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Physical Sciences Grade 12 Paper 2 NSC November 2023 Memo

MemorandumPhysical SciencesGrade 12202325 pages

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Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 PHYSICAL SCIENCES: CHEMISTRY (P2) FISIESE WETENSKAPPE: CHEMIE (V2) NOVEMBER 2023 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 These marking guidelines consist of 23 pages. Hierdie nasienriglyne bestaan uit 23 bladsye. Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 2 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.1 D  (2) 1.2 D  (2) 1.3 A  (2) 1.4 B  (2) 1.5 D  (2) 1.6 C  (2) 1.7 C  (2) 1.8 A  (2) 1.9 B  (2) 1.10 D  (2) [20] QUESTION 2/VRAAG 2 2.1 Molecules/compounds containing carbon (atoms).  Molekule/verbinding wat koolstof(atome) bevat. (1) 2.2 2.2.1 2,3-dimethylbut-1-ene/2,3-dimethyl-1-butene 2,3-dimetielbut-1-een/2,3-dimetiel-1-buteen Marking criteria: Nasie  Correct stem i.e. but-1-ene.   Ko  IUPAC name completely correct including numbering, sequence, hyphens and commas.  sta but   IUP naa hee kor ins nom vol kop se kom 2.2.2 Butan-2-one/2-butanone/butanone  Butan-2-oon/2-butanoon/butanoon Copyright reserved/Kopiereg voorbehou
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 3 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Marking criteria: Nasien  Correct chain length, i.e But.   Korr  Everything else correct: IUPAC name completely correct including numbering, sequence, ketti hyphens and commas.  d.i. B  Alle reg: naa hee korr inslu nom volg kop en k  Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 4 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 2.3 2.3. 1  Marking criteria/Nasienkriteria: H H H H O H  Functional group correct Funksionele groep korrek. H C C C C C O C H  Whole structure correct.  Hele struktuur korrek. H H H H H  IF/INDIEN  More than one functional group/wrong functional group: Meer as een funksionele groep/foutiewe funksionele groep: ⁄  If condensed structural formulae used/Indien gekondenseerde struktuurformules gebruik: Max./Maks. ⁄ (2) 2.3.2 Marking criteria/Nasienkriteria: H   Six C atoms in longest chain.  H C Ses C-atome in langste ketting. H  Two F atoms on third C atom.  H Twee F-atome op die derde C-atoom.  H C  Ethyl substituent on fourth C atom.  H H F H H Etielsubstituent op die vierde C-atoom. H C C 3C C C C H IF/INDIEN 4 H-atom or bond omitted/H-atoom of  H H F H H H binding uitgelaat Max/Maks: ⁄3 (3) gebruik: 2.3.3 CnH2n  (1) ⁄ 2.3.4 O ACCEPT/AANVAAR:  C C C O R C R’ (1) 2.3.5 Methanol/Metanol  NOTE/NOTA: 1-methanol/methan-1-ol/1-metanol/metan-1-ol Max./Maks. ⁄ (2) 2.4 2.4.1 B (1) 2.4.2 D and/en G  (1) [16] Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 5 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 3/VRAAG 3 3.1 Marking criteria/Nasienkriteria If any one of the underlined key phrases in the correct context is omitted, deduct 1 mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is, trek 1 punt af. The underlined phrases must be in the correct context. / Die onderstreepte frases moet in die korrekte konteks wees. The temperature at which the vapour pressure of a substance equals atmospheric pressure.  Die temperatuur waarby die dampdruk van die stof gelyk is aan atmosferiese druk. (2) OPTION 1 FOR 3.2 AND 3.3/OPSIE 1 VIR 3.2 EN 3.3 3.2 Marking criteria/Nasienkriteria:  Dependent and independent variables correctly identified.  Afhanklike en onafhanklike veranderlikes korrek geïdentifiseer.  Correct relationship between dependent and independent variables stated.  Korrekte verwantskap tussen die afhanklike en onafhanklike veranderlikes gestel IF/INDIEN: Directly proportional/Direk eweredig Max/Maks: ⁄ The higher the molecular mass the higher the boiling point.  OR As the molecular mass increases the boiling point increases. OR The longer the C-chain the higher boiling point OR The boiling point and the molecular mass are proportional. Hoe hoër die molekulêre massa hoe hoër die kookpunt. OF Soos die molekulêre massa toeneem, neem die kookpunt ook toe. OF Hoe langer die C-ketting hoe hoër is die kookpunt. OF Die kookpunt en die molekulêre massa is eweredig. (2) 3.3 Marking criteria:  Strength of intermolecular forces.   Energy required to overcome intermolecular forces.  Nasienkriteria:  Sterkte van intermolekulêre kragte.   Energie benodig om intermolekulêre kragte te oorkom.   Strength of the intermolecular forces increases / More sites for London forces with increase of molar mass/chain length/surface area.   More energy is needed to overcome/break intermolecular forces.   Sterkte van die intermolekulêre kragte neem toe. / Meer punte vir Londonkragte met toename in molêre massa/kettinglengte/kontakoppervlak.  Meer energie benodig om intermolekulêre kragte te oorkom/breek. (2) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 6 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne OPTION 2 FOR 3.2 AND 3.3/OPSIE 2 VIR 3.2 EN 3.3 3.2 Curve P represents carboxylic acids.  Kurwe P verteenwoordig karboksielsure. OR/OF For every molar mass, P has the highest boiling point. Vir elke molêre massa, het P die hoogste kookpunt. (2) 3.3 Marking criteria:  Strength of intermolecular forces.   Energy required to overcome intermolecular forces.  Nasienkriteria:  Sterkte van intermolekulêre kragte.   Energie benodig om intermolekulêre kragte te oorkom.   Curve P/carboxylic acids has strongest intermolecular forces.  Most energy is needed to overcome/break intermolecular forces.   Kurwe P/karboksielsure het die sterkste intermolekulêre kragte.  Meeste energie word benodig om intermolekulêre kragte te oorkom/breek. (2) 3.4 3.4.1 Aldehyde / Aldehiede  (1) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 7 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 3.4.2 Marking criteria:  Comparing the strength of intermolecular forces of aldehydes/S with alcohols/R and/or carboxylic acids/P.   Linking the intermolecular forces to boiling point/energy needed.  Nasienkriteria:  Vergelyk die sterkte van die intermolekulêre kragte van aldehyde/S met alkohole/R en/of karboksielsure/P.   Trek die verband tussen die intermolekulêre kragte en die kookpunte/energie benodig.   Aldehydes/S have the weakest/weaker intermolecular forces.   Therefore, aldehydes/S have the lowest/lower boiling points / least/lower energy needed to overcome/break intermolecular forces.  OR  The strength of the intermolecular forces in aldehydes/S is weaker than in alcohols/R / carboxylic acids/P.  Therefore, aldehydes/S have lower boiling points / need less energy than alcohols/carboxylic acids to overcome/break intermolecular forces OR  Carboxylic acids/P have the strongest intermolecular forces.  Therefore, carboxylic acids/P have the highest boiling points / need most energy to overcome/break intermolecular forces. OR  Carboxylic acids/P and alcohols/R have stronger intermolecular forces than aldehydes/S.  Therefore, carboxylic acids/P and/or alcohols/R have higher boiling points/ need more energy than aldehydes to overcome/break intermolecular forces.  Aldehiede/S het die swakste/swakker intermolekulêre kragte.   Dus het aldehiede/S die laagste/laer kookpunt / die minste/minder energie nodig om die intermolekulêre kragte te oorkom/breek.  OF  Die sterkte van intermolekulêre kragte tussen aldehiede is swakker as tussen alkohole/R / karboksielsure/P.  Dus het aldehiede/S ʼn laer kookpunt as alkohole/R/ karboksielsure/P/ minder energie nodig om die intermolekulêre kragte te oorkom/breek. OF  Karboksielsure/P het die sterkste intermolekulêre kragte.  Dus het karboksielsure/P die hoogste kookpunt / die meeste energie nodig om die intermolekulêre kragte te oorkom/breek. OF  Karboksielsure/P en alkohole/R het sterker intermolekulêre kragte as aldehiede/S.  Dus het karboksielsure/P/alkohole/R 'n hoër kookpunt as aldehiede / meer energie nodig om die intermolekulêre kragte te oorkom/breek. (2) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 8 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 3.5 3.5.1 60 (g∙mol-1)  Range/Gebied: 58 – 62 g∙mol-1 (1) 3.5.2 Propan-1-ol/1-propanol  Marking criteria: Nasienkriteria:  Correct stem of alcohol, i.e Propanol.   Korrekte stam vir alkohol d.i. Propanol.   Correct position of functional group and  Korrekte posisie van die funksionele everything else correct: IUPAC name groep en alles verder reg: IUPAC-naam completely correct including numbering heeltemal korrek insluitende nommering and hyphens.  en koppeltekens.  (2) 3.6 Marking criteria:  State that carboxylic acids have two sites for hydrogen bonding.   State that alcohols have one site for hydrogen bonding.   Comparing the strength of IMFs / the energy needed to overcome IMFs.  Nasienkriteria:  Stel dat karboksielsure twee plekke het vir waterstofbindings.  Stel dat alkohole een plek het vir waterstofbinding.  Vergelyk die sterkte van die IMKs / energie benodig om IMKs te oorkom.  Carboxylic acids/B/Propanoic acid have, (in addition to London forces and dipole-dipole forces), two sites for hydrogen bonding between molecules.  OR Carboxylic acid/B/Propanoic acid can form dimers due to strong hydrogen bonding between molecules.  Alcohols/A/Butan-1-ol have, (in addition to London forces and dipole-dipole forces), one site for hydrogen bonding between molecules.   Intermolecular forces in carboxylic acids are stronger.  OR More energy needed to overcome/break intermolecular forces in carboxylic acid/B/propanoic acid.  Karboksielsure/B/Propanoësuur het, (in toevoeging tot Londonkragte en dipool-dipoolkragte), twee punte vir waterstofbinding tussen molekule. OF Karboksielsure/B/Propanoësuur kan dimere vorm as gevolg van sterk waterstofbindings tussen molekule.  Alkohole/A/Butan-1-ol het, (in toevoeging tot Londonkragte en dipool- dipoolkragte), een punt vir waterstofbinding tussen molekule.  Intermolekulêre kragte in karboksielsure is sterker. OF Meer energie word benodig om intermolekulêre kragte in karboksielsure/ B/Propanoësuur te oorkom/breek. (3) [15] Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 9 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 10 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 4/VRAAG 4 4.1 4.1.1 Marking criteria/Nasienkriteria If any one of the underlined key phrases in the correct context is omitted, deduct 1 mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is, trek 1 punt af. The underlined phrases must be in the correct context. / Die onderstreepte frases moet in die korrekte konteks wees. The chemical process/reaction in which longer chain hydrocarbon/alkane molecules/ are broken down to shorter (more useful) molecules.  Die chemiese proses/reaksie waarin langer kettingkoolwaterstof/alkaan- molekule afgebreek word in korter (meer bruikbare) molekules. (2) 4.1.2 X = 12  Y=2 Z=4 ACCEPT/AANVAAR: C16H34 → C6H14 + C6H12 + 2C2H4 (3) 4.1.3 Marking criteria/Nasienkriteria  O2   Products  / Produkte  Balancing /Balansering 2C6H14 + 19O2  → 12CO2 + 14H2O  Bal  Notes/Aantekeninge:  Ignore double arrows and phases./Ignoreer dubbelpyle en fases.  Marking rule 6.3.10/Nasienreël 6.3.10.  If condensed structural formulae used:/Indien gekondenseerde struktuurformules gebruik: Max/Maks. 2 3 (3) 4.2 4.2.1 Marking criteria/Nasienkriteria If any one of the underlined key phrases in the correct context is omitted, deduct 1 mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is, trek 1 punt af. The underlined phrases must be in the correct context. / Die onderstreepte frases moet in die korrekte konteks wees. Compounds with the same molecular formula, but different positions of the side chain / substituents / functional groups on the parent chain.  Verbindings met dieselfde molekulêre formule, maar verskillende posisies van die syketting / substituente / funksionele groepe op die stamketting. (2) 4.2.2 Addition/hydrohalogenation/hydrochlorination  Addisie/hidrohalogenering/hidrochlorinering (1) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 11 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 4.2.3 Marking criteria/Nasienkriteria: H H H H H  Chlorine atom bonded to any C-atom.   Chlooratoom gebind aan enige C-atoom. H C C C C C H  Correct functional group on third C-atom.  Korrekte funksionele groep op derde C-atoom.   Whole structure correct.  H H Cℓ H H  Hele struktuur korrek. (3) 4.2.4 HCℓ  (1) 4.2.5 (Concentrated/ conc.) H2SO4 / sulphuric acid / H3PO4 / phosphoric acid  (Gekonsentreerde/ gek.) H2SO4 / swawelsuur / H3PO4 / fosforsuur IF/INDIEN: Dilute/Verdun: ⁄ (1) 4.2.6 Concentrated strong base  OR Concentrated NaOH / KOH / LiOH / sodium hydroxide/ potassium hydroxide/ lithium hydroxide OR Strong base/NaOH/KOH/LiOH/sodium hydroxide/ potassium hydroxide/lithium hydroxide in ethanol. Gekonsentreerde sterk basis OF Gekonsentreerde NaOH /KOH/ LiOH /natriumhidroksied/ kaliumhidroksied/ litiumhidroksied OF Sterk basis/NaOH /KOH/ LiOH / natriumhidroksied/kaliumhidroksied/litium- hidroksied in etanol (1) 4.2.7  Elimination   Dehydrohalogenation/dehydrochlorination   Eliminasie  Dehidrohalogenering/dehidrohalogenasie/dehidrochlorinasie/ dehidrochlonering (2) [19] Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 12 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5 5.1 ANY ONE:  Change in concentration  of products/reactants per (unit) time.   Change in amount/number of moles/volume/mass of products or reactants per (unit) time.  Amount/number of moles/volume/mass of products formed/reactants used per (unit) time.  Rate of change in concentration/amount/number of moles/volume/ mass. (2 or 0) ENIGE EEN:  Verandering in konsentrasie van produkte/reaktanse per (eenheid) tyd.  Verandering in hoeveelheid/getal mol/volume/massa van produkte of reaktanse per (eenheid) tyd.  Hoeveelheid/getal mol/volume/massa van produkte gevorm/reaktanse gebruik per (eenheid) tyd.  Tempo van verandering in konsentrasie/ hoeveelheid/getal mol/ volume/massa. (2 of 0) (2) 5.2 Concentration (of Na2S2O3)  Konsentrasie (van Na2S2O3) (1) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 13 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 5.3 Marking criteria/Nasienkriteria:  Substitute/Vervang 0,03 and/en 0,13 OR/OF30 and/en 0,13.   Substitute/Vervang 0,05 OR/OF 50.   Final correct answer/Finale korrekte antwoord: 0,078 mol∙dm-3.  Range 0,075 to/tot 0,08 mol∙dm-3 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 n c1V1 = c2V2 c= (0,13)(0,030)  = c2 (0,050)  n c2 = 0,078 (mol∙dm-3)  0,13 = 3  n = 3,9 x 10-3 moles/mol n c= -3 39 c=  = 0,078 (mol∙dm-3)  OPTION 3/OPSIE 3 Marking criteria/Nasienkriteria:  Substitute/Vervang 0,05 and/en 0,13 OR/OF 50 and/en 0,13 OR/OF 0,05 and/en 0,10.   Substitute/Vervang 0,05 OR/OF 0,0550.   Final correct answer/Finale korrekte antwoord: 78 mol∙dm-3.  -3 Range: 0,075 to/tot 0,08 mol∙dm n c= OR/OF n n 0,13 = c=  n = 6,5 x 10-3 moles/mol n 0,10 =  V2 : V1 n = 5 x 10-3 moles/mol 3 :5 3,9 x 10-3 : 6,5 x 10-3 V2 : V1 3 :4 n 3,75 x 10-3 : 5 x 10-3 c= -3 n 39 c= c=  -3 = 0,078 (mol∙dm-3)  37 c=  = 0,075 (mol∙dm-3)  OPTION 4/OPSIE 4 3 3  (0,13)  = 0,078 (mol∙dm-3)  OR/OF  (0,10)  = 0,075 (mol∙dm-3)  (3) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 14 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 5.4 Marking criteria: Nasienkriteria:  Substitute M = 32 g·mol-1 in formula  Vervang M = 32 g·mol-1 in formule m m n(S) =  n(S) =   Use mol/M ratio:  Gebruik mol/M-verhouding: n(S) = n(Na2S2O3)  n(S) = n(Na2S2O3)   Substitute M = 158 g·mol-1 in  Vervang M = 158 g·mol-1 in formula m m formula n(Na2S2O3) =  n(Na2S2O3) =   Divide by 20,4 s.   Deel deur 20,4 s.   Final correct answer: 0,051 (g·s-1)   Finale korrekte antwoord: 0,051 (g·s-1) Range: 0,048 to 0,080 (g·s-1) Gebied: 0,048 tot 0,080 (g·s-1) OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 m 158 g Na2S2O3  32 g S  n(S) = g 0,21 g  = 1,04 g = 3  = 0,00656 moles/mol (6,56x10-3) n(S) = n(Na2S2O3) = 0,00656 moles/mol  m n(Na2S2O3) = m 0,00656 = 8 m(Na2S2O3) = 1,04 g m Rate/Tempo = =  = 0,051 (g·s-1)  ACCEPT/AANVAAR: ACCEPT/AANVAAR: n m c= c= n m 0,13 = 0,13 = ( 8( = 0,00656  m m = 1,03 g n(Na2S2O3) = m m 0,00656 = Rate/Tempo = 8 = 1,03 g (1,027) 3 =  m = 0,05 (g·s-1)  Rate/Tempo = 3 =  = 0,05 (g·s-1)  Max/Maks. 3⁄ Max/Maks. 3⁄ (5) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 15 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 5.5 Marking criteria: A  Both axis labelled correctly.  Number of particles/  Both curves start at origin and have correct shape.  B   Peak of curve B must be lower than curve A.   Curve B must have higher kinetic Aantal deeltjies energy than curve A from the peak up to end of curve B.    Nasienkriteria:  Beide asse korrek benoem.  Kinetic energy/Kinetiese energie  Beide kurwes begin by die oorsprong en het dieselfde vorm. IF/INDIEN:  Maksimum van kurwe B moet Both curves end on the x-axis then B has laer wees as kurwe A. to end to the right of A.  Maksimum van kurwe B moet Altwee kurwes op die x-as eindig, moet B hoër kinetiese energie as kurwe regs van A eindig. ⁄ A vanaf die piek van B tot by einde van die kurwe B. Curves not labelled. Max/Maks. ⁄ Kurwes nie benoem nie. (4) 5.6 OPTION 1  At a higher temperature particles move faster/have higher kinetic energy.   More molecules have enough/sufficient kinetic energy for an effective collision.  OR More molecules have kinetic energy/Ek equal to or greater than the activation energy.  More effective collisions per unit time/second.  OR Frequency of effective collisions increases.  Reaction rate increases.  OPTION 2  At a lower temperature particles move slower/have lower kinetic energy.  Less molecules have enough/sufficient kinetic energy for an effective collision. OR Less molecules have kinetic energy/Ek equal to or greater than the activation energy.  Less effective collisions per unit time/second. OR Frequency of effective collisions decreases.  Reaction rate decreases.  Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 16 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne OPSIE 1:  By 'n hoër temperatuur beweeg die deeltjies vinniger/het die deeltjies hoër kinetiese energie.   Meer molekule het genoeg/voldoende kinetiese energie/Ek vir 'n effektiewe botsing.  OF Meer molekule het kinetiese energie gelyk aan of groter as die aktiveringsenergie.  Meer effektiewe botsings per eenheidtyd/sekonde.  OF Frekwensie van effektiewe botsings verhoog.  Reaksietempo neem toe.  OPSIE 2:  By 'n laer temperatuur beweeg die deeltjies stadiger/het die deeltjies laer kinetiese energie.   Minder molekule het genoeg/voldoende kinetiese energie/Ek vir 'n effektiewe botsing.  OF Minder molekule het kinetiese energie gelyk aan of groter as die aktiveringsenergie.  Minder effektiewe botsings per eenheidtyd/sekonde.  OF Frekwensie van effektiewe botsings verlaag. Reaksietempo neem af.  (4) [19] Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 17 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 6/VRAAG 6 6.1 A reaction where products can be converted back to reactants  (and vice versa). OR Both forward and reverse reactions can take place. OR A reaction which can take place in both directions. OR Products can be converted back to reactants. 'n Reaksie waarin produkte terug na reaktanse, en (omgekeerd), omgeskakel kan word. OF Beide voor-en terugwaartse reaksies kan plaasvind. OF ’n Reaksie wat in beide rigtings kan plaasvind. OF Produkte kan omgeskakel word na reaktanse. (1) 6.2 Marking criteria/Nasienkriteria: If any one of the underlined key phrases in the correct context is omitted, deduct 1 mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is, trek 1 punt af. The underlined phrases must be in the correct context. / Die onderstreepte frases moet in die korrekte konteks wees. When the equilibrium in a closed system is disturbed, the system will re-instate a new equilibrium by favouring the reaction that will cancel/oppose the disturbance.  Wanneer die ewewig in 'n geslote sisteem versteur word, sal die sisteem 'n nuwe ewewig instel deur die reaksie te bevoordeel wat die versteuring kanselleer/teenwerk. (2) 6.3 6.3.1 The amount/concentration of A2(g) was increased./A2 was added to the container. Die hoeveelheid/konsentrasie A2(g) is verhoog./A2 is bygevoeg tot die houer. (1) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 18 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 6.3.2  Increase in A2 /concentration favours the reaction that uses or decreases the amount/concentration of A2.   The reverse reaction is favoured.  OR Amount or concentration of products decreases OR Amount or concentration of reactants increases.  'n Toename in A2 /konsentrasie bevoordeel die reaksie wat die hoeveelheid/konsentrasie van A2 verlaag  Die terugwaartse reaksie is bevoordeel OF Hoeveelheid of konsentrasie van die produkte neem af OF Die hoeveelheid of konsentrasie van die reaktante neem toe. (2) 6.4 OPTION 1/OPSIE 1: OPTION 2/OPSIE 2: Kc =  Kc =  8 ( )( ) ( )( )  = = ( )  = 0,16  ( )  = 0,16  OPTION 3/OPSIE 3: OPTION 4/ OPSIE 4: Kc =  Kc =  ( )( )  ( )( )  = = ( )  = 0,44  ( )  = 0,44  IF/INDIEN: Wrong Kc expression: Verkeerde Kc-uitdrukking: Max./Maks. ⁄ No Kc expression: Geen Kc-uitdrukking Max./Maks. 3⁄ (4) 6.5 Marking criteria/Nasienkriteria: 6.5.1  Both axes correctly labelled and shape of Ep curve.  Potential energy/  Asse korrek benoem en vorm van  Ep-kurwe  Shape of Ep curve for endothermic reaction as shown.  Potensiële energie Vorm van kurwe vir endotermiese reaksie soos getoon. ACCEPT/AANVAAR: Time(s)/Tyd(s) Course of reaction/ Verloop van reaksie (3) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 19 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 6.5.2  Less than   Amount/concentration of products/B2/A2 decreases.  OR Amount/concentration of reactants/AB increases. OR The reverse reaction is favoured. / Equilibrium (position) shifts to the left.  Kleiner as  Hoeveelheid/konsentrasie van produkte/B2/A2 neem af. OF Hoeveelheid/konsentrasie van reaktanse/AB neem toe. OF Die terugwaartse reaksie word bevoordeel./Die ewewigs(posisie) skuif na links. (3) 6.6 Gradients (of all three curves) will be steeper  and reach the same equilibrium  values. OR Gradients of curve become zero  at same equilibrium  values before 40 s.  OR The curves are horizontal at same equilibrium values before 40 s / reaches same equilibrium sooner/less than 40 s. Gradiënte (van al drie kurwes) is steiler en bereik dieselfde ewewig-waardes. OF Gradiënte van die kurwes word nul by dieselfde ewewig-waardes voor 40 s. OF Kurwes is horisontaal by dieselfde ewewig-waardes voor 40 s/ bereik dieselfde ewewig gouer/minder as 40 s. IF/INDIEN: Curves are identified all three must be named. Kurwes geindentifiseer word, moet al drie genoem word. (3) [19] Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 20 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 7/VRAAG 7 7.1 A strong base (ionises) dissociates completely  in water to form a high concentration of OH- ions.  ‘n Sterk basis ioniseer/dissosieer volledig in water om 'n hoë konsentrasie OH--ione te vorm. ACCEPT/AANVAAR: A strong base (ionises) dissociates completely  in water.  ‘n Sterk basis ioniseer/dissosieer volledig in water. (2) 7.2.1 n(Ba(OH)2) = cV = (0,15)(0,02)  = 0,003 mol  (3) 7.2.2 POSITIVE MARKING FROM QUESTION 7.2.1/ POSITIEWE NASIEN VAN VRAAG 7.2.1 Marking citeria: Nasienkriteria: (a) Use ratio: (a) Gebruik verhouding: 2nBa(OH)2 (7.2.1) = nHNO3  2nBa(OH)2 (7.2.1) = nHNO3  (b) Substitute nH3O+ or nHNO3 and (b) Vervang nH3O+ of nHNO3 en n n 0,025 dm3 in c =  0,025 dm3 in c =  + (c) Formula: pH = -log[H3O ]  (c) Formule: pH = -log[H3O+]  (d) Substitute [H3O+] in pH formula  (d) Vervang [H3O+] in pH formule  (e) Final correct answer: 0,62 (e) Finale korrekte antwoord: 0,62  nHNO3 reacted = 2nBa(OH)2 = 2(0,003) (a) = 0,006 mol OPTION 1/ OPSIE 1 OPTION 2/OPSIE 2 + n(H3O ) = n(HNO3) n [HNO3] = = 0,006 mol n = (b) + [H3O ] = = 0,24 mol∙dm-3 = (b) [H3O+] = [HNO3] = 0,24 mol∙dm-3 = 0,24 mol∙dm-3 + pH = -log[H3O ] (c) = -log(0,24) (d) = 0,62 (e) (5) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 21 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 7.3 POSITIVE MARKING FROM QUESTION 7.2.2/ POSITIEWE NASIEN VAN VRAAG 7.2.2 Marking criteria: Nasienkriteria: (a) Substitute [HNO3] = 0,4 mol∙dm-3 and (a) Vervang: [HNO3] = 0,4 mol∙dm-3 0,025 dm3  en 0,025 dm3  (b) Subtract: (b) Trek af: n(HNO3)ini – n(HNO3)excess (7.2.2)/ n(HNO3)aanv – n(HNO3)oormaat (7.2.2)/ [HNO3]ini – [HNO3]excess (7.2.2)  [HNO3]aanv – [HNO3]oormaat (7.2.2)  (c) Use of ratio (c) Gebruik verhouding: n(MCO3) = ½n(HNO3)  n(MCO3) = ½n(HNO3)  (d) Calculate the pure mass m(MCO3)  (d) Bereken suiwer massa m(MCO3)  (e) Substitute n(MCO3) and m(MCO3) in (e) Vervang n(MCO3) en m(MCO3) in m m n=  n=  -1 (f) Subtraction of 60 g∙mol from molar (f) Afrek van g∙mol-1 vanaf molêre mass.  massa.  (g) Correct answer: Mg  (g) Korrekte antwoord: Mg  OPTION 1/ OPSIE 1 OPTION 2/ OPSIE 2 n(HNO3)ini = cV 3 = d 3 n l 3 = (0,4)(0,025) (a) = 0,4 – 0,24  (b) = 0,01 mol = 0,16 mol∙dm-3 n(HNO3)react = n(HNO3)ini – n(HNO3)excess In 1 dm3 : 0,16 mol = 0,01 – 0,006  (b) In 0,025 dm3 : 0,004 mol  (a) = 0,004 mol n(MCO3) = ½n(HNO3) n(MCO3) = ½n(HNO3) = ½(0,004) (c) = ½(0,004) (c) = 0,002 mol = 0,002 mol 8 8 m(MCO3) = x 0,198 (d) m(MCO3) = x 0,198 (d) = 0,168 g = 0,168 g m n(MCO3) = m 8 (e) n(MCO3) = 0,002 = 8 (e) M(MCO3 = 8 g∙mol-1 0,002 = M(MCO3) = 84 g∙mol-1 Molar mass (M) = 84 - 60 (f) = g∙mol-1 Molar mass (M) = 84 - 60 (f) Therefore, metal M is Mg (g) = g∙mol-1 Therefore metal M is Mg (g) (8) [18] Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 22 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 8/VRAAG 8 8.1.1 Copper strip becomes thinner/corrodes/decreases in mass/solid/silver coloured particles in solution/the copper becomes plated with silver.  Koper plaatjie word dunner/korrodeer/massa neem af/vaste stof/silwer- kleurige deeltjies in oplossing. IF/INDIEN: Rust/Roes. ⁄ (1) 8.1.2 Ag+ (ion/-ioon) / Silver ion/ AgNO3/silver nitrate  Silwernitraat/Silwer-ioon (1) - 8.2 Ag+ (ion) is a stronger oxidising agent than Cu2+ ion  and will oxidise Cu  to Cu2+ ion. OR - Cu (ion) is a weaker oxidising agent  than Ag+ ion and Cu will be 2+ oxidised to Cu2+ ion. OR - Cu/Copper is a stronger reducing agent than Ag/Silver and will reduce silver  ions to silver.  - Ag+ (-ioon) is 'n sterker oksideermiddel as Cu2+ -ioon en sal Cu na Cu2+ - ioon oksideer. OF - Cu (-ioon) is 'n swakker oksideermiddel as Ag+ -ioon en daarom sal Cu na 2+ Cu2+ -ioon geoksideer word. OF - Cu/Koper is 'n sterker reduseermiddel as Ag/Silwer en sal silwer-ione na silwer reduseer. (3) 8.3 8.3.1 Silver/Ag/Silwer  (1) 8.3.2 CuSO4/Cu2+ /Copper (II) ions/copper(II) sulphate  Koper(II)-ione/ koper(II)sulfaat (1) ACCEPT/AANVAAR: Any soluble copper(II) salt e.g. Cu(NO3)2 Enige oplosbare koper(II)sout bv. Cu(NO3)2 8.3.3 2Ag+(aq) + Cu(s)  → 2Ag(s) + Cu2+(aq)  Bal  Marking criteria/Nasienkriteria:  Reactants  Products  Balancing:  Reaktanse Produkte Balansering  Ignore double arrows./Ignoreer dubbelpyle.  Ignore phases./Ignoreer fases.  Marking rule 6.3.10./Nasienreël 6.3.10. (3) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 23 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 8.4 K+  - [Ag+] decreases.  OR In silver half-cell concentration of positive ions decreases. OR The silver half-cell becomes negative. ACCEPT: Maintain the ion balance/electrical neutrality. [Ag+] neem af. OF In die silwerhalfsel neem die konsentrasie van die positiewe ione af. OF Die silwerhalfsel word negatief. AANVAAR: Handhaaf die ioonbalans/elektriese neutraliteit. (2) [12] QUESTION 9/VRAAG 9 9.1 ANY ONE/ENIGE EEN:  The chemical process in which electrical energy is converted to chemical energy.  (2 or 0)  The use of electrical energy to produce a chemical change.  Decomposition of an ionic compound by means of electrical energy.  The process during which an electric current passes through a solution/ionic liquid/molten ionic compound.  Die chemiese proses waarin elektriese energie omgeskakel word na chemiese energie.  (2 of 0)  Die gebruik van elektriese energie om 'n chemiese verandering te weeg te bring.  Ontbinding van 'n ioniese verbinding met behulp van elektriese energie.  Die proses waardeur 'n elektriese stroom deur 'n oplossing/ioniese vloeistof/gesmelte ioniese verbinding beweeg. (2) 9.2 Cu2+(aq) + 2e-  Cu(s)  ACCEPT/AANVAAR: Reduction (reaction) / Reduksie (reaksie) ⁄ Marking criteria/Nasienkriteria:  Cu( ← Cu2+(aq) + 2e- (2 ) Cu2+(aq) + 2e- ⇌ Cu(s) (1 ) 2 2 2+ - Cu (aq) + 2e ← Cu( 0 ( ) Cu(s) ⇌ Cu (aq) + 2e 2+ - 0 ( ) 2 2  Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op elektron.  If charge (+) omitted on Cu2+/Indien lading (+) weggelaat op Cu2+: Example/Voorbeeld: Cu2(aq) + 2e-  Cu(s) Max./Maks: 1 2  Ignore phases/Ignoreer fases. (2) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 24 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 9.3 R to/na Q  (1) 9.4 Marking criteria: Nasienkriteria: m m (a) Substitution of 63,5 into n =  (a) Vervang 63,5 in n =  23 -1 (b) Substitute 6,02 x 10 mol  (b) Vervang 6,02 x 10 mol-1  23 (c) n(electrons) = N(Cu atoms) x 2 OR (c) n(elektrone) = N(Cu-atome) x 2 OF n(electrons) = N(Cu atoms) x 1  n(elektrone) = N(Cu-atome) x 1  (d) Calculate t = (5)(60)(60)  (d) Bereken t = (5)(60)(60)  (e) Final correct answer: 2,68 A  (e) Finale korrekte antwoord: 2,68 A  Range: 1,34 to 2,70 A Gebied: 1,34 tot 2,70 A USING/GEBRUIK Cu2+ USING/GEBRUIK Cu+ m m n(Cu) = n(Cu) = n(Cu) = n(Cu) = 3 (a) 3 (a) = 0,25 mol = 0,25 mol n atoms(Cu) = n atoms(Cu) = 0,25 = 3 0,25 = 3 (b) (b) 23 N = 1,5 x 1023 N = 1,5 x 10 atoms atoms n(electrons) = (1,5 x 1023)(1)(c) n(electrons) = (1,5 x 1023)(2) (c) = 1,5 x 1023 electrons = 3 x 1023 electrons n(electrons) = OR/OF n(electrons) = OR/OF 1,5 x 1023 = - 9 3 x 1023 = - 9 = 24 080 C = 48 160 C I= I= 8 8 = (d) ( ( ( 18 000 (s) = ( ( ( (d) 18 000 (s) = 1,34 A (e) = 2,68 A (e) (5) Copyright reserved/Kopiereg voorbehou Please turn the page/Blaai om asseblief
Downloaded from hlayiso.com Physical Sciences P2/Fisiese Wetenskappe V2 25 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 9.5 - Ag/silver is a weaker reducing agent  than Cu/coper or Zn/zinc  and will not be oxidised. OR - Cu/coper or Zn/zinc is a stronger reducing agent  than Ag/silver  and Ag will not be oxidised. OR Voltage of power source is not effective enough (to oxidise Ag/silver).  - Ag/silwer is 'n swakker reduseermiddel as Cu/koper of Zn/sink en sal nie geoksideer word nie. OF - Cu/Koper of Zn/sink is 'n sterker reduseermiddel as Ag/silwer en Ag sal nie geoksideer word nie. OF Die potensiaalverskil van die energiebron is nie effektief genoeg om die Ag/silwer te oksideer nie. (2) [12] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou

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