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NASIONALE
SENIORSERTIFIKAAT
GRADE/GRAAD 12
SEPTEMBER 2023
PHYSICAL SCIENCES P2/ FISIESE
WETENSKAPPE V2
MARKING GUIDELINE/NASIENRIGLYN
MARKS: 150
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Physical Sciences Grade 12 P2 Eastern Cape Mock 2023 Memo
Grade 12 Physical Sciences Paper 2 memorandum from the Eastern Cape Mock Exam 2023 (English), 19 pages. Read online or download the free PDF.
Physical Sciences · Grade 12 · Eastern Cape Mock Exam · 2023 · English. Memorandum, 19 pages. Read online or download the PDF.
- Subject
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- 2023
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- Eastern Cape Mock Exam
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This exam
Questions in this paper
- Question 1Organic Compounds and Macromolecules20 marks
- Question 2Organic Compounds and Macromolecules17 marks
- Question 3Organic Compounds and Macromolecules17 marks
- Question 4Organic Compounds and Macromolecules14 marks
- Question 5Rate and Extent of Reactions19 marks
- Question 6Chemical Equilibrium16 marks
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2 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
QUESTION 1/VRAAG 1
1.1 D ✓✓ (2)
1.2 B ✓✓ (2)
1.3 A✓✓ (2)
1.4 D ✓✓ (2)
1.5 B ✓✓ (2)
1.6 C ✓✓ (2)
1.7 D ✓✓ (2)
1.8 A ✓✓ (2)
1.9 D ✓✓ (2)
1.10 B ✓✓ (2)
[20]
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 3
QUESTION 2/VRAAG 2
2.1.1 D✓ (1)
2.1.2 F✓ (1)
2.1.3 B✓ (1)
2.2 UNSATURATED ✓
It is an organic compound that contains double/triple/multiple bonds. ✓
ONVERSADIG
Dit is ʼn organiese verbinding wat dubbel/drievoudige/meervoudige bindings
bevat. (2)
2.3.1
H
Marking criteria/Nasienkriteria
H C H • Functional group correct ✓
H H H O Funksionele groep korrek
• Whole structure correct ✓
H C C C C C Hele struktuur korrek
H H H O H
H C H
H (2)
2.3.2 hept-3-yne ✓ ✓ / 3-heptyne Marking criteria/ Nasienkriteria
• Parent name and suffix correct (heptyne)✓
hept-3-yn / 3-heptyn Stam naam en agtervoegsel korrek (heptyn)
• Everything correct e.g. hyphens and
numbering ✓
Alles korrek bv koppeltekens en nommering
(2)
2.4 Tertiary. ✓
The carbon that is bonded to the hydroxyl group (-OH) is bonded to three
other carbons. ✓
OR
The carbon of the functional group is bonded to three other carbons.
Tersiêre
Die koolstof wat verbind is aan die hidroksielgroep (-OH) is verbind aan
drie ander koolstowwe.
OF
Die koolstof van die funksionele groep is aan drie ander koolstowwe verbind. (2)
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4 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
2.5 Butan-2-ol / 2-butanol ✓✓ NOTE/LET WEL: Butan-1-ol / 1-butanol (1/2) (2)
2.6.1 Compounds with the same molecular formula ✓ but different functional
groups ✓/belong to different homologous series.
Verbindings met dieselfde molekulêre formule, maar verskillende
funksionele groepe / behoort aan verskillende homoloë reeks. (2)
2.6.2 CH3COCH3 ✓✓ OR/OF O
II
CH3CCH3 (2)
[17]
QUESTION 3/VRAAG 3
3.1 Marking criteria/ Nasienriglyne
If any of the underlined key words/phrases in the correct context are
omitted: -1 mark per word/phrase.
Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
word: -1 punt per woord/frase
The temperature at which the vapour pressure of a liquid equals the
atmospheric pressure ✓✓
Die temperatuur waarby die dampdruk van ʼn vloeistof gelyk is aan die
atmosferiese druk. (2)
3.2.1 Molecular size ✓ / Surface area / Chain length / London forces
Molekulêre grootte / Oppervlakte / kettinglengte / Londonkragte (1)
3.2.2 Functional group ✓/ Homologous series
Funksionele groep / Homoloë reeks (1)
3.3 London forces / induced dipole forces / dispersion forces ✓
Londonkragte / geїnduseerde dipoolkragte / verspreidingskragte (1)
3.4 129 °C ✓ (1)
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 5
3.5 Marking criteria/Nasienkriteria
• Compare the molecular size of 2-methylbutan-1-ol to butan-1-ol ✓
• Relate the molecular size to London forces/induced dipole
forces/dispersion forces. ✓
• Compare the chain length of 2-methylbutan-1-ol to pentan-1-ol ✓
• Relate the chain length to London forces/induced dipole
forces/dispersion forces ✓
• Vergelyk die molekulêre grootte van 2-metielbutan-1-ol aan butan-1-ol
• Verwys die molekulêre grootte na die Londonkragte/ geїnduseerde
dipoolkragte / verspreidingkragte
• Vergelyk die kettinglengte van 2-metielbutan-1-ol met pentan-1-ol
• Verwys die kettinglengte na die Londonkragte / geїnduseer
dipoolkragte / verspreidingkragte
• 2-methylbutan-1-ol has a larger molar mass/molecular size than butan-
1-ol ✓
• London forces/induced dipole forces/dispersion forces of
2-methylbutan-1-ol is stronger than that butan-1ol ✓
• The boiling point will higher than that of butan-1-ol
• 2-methyl butan-1-ol has a shorter chain length than pentan-1-ol✓
• London forces of 2-methyl butan-1-ol is weaker than that of
pentan-1-ol ✓
• The boiling point will be lower than that of pentan-1-ol
• 2-metielbutan-1-ol het ‘n groter molekulêre massa/molekulêre grootte
as butan-1-ol
• Londonkragte/geїnduseerde dipoolkragte/verspreidings van
2-metielbutan-1-ol is sterker as dié van butan-1-ol
• Die kookpunt is hoër as dié van butan-1-ol
• 2-metielbutan-1-ol het ‘n korter kettinglengte as pentan-1-ol
• Londonkragte van 2-metielbutan-1-ol is swakker as dié van
pentan-1-ol
• Die kookpunt sal laer wees as dié van pentan-1-ol (4)
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6 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
OR /OF
• Butan-1-ol has a smaller molar mass/molecular size than 2-methylbutan-1-ol
• London forces/induced dipole forces/dispersion forces of butan-1-ol is
weaker than that 2-methylbutan-1-ol
• The boiling point will higher than that of butan-1-ol
• Pentan-1-ol has a larger chainlength than 2-methyl butan-1-ol
• London forces/induced dipole forces/dispersion forces of pentan-1-ol is
stronger than that of 2-methyl butan-1-ol
• The boiling point will be lower than that of pentan-1-ol
• Butan-1-ol het ʼn kleiner molekulêre massa/molekulêre grootte as
2-metielbutan-1-ol
• Londonkragte/geїnduseerde dipoolkragte/verspreidings van butan-1-ol is
swakker as dié van 2-metielbutan-1-ol
• Die kookpunt is hoër as dié van butan-1-ol
• Pentan-1-ol het ʼn langer kettinglengte as 2-metielbutan-1-ol
• Londonkragte van pentan-1-ol is sterker as dié van 2-metielbutan-1-ol
• Die kookpunt sal laer wees as dié van pentan-1-ol
3.6.1 Marking criteria/Nasienkriteria
If any of the underlined key words/phrases in the correct context are omitted:
- 1 mark per word/phrase.
Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
word: - 1 punt per woord/frase
The pressure exerted by a vapour at equilibrium with its liquid in a closed
system. ✓✓
Die druk uitgeoefen deur ʼn damp in ewewig met sy vloeistof in ʼn geslote sisteem. (2)
3.6.2 Q✓ (1)
3.6.3 Marking criteria/Nasienkriteria
• Propan-1-ol has hydrogen bonds ✓(and London forces/induced dipole
forces/dispersion forces
• Propanal has dipole-dipole forces ✓( and London/induced dipole
forces/dispersion forces
• Compare the strength of the hydrogen bonds to dipole-dipole forces ✓
• Relate strength of intermolecular forces to vapour pressure ✓
• Propan-1-ol het waterstofbindings (en Londonkragte/geїnduseerde
dipoolkragte/verspreidingskragte)
• Propanal het dipool-dipoolkragte (en Londonkragte/geїnduseerde
dipoolkragte/verspreidingskragte)
• Vergelyk die sterkte van die waterstofbindings met die dipool-dipoolkragte
• Verwys die sterkte van die intermolekulêrekragte met die dampdruk
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 7
• Propan-1-ol has hydrogen bonds ✓(and London forces/induced dipole
forces/dispersion forces)
• Propanal has dipole-dipole forces (and London forces/induced dipole
forces/dispersion forces) ✓
• Hydrogen bonds are stronger than the dipole-dipole forces ✓
• Stronger intermolecular forces result in lower vapour pressure ✓
• Propan-1-ol het waterstofbindings (en Londonkragte/geїnduseerde
dipoolkragte/verspreidingskragte)
• Propanal het dipool-dipoolkragte (en Londonkragte/geїnduseerde
dipoolkragte/verspreidingskragte)
• Waterstofbindings is sterker as dipool-dipoolkragte
• Sterker intermolekulêrekragte het laer dampdruk
OR / OF
• Propan-1-ol has Hydrogen bonds ✓ (and London forces/induced dipole
forces/dispersion forces)
• Propanal has dipole-dipole forces ✓( and London/induced dipole
forces/dispersion forces)
• Dipole-dipole forces are weaker than the hydrogen bonds✓
• Weaker intermolecular forces result in higher vapour pressure ✓
• Propan-1-ol het waterstofbindings (en Londonkragte/geїnduseerde
dipoolkragte/verspreidingskragte)
• Propanal het dipool-dipoolkragte (en Londonkragte/geїnduseerde
dipoolkragte/verspreidingskragte)
• Dipool-dipoolkragte is swakker as waterstofbindings
• Swakker intermolekulêrekragte het hoër dampdruk (4)
[17]
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8 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
QUESTION 4/VRAAG 4
4.1.1 Hydrolysis / Hidrolise ✓ (1)
4.1.2 Pentan-2-ol / 2-pentanol ✓✓ (2)
4.1.3 Concentrated strong base✓ OR concentrated NaOH OR concentrated KOH OR
concentrated LiOH
Gekonsentreerde sterk basis OF gekonsentreerde NaOH OF gekonsentreerde KOH
OF gekonsentreerde LiOH (1)
4.1.4 Marking criteria/Nasienkriteria
H H H H H • Functional group correct ✓
Funksionele groep korrek
H C C ✓C C C H✓ • Whole structure correct ✓
Hele struktuur korrek
H H H (2)
4.1.5 Sulphuric acid / Swawelsuur ✓ (1)
4.1.6 Dehydration / Dehidrasie / Dehidratering ✓ (1)
4.2.1 Esterification / Condensation / Esterifikasie / Verestering ✓ (1)
4.2.2 Alcohols are flammable✓ /prevent fire
Alkohole is vlambaar / om ʼn vuur te voorkom (1)
4.2.3 H H
O H H Marking criteria/Nasienkriteria
✓ • Functional group correct ✓
H C C O C C C H Funksionele groep korrek
H H H H • Whole structure correct ✓
Hele struktuur korrek
ethyl ✓propanoate ✓ / etiel-propanoaat (4)
[14]
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 9
QUESTION 5/VRAAG 5
5.1 Marking criteria/ Nasienriglyne
If any of the underlined key words/phrases in the correct context are
omitted: - 1 mark per word/phrase.
Indien enige van die sleutelwoorde/frases in die korrekte konteks
weggelaat word: - 1 punt per woord/frase
ANY ONE
Change in concentration ✓of reactant or product per (unit) time.✓
Change in amount/number of moles/volume/mass of products or
reactants per (unit) time.
Change in amount/number of moles/volume/mass of products formed or
reactants used reactants per (unit) time.
ENIGE EEN
Verandering in konsentrasie van reaktanse of produkte per (eenheid) tyd.
Verandering in hoeveelheid/getal mol/volume/massa van reaktanse of
produkte per (eenheid) tyd.
Verandering in hoeveelheid/getal mol/volume/massa van produkte
gevorm/reaktanse gebruik per (eenheid) tyd.
OR/OF
The rate of change in concentration / amount of moles / number of moles /
volume / mass. (2 or 0)
Die tempo van verandering in konsentrasie/hoeveelheid mol/getal
mol/volume/massa ✓✓ (2 of 0) (2)
5.2 Stopwatch ✓/Timer/ Measuring cylinder
Stophorlosie / Tydhouer / Meetsilinder (1)
5.3 Reaction is exothermic / reaction releases heat ✓
Reaksie is eksotermies / reaksie gee hitte af (1)
5.4 SHORTER / KORTER ✓ (1)
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10 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
5.5 For Exp. 2
• Higher concentration results in more particles colliding with correct
orientation✓
• The number of effective collision per unit time increases / frequency
of the effective collisions increases ✓
Vir Eksp. 2
• Hoër konsentrasie beteken meer deeltjies bots met die korrekte
orientasie
• Die aantal effektiewe botsings per eenheid tyd neem toe/ frekwensie
van die effektiewe botsings neem toe.
OR / OF
For Exp. 1
• Low concentration results in fewer particles colliding with correct
orientation ✓
• The number of effective collision per unit time decreases / frequency
of effective collisions decreases ✓
Vir Eksp. 1
• Lae konsentrasie beteken minder deeltjies bots met die korrekte
orientasie
• Die aantal effektiewe botsings per eenheid tyd neem af / frekwensie
van die effektiewe botsings neem af. (2)
5.6.1 Rate/ Tempo = ∆c
∆t
= 250-0 ✓ Accept / Aanvaar 250
5,28-0 ✓ 5,28
= 0,95✓(cm3·min-1) (3)
5.6.2 Marking criteria / Nasienkriteria
• VCO2 remaining / oorbly = 150 cm3
• Substitution into / Vervanging in n = V/Vm
• Subst. into / Vervanging in n = m/M
• Final answer / Finale antwoord
V(CO2) remaining / oorbly = 250 – 100 = 150 cm3 ✓
n = V/Vm = 150/25 000 ✓
= 6 x 10 -3 mol
n(CO2) = m/M
6 x 10 -3 = m / 44 ✓
m = 0,264 g ✓/0,26 g (4)
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 11
5.7.1 P✓ (1)
5.7.2 C2H4O2 is a weaker acid ✓(than HCℓ) which will result in a LOWER
reaction rate ✓ (for Expt. 3) / Lower gradient/Longer reaction time
C2H4O2 is ʼn swakker suur (as HCℓ) wat sal lei na ʼn LAER reaksietempo
(vir Eksp. 3) / laer gradiënt / langer reaksietyd
OR / OF
HCℓ is stronger acid ✓(than C2H4O2) which will result in a HIGHER
reaction rate ✓ for Expt. 1/ Higher gradient/Shorter reaction time
HCℓ is ʼn sterker suur (as C2H4O2) wat sal lei na ʼn HOЁR reaksietempo
(vir Eksp. 1) / hoër gradiënt / korter reaksietyd (2)
5.7.3 EQUAL TO ✓
Final amount of CO2 is the same ✓ (in both experiments)
GELYK AAN
Finale hoeveelheid van CO2 is gelyk (in beide eksperimente) (2)
[19]
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12 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
QUESTION 6 / VRAAG 6
6.1.1 Reversible reaction ✓ /Products can be converted back to reactants
Omkeerbare reaksie / Produkte kan na reaktanse omgeskakel word
NOTE: Do not accept “Reaction is at equilibrium”
LET WEL: Moenie “Reaksie is by ewewig” aanvaar nie. (1)
6.1.2 (Chemical) Equilibrium / (Chemiese) Ewewig ✓ (1)
6.1.3 HEATED / VERHIT ✓ (1)
6.1.4 ENDOTHERMIC / ENDOTERMIES ✓ (1)
6.1.5 • Increase in temperature favoured the forward reaction ✓ / The rate of the
forward reaction increased more than the rate of the reverse reaction.
• Increase in temperature favours the endothermic reaction. ✓
• Toename in temperatuur bevoordeel die voortwaartse reaksie / Die
tempo van die voortwaartse reaksie is hoër as die terugwaartse reaksie
• ʼn Toename in temperatuur bevoordeel die endotermiese reaksie (2)
6.1.6
Reaksie tempo/
Reaction rate
(mol·dm-3·min-1)
Time (minutes) / Tyd (minute)
Marking criteria/ Nasienkriteria
• Both rates increase; new equilibrium at a higher rate when P is
increased ✓
Beide tempos neem toe; nuwe ewewig is by ʼn hoër tempo wanneer
P verhoog
• The increase in reverse reaction is HIGHER than for the forward
reaction and eventually there is horizontal section for both ✓
Die toename in die terugwaartse reaksie is HOЁR as die
voortwaartse reaksie en daar is horisontale gedeelte by die einde vir
beide.
NOTE: Do not penalise if axes are not labelled.
LET WEL: Moenie penaliseer as asse nie benoem is nie.
(2)
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 13
6.2 MOLE CALCULATIONS / MOL BEREKENINGE
a. Correct KC expression (formula in square brackets) ✓
b. Substitution of equilibrium concentration of CO2 into KC expression ✓
c. Determining the nequilibrium CO ✓
d. Determining the n CO reacted
e. Correct mol ratio for CO:C ✓
f. Determining the initial mol of C✓
g. Correct substitution into percentage formula ✓
h. Final answer ✓
a. Korrekte Kc-uitdrukking (Formule formule tussen vierkanthakies)
b. Vervanging van ewewigkonsentrasie van CO2 in KC – uitdrukking
c. Bepaal die newewig CO
d. Bepaal n CO reageer
e. Korrekte molverhouding vir CO : C
f. Bepaal die aanvanklike mol van C
g. Korrekte vervanging in persentasie formule
h. Finale antwoord
• No Kc expression, correct
substitution / Geen Kc-uitdrukking,
Kc = [CO]2 ✓ (a) korrekte, korrekte substitusie.
[CO2] Max. / Maks. 7/8
• Wrong Kc expression / Verkeerde
0,05 = [CO]2 (b) Kc-uitdrukking. Max. Maks. 5/8
0,05 ✓
[CO] = 0,05 mol.dm-3
C (s) CO2 (g) 2 CO (g)
Initial mol /Aanvangs- 0
0,45 ✓(f)
hoeveelheid (mol)
Change/ Verandering in mol 0, 05✓(e) 0,1✓ (d)
Equilibrium/ Ewewig mol 0,40 0,1✓ (c)
Concentration/ Konsentrasie
- 0,05
(mol·dm-3)
% C reacted = ∆n/ninitial x 100
= 0,05/0,45 x 100 ✓ (g)
= 11,11%✓ (h) (8)
[16]
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14 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
QUESTION 7/VRAAG 7
7.1.1 An acid is a proton (H+ -ion) donor ✓✓
ʼn Suur is ʼn proton (H+ -ioon) skenker (2)
7.1.2 HC2O4 – ✓ (1)
7.1.3 Weak acid / Swaksuur ✓ (1)
7.1.4 The acid did not fully/completely ionise ✓✓ (in water). OR ionised
incompletely.
Die suur ioniseer nie volledig (in water) nie OF Suur ioniseer onvolledig (2)
7.2.1 Marking criteria/Nasienkriteria
• n = cV
• Subst. into / Vervanging in n = cV
• Final answer / Finale antwoord
n (CH3COOH) = cV ✓
= 0,1 x 25 x 10-3 ✓
= 2,5 x 10-3 mol ✓ (3)
7.2.2 Marking criteria/Nasienkriteria Marking criteria/Nasienkriteria
• Formula pH = - log [H3O+] ✓ • Formula pOH + pH = 14 ✓
• pH value substituted into • pH value substituted into
formula ✓ formula ✓
• Substitution in Kw formula ✓ • Substitution in pOH formula ✓
• Final answer ✓ • Final answer ✓
• Formule pH = - log [H3O+] • Formule pOH + pH = 14
• pH waarde vervang in formule • pH waarde vervang in formule
• Vervang in KW formule • Vervang van pOH waarde in
• Finale antwoord formule
• Finale antwoord
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 15
OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2
pH = - log [H3O+] ✓ pOH + pH = 14 ✓
12 ✓ = - log [H3O+] pOH + 12 ✓ = 14
[H3O+] = 1 × 10-12 mol·dm-3 pOH = 2
Kw = [OH–][H3O+] = 1 × 10-14 pOH = - log [OH–]
[OH–][H3O+] = 1 × 10-14 2 = - log [OH–] ✓
[OH–](1 × 10-12) = 1 × 10-14 ✓ [OH–] = 0,01 mol·dm-3 ✓
[OH–] = 0,01 mol·dm-3 ✓ (4)
7.2.3 Positive marking from / Positiewe nasien vanaf 7.2.1 and/ en 7.2.2
Marking criteria / Nasienkriteria
• Using ratio Acid : Base 1 : 1
• Subst. of base values into nNaOH excess = cV
• Addition of n remaining and n initial (NaOH)
• Subst. into c = n/V
• Multiplication of cdilute by 10
• Final answer
• Gebruik verhouding Suu r: Basis = 1 : 1
• Vervanging van basis waarde in nNaOH oormaat = cV
• Addisie van n oorbly en n aanvanklik (NaOH)
• Vervanging in c = n / V
• Vermenigvulding van cverdun met 10
• Finale antwoord
n (NaOH) reacting/ reageer = 2,5 x 10-3 mol ✓ From/Vanaf 7.2.1
n (NaOH) in excess/ oormaat = cV
n (NaOH) excess/ oormaat = (0,01)(60 x 10-3) ✓
n (NaOH) excess/ oormaat = 6 x 10-4 mol
n (NaOH)total/ totaal = 2,5 x 10-3 + 6 x 10-4 ✓
n (NaOH) = 3,1 x 10-3 mol (6)
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16 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
n
cdilute/verdun =
V
3,1 x 10-3
cdilute/verdun = ✓
35 x 10-3
cdilute/verdun = 0,08857 mol· dm-3
cconcentrated / = 0,08857 x 10 ✓
gekonsentreerd = 0,8857 mol·dm-3✓/0,89 mol· dm-3
[19]
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 17
QUESTION 8/VRAAG 8
8.1 Chemical energy is converted into electrical energy ✓✓
Chemiese energie word na elektriese energie omgeskakel. (2)
8.2.1 Fe2+ → Fe3+ + e- ✓✓ (2)
Marking criteria / Nasienkriteria
• Fe3+ + e- ← Fe2+ 2/2
• Fe ⇌ Fe + e
2+ 3+ - ½
• Fe + e- → Fe
3+ 2+ 0/2
• Fe3+ + e - ⇌ Fe2+ 0/2
• Ignore if the charge omitted on electron
Ignoreer indien lading op elektron weggelaat is
• If a charge of an ion is omitted
As lading weggelaat is op ʼn ioon.
e.g. / bv. Fe2 → Fe3 + e- Max. / Maks. ½
8.2.2 Ag ⎸Ag+✓ ⎸⎸✓ Fe3+,Fe2+✓⎸Pt ✓ (3)
Marking criteria/Nasienkriteria
• Ag ⎸Ag+ ✓
• Fe3+,Fe2+ ⎸Pt ✓
• ⎸⎸ ✓
8.2.3 Concentration: 1 mol·dm-3 ✓ and temperature: 25 °C ✓ / 298 K
Konsentrasie: 1 mol·dm-3 en temperatuur: 25 °C / 298 K (2)
8.3 Eθcell = Eθcathode/reduction/oxidising agent – Eθanode/oxidation/reducing agent ✓
Marking criteria/Nasienkriteria
Eθcell = (0,80) ✓ – (0,77) ✓ • Any other formula using unconventional
abbreviation , e.g.
Eθcell = 0,03 V ✓ Enige ander formule wat
onkonvensionele afkortings gebruik bv.
• Eθcell = EθOA –Eθ RA followed by the
correct substitution./ gevolg deur
korrekte vervangings ¾
(4)
8.4 Decrease / Afneem ✓ (1)
8.5 Cℓ– would form an insoluble salt/precipitate with the Ag+✓✓ / AgCℓ will
precipitate out. The Ag+ half-cell would no longer be neutral / Circuit would
be incomplete / Not enough electrolyte in half cell.
Cℓ – sal ʼn neerslag vorm/presipiteer met Ag+/ AgCℓ vorm ʼn neerslag / Die
Ag+halfsel sal nie meer neutraal wees nie / Stroombaan sal onvoltooїed
wees / Nie genoeg elektroliet in die halfsel nie. (2)
[16]
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18 PHYSICAL SCIENCES P2 (EC/SEPTEMBER 2023)
QUESTION 9/VRAAG 9
9.1 Marking criteria/ Nasienriglyne
If any of the underlined key words/phrases in the correct context are
omitted: - 1 mark per word/phrase.
Indien enige van die sleutelwoorde/frases in die korrekte konteks
weggelaat word: - 1 punt per woord/frase
The chemical process in which electrical energy is converted to chemical
energy. ✓✓
Die chemiese proses waarin elektriese energie word na chemiese
energie omgeskakel.
OR / OF
The use of electrical energy to produce a chemical change. ✓✓
Die gebruik van elektriese energie om chemiese energie te produseer (2)
9.2 ENDOTHERMIC / ENDOTERMIES ✓ (1)
9.3 2 Cℓ – → Cℓ2(g) + 2e− ✓✓ Ignore phases / Ignoreer fases (2)
Marking criteria / Nasienkriteria
• 2 Cℓ – ⇌ Cℓ2(g) + 2e− ½
• Cℓ2(g) + 2e− ← 2 Cℓ – 2/2
• Cℓ2(g) + 2e− ⇌ 2 Cℓ – 0/2
Ignore if the charge omitted on electron /
Ignoreer as lading op elektron weggelaat is
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(EC/SEPTEMBER 2023) PHYSICAL SCIENCES P2 19
9.4
m Marking criteria/Nasienkriteria
n =
M
• Subst. into n = m/M
0,369 • Use of mole ratio Cu : e-
n = ✓ • Subst. into n = N/NA
63,5
• Subst. into n = Q/qe
n = 5,811 x 10-3 • Formula Q = IΔt
• Subst. into Q = IΔt
n (e-) = 2 x 5,811 x 10-3 ✓
• Final answer with unit
n (e-) = 0,01162
• Vervang in n = m/M
• Gebruik van mol-
N verhouding Cu : e-
n =
NA • Vervang in n = N/NA
• Vervang in n = Q/qe
0,01162 = N ✓ • Formule Q = IΔt
6,02 x 10 23 • Vervang in Q= IΔt
• Finale antwoord met
N = 6,9964 x 1021 eenheid
Q = Nq
Q = 6,9964 x 1021 x 1,6 x 10-19 ✓
Q = 1 119,4310 C
I = Q
✓
Δt
I = 1 119,4310
✓
27 x 60
I = 0,69 A ✓ (7)
[12]
TOTAL/TOTAAL: 150
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