NATIONAL
SENIOR CERTIFICATE/
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GRADE/GRAAD 12
JUNE/JUNIE 2024
PHYSICAL SCIENCES: CHEMISTRY P2/
FISIESE WETENSKAPPE: CHEMIE V2
MARKING GUIDELINE/NASIENRIGLYN
MARKS/PUNTE: 150
This marking guideline consists of 19 pages./
Hierdie nasienriglyn bestaan uit 19 bladsye.
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Physical Sciences Grade 12 P2 Eastern Cape June 2024 Memo
Grade 12 Physical Sciences Paper 2 memorandum from the Eastern Cape June Exam 2024 (Afrikaans), 19 pages. Read online or download the free PDF.
Physical Sciences · Grade 12 · Eastern Cape June Exam · 2024 · Afrikaans. Memorandum, 19 pages. Read online or download the PDF.
- Subject
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- Memorandum
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- 2024
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This exam
Eastern Cape June Exam 2024
Questions in this paper
- Question 1Organic Compounds and Macromolecules20 marks
- Question 2Organic Compounds and Macromolecules34 marks
- Question 3Organic Compounds and Macromolecules19 marks
- Question 4Organic Compounds and Macromolecules23 marks
- Question 5Rate and Extent of Reactions18 marks
- Question 6Chemical Equilibrium19 marks
Show all 7 questions
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2 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
QUESTION 1/VRAAG 1
1.1 C (2)
1.2 D (2)
1.3 A (2)
1.4 D (2)
1.5 B (2)
1.6 B (2)
1.7 C (2)
1.8 C (2)
1.9 B (2)
1.10 B (2)
[20]
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(EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 3
QUESTION 2/VRAAG 2
2.1 A series of organic compounds that can be described by the same general
formula
ʼn Reeks organiese verbindings wat deur dieselfde algemene formule beskryf
kan word.
OR/OF
A series of organic compounds in which one member differs from the next with
a CH2 group
ʼn Reeks organiese verbindings waarin een lid van die volgende verskil met ʼn
CH2 -groep (2)
2.2 2.2.1 B (1)
2.2.2 A (1)
2.2.3 B (1)
2.2.4 C (1)
2.3 Secondary alcohol / Sekondêre alkohol
The carbon that contains the hydroxyl group/ -OH is bonded to two carbon
atoms.
Die koolstof wat die hidroksielgroep / -OH bevat is verbind aan twee ander
koolstowwe
OR/OF
The hydroxyl group / -OH is bonded to a secondary carbon.
Die hidroksielgroep / -OH is verbind aan ʼn sekondêre koolstof
OR/OF
The carbon that contains the hydroxyl group / OH contains one hydrogen atom
Die koolstof wat die hidroksielgroep / OH bevat het een waterstof-atoom (2)
2.4 2.4.1 CnH2n (1)
2.4.2 4-methylpent-2-ene Marking criteria/Nasienkriteria:
4-metielpen-2-een • Pent-2-ene / 2-pentene
OR/OF Pent-2-een / 2-penteen
4-methyl-2-pentene • Whole name correct
4-metiel-2-penteen Hele naam korrek
(2)
2.4.3 5,5-dimethylhexan-3-ol Marking criteria/Nasienkriteria:
5,5-dimetielhexan-3-ol • Hexan-3-ol / 3-hexanol
OR/OF
• Dimethyl / dimetiel
5,5-dimethyl-3-hexanol
• Whole name correct / hele naam
5,5-dimetiel-3-hexanol
korrek
(3)
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4 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
2.5 2.5.1 Marking criteria/Nasienkriteria
If any of the underlined key words/phrases in the correct context are
omitted: -1 mark per word/phrase.
Indien enige van die sleutelwoorde/frases in die korrekte konteks
weggelaat word: -1 punt per woord/frase.
Compounds that have the same molecular formula but different
functional groups.
Verbindings met dieselfde molekulêre formule maar verskillende
funksionele groepe. (2)
2.5.2
H H H O
H C C C C H
Marking criteria/Nasienkriteria
H H H • Functional group / funksionele
groep 1/2
• Whole structure correct / Hele
struktuur korrek 2/2 (2)
2.6 2.6.1 Esterification / Condensation / Esterifikasie / Kondensasie (1)
2.6.2 Mol C : Mol H : Mol O Marking criteria/Nasienkriteria
58,82 : 9,81 : 31,37 • % C divide by M (C/)
12 : 1 : 16 % C gedeel deur M (C)
• % H divide by M (H)/
4,90 : 9,81 : 1,96 % H gedeel deur M(H)
• % O divide by M (O)/
% O gedeel deur M (O)
2,5 : 5 : 1 • Simplest mole ratio/
Eenvoudigste molverhouding
5 : 10 : 2 • Molecular formula/
Molekulêre formule
Empirical formula / Empiriese formule: C5H10O2
Molecular Formula / Molekulêre formule: C5H10O2 (5)
2.6.3 M (CXHYO2) = 74 g·mol-1
12n + 2n + 2(16) = 74
n=3
Propanoic acid/Propanoësuur (4)
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(EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 5
2.6.4 Marking criteria/Nasienkriteria
• Determining the molar mass of alcohol P / Bepaal die molekulêre
massa van alkohol P
• Identifying alcohol P / Identifiseer alkohol P
• Name of ester / Naam van ester
• Structural formula of the ester/ Struktuurformule van die ester
Propanoic acid + alcohol P → ester + H2O
Propanoësuur + alkohol P→ ester + H2O
M (Alcohol / Alkohol P) = 102 + 18 – 74 = 46 g·mol-1
Alcohol / Alkohol P = Ethanol / etanol Marking criteria/Nasienkriteria
• Functional group /
Ester = ethyl propanoate funksionele groep 1/2
Ester = etielpropanoaat C6H12O2 • Whole structure correct /
Hele struktuur korrek 2/2
H H O H H
H C C C O C C H
H H H H (6)
[34]
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6 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
QUESTION 3/VRAAG 3
Marking criteria/ Nasienkriteria
If any of the underlined key words/phrases in the correct context are omitted: - 1 mark
per word/phrase.
Indien enige van die sleutelwoorde frases in die korrekte konteks weggelaat word:
-1 punt per woord/frase.
3.1 Boiling point is the temperature at which the vapour pressure of a liquid /
substance equal the atmospheric pressure
Kookpunt is die temperatuur waarby die dampdruk van ʼn vloeistof/stof gelyk
aan die atmosferiese druk is. (2)
3.2 Alcohols are flammable / Alkohole is vlambaar (1)
3.3 140 (°C) (1)
3.4 YES. Compounds have the same molecular mass/ compounds are
Isomers / only one independent variable.
JA. Verbindings het dieselfde molekulêre massa/ verbindings is isomere /
slegs een onafhanklike veranderlike. (2)
3.5 2-methylbutan-1-ol 2-metielbutan-1-ol Marking criteria/Nasienkriteria:
OR/OF • butan-1-ol
2-methyl-1-butanol 2-metiel-1-butanol • Whole name correct / hele naam
korrek
(Accept/Aanvaar)
3-methylbutan-1-ol 3-metielbutan-1-ol
OR/OF
3-methyl-1-butanol 3-metiel-1-butanol (2)
3.6 Alcohol 3 accept: 2,2-dimethylpropan-1-ol / 2,2-dimethyl-1-propanol
Alkohol 3 aanvaar: 2,2-metielpropan-1-ol/ 2,2-dimetiel-1-propanol (1)
3.7 Marking criteria / Nasienkriteria
• Chain length decreases from 1 to 3
Kettinglengte neem af vanaf 1 tot 3
• Decrease in the strength of the London forces/dispersion forces/induced
dipole forces from 1–3
Afname in die sterkte van die Londonkragte/verspreidingskragte/
Geїnduseerde dipool-dipool kragte vanaf 1–3
• Relate the strength of London forces/dispersion forces/induced dipole to
energy involved
Vergelyk the sterkte van die Londonkragte/verspreidingskragte/
Geїnduseerde dipool-dipool kragte na die energie
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From 1 to 3
• Surface area / chain length decreases / increased in the number of
branches
Oppervlakte / kettinglengte neem af / toename in die aantal takke
• Strength of London forces/dispersion forces/induced dipole forces
decreases
Sterkte van die Londonkragte/verspreidingskragte/geїnduseerde dipool-
dipool kragte neem af
• Less energy is needed to overcome intermolecular forces
Minder energie word benodig om die intermolekulêre kragte te oorkom
OR/OF
Marking criteria/Nasienkriteria
• Chain length increases from 3 to 1
Kettinglengte neem toe vanaf 3 na 1
• Increase in the strength of the London forces/dispersion
forces/induced dipole forces from 3 to 1
Toename in die sterkte van die Londonkragte/Verspreidingskragte /
geїnduseerde dipool-dipool kragte vanaf 3 na 1
• Relate the strength of London forces to energy involved.
Vergelyk the sterkte van die Londonkragte/Verspreidingskragte/
geїnduseerde dipool-dipool kragte na die energie
From 3 to 1 / Vanaf 3 tot 1
• Surface area / chain length increases/ decreased in the number of
branches
Oppervlakte/ kettinglengte neem toe/ afname in die aantal takke
• Strength of London forces/Dispersion forces/Induced dipole forces
increases
Sterkte van die Londonkragte/Verspreidingskragte /Geїnduseerde
dipool-dipool kragte neem toe
• More energy needed to overcome intermolecular forces
Meer energie word benodig om die intermolekulêre kragte te oorkom (3)
3.8 3.8.1 Marking criteria/ Nasienkriteria
If any of the underlined key words/phrases in the correct context are
omitted: - 1 mark per word/phrase.
Indien enige van die sleutelwoorde/frases in die korrekte konteks
weggelaat word: - 1 punt per woord/frase.
The pressure exerted by a vapour at equilibrium with its liquid in a
closed system. /
Die druk uitgeoefen deur ʼn damp in ewewig met sy vloeistof in ʼn geslote
sisteem. (2)
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8 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
3.8.2 Marking criteria/Nasienkriteria
• Butan-1-ol has hydrogen bonds ✓/
Butan-1-ol het waterstofbinding
• Butanone has dipole-dipole forces ✓ /
Butanoon het dipool-dipool kragte /
• Compare the strength of the hydrogen bonds to dipole-dipole forces ✓/
Vergelyk die sterkte van die waterstofbinding met dipool-dipoolkragte /
• Relate strength intermolecular forces to vapour pressure ✓/
Verwys die sterkte van die intermolekulêrekragte met die dampdruk
• Butan-1-ol has hydrogen bonds (and London forces) /
Butan-1-ol het waterstofbinding (en Londonkragte)
• Butanone has dipole-dipole forces (and London forces) /
Butanoon het dipool-dipoolkragte (en Londonkragte)
• Hydrogen bonds is stronger than the dipole-dipole forces /
Waterstofbinding is sterkter as die dipool-dipoolkragte
• Stronger intermolecular forces result in lower vapour pressure /
Sterker intermolekulêrekragte lei tot laer dampdruk
OR/OF
• Butan-1-ol has for hydrogen bonds (and London forces) /
Butan-1-ol het waterstofbinding (en Londonkragte)
• Butanone has dipole-dipole forces (and London forces) /
Butanoon het dipool-dipoolkragte (en Londonkragte)
• Dipole-dipole forces weaker than the hydrogen bonds /
Dipool-dipoolkragte is swakker as die waterstofbinding
• Weaker intermolecular forces result in higher vapour pressure /
Swakker intermolekulêrekragte sal tot ʼn hoër dampdruk lei (4)
3.8.3 INCREASE / TOENEEM ✓ (1)
[19]
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QUESTION 4/VRAAG 4
4.1 4.1.1 Dehydration / Dihidratering / dihidrasie (1)
4.1.2 Sulphuric acid / swawelsuur / H2SO4 (1)
4.1.3 Marking criteria/Nasienkriteria:
Organic compounds only/ Slegs vir organiese verbinding
• Functional group/ funksionele groep 1/2
• Whole structure correct / Hele struktuur korrek (2/2)
Hele struktuur korrek 2/2
H
H H O H H H H H
H C C C C H H C C C C H
H H H H H H
+ H2O (4)
4.1.4 Addition / hydrohalogenation / Addisie / hidrohalogenering/
hidrohalogenasie (1)
4.1.5 2-bromobutane / Marking criteria/ Nasienkriteria
2-bromobutaan Name of compound / Naam van
verbinding
• Butane / butaan 1/2
H Br H H
• Whole name correct 2/2
hele naam korrek
H C C C C H Structure /
• Functional group 1/2
H H H H funksionele groep
• Whole structure correct /Hele
struktuur korrek 2/2
hele struktuur korrek (4)
4.1.6 Mild heat and dilute strong base /LiOH/KOH/NaOH /
Matige hitte en verdunde sterk basis /LiOH/KOH/NaOH (2)
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10 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
4.2 4.2.1 Breaking down of long chain hydrocarbon molecules into more useful
shorter chains (2 or 0) /
Die proses waarin langer kettingkoolwaterstof-molekule afgebreek
word in korter, meer bruikbare, molekule (2 of 0) (2)
4.2.2 Minimize the UV light present / No substitution reaction can occur in
the saturated hydrocarbon /
Verminder die teenwoordige UV-lig / Geen substitusiereaksie kan in
die versadigde koolwaterstof plaasvind nie (1)
4.2.3 C4HZ. It readily reacts with bromine (without the presence of UV-
light)
C4HZ. Dit reageer geredelik met broom (sonder die teenwoordigheid
van UV-lig) (2)
4.2.4 Marking criteria/Nasienkriteria
H H H H • Functional group ½
Funksionele groep
• Whole structure correct/ 2/2
H C C C C H
Hele struktuur korrek
H H (2)
4.2.5 2 C4H10 + 13 O2 → 8 CO2 + 8 H2O ( bal.)
Marking criteria / Nasienkriteria
• Reactants / Reaktanse 1/3
• Products / Produkte 2/3
• Balancing / Balansering 3/3
(3)
[23]
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QUESTION 5/VRAAG 5
5.1 Marking criteria/ Nasienkriteria
If any of the underlined key words/phrases in the correct context are omitted: - 1
mark per word/phrase. /
Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
word: - 1 punt per woord/frase
ANY ONE
Change in concentration ✓ of reactant or product per (unit) time. ✓
Change in amount/number of moles/volume/mass ✓of products or reactants per
(unit) time. ✓
Change in amount/number of moles/volume/mass ✓ of products formed or
reactants used reactants per (unit) time. ✓
ENIGE EEN
Verandering in konsentrasie van reaktanse of produkte per (eenheid) tyd.
Verandering in hoeveelheid/getal mol/volume/massa van reaktanse of produkte
per (eenheid) tyd.
Verandering in hoeveelheid/getal mol/volume/massa van produkte gevorm /
reaktanse gebruik per (eenheid) tyd.
OR/OF
The rate of change in concentration/amount of moles/number of moles / volume /
mass. (2 or 0)
Die tempo van verandering in konsentrasie / hoeveelheid mol / getal mol / volume
/ massa. (2 of 0) (2)
5.2 Temperature / Temperatuur (1)
5.3 5.3.1 Experiment / Eksperiment 2 (1)
5.3.2 OPTION 1 / OPSIE 1
• In experiment 2 more particles are exposed / larger surface area
• More particles will collide with the correct orientation
• More effective collisions per unit time / Frequency of the effective
collisions increases
• In eksperiment 2 word meer deeltjies blootgestel / groter oppervlakte
• Meer deeltjies sal met die korrekte oriëntasie bots
• Meer effektiewe botsings per tydseenheid / Frekwensie van die
effektiewe botsings neem toe
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12 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
OR/OF
OPTION 2 / OPSIE 2
• In experiment 3 less particles are exposed / smaller surface area
• Less particles will collide with the correct orientation
• Less effective collisions per unit time / Frequency of the effective
collisions decreases
• In eksperiment 3 word minder deeltjies blootgestel / kleiner
oppervlakte
• Minder deeltjies sal met die korrekte oriëntasie bots
• Minder effektiewe botsings per tydseenheid / Frekwensie van die
effektiewe botsings neem af (3)
5.4 5.4.1 Marking criteria / Nasienkriteria
• Subst. Into the rate equation • Vervang in die tempo
• Subst. into n = m/M vergelyking
• Using the mol ratio CO2 : • Vervang in n = m/M
MgCO3 • Gebruik die mol verhouding CO2
• Formula m = nM : MgCO3
• Subst. into m = nM • Formule m = n/M
• Final answer • Vervanging in m = n/M
• Finale antwoord
Rate/ Δm
=
Tempo Δt
m–0
0,25 =
10,44
m = 2,61 g
M
n =
m
2,61
n =
44
n = 0,0593 mol
n (CO2) = n (MgCO3) = 0,0593 mol
m = nM ✓
m = (0,0593)(84)
m = 4,9812 g (6)
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5.4.2 V
n =
Vm
1,47
0,0593 =
Vm
Vm = 24,79 dm3 (3)
5.5 Marking criteria / Nasienkriteria
B
• Shape of B starting at the origin
Number of CO2
Vorm van B begin by oorsprong
A • Curve of B is higher / Kurwe B is hoër
NOTE: A or B must be indicated
molecules/Aantal CO2-
Ignore the labels of the axes.
molekules
LET WEL: A of B moet aangedui
word.
Ignoreer die benoeming van die asse.
Kinetic energy / Kinetiese energie (2)
[18]
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14 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
QUESTION 6/VRAAG 6
6.1 6.1.1 Marking criteria/ Nasienkriteria
If any of the underlined key words/phrases in the correct context are
omitted: - 1 mark per word/phrase.
Indien enige van die sleutelwoorde/frases in die korrekte konteks
weggelaat word: - 1 punt per woord/frase
When the equilibrium in a closed system is disturbed, the system will re-
instate a new equilibrium by favouring the reaction that will
oppose/cancel the disturbance.
Wanneer die ewewig in ʼn geslote sisteem versteur word, sal die sisteem
ʼn nuwe ewewig deur die reaksie wat die versteuring teenwerk, te
bevoordeel (2)
6.1.2 EQUAL TO / GELYK AAN
Chemical equilibrium is reached / Chemiese ewewig word bereik (2)
6.1.3 Y
2 mol of SO2 will react for every 1 mol of O2 /
2 mol van SO2 sal reageer met elke 1 mol van O2
OR/OF
The rate at which SO2 is consumed is twice that of O2./
Die tempo waarteen SO2 verbruik word is twee keer as dié van O2
OR/OF
0,925 mol of SO2 reacted with 0,46 mol of O2 /
0,925 mol van SO2 reageer met 0,46 mol O2 (2)
6.1.4 NEGATIVE / NEGATIEF (1)
6.1.5 • The amount/concentration of SO3 increased / SO2 and O2
decreased
• (According to Le Chatelier’s principle) A decrease in temperature
favours the exothermic reaction.
• The forward reaction was favoured / The equilibrium position shifted
towards the right
• Die hoeveelheid/konsentrasie van SO3 neem toe / SO2 en O2 verlaag
• (Volgens Le Chatelier se beginsel) ʼn Afname in temperatuur
bevoordeel die eksotermiese reaksie
• Die voorwaartse reaksie word bevoordeel / Die ewewigsposisie
verskuif na regs (3)
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(EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 15
6.2 6.2.1 OPTION 1: MOLE CALCULATIONS / OPSIE 1: MOLBEREKENINGE
a. Determine the change in mol of NOCℓ / Bepaal die verandering in mol van
NOCℓ
b. Correct ratio NOCℓ : NO : Cℓ2 / Korrekte verhouding NOCℓ : NO : Cℓ2
c. Determine the equilibrium mol for NOCℓ , NO and Cℓ2 / Bepaal die ewewig
mol van NOCℓ , NO en Cℓ2
d. Dividing by/ Deel deur 1,5
e. Correct Kc expression with square brackets / Korrekte Kc uitdrukking met
vierkanthakkies
f. Subst. into the correct Kc expression /Vervanging in korrekte Kc
uitdrukking
g. Final answer / Finale antwoord
Δn (NOCℓ) = 2,5 x 28/100 = 0,7 (a)
2 NOCℓ 2 NO (g) Cℓ2 (g)
Initial mol
2,5 - -
Aanvangsmol
Change in mol
Verandering in 0,7 0,7 0,35 (b)
mol
Equilibrium (c)
mol 1,8 0,7 0,35
Ewewigsmol
Concentration =1,8 / 1,5 = 0,7 / 1,5 =0,35 / 1,5 (d)
Konsentrasie = 1,2 = 0,47 0,23
[NO]2[Cℓ2]
Kc = (e)
[NOCℓ]2
(0,47)2(0,23)
Kc = (f)
(1,2)2
Kc = 0,035 (g)
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16 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
OPTION 2: CONCENTRATION CALCULATIONS / OPSIE 2:
KONSENTRASIE BEREKENINGE
a. Determine the initial concentration NOCℓ / Bepaal die aanvanklike
konsentrasie van NOCℓ
b. Determine the change in conc of NOCℓ / Bepaal die verandering in
konsentrasie van NOCℓ
c. Correct ratio NOCℓ : NO : Cℓ2 / Korrekte verhouding NOCℓ : NO : Cℓ2
d. Determine the equilibrium conc. for NOCℓ , NO and Cℓ2 / Bepaal die
ewewigs konsentrasie van NOCℓ , NO en Cℓ2
e. Correct Kc expression with square brackets / Korrekte Kc uitdrukking
met vierkanthakkies
f. Subst. into the correct Kc expression/ Vervanging in korrekte Kc
uitdrukking
g. Final answer / Finale antwoord
ci (NOCℓ) = 2,5 ÷ 1,5 = 1,67 ✓ (a)
Δc (NOCℓ) = 1,67 x 28 / 100 = 0,47 ✓ (b)
2 NOCℓ 2 NO (g) Cℓ2 (g)
Initial concentration
1,67 - -
Aanvangskonsentrasie
Change in
concentration 0,47
0,47 0,235 (c)
Verandering in
konsentrasie
Equilibrium
concentration 1,2 0,47 0,235
(d)
ewewigskonsentrasie
[NO]2[Cℓ2]
Kc = (e)
[NOCℓ]2
(0,47)2(0,23)
Kc = (f)
(1,2)2
a.Kc = 0,035 (g) (7)
6.2.2 REMAINS THE SAME / BLY DIESELFDE
Only temperature has an effect on the value of the equilibrium constant. /
Slegs temperatuur het ʼn effek op die waarde van die ewewigskonstante (2)
[19]
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(EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 17
QUESTION 7/VRAAG 7
7.1 7.1.1 Acids produce hydrogen ions (H+/H3O+/ hydronium ions) in aqueous
solutions. /
ʼn Suur is ʼn stof wat waterstof-ione (H+/H3O+/ hydroniumione) vorm
wanneer dit in water oplos (2)
7.1.2 H2O and / en HSO4– (2)
7.1.3 H2SO4 + 2 KOH → K2SO4 + 2 H2O ( bal.)
Marking criteria/ Nasienkriteria
• Reactants / Reaktanse
• Products /Produkte
• Balancing / Balansering (3)
7.2 7.2.1 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2
m m
c = n =
MV M
3,812 3,812
c = n =
(40)(100x10-3) 40
c = 0,953 mol· dm-3 n = 0,0953 mol
n
c =
V
0,0953
c =
100x10-3
c = 0,953 mol·dm-3 (3)
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18 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024)
7.2.2 OPTION 1 / OPSIE 1
Marking criteria/ Nasienkriteria
• Subst. c and V of NaOH into n = cV / Vervang van c en V van
NaOH in n = Cv
• Use of ratio CH3COOH : NaOH
• Gebriuk van verhouding CH3COOH : NaOH
• Subst. of n and V of CH3COOH into c = n/V / Vervang van c en V
van CH3COOH in n = cV
• Formula / Formule m = cMV
• Subst. into / Vervanging in m = cMV
• Subst. into percentage formula / Vervanging in persentasie-
formule
• Final answer / Finale antwoord
n (NaOH) = cV
n (NaOH) = (0,953)(21,8 x 10-3)
n (NaOH) = 0,0207754 mol
n (CH3COOH) = n (NaOH) = 0,0207754 mol
n
c =
V
0,0207754
c =
25 x 10-3
c = 0,831016 mol·dm-3
m = cMV
m = (0,831016)(60)(25 x 10-3)
m = 1,2465 g
Percentage mass / 1,2465
= X 100 %
Persentasie massa 25
Percentage mass / Persentasie massa = 4,986 %
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(EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 19
OPTION 2 / OPSIE 2
Marking criteria / Nasienkriteria
c V n
• Subst. into / Vervang in na and/ en nb ca Va = na
b b b
ca Va na
• Subst. into / Vervang in Va c V = n
b b b
c V n
• Subst. into / Vervang in cb and/ en Vb ca Va = na
b b b
• Formula /Formule m = cMV
• Subst into / Vervanging in m = cMV
• Subst into percentage formula / Vervanging in persentasie
formule
• Final answer / Finale antwoord
caVa na
=
cbVb nb
ca(25) 1
=
(0,953)(21,8) 1
ca = 0,831016 mol·dm-3
m = cMV
m = (0,831016)(60)(25 x 10-3)
m = 1,2465 g
Percentage mass / 1,2465
= X 100%
Persentasie massa 25
Percentage mass / Persentasie massa = 4,986% (7)
[17]
TOTAL/TOTAAL: 150
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