Physical Sciences Grade 12 Paper 1 MP Mock 2023 Paper & Memo

— — —— a — —_—— + education DEPARTMENT: EDUCATION MPUMALANGA PROVINCE NATIONAL MARKS: 150 TIME: 3 hours This question paper consists of 21 pages including 3 information sheets. Ploase tun aver Copypngn reversed —————— ———

Physigg | Sci s/P ° jownloaded from Stanmorepitysics.com MDE/September 2023 INSTRUCTIONS AND INFORMATION ue 2. 10. Ns 12. Write your name on the ANSWER BOOK. This question paper consists of ELEVEN questions. Answer ALL the questions in the WER BOOK. Start H question on a NEW page in the ANSWER BOOK. Nu lhe answers correctly according to the numbering system used in this question paper. Leave ONE line between two subquestions, e.g. between QUESTION 2.1 and QUESTION 2.2. You may use a non-programmable calculator. You may use appropriate mathematical instruments. Show ALL formulae and substitutions in ALL calculations. Round off your FINAL numerical answer to a minimum of TWO decimal places. Give brief motivations, discussions, etc. where required. You are advised to use the attached DATA SHEETS. Write neatly and legibly. Copyright reserved Please turn over

Physical Sciences/P1 MDE/September 2023 Downloaded from Stanmonephysics. com QUESTION 1: MULTIPLE CHOICE QUESTIONS Various options are provided as possible answers to the following questions. Choose the answer and write only the letter (A-D) next to the question number (1.1 to 1.10) in the ANSWER BOOK, e.g. 1.11 D. Each question has only ONE correct answer. 11 Which O f the following groups of physical quantities are vectors? A eration, speed and velocity B Mass, distance and acceleration Cc Acceleration, force and velocity D Electric field, current and charge (2) 1.2 In which ONE of the following cases is the resultant force acting on an object equal to zero? A An object moving with constant acceleration. B When the only force acting on the object is the gravitational force. [o} An object undergoes equal displacements every second. D An object moving with increasing acceleration. (2) 1.3 Which ONE of the examples stated below best describes weightlessness? A An object accelerates downwards towards the Earth at an acceleration of 9,8 m.s®. B An object moving at a constant velocity upwards away from the ground. Cc An object moving at constant velocity downwards towards the ground. D An object that is accelerated upwards away from the ground by a constant applied force. (2) Naas Copyngit (oLorod Plodse lui over

; ’ MDE/September 2023 pmsiigamtiiided from Stanmoreghysics.com _ 1.4 The graph below indicates the net force exerted on an object over a period of time. a Fret (N) At(s) The area under the graph represents the .....of the object. A momentum B impulse Cc rate of change of momentum D acceleration (2) Copyright reserved Die Ploase turn ovel

Prysicddenoprnuaded from Stanmoreghysics.com MDE/September 2023 1.5 An object is dropped from a height, h, above the ground level. Ignore the effects of air resistance. Which ONE of the following graphs represents the relationship between kinetic energy, Ex, and the height, h, above the ground the BEST? Ex Ex (2) 1.6 Which ONE of the following describes the effect of the Doppler shift on the spectral lines if the star moves AWAY from the earth? The spectral lines... A shift to the red end of the spectrum. B shift to the blue end of the spectrum. Cc appear more dim. D show no change at all. (2) , Piedad lin aver Copyright reserved

1 . MDE/September 2023 PuRsWhloaded from Stanmorepaysics.com 1.7. Two identical charges are placed a distance r from each other in a vacuum. Charge Q1 experiences an electrostatic force F due to charge Qz. The charge on Q2 and the distance between the charges is changed. 5 —_——=} ae cS CT Cast! Which ONE of the following combinations will result in a force of 16 F exerted on Qi? Charge Q2 Distance r A Ye Qa 2r B 4Q2 Yer [e} 2Q2 Yer D 8Q2 2r (2) 1.8 Three identical bulbs are connected to a cell with internal resistance.The switch S is CLOSED as shown in the circuit diagram below. Switch S is now opened. Which ONE of the following gives the CORRECT changes observed on the ammeter and voltmeter? AMMETER READING VOLTMETER READING A Increases Increases B Increases Decreases Cc Decreases Decreases D Decreases a Increases (2) Copyright reserved Please turn over

PmpraWnteatld from Stanmorephiysics.com MDE/September 2023 1.9 In the graph below the solid curve shows how the emf produced by a simple generator changes with time. The broken curve shows the output of the same generator had been made to the generator. Which change has been made to result in the broken curve? A B c D Copyngi fevered The number of windings in the coil is doubled. The speed of rotation is doubled. A split ring commutator is added. The strength of the magnets is doubled. (2) Pladoe Niet ower

Physical Science: 1 B MDE/September 2023 ownloaded from Stanmorephygics.com ‘ 1.10 The diagram below shows the possible transitions of electrons between ENERGY LEVELS (E: to Es) in an atom of a specific element. Es E; Which transition will produce the line of the SHORTEST WAVELENGTH on the emission spectrum of the element? A Transition a B_ Transition b C_ Transition c D_ Transition d (2) [20] Copyright reserved Please turn over

PryParinweted from Stanmorephysics.com QUESTION 2 (Start on a new page.) MDE/September 2023 Block A with mass 4 kg, that is at rest on a rough horizontal table, is connected to another block B with mass 8 kg by a light inextensible string passing over a frictionless pulley. A force F; of itude 96 N is applied vertically upwards on block B as shown in the diagram belo’ Fi=96N 8kg A force Fz of magnitude 75 N is now applied at an angle of 25° with the horizontal on block A and the block accelerates to the left. The kinetic frictional force on block A is 11,76 N. Ignore the effects of air friction. 2.1 State Newton's Second Law of Motion in words. 2.2 Draw a labelled free-body diagram for block A. 2.3 Calculate the magnitude of the: 2.3.1 Acceleration of block A 2.3.2 Tension in the rope connected to block A Copyright reserved Please tum over (2) (5) (5) (2) [14]

Physi | sonlaects own , 10. loaded from Stanmorepisysics.com QUESTION 3 (Start on a new page.) The position-time graph for a ball thrown vertically downwards from the top of a 48 m MDE/September 2023 high building is shown below. The ball bounces off the ground, reaching a maximum (2) (4) (3) (3) height of 8 m. Ignore the effe air resistance and the contact time with the ground. The graph is not drawn to scal E c 2 = Q ok at eel cl renee alla em aebow a Time (s) 3.1 Explain what is meant by a projectile. 3.2 Calculate the speed with which the ball: 3.2.1 is thrown downwards 3.2.2 hits the ground 3.2.3. bounces upwards from the ground 3.3 Draw a velocity-time graph for the entire motion of the ball. Indicate the following on your graph: (i) initial wele which the ball was thrown the ball hits the ground ball to hits the ground hich the ball bounces off the grou (iii) time (iv) the Copyright reserved Please turn over (4) [16]

Prsi\SiMiedided from Stanmoreglhysics.com QUESTION 4 (Start on a new page.) MDE/September 2023 A tennis ball with a mass of 15,5 g strikes a stationary 8,45 kg block with a speed of 45 m:s"' and bounces straight back with a speed of 10,60 m-s‘'. The block moves 1,32 m to the right as indicated in the diagram below. 41 State the principle of conservation of linear momentum in words. 4.2 Calculate the magnitude of the: 4.2.1. Velocity of the block immediately after collision 4.2.2 Copyright reserved Frictional force between the block and the table if the block moves 1,32 m before coming to rest lz Please tum over (2) (4) (5) {11}

Ph 1 Sci s/PA ° MDE/September 2023 “Bownloaded from Stanmorepkysics.com = QUESTION 5 (Start on a new page.) A child with a mass 50 kg on a board mass 3 kg slides from rest down a sand dune. The sand dune has an angle of 30° with the horizontal and a height of 35 m. The coefficient iction between the board and the sand is 0,45. gat c 5.1 Define the term non-concervative force. (2) 5.2 Draw a labelled free-body diagram for the child and the board at point B. (3) 5.3 Calculate the frictional force that the child and the board experience as they (3) slide down the sand dune. 5.4 State the work-energy theorem in words. (2) 5.5 Calculate the final velocity that the child and board have when they reach (5) point B. [15] Cap yng teverved Plgase tun aver

Physical Sciences/P1 13 . MDE/September 2023 Downloaded from Stanmorephysics.com QUESTION 6 (Start on a new page.) A siren of a stationary train emits sound waves of a constant frequency of 780 Hz. A person in a car with a detector accelerates constantly from rest at point X towards the train. Take the speed of sound in air as 340 m:s"'. —_— —® —@e ; 83,11 m _____Y 6.1 Name the phenomenon that was observed by the listener. (1) 6.2 Calculate the wavelength of the emitted sound waves. (2) 6.3 Explain why the observed frequency is higher than the emitted frequency. (2) At point Y, 83,11 m from point X, the person in the car measures an observed frequency of 850 Hz. 6.4 Calculate the: 6.4.1 speed of the car at point Y (5) 6.4.2 acceleration of the car (3) [13] Copyright reserved Ploase tum over

prBowneaded from Stanmorephysics.com MOEN 2025 QUESTION 7 (Start on a new page.) Sphere N, with charge -30 UC, is placed on an isolated stand. Sphere M, with charge -20 uC hangs on an inextensible string from a horizontal beam and is a distance of 80 cm from sphere shown in the diagram below. 7.1. State Coulomb's Law in words. (2) 7.2 Drawa labelled free-body diagram for sphere M. (3) 7.3 Calculate the magnitude of the: 7.3.1 electrostatic force between the two spheres (3) 7.3.2 tension T in the string if the mass of sphere Mis 90 g (4) [12] Copyright reserved Please tur over

ees nc MDE/September 2023 Bownloaded from Stanmorephysics. com — QUESTION 8 (Start on a new page.) Two small spheres, A with a charge of +5 nC and B with a charge of-4 nC respectively, are placed a certain distance from each other in a vacuum as shown in the diagram below. A +5 nC -4nCc 8.1 Define the term electric field in words. (2) 8.2 Draw the electric field pattern between spheres A and B. (3) P is a point LEFT of spheres A and B. Point P is at a distance r from sphere A and sphere A is at a distance 3r from sphere B as shown in the diagram below. The net electric field at point P is 4128 N-C*' west. N P B ee ae | nk ce ry wel> E +5 nC -4nc S 8.3 Calculate the value of r. (6) (14) , Copying (euerved Plodae lun ower

phaweieaded from Stanmorephysics.com MDE/September 2023 NSC QUESTION 9 (Start on a new page.) A battery with an internal resistance of 0,5 Q and emf (€) of 24 V is connected to four resistors , a closed switch, a high resistance voltmeter(V) with 22,3 V and ammeter of negligible resi ce, as shown in the diagram below. The resistan the connecting wires must be ignored. Ss 30 9.4 Explain the term emf of 24 V with reference to work done. (2) 9.2 Calculate the: 9.2.1 Current in the 3 Q resistor (3) 9.2.2 Power dissipated in the 18 Q resistor (5) 9.2.3 Current in resistor R (4) Resistor R_ is removed from the circuit. 9.3 Will the power dissipated in the 18 Q resistor INCREASE, DECREASE or REMAIN THE SAME? Explain the answer. (3) (17) Copyngil teberved Vischoet TH wens

Physical Sciences/P1 17 Downloaded from Stanmore}tiysics.com QUESTION 10 (Start on a new page.) MDE/September 2023 The simplified diagram below represents an alternating current (AC) generator. 10.1 Write down the energy conversion that occurs in an AC generator. (2) 10.2 Which structural change must be done to the components of the AC generator (1) to change it into a DC generator? A3 Q resistor is connected to the AC generator. 10.3 Calculate the maximum current that flows through the resistor if the resistor has an average power of 100 W. (5) (8] Copyright teveryod Hladae Wit aver

Physhapedoaditd from Stanmorepltysics.com MDE/September 2023 QUESTION 11 (Start on a new page.) Learners conduct an experiment to investigate the photoelectric effect.Metal disc M is irradiated with three light sources of different wavelengths and the results obtained are noted in the ew Light length | Emission of photoelectrons source ‘8 m) A 77480 Photoelectrons emitted that move away from metal B 620 No photoelectrons emitted ¢ 570 Photoelectrons emitted and do NOT move away from metal 141.1 Define the term work function in words. (2) 11.2 Explain why light source A releases photoelectrons from the metal disc M, but not light source B. (2) 11.3. Calculate the: 11.3.1 Work function of metal M (3) 11.3.2 Speed with which the photoelectrons are moving if metal disc M is (5) irradiated with light source A 11.4 Light source Ais BLUE light and light source B is ORANGE light. Which colour of light is light source C? Choose between VIOLET, GREEN or RED. (1) [13] TOTAL:150 Copynigit revered Ploase tum over

Physical Sciences/P1 Downloaded from Stanmorephysics.com 19 MDE/September 2023 DATA FOR PHYSICAL SCIENCES GRADE 12 PAPER 1 (PHYSICS) GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12 VRAESTEL 1 (FISIKA) TABLE 1: PaeaPAL CONSTANTS/TABEL 1: FISIESE KONSTANTES NAME/NAAM SYMBOL/SIMBOOL | VALUE/WAARDE Unherooe iraviasiohonstan Rar nto Nae ha" Cocke bs wrestle : Serene bedi co. menen : =e oatmeal Me 9,11 x 10°" kg Padlus van die Aarde Pe sala Lagi fopetved Mleoe lit aver

Physical WiaaeY from Stanmorepitysics.com MDE/September 2023 TABLE 2: FORMULAE/TABEL 2: FORMULES MOTION/BEWEGING vy =v, +aapaal Ax=v,At+tadt® or/of Ay =v At+taat? . v, +V itv, at we +2 oot v? =v! + 2aty Ax = ( 1 +a or/of Ay = (“st 2 seat FORCE/KRAG Fret = Ma p=mv iO =pN f,_ =1,N F,,At=Ap w=mg Ap =mv, — mv, F= ot oof =F= qe g -a4 or/of g wigs. 5 r WORK, ENERGY AND POWER/ARBEID, ENERGIE EN DRYWING W-=Faxcos@ U=mgh oof E,=mgh Wrer =AK —orfof Wye, = AE, K=3mv? oof =E, =3mv AK=K,-K, Orof AE, =E,, -E, Ww W,. =AK+AU or/of W,, = AE, + AE, pas Pos = FV sve / Poemis * FV cemis WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG vat, Ts —i4 viv, viv, {, oof {,=~2“44, |E=ht orf Eq vt b f,= E=W, +E yay) offof E = W, +K,,,, where/waar unas) mae ka mas E=ht and/en W, =hf, and/en E - Snvi or/of K,. = ala Copy fevered Ploase lin over

Physical Sciences/P1 21 Downloaded from Stanmorephysics.com ELECTROSTATICS/ELEKTROSTATIKA ve q Fevey n= n= 2 = e Q ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE emf (£) = I(R+1) R=~ emk (£) = I(R +r) R, =R, +R, + R, R, R, w-Vq Paw At W-VIAt P=VI W=FPRAt vi P =I'R =-— 2 = po R ALTERNATING CURRENT/WISSELSTROOM I , Pee =Veslims Poems = Var Ly Jing = / Vgk = maks v2 2 TPA! Pr = ER V, V, Ving == / Vi, =—ms. 2 2 2 mb Pet iP - Copyright reverved MDE/September 2023

Downloaded from Stanmorephysics.com education DEPARTMENT: EDUCATION MPUMALANGA PROVINCE NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) SEPTEMBER 2023 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 These marking guideline consists of 14 pages Hierdie nasienriglyne bestaan uit 14 bladsye Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physoowiealeondad wheekapstanmorephysics.com ——_ mpu/september 2023 NSC/NSS-Marking Guideline/Nasienriglyn QUESTION 1 / VRAAG 1 11. Cvv (2) 12 Cvv (2) 13° Avv (2) 14. BYv (2) 15 Dvv (2) 16 Avy (2) 17 Byv (2) 18 Cvv (2) 19 BYv (2) 1.10 Dvv (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physluosaalegrdiad weteerapstanmorephysics. com MPU/September 2023 NSC/NSS-Marking Guideline/Nasienriglyn QUESTION 2/ VRAAG 2 2A 22 Copyright reserved/Kopiereg voorbehou Marking criteria/Nasienkriteria If any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /indien enige van die onderstreepte sleutelwoorde/frases in die korrektejkonteks uitgelaat is, trek 1 punt af. When a netforce acts on an object, the object will accelerate in the direction of Sand the acceleration is directly proportional to the resultant/net force 'sély proportional to the mass of the object. vv Wanneee-n resulterende/netto krag op 'n voorwerp inwerk, versnel die voorwerp in die rigting van die krag teen 'n versnelling direk eweredig aan die resultante/netto_krag en omgekeerd eweredig aan die massa van die voorwerp. OR/OF The resultant/net force acting on an object is equal to the rate of change of momentum of the object. (2 or 0) Die resulterende/netto krag wat op ‘n voorwerp inwerk is gelyk aan die tempo van verandering van momentum. (2 of 0) Fv a Tv fv wv Accepted labels / Aanvaarde benoemings w Fg / Fw/ force of earth on block / weight / mg / gravitational force / VALUE F Fapplied / Fa / Applied force T Tension in rope / Fr F Firiction / Fr / frictional force / N Normal force / Fn Notes/Aantekeninge: e Mark awarded for label and arrow. e Any additional forces: deduct 1 mark: max She e No labels: deduct 1 mark: max4/. e If everything correct, but no arrows: deduct 1 mark: 4/, e Force(s) not touching object: deduct 1 mark: max 4/5 e Ignore relative sizes of the vectors (2) (5) Please turn over/Blaai om asseblief

Physlosatalegndiad whteesxapstanmorephysics.com 2.3.1 2.3.2 NSC/NSS-Marking Guideline/Nasienriglyn MPU/September 2023 Marking criteria/Nasienkriteria: e Formula for block A or block B ¥ e Substitution of Fnet for block A v e Substitusion of Fnet for block B v For Block B: Fnet =. mat, Fnet = ma eS noe a anyone fee) = ma (75)cos25 —T — 11,76 Vv = 4a v 18,4 + T-96 v= 8a 56,21 -T =4a T -17,6=8a T =-4a +56,21 T=8a+17,6 - -4a + 56,21 = 8a+ 17,6 12a = 38,61 a=3,22ms?v POSITIVE MARKING FROM QUESTION 2.3.1 Marking criteria/Nasienkriteria: e Substitution to calculate T ¥ e Answer v For Block A: For Block B: T = -4a +56,21 T =8a+ 17,6 = (-4)(3,22) + 56,21 v = (8)(3,22) + 17,6 = 43,33 NV = 43,36 N QUESTION 3/ VRAAG 3 3.1 3.2.1 Copyright reserved/Kopiereg voorbehou An object which has been given an initial velocity and then it moves under the influence of the gravitational force only. ¥ Y (2 or 0) 'n Voorwerp waaraan 'n beginsnelheid gegee is en wat dan slegs onder die invioed van die gravitasiekrag beweeg. (2 or 0) Upwards positive/ Downwards positive/ Opwaarts positief: Afwaarts positief: Ay = viAt + Yalt? v Ay = viAt + “alt -48 v = vi(2,8) + % (-9,8)(2.8)? v vi = -3,42 vi = 3,42 m-s? v (5) (2) [14] (2) (4) Please turn over/Blaai om asseblief

Physlosatalegndiad wheesxapstanmorephysics.com MPU/September 2023 NSC/NSS-Marking Guideline/Nasienriglyn 3.2.2 | POSITIVE MARKING FROM QUESTION 3.2.1 POSITIEWE NASIEN VANAF VRAAG 3.2.1 Upwards Positive/ Opwaarts positief OPTION 1 Upwards Positive/ Downwards Positive/ Opwaarts-positief Afwaarts positief Vr = vi taAby v= vi ta At ¥ ve = -3 vr = 3,42 + (9,8)(2,8) Vv v= -30,86)m-s"! Vr = 30,861m-s! Vv vr = 30,86 ms? ¥ OPTION 2 Downwards Positive/ Afwaarts positief ve = vi? + 2a Ay ¥ ve? = (3,42)? + 2(9,8)(48) ¥ vi = 30,86 m-s? v OPTION 3 Upwards Positive/ Opwaarts positief +y; Ax= ele Atv - 3,42 -48= —_— 2,8 V vr = -30,87 m-s* vr = 30,87 ms? v Downwards Positive/ Afwaarts positief VEtV; ( f ) at + 3,42 4g= 34), 3 v vr = 30,87 m-s? ¥ OPTION 4 (Em)a = (Em)B Anyone Vv (mgh + Yamv2)a = (mgh +% mv2)e Enige een m(9,8)(48) + % m(3,42)? = 0 + “mv? ¥ v = 30.86 mst v 9,8)(2,9) = vi— 3,42 v v = 30.86 ms? v OPTION 5 Fret At = Ap Fret-At = mvs — mvi Anyone ¥ mgAt = mvr— mvi Enige een gAt= w—-vi (3) 3.2.3 | Upwards positive / Opwaarts positief ve = vi? + 2a Ay ¥ 0 = vi? + 2(-9,8)(8)” vi= 12,52 m-s'¥ Downwards posi Afwaarts positie’ ve = vi2 + 2a Ay 0 = v2 + 2(9,8)(-8): vi= 12,52 m-s1v (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physoowienlegndad wheekapstanmorephysics.com —— mpu/september 2023 NSC/NSS-Marking Guideline/Nasienriglyn 3.3. | Marking criteria/Nasienkriteria: e Initial velocity with which the ball was thrown (3.2.1) “ e Beginsnelheid waarmee bal gegooi is e Final velocity with which the ball hit the ground (3.2.2) Vv e Ejndsnelheid waarmee die bal die grond tref ° Time taken to hit the ground (2,8 s)” ¢ Tydjom die grond te tref (2,8 s) . The velocity with which the ball bounces off the ground — line parallel to “other line (3.2.3) v e Die snelheid waarmee die bal van die grond as bons — lyn parallel met ander lyn POSITIVE MARKING FROM/POSITIEWE MERK VANAF 3.2.1., 3.2.2 & 3.2.3 UPWARDS POSITIVE/OPWAARTS POSITIEF 12,52 /------------------ At (s) V (ms) -3,42 -30,86 DOWNWARDS POSITIVE/AFWAARTS POSITIEF 30,86 3,42 V (m-s*) i=} -12,52 ‘ (4) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physoowealegrdiad wheekapstanmorephysics.com —— mpu/September 2023 NSC/NSS-Marking Guideline/Nasienriglyn QUESTION 4/ VRAAG 4 4.1 Marking criteria/Nasienkriteria If any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. The total{linear) momentum of an isolated/closed system remains constant/is Die totaléi(lineére) momentum in 'n geisoleerde sisteem bly konstant/behoue. = (2) 4.2.1 | TAKE TO THE LEFT AS POSITIVE/NEEM LINKS AS POSITIEF Zpi = Zpr (mvi)1 + (mvi)2 = (mvs)1 + (mvs)2 (0,015)(-45) + (8,45)(0) v = (0,015)(10,60) + (8,45)(vr) v v=-0,10 ms v=0,10 mst ¥ TAKE TO THE RIGHT AS POSITIVE/NEEM REGS AS POSITIEF Zpi = Zpr (mvi)1 + (mvi)2 = (mve)1 + (mve)2 (0,015)(45) + (8,45)(0) v = (0,015)(-10,60) + (8,45)(vs) ¥ v= 0,10 ms? ¥ (4) } v Any one/enige een v Any one/enige een 4.2.2 | POSITIVE MARKING FROM QUESTION 4.2.1 OPTION 1 ve = vit + 2a Ay 02 v= (0.10)? + 2(a)(1,32)¥ a =-0,00378 m-s? (a= -3,79 x10 m-s*) Fret = mav f = (8,45)( - 0,00378) v f=0,03 Nv POSITIVE MARKING FROM QUESTION 4.2.1 OPTION 2 ve = vi? + 2a Ay 0? = (0.10)? + 2(a)(1,32)” a =-0,00378 m:s? (a= -3,79 x10 m-s*) ve =vita At 0 = 0,10 + (- 0,00378) At At = 26,39 sv Fret-At = mv — mvi ¥ (26.39) = (8,45)(0) — (8,45)(0,10) v f=-0,03N f =0,03 Nv (5) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physlowatalemndiad whteexapstanmorephysics.com NSC/NSS-Marking Guideline/Nasienriglyn QUESTION 5/ VRAAG 5 5.1 5.2 5.3 5.4 5.5 Copyright reserved/Kopiereg voorbehou MPU/September 2023 Marking criteria/Nasienkriteria If any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /Indien enige van die onderstreepte sleutelwgorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. A force forwhich the work done in moving an object between two points depends‘on the path takenv v ‘n Krag-waarvoor die arbeid verrig om 'n_voorwerp tussen twee punte te beweeg, afhanklik is van die roete wat gevolg word. Nv fv wv Accepted labels / Aanvaarde benoemings w Fg / Fw/ force of earth on block / weight / mg / gravitational force / f Firiction / Fr / frictional force N Normal force / Fn fk = pxN ¥ N= Fot = (0,45)(449,81) v = (53)(9,8)cos30° = 202,42 Nv = 449,81 N Marking criteria/Nasienkriteria If any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. The net work done on an object is equal to the change in kinetic energy of the object. vv Die netto arbeid verrig op 'n voorwerp is gelyk aan die verandering in kinetiese energie van die voorwerp OF die arbeid verrig op die voorwerp deur 'n netto krag is gelyk aan die verandering in kinetiese energie van die voorwerp. POSITIVE MARKING FROM Q5.3 OPTION 1 Whet = AEx fAxcosQ + NAxcosO + FgAxcosO = Yamvi*? — Ymvi2 ¢ (202,42)(35)cos180°V + 0 + (53)(9.8)(35)cos60° Vv = %4(53)v"? VY —0 ve = 8,70 mst ¥ (2) (3) (3) (2) Please turn over/Blaai om asseblief

Physloowienlegndad wheekapstanmorephysics.com ——_ mpu/September 2023 NSC/NSS-Marking Guideline/Nasienriglyn OPTION 2 Whe = AEk + AEp } Any one Y fAx cosO= [Yamvi* — Yamvi? ]+ [mghr— mghi] (202,42)(35)cos180°v = [74(53) vi v— 0] +[(53)(9,8)(17,5) — (53)(9,8)(35)1” v= 8,70m-s" ¥ (5) [15] QUESTION 6 G6 6.1 Doppler effect / effek (1) 6.2 v=fA 340 = 780A Vv A=0,44mv (2) 6.3. Waves in front of source are more compact/ wavelength decreases Vv More waves per second reaches the listener v Golwe voor die bron is meer kompak/ golflengte neem af Meer golwe per sekonde bereik die luisteraar (2) 6.4.1 VEVL v ape as =—_ f= aagis” OR f= cfs 340 + vy v=( ———_ Vv v 850 34040 780 v_ = 30,51 ms! ¥ (5) 6.4.2 vi = vit + 2aAy Vv (30,51) = 0? + 2a (83,11) ¥ a=5,60 ms? v (3) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physluosaalegrdiad whteerapStanmorepiysics. com MPU/September 2023 NSC/NSS-Marking Guideline/Nasienriglyn QUESTION 7 / VRAAG 7 Tal 7.2 Copyright reserved/Kopiereg voorbehou Marking criteria/Nasienkriteria If any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /indien enige van die onderstreepte sleuteloGrde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. Not itmasses used ( %, ) The magnitude of the electrostatic force exerted by one point charge (Q,) on another point charge (Q,) is directly proportional to the product of the magnitudes of the charges Y and inversely proportional to the square of the distance (r) between them v Die grootte van die elektrostatiese krag wat een puntlading (Q,) op 'n ander puntlading (Q,) uitoefen, is direk eweredig aan die produk van die groottes van die ladings v en omgekeerd eweredig aan die kwadraat van die afstand (r) tussen hulle. ¥ Tv Fe v Fg v Accepted labels / Aanvaarde benoemings Ww Fg / Fw/ force of earth on block / weight / mg / gravitational force / 0,392 N Fe Electrostatic force T Tension in rope / Fr Notes/Aantekeninge: e Any additional forces: deduct 1 mark: max 2/5 ¢ No labels: deduct 1 mark: max 2h, * No arrows: 9/, e Force(s) not touching object: deduct 1 mark: max 2/3 e Ignore relative sizes of the vectors (2) (3) Please turn over/Blaai om asseblief

Physioowienleondad wheekapstanmorephysics.com —— mpu/september 2023 NSC/NSS-Marking Guideline/Nasienriglyn 7334 R= rev _(ox0?) (30 x 10°) 20 x 10°) agp O87 F=8 al (8,4375 N) 7.3.2 | Fg = — = (0,09)(9,8) = 0,882 Nv T2=Fe2 + Fg? v = (8,44)? + (0,882 v T=8,49NV QUESTION 8 / VRAAG 8 8.1 Marking criteria/Nasienriglyne: -1 mark for each of the 3 key words omitted in the correct context. -1 punt vir elk van die 3 sleutelwoorde weggelaat in die korrekte konteks. The electric field is an area in space where an electric charge experiences a force. vv Die elektriese veld is ‘n gebied in die ruimte waarin ‘n elektriese lading ‘n krag ondervind 8.2 Criteria for sketch/Kriteria vir skets Marks/Punte Correct shape as shown. v Korrekte vorm soos getoon. 1 Direction away from positive to negative. v Rigting weg van positief na negatief. Field lines start on spheres and do not cross for correct al v diagram. Veldlyne begin op elke sfeer en kruis nie vir korrekte diagram. (3) (4) [12] (2) (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physoowienlegndad wheekapstanmorephysics.com —— mpu/september 2023 NSC/NSS-Marking Guideline/Nasienriglyn 83 | Ene =E, + E> Enet = “2 - "ev (Mark for/Punt vir ~) 9 9 9 -9 CRD 9x107)(5x10 dy _ vy Gxi0 )(4x10 dy 1 (4r)? 4128 = — = 72 Tort r =0,10m¥ (6) [11] QUESTION 9/ VRAAG 9 9.1 24 Joule” per unit coulomb charge work done. ¥ Arbeid van 24 Joule per eenheid coulomb lading (2) 2. lost V 9.2.1 = es y I= 24-223 0,5 =3,4 AY (3) 9.2.2 | POSITIVE MARKING FROM Q9.2.1 V30=IR Paen= ve re = 3,4(3) ¥ 180° R =10,2V (12.17 Pagn=— 3 Vi = 22,3- 10,2 v _ 18 =12,1V = 8,314 W¥ (5) 9.2.3 POSITIVE MARKING FROM Q9.2.1 & Q9.2.2 Vv Vv loo= RY hen=R - 12,1 y - 124 18 =2,02A =0,67A IR = ltot - Ten - ga = 3,4 — 2,02 -0,67 =0,71AV (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physioowinlegdiedwheekapstanmorephysics.com —— mpu/september 2023 NSC/NSS-Marking Guideline/Nasienriglyn 9.3 Increase ¥ R (18Q) remains constant, Viincreases v Current in circuit decreases P=zVv QUESTION 10/VRAAG 10 10.1. Kinetic/mechanical energy TO electrical energyY V Kinetiese/meganiese energie NA elektriese energie 10.2 — Slip rings (AC) and split rings (DC)” Sleepringe (WS) en splitringe (GS) (3) [17] (2) (1) 10.3 {OPTION 4 OPTION 2 Pave= Fak v Pave= sR v 100= I245(3)” Tmax v= v v lime = 577A ava Imax = 8,16AY Tax v lee = rms V2 577 = Tmax v Imax = 8,16AY (5) QUESTION 11 / VRAAG 11 11.1 Marking criteria/Nasienkriteria If any one of the underlined key words/phrases in the correct context is omitted, deduct 1 mark. /Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af. The minimum energy that an electron in the metal needs to be emitted from the metal surface. vv Die minimum energie benodig om 'n elektron uit die opperviak van 'n metaal vry te stel.. 11.2. Light source A — higher frequency than fo ~ OR Light source B — lower frequency than fo Ligbron A — hoér frekwensie as fo i OF Ligbron B — laer frekwensie as fo fact Wavelength 4 7 Golflengte a F [8] (2) (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

Physlsoutalemdiad wheesapstanmorephysics.com MPU/September 2023 NSC/NSS-Marking Guideline/Nasienriglyn 11.3.1 (3) 11.3.2 | POSITIVE MARKING FROM 11.3.1 E = Wot Ex(max)” “ = Wo + “mv? 334 8, WY =(3,489x107)v + %4(9,11%10°" yvev 10°m-st v (5) 11.4 Green/Groenv (1) [13] Copyright reserved/Kopiereg voorbehou TOTALITOTAAL: 150

Downloaded from Stanmorephysics.com education ) DEPARTMENT: EDUCATION MPUMALANGA PROVINCE ERRATA PHYISCAL SCIENCES 2023 GRADE 12 TRIAL PAPER 1 Question | Correction 1.5 Answer is A 55) Q5.5 should not be marked; statement was in complete. BASED ON Q5.5 ABOVE THE TOTAL OF THE PAPER IS NOW 145 MARKS