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Mechanical Technology Grade 12 NSC November 2012 Memo (Eng)

MemorandumMechanical TechnologyGrade 12201217 pages

Grade 12 Mechanical Technology memorandum from the NSC November Exam 2012 (English), 17 pages. Read online or download the free PDF.

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Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 MECHANICAL TECHNOLOGY NOVEMBER 2012 MEMORANDUM MARKS: 200 This memorandum consists of 17 pages. Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 2 DBE/November 2012 NSC – Memorandum QUESTION 1: MULTIPLE-CHOICE QUESTIONS 1.1 B (1) 1.2 A (1) 1.3 D (1) 1.4 B (1) 1.5 A or B  (1) 1.6 B (1) 1.7 A (1) 1.8 C (1) 1.9 D (1) 1.10 A (1) 1.11 D (1) 1.12 B (1) 1.13 B (1) 1.14 C (1) 1.15 A (1) 1.16 C (1) 1.17 D (1) 1.18 A (1) 1.19 C (1) 1.20 D (1) [20] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 3 DBE/November 2012 NSC – Memorandum QUESTION 2: TOOLS AND EQUIPMENT 2.1 Causes of low compression: • Worn cylinders  • Worn compression rings  • Worn piston  • Worn valves  • Worn head gasket  (Any 3 x 1) (3) 2.2 Torsion: Torsion is the twisting action in a member  caused by two opposing moments along the longitudinal axis.  (2) 2.3 Multimeter: A – LCD display screen  B – Range selector switch  C – 10 A DC terminal socket (Input terminal)  D – VΩmA terminal socket (Input Terminal)  E – Common terminal socket  (5) 2.4 Cylinder leakage tester: • Listen at the carburettor and/or inlet manifold for hissing noise.  (inlet valve is leaking)  • Listen to the exhaust pipe or exhaust manifold for a hissing noise.  (exhaust pipe is leaking)  • Listen for hissing noise in the dipstick hole.  (piston rings worn)  • Remove the filler cap on the tappet cover and listen for hissing noise.  (rings are worn)  • If you see bubbles in the radiator water,  (the cylinder head gasket is blown or the cylinder block is cracked)  (Any 3 x 2) (6) 2.5 MAGS/MIGS – meaning • MAGS: Metal Arc Gas Shielded  • MIGS: Metal Inert Gas Shielded  (2) 2. 6 MAGS/MIGS gases • Argon  • CO 2  • Helium  (Any 2 x 1) (2) [20] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 4 DBE/November 2012 NSC – Memorandum QUESTION 3: MATERIALS 3.1 Non-ferrous materials and composites: • Non-ferrous Metals are metallic and composites are non-metallic.  • Non-ferrous metals are original substances and composites are combinations of two or more materials.  (Any 1 x 2) (2) 3.2 Compressive strength test: 3.2.1 Material A has the highest compressive strength.  (1) 3.2.2 The material that can resist a large compression force will have little deformation or compression, and has a higher compressive strength.  (2) 3.3 Carbon steel: • Low-carbon steel  • Medium-carbon steel  • High-carbon steel  (3) 3.4 Carbon steel – properties: • Greater hardness is obtained  • Tensile strength is increased  • Ductility is decreased  • Welding ability is decreased  (4) 3.5 Uses and properties of engineering materials: 3.5.1 Uses of Duralumin: It is used to make the following: • Bars  • Sheets  • Piston rods  • Tubes  • Rivets  • Motorcar and aircraft parts  (Any 2 x 1) (2) Properties of Duralumin: o Lightweight  o High tensile strength  o Good resistance to corrosion  o Hardens with age  (Any 2 x 1) (2) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 5 DBE/November 2012 NSC – Memorandum 3.5.2 Uses of PVC: It is used to make: • Pipes and fittings  • Cable and services ducting  • Roofing and ceiling systems and membranes  • Healthcare materials  • Automotive industry materials  (Any 2 x 1) (2) Properties of PVC: • Lightweight  • Weather resistant  • Rigid or flexible  • Clear or coloured  • Good electrical insulator  • Good resistance to corrosion  (Any 2 x 1) (2) [20] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 6 DBE/November 2012 NSC – Memorandum QUESTION 4: SAFETY, TERMINOLOGY AND JOINING METHODS 4.1 Beam bending tester: • Make sure that the object to be tested is firmly secured.  • Make sure that all the holding devices are properly fitted.  • Check components of tester for wear.  • Check for leaks at the hydraulic pump ram and hose.  • Make sure that the tester is clean and free from oil and grease.  (Any 3 x 1) (3) 4.2 Gas cylinders: • Store full cylinders apart from empty cylinders.  • Keep in cool, dry place away from sunlight.  • Acetylene cylinders should be stored in an upright position.  • Oxygen cylinders should be stored away from acetylene cylinders.  • Do not allow cylinders to fall.  • No oil and grease should come into contact with oxygen cylinders and fittings.  (Any 3 x 1) (3) 4.3 Milling operations: 4.3.1 Upcut milling: • Less vibration occurs.  • Less strain on the cutter and arbor.  • There is positive pressure on the feed screw spindle and its nuts because of the direction of the cutter.  • A coarser feed may be used.  (Any 2 x 1) (2) 4.3.2 Down-cut milling: • Deeper cuts can be made because the force of the cutter is downwards.  • A finer finish is obtained.  (2) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 7 DBE/November 2012 NSC – Memorandum 4.4 Indexing: 4.4.1 40 Indexing =  A 40 =  60 4× 4  = 6× 4 16 20 26 28 34 36 44 = or or or or or or  24 30 39 42 51 54 66 16 holes on the 24-hole circle or 20 holes on the 30-hole circle or 26 holes on the 39-hole circle or 28 holes on the 42-hole circle or 34 holes on the 51-hole circle or 36 holes on the 51-hole circle or 44 holes on the 44-hole circle (4) 4.4.2  = ( A − n )× = (N − n )× Dr 40 Dr 40 OR Dv A Dv N  = (60 − 63)× = (60 − 63)× Dr 40 Dr 40 Dv 60 Dv 60 Dr − 120 Dr − 120  = = Dv 60 Dv 60 Dr − 12 × 4 Dr − 12 × 4 = =  Dv 6 ×4 Dv 6 ×4 Dr − 48 56 64 Dr − 48 56 64 = or or = or or  (5) Dv 24 28 32 Dv 24 28 32 Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 8 DBE/November 2012 NSC – Memorandum 4.5 Cutting feed: V = πDN  V N=  πD 20  N= π × 0,08 N = 79,577 r/min  f = f1 × T × N  f = 0,08 × 14 × 79,577  f = 89,13 mm/min  (7) 4.6 Ultrasonic test: • A high frequency sound wave is send into the metal for a very short period of 1 to 3 microseconds.  • The same unit which was used to send the sound wave then acts as a receiver to listen to the ultrasonic waves it reflected through the metal.  • This cycle is repeated from one to five million times per second. • The oscilloscope is calibrated only to pick up defects of a size that would be considered harmful.  • The oscilloscope wave pattern is also calibrated to show the distance between the searching unit and any defects found.  (5) 4.7 Weld defects: 4.7.1 Slag inclusion: Causes: • Included angle too narrow  • Rapid cooling  • Welding temperature too low  • High viscosity of molten metal.  • Welding second run without removing slag  (Any 2 x 1) (2) Prevention: • Increase the included angle.  • Let the welded metal cool slowly  • Pre-heat the metal  • Remove slag before welding a second run  (Any 1 x 1) (1) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 9 DBE/November 2012 NSC – Memorandum 4.7.2 Undercutting: Causes: • Faulty electrode manipulation  • Arc length too long  • Current too high  • Welding speed too fast  (Any 2 x 1) (2) Prevention: • Use a uniform weaving movement in butt joint  • Use the correct electrode  • Use the correct current  • Weld slowly  (Any 1 x 1) (1) 4.8 Milling Cutters: 4.8.1 Spur gear – Involute cutter  4.8.2 Groove – Side-and-face cutter or end mill or slot drill  4.8.3 Rack – Involute cutter/Fly cutter  4.8.4 Blind hole – Flute-end mill  (4) 4.9 Dividing head of a milling machine: A = Index plate  B = Index crank  C = Sector arms  D = Single-start worm  E = Wormwheel/gear  (5) 4.10 Classification of milling cutters: Arbor cutters  (1) Examples: Plain cutter , side cutter, staggered-tooth cutter, slitting-saw cutter, angular cutter, profile/form cutters, side-and-face cutter, helical cutter  (Any 1 x 1) (1) Shank cutters  (1) Examples: End mill; shell end mill; T-slot cutter and Woodruff keyseat cutter (Any 1 x 1) (1) [50] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 10 DBE/November 2012 NSC – Memorandum QUESTION 5: MAINTENANCE AND TURBINES 5.1 Clutch 5.1.1 Parts: A. Crankshaft  B. Clutch plate  C. Gearbox shaft  D. Diaphragm spring  E. Pressure plate  F. Flywheel  (6) 5.1.2 Functions: • To provide friction between the clutch and pressure plate  • To connect the flywheel to the gearbox shaft  (4) 5.1.3 Causes of slip: • Oil on the friction surfaces  • Worn friction surfaces  • Lack of compressive force on the friction surfaces caused by weak springs  • Lack of compressive force on the friction surfaces caused by incorrect clutch settings  • Uneven friction surfaces  • Overheating  (Any 3 x 1) (3) 5.1.4 Clutch types: • Single-disc clutch  • Multi-disc clutch  • Centrifugal clutch  (Any 2 x 1) (2) 5.2 Functions of lubricating oil: • Provides lubrication between contact surfaces  • Resists oxidation  • Prevents rust  • Avoids foaming  • Resists carbon forming  • Prevents corrosion  • Resists extreme pressure  (Any 3 x 1) (3) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 11 DBE/November 2012 NSC – Memorandum 5.3 Cutting fluid: • Avoid contamination of the cutting fluid by draining and regularly replacing it.  • Always clean metal cuttings from the machine’s splash tray after use.  • Regularly wipe cutting fluid splashes off machine parts when machine is stationary.  • Ensure that the sump is topped up from time to time, and check that there is sufficient flow of cutting fluid to the cutting tool.  • Check for correct ratio of cutting fluid to water.  (Any 3 x 1) (3) 5.4 Supercharger 5.4.1 Centrifugal type  (1) 5.4.2 Parts: A. Inlet port  B. Outlet port  C. Rotor  D. Vane  (4) 5.4.3 Operation: • The engine drives the rotor  • Air is drawn in behind the rotor  • The air is forced around into a decreasing volume  • This raises the pressure of the air  • The air is forced into the inlet manifold and into the cylinders  (5) 5.4.4 Advantages of a supercharger: • More power is developed compared to a similar vehicle without a supercharger  • Supercharged engines are more economical per given kilowatt output  • Less fuel is used compared to engine mass  • Power loss above sea level is eliminated  (Any 3 x 1) (3) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 12 DBE/November 2012 NSC – Memorandum 5.5 Steam turbines: • Condensing turbines  • Non-condensing turbines  • Reheat turbines  • Extracting turbines  • Induction turbines  (Any 3 x 1) (3) 5.6 Advantages of gas turbine: • High power output from a given weight of engine.  • The torque output permits a notable simplification of the transmission system.  • Smooth vibrationless running due to absence of reciprocating parts.  • No rubbing parts such as piston so that internal friction and wear are almost eliminated.  • Easy starting.  • Can use a wide range of fuels without expensive anti-knock additives.  • Low lubricating oil consumption.  • No water cooling system needed.  • Non-poisonous exhaust gases gives very little trouble with pollution.  • Requires little routine maintenance.  (Any 3 x 1) (3) [40] Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 13 DBE/November 2012 NSC – Memorandum QUESTION 6: FORCES, SYSTEMS AND CONTROL 6.1 Hydraulics: 6.1.1 Fluid pressure: Rounded off Fully extended πD 2 πD 2 AA =  AA =  4 4 π × (0,038 ) π × (0,038 ) 2 2 = = 4 4   = 1,13 × 10 −3 m 2 = 0,001134114 m 2 F F P= A P= A  AA  AA 300 300 P=  P= 1,13 × 10 −3 0,001134114  = 0,27 MPa  = 264523,45 Pa  (5) 6.1.2 Load lifted by piston B: Rounded off Fully extended πD 2 πD 2 AB =  AB =  4 4 π × (0,175 ) π × (0.175 ) 2 2 = = 4 4 = 24,05 × 10 −3 m 2  = 0,024052818 m 2  FB FB P=  P=  AB AB FB = AB × P  FB = AB × P   = (0,024052818 × 264523,45  = (24,05 × 10 −3 ) × 0,27 × 10 6 = 6,49 kN  = 6362,54 N  (6) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 14 DBE/November 2012 NSC – Memorandum 6.2 Stress and Strain: Tensile force: Rounded off Fully extended ΔL  ΔL  ε= ε= OL OL 0,2 0,2 = = 300 300 = 0,66 × 10 −3  = 0,0006666  σ σ E=  E=  ε ε σ = E×ε σ = E×ε = 245 × 10 9 × 0.66 × 10 −3  = 245 × 10 9 × 0,000666666   = 163333333,3 Pa  = 161.7 × 10 Pa 6 F F σ= σ= A  A  F =σ×A F =σ×A   = 161,7 × 10 × 2,2 × 10 6 −6  = 163333333,3 × 2,2 × 10 −6  = 355,74 N  = 359,33 N  (9) 6.3 Belt drives: 6.3.1 Rotation frequency of the driven pulley: driven pulley: N A × DA = N B × DB N × DA  NB = A DB 1000 × 0,25 = 0,35  = 714,29 rpm r/min  (3) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 15 DBE/November 2012 NSC – Memorandum 6.3.2 Power transmitted: P= (T1 − T2 )πDN 60  P= (200 − 90 )× π × 0,25 × 1000  60 P = 1439,90 Watts P = 1,44 kW  (3) 6.3.3 Belt speed: πDN  v= 60  π × 0,25 × 1000 = 60  v = 13,09 m.s −1 (3) 6.4 Gears: 6.4.1 Rotation frequency of the output shaft: N F TA × TC × TE N F Product of driven gears = or =  N A TB × TD × TF N A Product of driver gears TA × TC × TE × N A 24 × 20 × 42 × 1440  NF = = TB × TD × TF 40 × 48 × 90  24 × 20 × 42 × 1440 NF = = 168 rpm r/min 40 × 48 × 90  = 168 rpm r/min (4) 6.4.2 Velocity ratio: NA VR =  NF 1440 VR = 168 VR = 8.57 : 1  (2) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 16 DBE/November 2012 NSC – Memorandum 6.5 Differential wheel and axle: 6.5.1 Mechanical advantage: W  MA = F 2400 MA = 400 MA = 6  (2) 6.5.2 Velocity ratio: 2D VR =  d1 − d 2 2(210 )  VR = 160 − 140 420 VR = 20 VR = 21 : 1  (3) 6.5.3 Mechanical efficiency: MA ηmech = × 100%  VR 6 = × 100% 21 = 28.57%  (2) Copyright reserved Please turn over
Downloaded from hlayiso.com Mechanical Technology 17 DBE/November 2012 NSC – Memorandum 6.6 Clutches: 6.6.1 Diameter of clutch plate: T = μWnR  T R=  μWn 336  R= 0,4 × 3500 × 2 R = 0,12 m D = 2 × 0,12  D = 0,24 m = 240 mm  (5) 6.6.2 Power transmitted at 3500 rpm in kW: 2π NT P=  60 2 × π × 3200 × 336 P=  60 P = 112,59kW  (3) [50] TOTAL: 200 Copyright reserved

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