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Technical Mathematics Grade 12 P1 Gauteng Mock 2023 Addendum

AddendumTechnical MathematicsGrade 1220232 pages

Grade 12 Technical Mathematics Paper 1 addendum from the Gauteng Mock Exam 2023 (Afrikaans), 2 pages. Read online or get the free PDF download.

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ADDENDUM TECHNICAL MATHEMATICS/TEGNIESE WISKUNDE Prelimanary Examination / Voorbereidende Eksamen Paper / Vraestel 1 September 2023 FINAL MARKING GUIDELINES (ADDITIONAL NOTES) FINALE NASIENRIGL YNE (ADDISIONELE NOTAS) ITEM DESCRIPTION/BESKRWING NPU and NPR is valid for all questions where applicable / NPU en NPR is geldig op alle vrae waar van toepassing. After factorizing, the bracket has to be a quadratic expression in order to CA the answer. 1.1.2 Nadat daar gefaktoriseer is, moet die uitdruikking in die hakkie kwadraties wees om die CA vir die antwoorde te doen. Accept the following as an answer: / Aanvaar die volgende as ‘n antwoord: 1.1.4 𝑧̅𝑇 = −2 + 𝑖 3.1.2 It the learner changed the -2 to 2 and kept −𝑖 then the learner gets 0 for the answer. Indien die leerder die -2 na 2 toe verander het en die −𝑖 gehou het, kry die leerder 0 vir die antwoord. No penalty if the calculation is not shown/ indicated. 4.1.3 Geen straf as die bewerking nie gewys word nie. Only ONE point if intersection. 5.5 Slegs EEN punt waar hulle sny. Accept the following due to an error on the information sheet: Aanvaar die volgende as gevolg van ‘n fout op die inligtingsblad. 𝐴 = 𝑃(1 + 𝑖)2 ✓F A 0,092 2 = 3 400 (1 + 365 ) ✓ SF A 0,092 = 𝑅3 401,71 ✓ A 365 = 𝑅3 402 ✓ R3 402 CA 6.2.1 OR / OF 𝐴 = 𝑃(1 + 𝑖)2 ✓F A 0,092 2 = 3 400 (1 + 2 ) ✓ SF A 0,092 = 3 719,9944 ✓ 2 A = 𝑅3 720 ✓ R3 402 CA (4) Accept the following due to an error on the information sheet: Aanvaar die volgende as gevolg van ‘n fout op die inligtingsblad. 6.3 𝐴 = 𝑃(1 + 𝐼)2 0,125 2 0,125 = 20 000 (1 + ) ✓ A 12 12 = 20 418,836 ✓ 20 418,836 CA
𝐴 = 𝑃(1 + 𝑖)2 ✓ SF CA 0,098 2 0,098 = 20 418,836 (1 + 4 ) ✓ 4 A = R21 431,62 ✓ 21 431,62 CA OR/OF 12,5 2 9,8 2 0,125 100 𝐴 = 20 000 (1 + 12 ) . (1 + 4 ) 100 ✓ 12 A 𝐴 = 𝑅21 431,62 ✓M A 9,8 ✓ 4 100 A ✓M A ✓ 21 431,62 CA OR / OF 𝐴 = 𝑃(1 + 𝐼)2 0,125 2 0,125 = 20 000 (1 + 2 ) ✓ 2 A = 22 578,125 ✓ 22 578,125 CA 𝐴 = 𝑃(1 + 𝑖)2 ✓ SF CA 0,098 2 0,098 = 20 418,836 (1 + 2 ) ✓ 2 A = R24 844,99 ✓ 24 844,99 CA OR/OF 12,5 2 9,8 2 0,125 100 𝐴 = 20 000 (1 + 2 ) . (1 + 2 ) 100 ✓ 2 A ✓M A 9,8 𝐴 = R24 844,99 ✓ 100 2 A ✓M A ✓ 24 844,99 CA When marking first principles, as soon as a learner makes a second mistake, you stop marking and do not allocate any further marks. ONLY in Question 7.1. 7.1 Wanneer ons eerste beginsels merk, hou ons op merk sodra die leerder ‘n tweede fout maak en dus gee ons nie verder punte nie. SLEGS in Vraaf 7.1. 3 If the learner only writes 𝑥 = 2, you may award full marks. 7.4 3 Indien die leerder slegs 𝑥 = 2 skryf, mag jy volpunte toeken. ✓ – 8𝑙𝑛𝑥 + 𝑐 If a learner omits the c in this question, DO NOT penalise the learner. 10.1.2 Indien die leerder die c weglaat in hierdie vraag, MOET die leerder NIE gepenaliseer word NIE. DATE APPROVED/DATUM GOEDGEKEUR 8 SEPTEMBER 2023 EXTERNAL/EKSTERNE MODERATORS/E INTERNAL /INTERNE MODERATORS/E Name Signature Name Signature HJ Swart

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