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Physical Sciences Grade 12 KZN March 2023 Paper & Memo

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Grade 12 Physical Sciences question paper and memo from the KZN March 2023, 23 pages. Read online or get the free PDF download.

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mownloaded from Stanmorephysics.com Ae Seeeseseeest P cy . " cy cy 1” 1" a" ry 1. 1. cy is » 100 TIME : 24Hours This question paper consists of 10 pages and 3 data sheets. Please turn over
Physi March 2023 Common Test “DSiioaded from Stanmorepfysics. com INSTRUCTIONS AND INFORMATION a Write your NAME in the appropriate spaces on the ANSWER BOOK. Zs This question paper consists of SEVEN questions. Answer ALL the questions in the AREER BOOK. 3. Start EACH question on a NEW page in the ANSWER BOOK. 4. Number the answers correctly according to the numbering system used in this question paper. 5. Leave ONE line between two subquestions, for example between QUESTION 2.1 and QUESTION 2.2. 6. You may use a non-programmable calculator. a, You may use appropriate mathematical instruments. 8. Show ALL formulae and substitutions in ALL calculations. 9. Round off your final numerical answers to a minimum of TWO decimal places. 10. Give brief motivations, discussions et cetera where required. 1. You are advised to use the attached DATA SHEETS. 12. Write neatly and legibly. Copyright reserved Please turn over
PrysiiSanfeaded from Stanmorepfiysics.com March 2073 Commonileet QUESTION 1: MULTIPLE-CHOICE QUESTIONS Various options are provided as possible answers to the following questions. Choose the answer and write only the letter (A-D) next to the question number (1.1-1.10) in the ANSWER BOOK, for example 1.11 D. 1.1 A bodys les along a frictionless horizontal surface at CONSTANT VELOCITY. For which ONE of the following pairs are the magnitudes of both physical quantities ZERO? A __ Displacement and momentum. Acceleration and momentum. Displacement and net force. Acceleration and net force. (2) 1.2 A satellite orbits the Earth at a point X, where the gravitational force is a quarter (% ) of the gravitational force it experiences on the surface of the Earth. X ©) _ satellite Earth If the radius of the Earth is R, then the height of the satellite ABOVE THE SURFACE of the Earth will be... A 4R 2R R %R (2) Copyright reserved Please turn over
: , . ‘ch 2023 Common Test Physical Besiftoaded from Stanmorespysics.com 1.3 1.4 1.5 1.6 Copyright reserved A girl standing in a lift observes a 10N mass piece suspended from a spring balance that is fixed to the roof of the lift. She sees that the reading on the spring balance is GREATER than 10N for a short time interval. During this time interval the lift is.... Ln Bm at constant velocity. C accelerating upwards. D accelerating downwards. (2) A ball of mass m hits a wall at a speed of v and rebounds in a straight line in the opposite direction with the same speed. The magnitude of the change in momentum of the ball will be... A Oo B 2mv Cc ‘’mv D mv (2) A ball is thrown vertically upwards. Which ONE of the following physical quantities has a NON-ZERO value at the instant the ball changes direction? A __ Acceleration B__ Kinetic energy C Momentum D Velocity (2) The molecular formula of an organic compound is C4H100. Which ONE of the following is the FUNCTIONAL GROUP of the organic compound? A __ Formyl group Hydroxyl group Carboxyl group 0 9O BB Carbonyl group (2) Please turn over
Physics Semnfetaded from Stanmorepfiysics.com 17. A FUNCTIONAL ISOMER of ethyl propanoate is .. . A 1.8 Which ONE of the following is the EMPIRICAL FORMULA of C4HgCHO. ‘GH3(CH2)3CHO. 2 — methylpentane? March 2023 Common Test (2) (2) A CsH7 Bo CeHta CC CeHi2 D- CsHe 1.9 Which ONE of the following represents a product of the thermal cracking of butane? A C2H2 B C2Ha C CaHe D = C4Hi0 1.10 Consider the structural formula of an organic compound given below: H H fe} H | | i} | H =|" = Cm C=} 0 + I | ! H H H This compound is the product of the reaction between . . . A ethanol and propanoic acid. propanol and propanic acid. ethanol and ethanoic acid. propanol and ethanoic acid. Copyright reserved H | Cc I H ) kb (2) [20] Please turn over
PosiyGWitoaded from Stanmoreggysics.com QUESTION 2 (Start on a new page.) A force of magnitude F is applied at an angle @ with the horizontal to a box of mass 60 kg placed on the floor. With force F applied, the magnitude of the maximum static frictional force between the floor and the box is 140 N . The coefficient of static friction between ttiebox and the floor is 0,3. The applied force-daes not cause the box to lift off the floor. 2.1 2.2 2.3 2.4 ae ------ 2) 60kg Define normal force. Draw the free body diagram showing all forces acting on the box. Calculate the magnitude of the normal force when the static frictional force is at its maximum. Determine the angle 6 QUESTION 3 (Start on a new page.) A ball of mass 0,5 kg is projected vertically downwards from a height of 1,8 m with an initial velocity of 2 m.s*'. The ball hits the ground and bounces two times. The position — time graph for the motion of the ball from the instant it is projected until it hits the ground after the second bounce is shown below. Ignore the effects of friction. Position (m) 3.1 3.2 Sopyright reserved Write down the maximum vertical height reached by the ball after the SECOND bounce? = The ball strikes the ground with a speed of 6,27 m.s* and is in; eantact with the ground for 0,2 s during the first bounce. i 3.2.1 Calculate the time t1 as indicated on the graph. 3.2.2 Determine the velocity with which the ball leaves the ground after the first bounce. 3.2.3 Calculate the magnitude of the force exerted by the ground on the ball during the first bounce. March 2023 Common Test (2) (4) (3) (4) [13] (1) (4) (4) (4) Please turn over
Physi Saimfeaded from Stanmorep{jysics.com Atesoy) 2028 Common est 3.3 Draw a velocity — time graph for the motion of the ball from the time that it is projected to the time it rebounds to a height of 0.9 m. Clearly show the following on your graph: ° Theé+time when the ball hits the ground ° The;velocity of the ball when it hits the ground ° The ivelocity of the ball when it rebounds off the ground. QUESTION 4 (Start on a new page.) Two balls, A and B, of mass 250 g and 300 g respectively collide head-on. Before the collision, ball A was moving at a velocity of 4 m.s“ to the right and ball B at 6 m.s* to the left. After the collision ball A moved to the left with a velocity of 2 m.s7'. Before collision 4m.s1 6 m.s* —> ee A G9) : 4.1 Explain what is meant by an isolated system in Physics. 4.2 Calculate the velocity of ball B immediately after the collision. 4.3. Is the collision between the ball A and ball B ELASTIC OR INELASTIC? Show how you arrived at the answer by means of a calculation. (3) [16] (2) (4) (5) [11] Copyright reserved Please turn over
eer ; ee “msicaiSemmoaded from Stanmorefhysics.com March 2023'Common QUESTION 5 (Start on a new page.) Consider the letters A to E in the table below: A H | H — C —H ie | i inet ai Sate Wipe | H H | H H H — C —H | H C4H100 CHsCCCH2CH3 but - 2- ene E H H fe} | | ll H —C —cC —C —OW—H | HW H — C — H | H e H H H H H H | | | | | | Rta Srdlmaiiuiieee Lalas s H H H H H I Use the information in the table to answer the questions that follow. J 5.1. Write down the: iz ==] 5.1.1 IUPAC name of compound A. rata (3) 5.1.2 _ Letter that represents a compound that belongs to the same homologous series as ethyne. (1) 5.1.3 NAME of the functional group of compound E. (1) 5.1.4 General formula of the homologous series to which compound A belongs. (1) Copyright reserved Please turn over
Physi SWATOaded from Stanmorepfysics.com 5.2 5.3 5.4 5.5 Compound B represents a TERTIARY alcohol. Write down the structural formula of compound B. Compound D has CHAIN and POSITIONAL isomers. positional isomer @ down the IUPAC NAME of the POSITIONAL isomer of compound D 5.3.3 Write. down the structural formula of a CHAIN isomer of compound D ls compound C saturated or unsaturated? Give a reason for the answer Compound F undergoes complete combustion. Write a balanced equation using MOLECULAR FORMULAE to represent the reaction that takes place. QUESTION 6 (Start on a new page.) The table below shows the results obtained during a practical investigation. Two experiments were conducted to determine the BOILING POINTS of compounds under the same conditions. Experiment Compound Molecular Mass (g.mol) | Boiling Point (°C) 1 A_- | CH3COOH 60,5 11,8 B__| CHs(CHz)20OOH 88,1 163 2 C_ | CHsCH2CH2OH 60,1 97 D | CHs(CH2)3CH20H 88,1 137 6.1 Define boiling point. 6.2 Apart from the conditions for determining boiling points, state the controlled variable for experiment 1. 6.3 Write down the general conclusion for this investigation. 6.4. Which compound will have the highest vapour pressure? 6.5 The boiling points of compounds B and D are compared. Copyright reserved 6.5.1 Write down the independent variable for this comparison. 6.5.2 Fully explain the difference in the boiling points of the twé'eompounds. March 2023 Common Test (2) (2) (1) (2) (2) (3) [18] (2) (1) (2) (1) (1) (3) [10] Please turn over
PrysiearS@ifoaded from Stanmorephysics.com QUESTION 7 (Start on a new page.) In the flow diagram below I, Il and Ill represent organic reactions. P and Q are different organic compounds. Q is the major organic product. 7.1 Name the TYPE of substitution reaction represented by reaction I. 7.2 Write down the STRUCTURAL formula for compound Q. 7.3 Name the inorganic reagent used in reaction III 7.4 Write down the type of reaction represented by reaction Ill 7.5 The same INORGANIC reagent is used in reactions I and II. Write down 7.5.1. The NAME or FORMULA of the inorganic reagent used. 7.5.2 ONE difference between the inorganic reagent used in reactions | and Il. 7.6 Write down the IUPAC name of: 7.6.1 Compound P 7.6.2 The organic product of reaction III TOTAL MARKS: Copyright reserved COMPOUND Q + KBr + H20 CHsCH2CHOHCH3 March 2023 Common Test (1) (2) (1) (1) (1) (2) (2) (2) [12] [100] Please turn over
Pusas6ifiivaded from Stanmoreptiysics.com DATA FOR PHYSICAL SCIENCES (PHYSICS) GRADE 12 GEGEWENS VIR FISIESE WETENSKAPPE (FISIKA) GRAAD 12 TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES March 2023 Common Test NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE Acceleration dué-to gravity 5 ekragver Mulling 9g 9,8 m-s Universal gravitational constant G 6,67 x 101 N.m2.kg? MOTIONIBEWEGING VA =Vitadt Ax =viAt+ daat? orfof Ay =vAt+Jadt? vi" = Vi? +2aAx orlof v,? =v? +2ady | Ax= (424) At orlofAy = (“ea K=E, =p mv? FORCE/KRAG Fret = Ma : p=mv FieAt =Ap=mv, —my, Fy =mg F= SOR; r f°" =y,N f, = HN Copyright reserved Please turn over
Posiewfibaded from Stanmoregfysics.com March 2023 Common Test DATA FOR PHYSICAL SCIENCES GRADE 12 CHEMISTRY TABLE 1: PHYSICAL CONSTANTS: NAME/NAAM paal SYMBOL/SIMBOOL VALUE/WAARDE Standard pressure) > ° 5 Standaarddruk Fi P 1,013 x10" Molar gas volume-at STP act Molére gasvolume by STD Vm 22.4 anit Standard temperature Standaardtemperatuur 7 273K Charge on electron 19 Lading op electron E “1,6 x10C Avogadro's constant 23 malt Avogadro-konstante Na 6,02 x 10*° mol TABLE 2: FORMULAE m N n=— n=— M Na n m eave ty] or/of cmay ON Ce a ne = +) CV, M PH = -log[H30*] Kw = [H30*][OH7] = 1 x 10-4 at/by 298 K Copyright reserved Please turn over
Physica Sg@privatded from Stanmorephysics.com 13 NSC TABLE 3: THE PERIODIC TABLE OF ELEMENTS March 2023 Common Test 1 2 3 4 5 6 7 8 9 10 «11 12 13 14 #15 16 #4917 + «618 (I) (Il) (y= (IV) (VY) (VI) (VN) s(VII) Atomic number 1 KEY 2 = H | He : 29 4 3 4 Electronegativity | ., Symbol 5 6 7 8 9 10 2 Li |% Be cao d ie eBIcSNISO Ne 7 9 : 11 12| 14| 16] 19/| 20 1 12 13| 14| 15| 16! «+17/ «418 & Na|= Mg Approximate relative atomic mass “Ae\? SiG P13 S |¢Ce!| Ar 23 24 27 | 28| 31/ 32/| 35,5| 40 19 20 21 22| 23] 24] 25| 26] 27| 28) 29| 30| 31| 32] 33] 34/] 35/ 36 @ K |2 Cal? Sc |Z Ti |? © Cr |2Mn|2 Fe |% Co|2 Ni |2 Cu |2 Zn |2 Ga|2 Ge |S As |S Se |§ Br| Kr 39 40 45 | 48 | 54 52| 55| 56| 59/| 59| 635] 65| 7o| 73| 75| 79| 80| 84 37 38 39 | 401 411 421 #43/| #44/ «45| #46| 47! #48| 49] So; 51] 52/ 53] 54 2 Rb? Sr i|% Y [Zr] Nb|2Mo/2? Te |S Ru|& Rh|s Pd |2 Ag |= Cd|= In |2 Sn |2 Sb|& Te |G | | Xe 86 88 s9 | 91| 92] 96 101| 103} 106| 108] 112| 115| 119| 122| 128| 127| 131 55 56 57 |. 72| 73| 741 +#»75| +#»+76| +#+77| ~«78;| «+79| 8o| 81| 82| 83] 84] 85| 86 Cs |2 Bal La|? Hf} Ta} W/ Re| Os| Ir| Pt} Au| Hg/2 Te |2 Pb|2 Bi |S Po|& At) Rn 133| 137| 139] 179] 181| 184| 186| 190| 192| 195| 197| 201| 204| 207| 209 87 88 89 n o o Fr |e sa Ac 58] 59 | 60 | 61 | 62 | 63 | 64 | 65 | 66 | 67 | 68 | 69 | 70 | 71 Ce | Pr | Nd | Pm| Sm} Eu | Gd J_Tb | Dy | Ho | Er | Tm| Yb | Lu 140 | 141 | 144 150 | 152 | 15717159 | 163 | 165 | 167 | 169 | 173 | 175 90 | 91 | 92 | 93 | 94 | 95 | 9641 97 | 98 | 99 | 100 | 101 | 102 | 103 Th | Pa | U | Np | Pu | Am| Cm] Bk | Cf | Es | Fm | Md | No} Lr 232 238 Copyright reserved
Downloaded from Stanmorephysics.com education Department: Education PROVINCE OF KWAZULU-NATAL NATIONAL SENIOR CERTIFICATE This Marking Guideline consists of 10 pages. Copyright reserved Please turn over
PnBavestoaded from Stanmorephysics.com March 2023 Common Test NSC - MARKING GUIDELINE QUESTION 1: MULTIPLE-CHOICE QUESTIONS 1.1 Dvv 1.2 Cv. 1.3 Cv 1.4 BYv 15 AvY 1.6 BYv 1.7 Cyvv 1.8 AVY 1.9 BYv 1.10 AVY [20] Copyright reserved
PhyPowmeaded from Stanmorephysics.com March 2023 Common Test NSC - MARKING GUIDELINE QUESTION 2 (Start on a new page.) 2.1 Normal force is the force or component of a force which a surface exerts on an object with which it is in contact, and which is perpendicular to the surface.v ¥ (2) ter OO] 2.2 fv WY Accept the following symbols N Normal Force/Normal/Fn f Static friction/ fs Ww Weight/Fw /Gravitational force/fg F Force applied/Fa Notes e Mark is awarded for label and arrow. e Do not penalize for length of the arrows. e Deduct 1 mark or any additional force. e If force(s) do not make contact with body/dot:Max:3/4 e lf arrows missing but labels are there: Max: 3/4 (4) 230° f™=uNV 140 =0,3N ¥ N = 466,67N ¥ (3) 2.4 POSITIVE MARKING FROM 2.3 F, =f," =140NV N=F,-F, 466,67 =(60)(9,8)—F, ¥ F, =121,33N tand=—= tang — 12433 V 0=40.91V¥ (4) [13] Copyright reserved
PhyPowmeaded from Stanmorephysics.com NSC - MARKING GUIDELINE QUESTION 3 (Start on a new page.) 3.1 3.2.1 0,5 mv oprah) OPSIE 1 Upwards positive = Ht vy, = v,tadtv ~6,27v = -2 + (-9,8)Atv At = 044sv Downwards positive V, = v, tadtv 6,27V =2 + (9,8)Atv At=0,44sv OPTION 2/OPSIE 2 Upwards positive Ay = vAt+ % aAt’ v -1,8 V= (-2)At+ % (-9,8)At V At =_DENb* =4ac 2a we2tvey -4(4.9)(-1.8) 2(4.9) =0,44sv Downwards positive Ay =vAt+ % alt v 1,8 V= (2)At+ % (9,8)At ¥ aa=2et Vb’ —4ac 2a aewt (-2)’ -4(4.9)(-1.8) 2(4.9) =0,44sv Copyright reserved March 2023 Common Test (1) (4)
PhyPoameaded from Stanmorephysics.com 3.2.2 3.2.3 NSC - MARKING GUIDELINE OPTION 3 ay - VAM) ary 2 Lev (2+6,27)) , 2 At = sv fe positive: ve = vy, + 2aly VY O° =v, + 2(-9,8)(0,9)¥ V,= 4.2 m:s” upwards ¥ Atv Downwards positive: ve = v, + 2ahy Vv 2 2 0 =v, + 2(9,8)(0,9) ¥ V,= 4.2 m:s” ¥ upwards¥ Upwards positive: March 2023 Common Test F. At = mAv E (0:2) = (0,5)[(4,2 ~ (-6,27 Y for either equation F,9:= 26,175 N Fret = F-Fg 26,1755 = F - (0,5)(9,8) ¥ F = 31,075 NV Downwards positive: F_ At = mAv ¥ F et (0.2) = (0 5) (azo 6 27) “—— F set = -26,175 N Y for either equation F 9 = 26,175 N a Fret Fg - - 26,1755 = (0,5)(9,8) - FY F = 31,075 NY Copyright reserved (4) (4) (4)
PhyPoameaded from Stanmorephysics.com March 2023 Common Test NSC - MARKING GUIDELINE 3.5 Upwards positive: t(s) -6,.27 Downwards positive: t(s) Criteria for graph Marks 2 straight discontinuous parallel lines, one above and one below v the time axis First part of the graph starts at v = 2 ms at t=0s and extends 4 v until v=6,27 m:s_att=0,44s. Second part of graph starts at v = 4,2 ms att = 0,64 s until y, v=Oms.. (3) [16] Copyright reserved
PhyPoameaded from Stanmorephysics.com NSC - MARKING GUIDELINE QUESTION 4 (Start on a new page.) 4.1 4.2 4.3 A system on which the net external force is zero.v¥ ¥ Right a: itive: rp=2 Any ApA = onev MY, +MgV;, = MV, + MpVy, (0, 25)(4) + (0, 3)(—6) = (0, 25)(—2) + (0, 3)(v he \¥v v,, =—1m.s* v,, =1m.s* to the left Left as Positive: 2p,= Zp, ApA = - ApB M,V,, +M,V,, =M,V;,, +MzV/, Any onev (0, 25)(—4) + (0, 3)(6) = (0, 25)(2) +(0,3)(v, )¥¥ v,, =1m.s* v,, =1m.s* to the leftY 1 v, > +—m,v,° 4% in 15 MBVin (0,25)(4)° + ; (0,3)(-6)° ¥ 1 ZEk iwefore) ama Nle 1 CE atten = 2 a #ZE ZEk (before) Kaen)” -. INELASTICY NOTE: If starts with 2Ek gooe= ZEk cate) maximum Copyright reserved March 2023 Common Test 2/5 (2) (4) (5) [11]
PhyPoameaded from Stanmorephysics.com NSC - MARKING GUIDELINE QUESTION 5 5.1.1 5.1.2 5.1.3 5.1.4 5.2 5.3.1 5.3.2 4,5 — dimethylv hex — 2 —- Venev Marking criteria: Cv carboxyl v CnHan ¥ H | H Oo H | | | H—C—C—C—H | | H | H H—C —H | H Marking criteria: ¢ Correct functional group: % e Whole structure correct: x Organic molecules with the same molecular formula but different positions of the side chains/substituents/functional groups on the parent chain vv but - 1- ene v Copyright reserved March 2023 Common Test (3) (1) (1) (1) (2) (2) (1)
PhyPoameaded from Stanmorephysics.com NSC - MARKING GUIDELINE 5.3.3 i - ia =cC—_—H Marking criteria: e 3 carbons in parent chain with the double bondY —H e Methyl group as a substituent 5.4 Unsaturatedv There multiple bonds between C atoms in the hydrocarbon chain/triple bond between C atoms in the hydrocarbon chain. v 5.5 2CeHia + 1902 — 12COz2 + 14H20 Reactants ¥ Productsv Balancing Vv QUESTION 6 6.1 The temperature at which the vapour pressure equals atmospheric (external) pressure. vv (2 or 0) 6.2 Compounds have the same functional group/belong to the same homologous seriesY 6.3 As the length of the carbon chain/molecular mass increases the boiling point increases for the same functional group/homologous seriesv Vv 6.4 AY 6.5.1 Type of functional group/organic compound/homologous series. ¥ 6.5.2 e Bhas 2 sites for hydrogen bondingY and e therefore has stronger intermolecular forcesY That require more energy to overcome. v OR D has only 1 site for hydrogen bondingY and therefore has weaker intermolecular forcesY That require less energy to overcome. Copyright reserved March 2023 Common Test (2) (2) (3) [18] (2) (1) (2) (1) (1) (3) [10]
PhydRowmceded from Stanmorephysics.com Test NSC - MARKING GUIDELINE QUESTION 7 71 hydrolysisY H H H H | | | | H— C — C = €C — C —H | | H H Double bond between the second and third carbon atomsv Whole structure correct’ 7.3 Water(H20)/sulphuric acidH2SO«/phosphoric acidHsPO4/ hydrogen chloride(HCl) v 74 Addition/hydration V 7.5.1 Potassium hydroxide/KOH ¥ 7.5.2. KOH in reaction | is dilute. ¥ KOH in reaction Il is concentrated. v 7.6.1 2-bromov butanev 7.6.2 ButanY -2-olv TOTAL MARKS: Copyright reserved March 2023 Common (1) (2) (1) (1) (1) (2) (2) (2) [12] 100

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