track in a Physics laboratory. A compressed spring is placed between the two stationary trolleys. Trolley 1 has a mass of 500 g and trolley 2 has a mass of 30 The spring is released and trolley 1 moves away with a velocity of 2,4 m-s*. 41 State the law of conservation of momentum. (2) 4.2 Calculate the velocity of trolley 2 after the spring is released. (3) 4.3 If the release of the spring takes 0,12 s. Calculate the force which the spring exerts on each of the trolleys. (3) 44 Describe how the acceleration of the trolleys would be affected if the masses of the trolleys were doubled. Choose from INCREASE, DECREASE OR REMAINS THE SAME. Explain your answer. (2) [10] Copyright reserved Please turn over~-

prfrerealeaded from Stanmorephysics.com NW/September 2023 NSC QUESTION 5 (Start on a new page.) Acyclist cycles up to the top of a hill with a length of 50 m ata CONSTANT velocity. The force of kinetic friction that the bike encounters is 55 N. The combined mass of the cyclist and the bicycle is 70 e slope forms an angle of 30° with the horizontal. 5.1 Draw a labelled free-body diagram to show all the forces acting on the bicycle when the cyclist pedals up the slope. (4) §.2 When the bicycle in going up the slope, calculate work done by the: 5.2.1 Force of friction (3) 5.2.2 Gravitational force -(3) 5.2.3 Applied force (4) 5.3 Determine magnitude of the applied force (2) [16] ss Copyright reserved Please turn over.

rihewsltended from Stanmorephysics.com NW/September 2023 NSC QUESTION 6 (Start on a new page) 6.1 Diagram below represents sound waves which are emitted by the siren of a police car. The speed of the police car is 100 km-h~! and frequency of sound wav ‘ed is 800 Hz. The points L1 and Lz represents the stationery listen anding on the road. 6.1.1 State the Doppler effect in words. (2) 6.1.2 What is the name of the instrument used to measure the rate of blood flow in the arteries of a human being? (1) 6.1.3 Will the frequency of the sound heard by listener L1 be greater or less than 800 Hz? Explain the answer. (3) 6.1.4 Calculate the frequency of sound heard by the listener Li. (4) 6.2 Galaxy Ais 1 500 million and Galaxy B 5 000 million light years away from Earth. Light from which galaxy will have greater red shift? Explain your answer. (3) [13] Copyright reserved Please turn over ~

PpEWHIEeY from Stanmorepfysics.com NWiSeptember 2023 QUESTION 7 (Start on a new page.) Two dust particles are floating in the air. One dust particle carries a charge of -6 nC and other carries a charge of -3 nC. When they are a certain distance r from each other, they experience a force of 6,48 x 10° N. — danar ‘ar Lonny r > 7.1 Write down the name of the force that exists between these two particles and state the effect they have on each other. (2) 7.2 Suggest ONE way in which the particles could have acquired their charge. (1) 7.3 Draw the electric field pattern, which exists between the two particles. (2) 74 Calculate the distance r between the particles. (4) 7.5 Calculate the magnitude and direction of net electric field at a point X which is exactly halfway between the particles, when they are at distance rapart. (5) [14] Copyright reserved Please turn over_

Pyeunleaded from Stanmorephysics.com NWiSeptember 2023 NSC QUESTION 8 (Start on a new page.) Two 9 V batteries are connected in a circuit with an ammeter, a switch, a voltmeter, two 3 light bulbs and a resistor R as shown in the circuit diagram below. The battery has an internal resistance r. G) 30 30 8.1 When the switch is open, what will the reading be on the: 8.1.1 Voltmeter (1) 8.1.2 Ammeter (1) 8.2 When the switch is closed, voltmeter reading drops by 0,72 V and ammeter reads 7,2 A. 8.2.1 Explain why the voltmeter reading drops. (3) 8.2.2 Calculate the internal resistance r of the battery. (3) 8.2.3 Calculate the resistance of the resistor R (5) 8.3 If the resistor R is removed from the circuit, would the power dissipated in the light bulbs INCREASE, DECREASE or REMAINS SAME. Explain your answer without calculations. yA (3) . [16] ry Copyright reserved Please turn over

Downloaded from Stanmorephysics.com Physical Sciences/P1 14 NW/September 2023 NSC QUESTION 9 (Start on a new page.) A company that. manufactures electrical appliances has produced a new cordless electric drill which is operated by a 9 V battery. 9.1 Staté-the principle on which an electric motor works. (2) 9.2 Does the drill have a direct or alternating current motor? (1) The diagram below shows a simplified version of structure of a motor. The coil is placed between the opposite poles of two magnets. — 9.3 Name the structure that ensures the coil rotates in one direction only. (1) 9.4 If the current is flowing in the coil as indicated in the diagram, the coil is undergoing anticlockwise rotation. Is the magnetic field direction from B to Aor from A to B? (1) 9.5 Peter has an electric drill, which operates from an alternating current supply. The drill has the following markings on it: 240 V,1800 W, 50 Hz The current passing through the drill while operating is represented in the graph below: 10,6 1(A) -10,6 9.5.1 The current passing through the drill changes within every cycle. How long does it take to complete a cycle? (1) Copyright reserved Please tum over

Downloaded from Stanmorephysics.com Physical Sciences/P1 NW/September 2023 NSC 9.5.2 Calculate the rms current the drill draws when operating. (3) 9.5.3 What is the resistance of the drill? (4) faar 9.6 Smalilectric motors are used in remote controlled toy cars. =a On, o6ne Write down two modifications that can be made to increase toy ra car’s speed. (2) 9.6.2 As the motor turns, the wheels of the car rotates in one direction, moving it forwards. Write down TWO modifications to the motor that could make the car to move in reverse direction. (2) [17] QUESTION 10 (Start on a new page.) A scientist was investigating certain material for possible use in a solar cell, Firstly the scientist uses a source of blue light with wavelength 460 nm to produce photo electrons. The kinetic energy of photo electron is 1,6 x 101° J. The scientist then carries an experiment to find out whether light of other wavelengths also emits electrons from the material. He used red light with wavelength 700 nm in this experiment. 10.1 What type of energy conversion is taking place in a solar cell? (2) 10.2. What is the aim of his investigation? (2) 10.3 Show by calculation whethi light will be able to emit electrons from the material? ‘_ - (7) 10.4 Is the material used . suitable for making solar cells? Explain your answer. (2) [13] TOTAL: 150 * Copyright reserved

Dowplaadedstrom Stanmorephysics.com NW/September 2023 DATA FOR PHYSICAL SCIENCES GRADE 12 PAPER 1 (PHYSICS) EGEWENS VIR FISIESE WETENSKAPPE GRAAD 12 VRAESTEL 1 (FISIKA) TABLE 1: ICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE Acceleration due to gravity 7 Swaartekragversnelling g 9,8 ms? Universal gravitational constant G 6,67 x 101! N-m@-kg2 Universele gravitasiekonstant Speed of light ina vacuum Spoed van lig in 'n vakuum c 3.0 x 108 m-s Plank oe honsante hn G6s% 10" ts x Copyright reserved Please turn over

Phpsasishacnee eh from Stanmorephysics.com TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING Vv, =V, +a Atoay Ax=v,At+4aAt? orlof Ay =v,At++taat? VP =v? + Zan orlof v,? =v? +2ady | Ax= (“5a orlof Ay = (“Jas Lt FORCE/KRAG Fra = ma p=mv f°" =y,N f= HN F,,At=Ap w=mg Ap=mv, — mv, mm mm M M F=G~ a orlof F=G— > g “Ce orlof fe] =Gy WORK, ENERGY AND POWER/ARBEID, ENERGIE EN DRYWING W=FAxcos 0 U=mgh oof E,=mgh 4 1 Whret = AK oof Wah» = AE, K==mv? oof ££, =—mv? 2 2 AK=K,-K, ‘orof AE, =Ey —E, Wye = AK +AU or/of W,, = AE, + AE, “ Pare =FV ave! Poemia = FV gemia WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG 1 v=fr T= 7 vVtv VV, c f= Lf. f= Lf E=hf orfof E=h— r ‘viv, ° ‘viv, ? " 2 * E=W, +E may or/of E=W, +Ky, where/waar E=hf and/en W, =hfy and/en Ej ina =p mVi or/of K jax =5 fo Copyright reserved Please turn over NW/September 2023

Bowsleades.ifrom Stanmorephysics.com NW/September 2023 NSC ELECTROSTATICS/ELEKTROSTATIKA p_KQ.Q, eka vv ef q q Q n=2 otlof n= e le ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE emf(&) = (R+1r) emk (£) = (R+r) R,=R,+R,+ 1.1 1 q=1 At rs R, R, R, W = Vq Ww P=— At W = VIAt P=VIi W = PRAt , P =IR W = = p- ve R ALTERNATING CURRENT/WISSELSTROOM Trax - Tina Tins “2 / Tok ~ 2 Poe =Vinslms / Poemiddeld = Vig gk Vv Pye Ta — Paemidets = "Bg Vins = T= ! v2 P. _ Vine P Veck Vovox = am ae R ! R- 2 [aYaYay c= Copyright reserved

Downloaded, from Stanmorephysics.com education Department: Education North West Provincial Government REPUBLIC OF SOUTH AFRICA NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT " PHYSICAL SCIENCES: PHYSICS (P1) Hi jf FISIESE WETENSKAPPE: FISIKA (V1) i . SEPTEMBER 2023 i " MARKING GUIDELINES/NASIENRIGL YNE : MARKS/PUNTE: 150 These marking guidelines consist of 13 pages and a cognitive table/ Hierdie nasienriglyne bestaan uit 13 bladsye en ‘n kognitiewe tabel. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physpo Rseloadodsitscovredseqermorephysics.com NW/September 2022 NSC/NSS — Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.1 Bovv (2) 1.2 vv (2) 1.3 vv (2) 1.4 vv (2) 1.5 A vv (2) 1.6 Boovv (2) 1.7 Cc vw (2) 1.8 D vy (2) 1.9 G wx (2) 1.10 Cc vw (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

pryDavtleade disfromeBtanmoreph ics.com NW/September 2023 Ui NSC/NSS — Marking Guidelines/Nasienriglyne QUESTION 2/VRAAG 2 2.1.1 | Fs = UsFg Fs=usN | any onev = (0,6)(400)(9,8) v Fs = 2852 Nv (3) I~ 2.1.2 [OP 1/0PSIE 1 OPTION 2/OPSIE 2 Fr =/UkFa Fret = ma = pkN Fa — fk = 400 x 0 = (0,4)(400)(9,8) v Fa—0,4x 400x 9,8 =0V = 1868 No" Fa = 1568 N ¥ (2) 2.2.1. When object A exerts a force on object B, object B simultaneously exerts an oppositely directed force of equal magnitude on object A.v v Wanneer voorwerp A ‘n krag op voorwerp B uitoefen, sal voorwerp B gelyktydig ‘n krag van gelyke grootte en in die teenoorgestelde rigting op voorwerp A uitoefen. (2) 22:2: F Thrust /Frtoegepas F on rocket /F op vuurpyl F on gas F IF op gas 9 Fthrust/Fapplied by gas/FToegepas v Fg/mg/weight/ gravitational force/w/gravitasiekrag ve Fon rocket/| Fop vuurpyl Fon gas/ Fi ‘op gas Accept any of the 2 forces/Aanvaar enige 2 kragte (2) 2.2.3 vr = vi + adt ¥ 40 = 0 + (a)(1,6) ¥ a=25m:s Frotal/Totaal = W + ma = (20 000)(9,8) + (20 000)(25) v = 696 000 NY (4) 2.2.4 | Fnet= ma-w = (80)(25) - (80)(9,8) v = 1216 NY (2) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

pryBewnleedecisfromeBtapmoreph sics com NW/September 2023 ul NSC/NSS — Marking lelines/Nasienriglyne QUESTION 3/VRAAG 3 3.1 Motion during which the only force acting on an object is the force of gravity. “~~ Beweging waar die enigste krag wat op die voorwerp inwerk gravitasiekrag is. (2;0¥¢/0f 0) (2) 3.2 It has;4n initial velocity as it is rising with the helicopter.v Dit het“n aanvanklike snelheid soos dit saam met die helikopter opwaarts beweeg. OR/OF Package has same initial velocity of that of the helicopter. v Dit het ‘n aanvanklike snelheid dieselfde as die helikopter. Accept explanation based on Newton’s first law Aanvaar verduideliking gebaseer op Newton se eerste wet (1) 3:3 Consider upward motion of the package/Beskou opwaartse beweging van die pakkie: V=vi t+ adt ¥ 0 = vi + (-9,8)(0,8) v vi = 7,84 m-s upwards/opwaarts ¥ Initial velocity of the package is same as the velocity of helicopter. Die aanvanklike snelheid van die pakkie is dieselfde as die snelheid van die helikopter. (3) 3.4 vie = vit +2aAy ¥ (-49,8)? = (7,84)? + (2)(-9,8) Ay Ay = -123,4 m =123,4 m above the ground/bo die grond v (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

prybewnleedecisfromebtapmoreph ics.com NW/September 2023 Ui 3.5 3.6 3.7 NSC/NSS — Marking Guidelines/Nasienriglyne POSITIVE MARKING FROM QUESTION 3.3 POSITIEWE NASIEN VANAF 3.3 v (m-s*) t(s) 49,8v Marking criteria/Nasienkriteria Labelling/Benoem 7,84 and/en 49,8 on the graph/op die grafiek vv Labelling/Benoem 0,8 s and/en 6 s on the graph/op die grafiek V Height reached = area under the graph/ Hoogte = opperviak onder die grafiek Height/Hoogte = 2 bh = % (0,8)(7,84) v = 3,14 mv Ay = viAt =(7,84)(6) v = 47,04 mv QUESTION 4/VRAAG 4 4.1 4.2 Copyright reserved/Kopiereg voorbehou The total linear momentum of a closed system remains constant (is conserved). VV Die totale linieére momentum in ‘n geslote sisteem bly konstant. (2 or/of 0) ZPbefore/voor = ZPafterina mivi + mavi = mivr + mavs any one/enige een Vv 0 v= (0,5)(-2.4) +(0,3)(vi) ¥ vr = 4 m:s" towards right/na regs ¥ (3) (2) (2) [16] (2) (3) Please turn over/Blaai om asseblief

prybewnleedecisfromBteapmoreph NSC/NSS — Marking ics.com NW/September 2023 ines/Nasienriglyne 4.3 | Marking criteria/Nasienkriteria Formula v Substitution to calculate Fnet ¥ Final answer teen die trollie OPTION-4/OPSIE 1 OPTION 2/OPSIE 2 Fret At Al i any one Vv Fret At = AP any one ¥ Fret Ai + ip vi) enige een Fret At = m(vr— vi) enige een if -2,4) — (0,5) (0) ¥ Fret = (0,3)(4) — (0,3) (0) ¥ 0,12 0,12 Fost = “10 Nv Fret = 10 N against the trolley/ = 10 N against the trolley/ teen die trollie v (3) 4.4 Decreases/Afneem Vv Acceleration is inversely proportional to the mass/Versnelling is omgekeer eweredig aan die massa V 1 ax— (2) [10] QUESTION 5/VRAAG 5 5:1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 F Fn P Fa Fa Fy Fr Fg Fg Accepted labels/Aanvaarde benoemings Nv Fn/Normal/Normal force Normaal /Normaalkrag Fv Fa/Applied force force Fa/Toegepaste krag Fr/rv Force of friction/Wrywingskrag_| w ¥ OR/OF F,/mg/weight/ gravitational force: Fgi and/en Fgt Fg/mg/gewig/ gravitasiekrag 1a) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

pryBewnleededisfromeBtepmoreph ics.com NW/September 2023 1} NSC/NSS — Marking Guidelines/Nasienriglyne 5.2 .1 | Wer= Fr Ax cos® ¥ Wer= (55)(50) (cos180) ¥ = -2750 J ¥ (3) 5.2.2 | Fe =masind 70)(9,8)(sin 30°) N Wo -=Fgi Ax cos® “=-(343)(50)(cos180)V =-17150 J ¥ (3) 5.2.3. | POSITIVE MARKING FROM QUESTION 5.2.1 and 5.2.2 POSITIEWE NASIEN VANAF 5.2.1 and 5.2.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 Whret =Wrapp + Wet + Wegi “ | Wea = FaAxcos® ¥ 0 Y= Weapp -2750-17150 ¥ = (70 x 9.8 x sin30°+ 55) v(50)(cos0")” Wrapp = 19900 J¥ = 19900 J v (4) 5.3 POSITIVE MARKING FROM QUESTION 5.2.3 POSITIEWE NASIEN VANAF 5.2.3 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 W Fapp = Fapp Ax cos® Fapp = Fr+ Fai 49900 = Fapp x 50 x cos’ ¥ Fapp = 55 + 343 V Fapp = 398 NV Fapp = 398 NV (2) OPTION 3/OPSIE 3 Fnet = ma Fa — (Fg + f) =ma Fa = (70 x 9,8 x Sin 30°) + 55 v = 398 Nv [16] QUESTION 6/VRAAG 6 6.1.1. The change in frequency (or pitch) V of the sound detected by a listener because the sound source and the listener have different velocities relative to the medium of sound propagation. v / Die verandering in_die frekwensie (toonhoogte) van die waargenome klank deur die luisteraat- ag Wv die klankbron en die luisteraar wat verskillende snelhede relatief: fot mekaar het. OR/OF An (apparent) change in (observed/detected) frequency.(pitch),” as a result of the relative motion between a source and an observer V (listener). 'n (Skynbare) verandering in (waargenome) frekwensie_ (toonhoogte), as gevolg van die relatiewe beweging tussen die bron en _'n waarnemer/luisteraar. (2) 6.1.2 Doppler flow meter/Doppler vioeimeterY (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

pryBownleedecisfromeBteapmoreph ics.com NW/September 2023 Ui NSC/NSS — Marking Guidelines/Nasienriglyne 6.1.3. Less than/Minder as 800 Hz. ¥ As the police car moves away, fewer waves arriving per secondy v and lesser the frequency/Soos die polisiemotor weg beweeg, verminder die golwesper sekonde en verminder die frekwensie OR/OF/ wavelength is inversely proportional to the frequency golfle is omgekeerd eweredig aan die frekwensie (3) 6.1.4 | Marking criteria/Nasienkriteria Formula to calculate fl ” Substitution of (340-0) v Substitution of (800) v Final answer ¥ _Vtv, v f= viv, f Vs = 100 km-ht Vs = 27,78 ms ' fL= (340-0)v (800) v (340+27,78) f. = 739,57 Hz Vv (4) 6.2 Galaxy/Sterreste/lsel B~” The more distant the galaxy is,“ the greater the speed at which it is moving.” Hoe verder weg die sterrestelsel is, hoe groter is die spoed waarteen dit beweeg. (3) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

pryBownleedecisfromeBteapmoreph ics.com NW/September 2023 Ui NSC/NSS — Marking Guidelines/Nasienriglyne QUESTION 7/VRAAG 7 7.1 7.2 7.3 7.4 7.5 Copyright reserved/Kopiereg voorbehou Electrostatic force/Elektrostatiese krag V They repel each other/stoot mekaar wegv Marking criteria/Nasienkriteria Shape/Vormv Correct direction/Korrekte rigtingY kQ:Q, 2 6,48 x 10° v = (9x 109) (6 x 10°) (3x 10%) V (r? r =0,005mv/5x10%m Marking criteria/Nasienkriteria Formula to calculate E/Formule om E te bereken Vv Correct substitution to calculate Eenc/Korrekte vervanging om Eéenc te bereken Correct substitution to calculate Esnc/Korrekte vervanging om Enc te bereken ~ Vector addition (subtraction) to calculate Enet/ Vektor addisie (aftrekking) om Enet te bereken ~ Final answer/Finale antwoordv POSITIVE MARKING FROM QUESTION 7.4 POSITIEWE NASIEN VAN VRAAG 7.4 pKa, " Eone=( 6x 10°) v 10°): = x N-C*t to the left/na links fact Esne =( 9 x 102) (3 x 10°) v px = 4,32 x 10° N-C*t to the right/na regs Enet = (8,64 x 10°) — (4,32 x 106) v = 4,32 x 10° N-C"' to the left/na links V (2) (1) (2) (4) (5) [14] Please turn over/Blaai om asseblief

pryBewnleedecisfromeBtapmoreph ics.com NW/September 2023 uide| NSC/NSS — Marking ines/Nasienriglyne QUESTION 8/VRAAG 8 8.1.1 18VVv (1) (1) 16 charges moves through the battery, some of the energy is lost ¥ in théiform of heat due to internal resistance. V Therefore there is less potential difference available to the charges. V Soos wat ladings deur die battery beweeg, sal van die energie verlore gaan in die vorm van hitte a.g.v. interne weerstand. Daarom is daar minder potensiaalverskil bekikbaar vir die ladings. (3) 8.2.2 | Viostivertore = |r ¥ 0,72=7,2rv r=0,1Q9V (3) 8.2.3 [POSITIVE MARKING FROM QUESTION 8.1.1 and 8.2.2 POSITIEWE NASIEN VAN VRAAG 8.1.1 EN 8.2.2 emf (£)=\(R +1) ¥ 18 v= 7,2 (Rr+ 0,1) Vv Rr=2,40 1.1 1 —=— ++ R, R, R, has 2; tiv av (5) Rolo < 2s 4 R= 8.3 Decreases/Afneem Vv There are fewer bulbs in parallel. Total resistance of the external circuit increases and total current decreases. V Decrease in current results in a decrease in the power. v Daar is minder gloeilampe in parallel. Totale weerstand van die eksterne stroombaan verhoog en totale stroom(sterkte) neem af. Afname in stroom(sterkte) lei tot ‘n afname in drywing. (3) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

pryBewnleedecisfromeBtapmoreph ics.com NW/September 2023 ul NSC/NSS — Marking lelines/Nasienriglyne QUESTION 9/VRAAG 9 9.1 A current carrying conductor will experience a force,v when placed in a magnetic field.” Accept:Fleming’s left hand motor rule. ‘n Stroomdraende geleier sal ‘n krag ervaar wanneer dit in ‘n magnetiese veld geplaas word. Aanvaar: Fleming se linkerhand motorreél (2) 9.2 Direct current motor/Gelykstroom motor v (1) 9.3 Split ring commutator/Split ring kommutatorY” (1) 9.4 A to B/A na BY (1) 9.5.1 | T=1 50 =0,02 s v (1) 9.5.2 I on = max wv V2 _ 10,6 Z V2 lms =7,5A% (3) 9.5.3 | POSITIVE MARKING FROM POSITIVE MARKING FROM QUESTION 9.5.2 QUESTION 9.5.2 POSITIEWE MERK VAN VRAAG 9.5.2 | POSITIEWE MERK VAN OPTION 1/OPSIE 1 VRAAG 9.5.2 Pave = I?rms x R ¥ OPTION 2/OPSIE 2 1800 v= 7,52 xRv¥ Pave = V2ims R=32QV R 1800 v= 2402 v R R=32QVv (4) 9.6.1 Use stronger magnets/Gebruik sterker magnetev Use a higher voltage battery/Gebruik 'n battery met hoér potensiaalverskilV Increase number of turns of the armature (coil)./Verhoog die aantal draaie(windings) van die spoel. Any twolenige twee ann} (2) 9.6.2 Rotate poles of the magnetY OR change the poles of the battery Roteer die pole van die magneet OF verander die pole van-die battery (2) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Prydso necloadedsifvcoveredseadermorephysics.com NSC/NSS — Marking Guidelines/Nasienriglyne QUESTION 10/VRAAG 10 10.1 10.2 10.3 Copyright reserved/Kopiereg voorbehou Light energy converts to electrical energy/Lig energie omgeskakel in elektriese energie VV To determine which wavelengths of light are suitable for use in a solar cell¥ivs= OPTION 1/ OPSIE 1 Marking criteria/Nasienkriteria Any of the formula/Enige formule ” Correct substitution to calculate E for blue light/Korrekte substitusie om E vir die blou lig te bereken Correct substitution of kinetic energy/Korrekte substitusie van kinetiese energie” Final answer for Wo/Finale antwoord vir Wo ¥ Correct substitution to calculate E for red light/Korrekte substitusie om E vir die rooi lig te bereken ~ Final answer for E for red light/Finale antwoord vir E van die rooi lig V Writing the answer/Skryf van die antwoord Ered/rooi > Wo ¥ E = Wo + Exmax) he = hfo + % mv? A any one/enige een Vv E= he A Wo = (6,63 x 10°)( 3 x 108) v- (1,6 x 10°79) v (460 x 10°) =2,72X109 Sv Energy of a red light photon/Energie van ‘n rooilig foton E= he rN E = (6,63 x 10°%4)(3 x 108) v (700 x 10°) = 2,84 X 10°19 J v Red light will emit electrons since/Rooilig sal fotone vrystel want Ered/rooi > Wo i NW/September 2022 (2) (2) Please turn over/Blaai om asseblief

Phydpo necloadedsidzeoretedseavermorephysics.com NW/September 2022 10.4 NSC/NSS — Marking Guidelines/Nasienriglyne OPTION 2/ OPSIE 2 Marking criteria/Nasienkriteria Any of the formula/Enige formule v Corregt-substitution to calculate E for blue light/Korrekte substitusie om E vir die-blou lig te bereken~” Correct substitution of kinetic energy/Korrekte substitusie van kinetiese energiew Finalanswer for Wo/Finale antwoord vir Wo Correct substitution to calculate fo/Korrekte substitusie om fo te bereken ~ Correct substitution to calculate f for red light/Korrekte vervanging om f van die rooi lig te bereken.v Writing the answer/Skryf die antwoord f > fo v E = Wo + Eximax) he = hfo + % mv? A any one/enige een ¥ E= he A E = (6,63 x 10°°4)(3 x 108 ) v (460 x 10°9) =4,32 x10? J E = Wo + Eximax) (4,32 x 1079) =Wo+(1,6x 109 v) Wo = 2,72 x10"9 J v Wo = hfo (2,72 x 10°19) = (6,63 x 10°4) (fo)” fo = 4,10 x 10% Hz ye >1lo f=3x 108 v 700 x 10° = 4,29 x 1014 Hz ¥ Red light will emit electrons since/Rooilig sal fotone vrystel want f > fo v (7) Yes/Jav Red light has the longest wavelength in the visible light spectrum.” If red light could emit electrons from the material, all other: colours will emit electrons. Rooilig het die langste golflengte in die sigbare ligspektrum-2 Indien rooilig elektrone vrystel vanuit die materiaal, sal alle-ander kleure lig ook elektrone kan vrystel. (2) [13] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou

Phyddo necloadedsifeovredsearermorephysics.com NW/September 2023 NSC/NSS — Cognitive Grid/Kognitiewe Tabel SUBJECT: PHYSICAL SCIENCES PAPER 1 GRADE 12 ANALYSIS GRID SEPTEMBER 2023 jnitive Levels Topics Difficulty Levels z a i a 2 = rs el x ¢ |3~ I36 ee | Se ee | a! & ole/falaX FZela2 ° 3 S 3 wl s St(g=F ole 2 Else] © ms |S = 3] 4 $2|$22/355/ 252 2/4 os |s S| Pay) SoG 23 |Feaslusul|see iF 2 2 2 2 2 a2. 2 2 z 2 2 13 = 2 2 2 Z 14 2 2 2 2 2 15 2 2 2 2 2 16 2 2 2 2 2 aed: 2 2 2 2 z 18 2 2 2 2 2 1.9 24 2 2 2 2 1.10 | 2 2 2 2 Ques1 | 20/ 6 | 6/8] 0 8 2 8 2 20 10 4 6 2.1.1 3 3 3 3 3 212 2 2 2 2 2 2.2.1 2 2 2 2 2 2.22 2 - z 2 2 2.23 4 4 4 4 4 2.24 ] 2 2 2 2 | Ques2| 15| 2/4/99] 0] 15 o 0 oO 15 5 6 4 3.1 | 2 2 2 2 3.2 1 1 1 1 1 33 3 3 3 3 3 34 3 3 3 3 3 3.5 3 3 3 3 3 3.6 2 2 2 2 2 37 23 2 2 2 2 Ques3 | 16/2/2/9] 3] 16 0 0 0 16 4 5 7 41 Z 2 2 2 2 42 3 3 3 3 3 43 3 3 3 3 3 44 2 2 2 2 2 Ques4{10/2/5/ 3] 0] 10 oO 0 0 10 2 3 5 51 4 4 4 4 4 §.2.1 3 3 3 3 3 §.2.2 3 3 3 3 3 §.2.3 4 4 4 4 4 5.3 2 2 2 2 2 Ques5 | 16/0/6| 8/2] 16 oO 0 oO 16 oO 10 6 6.1.1 2 2 2 2 2 6.1.2 1 1 1 1 6.13 3 3 3 3 6.14 4 4 4 4 4 6.2 3 3 3 3 3 Ques6 | 13/ 2/8| 3] 0 0 13 C) 0 13 3 4 71 2 2 2 2 72 i 1 1 1 73 2 2 2 2 74 4 4 4 4 4 75 5 5 5 5 5 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

pryBewnleedecisfromeBtepmoreph ics.com NW/September 2023 ju NSC/NSS — Marking Guidelines/Nasienriglyne SUBJECT: PHYSICAL SCIENCES PAPER 1 GRADE 12 ANALYSIS GRID SEPTEMBER 2023 Cognitive Levels Topics Difficulty Levels z a = : = a ° =| = Hoof s if ise *lelelf| F a| 8 wl/e|s)/ee/@L |§FZe) a2 elgi sie =] fe /SaglE2s|/s52 ee a >Peloa Fe = Go sSl|E535/8e5| aac 23 |Ses|uso|sss Ques7 [14] 2/7] 5] 0 0 0 14 0 14 5 9 0 8.11 1 1 1 1 1 8.1.2 a 1 1 1 1 8.21 3 3 3 3 3 8.22 3 3 3 3 3 8.23 5 5 5 5 5 83 3 3 3 3 3 Ques8| 16/2] 8/6] 0 o 0) 16 o 16 2: 9 5 91 2 2 2 2 2 9.2 1 1 1 1 1 93 1 1 1 1 1 94 1 1 1 1 1 951 1 1 1 1 1 952 3 3 3 3 3 953 4 4 a 4 4 96.1 2 2 2 2 2 9.6.2 2 2 2 2 2 Ques9 [17/3 [5/8] 14 0 0 17 0 17 £ 9 1 10.1 ee 2 2 iz 2 10.2 2 2 2 2 2 10.3 7 7 7 7 7 10.4 2 v3 2 2 Y4 Ques 10] 13 | 2/2/21] 7 0 0 0 13 413 4 2 7 |Norm%] 100] 15/35] 40] 10] | =f TT 0 | 40 | 30 Copyright reserved/Kopiereg voorbehou