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Physical Sciences Grade 12 Paper 2 MP Mock 2023 Paper & Memo
Grade 12 Physical Sciences Paper 2 question paper and memo from the MP Mock Exam 2023, 31 pages. Read online or get the free PDF download.
Physical Sciences · Grade 12 · MP Mock Exam · 2023. Question paper and memorandum, 31 pages. Read online or download the PDF.
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- Physical Sciences
- Grade
- Grade 12
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- Question paper and memo
- Year
- 2023
- Exam period
- MP Mock Exam
- Paper
- 2
- Curriculum
- CAPS
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- 31
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- 6.9 MB
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Physical Sciences/P2 3 MDE/September 2023
NSC
QUESTION 1: MULTIPLE-CHOICE QUESTIONS
Four options are provided as possible answers to the following questions. Each
questi is only ONE correct answer. Choose the answer and write only the
letter ) next to the question number (1.1 — 1.10) in the ANSWER BOOK, for
exam Pc 9
1.1 ich ONE of the following organic condensed structures is
2,3-dimethylpentane?
A (CH3)3CCH(CHs)2
B (CH3)2CHCH2CH(CHs)2
Cc CHsCH2C(CHs)2CH2CHs
D (CHs)2CHCH(CH3)CH2CH3 (2)
1.2 The boiling points of branched alkanes are lower than those of straight
chain alkanes containing the same number of carbon atoms because
branched alkane chains have ...
A larger molecular mass.
B longer chain lengths.
Cc smaller effective molecular surface areas.
D more electrons. (2)
1.3. Consider the reaction given below.
CHs(CH2)4CH3s + CH3sCHCH2 + H2 + Z
Which ONE of the following combinations correctly identifies the type of
reaction that takes place and the IUPAC name of product Z?
TYPE OF -
REACTION
A Addition Propane
B Addition Propene
Cc Elimination Propane
D Elimination Propene (2)
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Physical Sciences/P2 MDE/September 2023
1.4
1.5
Nsc
Consider the graphs A and B below. Graph A shows the potential energy
curve for the same reaction.
G B shows the distribution of molecular energy. X represents the
um kinetic energy needed for a reaction to take place.
Graph A Graph B
Number of
molecules
* Xx
Course of reaction Kinetic energy
Which of the following will be the correct value for X in graph B?
A 103 kJ
B 93 kJ
Cc 35 kJ
D 10 kJ (2)
Consider the following hypothetical reaction taking place in a container that
has a fixed volume:
Asa(g) + Ba(g) = 3AB(g) AH<0O
The temperature of the system is doubled. Which ONE of the following
combinations correctly indicates the change in the NUMBER OF MOLES
of As(g) and the TOTAL MASS in the container?
NUMBER OF MOLES OF TOTAL MASS IN
A3(g) CONTAINER?
A Decreases Increasgaal
B Increases Decrea;
Cc Increases Remains constant
D Decreases Remains constant (2)
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Physical Sciences/P2 MDE/September 2023
Nec
1.6 The following reversible reaction reaches equilibrium in a closed container:
He(g) + la(g) = 2HI(g) AH <0
equilibrium was first established after 5 minutes. (The broken line on
raph represents the reverse reaction.)
a
Rate of reaction
>
5 10 Time (minutes)
What possible change could have been made to the reaction conditions at
t= 10 minutes?
A The concentration of H2 increases
B The temperature was increased
Cc The temperature was decreased
D The external pressure on the reaction mixture was increased. (2)
1.7. Chlorine gas, C£2(g), is used to disinfect water in public swimming pools.
Cfa(g) reacts with water, H2O(t) according to the following balanced
equation.
Clg) + H20(f), + HOCK(aq) + HCt(aq)
The addition of Cf2(g) changes the pH of water in the swimming pools.
Which ONE of the following substances must be add: public swimming
pools periodically to increase the pH?
A NazCO3
B NH4Ct
Cc H2SO4
D KCL (2)
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NSC
1.8 The following equations represent two hypothetical half-reactions.
Which ONE of the following substances from these hypothetical
half-reactions will be the strongest oxidising agent?
X2+ 2e = 2X +1,09V
Yrte HY -2,8V
A x
B X2
Cc x
D ¥. (2)
1.9 Which of the following combinations CORRECTLY shows the products
formed during the electrolysis of concentrated sodium chloride?
ANODE CATHODE
A | Chlorine Hydrogen
B Hydrogen Oxygen
C_ | Chlorine Oxygen
D_ | Hydrogen Chlorine (2)
1.10 Which ONE of the following equations is spontaneous?
A Zn(s) — Zn?*(aq) + Mg(s)
B u(s) + Cu?*(aq) + Mg(s)
Cc Cu?*(aq) + 2Ag(s) — 2Ag*(aq) + Cu(s)
D 2Ag*(aq) + Pb(s) — Pb?*(aq) + 2Ag(s) (2)
[20]
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Physical Sciences/P2 7 MDE/September 2023
NSC
QUESTION 2 (Start on a new page.)
Compound A and B are hydrocarbons.
A B
CH, CH,
3-ethyl-2,5-dimethylheptane
3c-——CH—CH,—C—CH,
2.1. Define the underlined term. (1)
2.2 Write down the:
2.2.1. IUPAC name of compound A. (3)
2.2.2 GENERAL FORMULA of the homologous series to which
compound A belongs. (1)
2.2.3. The STRUCTURAL FORMULA of compound B (3)
2.2.4 NAME of the solution that can be used in the laboratory to test
whether compound A and B are saturated or unsaturated. (1)
2.3. Consider the following compound: CHsCH2CH2CHO
Write down the:
2.3.1. Homologous series to which this compound belongs? (1)
2.3.2 NAME of the functional group. (1)
2.3.3. IUPAC name of the CHAIN isomer for this compound. (2)
2.3.4 STRUCTURAL FORMULA of the FUNCTIONAL isomer for this
compound. (2)
2.4 Consider the compound below:
(CH3)2C(OH)CH2CH2CH3
2.4.1 Write down the IUPAC name of this compound (2)
2.4.2 Is the compound a PRIMARY, SECOND, R TERTIARY
alcohol. Give a reason for the answer. (2)
[19]
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Physical Sciences/P2 MDE/September 2023
NSC
QUESTION 3 (Start on a new page.)
Four compounds (A to D) are used to investigate factors affecting the melting
points. The results obtained are shown in the table below.
3.1
3.2
3.3
3.4
COMPOUNDS ek ial
A_ | Propane -188
B_ | Butane -138
C | Butanal -96,9
D_ | Butan-1-ol -89,8
Define the term melting point. (2)
The melting points of compounds A and B are compared.
3.2.1 Write down the independent variable for this investigation. (1)
3.2.2 Explain the difference in the melting points of these two
compounds. (3)
Which ONE of the compounds B, C or D has the lowest vapour pressure?
Explain the answer (2)
The melting points of compounds C and D are now compared.
3.4.1. Which variable must be kept constant in this experiment? (1)
3.4.2 Refer to the TYPES of intermolecular forces to explain the
difference in melting points between compound C and D. (4)
[13]
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ciences: MDE/September 2023
NSC
QUESTION 4 (Start on a new page.)
Study the flow diagram of organic reactions below and answer the questions that
follow. The letters X, Y and Z represent organic compounds and letters A to E
represe: lanic reactions.
Compound Z
C4Hi0
HCOOH
Reaction B Reaction E
Compound X ra But-1-ene }——————_»| Compound Y
41
4.2
4.3
44
45
4.6
Reaction A Reaction C
Reaction D |
Write down the type of addition reactions that take place in:
4.1.1 ReactionA (1)
4.1.2 Reaction B (1)
4.1.3 Reaction C (1)
For reaction D, write down:
4.2.1 The type of reaction that takes place. (1)
4.2.2 TWO reaction conditions necessary for the reaction to occur. (2)
4.2.3 The INORGANIC product that is formed. (1)
Give the FORMULA of the catalyst required for reaction B (1)
Write down a balanced chemical equation using CONDENSED
STRUCTURAL FORMULAE for reaction A. Compound X is the main
product. (3)
To which homologous series does compound Y belon (1)
For reaction E, write down the:
4.6.1. NAME of the type of reaction (1)
4.6.2 IUPAC name of compound Z. (2)
[15]
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Physical Sciences/P2 MDE/September 2023
NSC
QUESTION 5 (Start on a new page.)
The reaction between zinc, Zn(s), with EXCESS dilute hydrochloric acid, HCf(aq),
is used to i tigate factors that affect the rate of a reaction.
The balan quation for the reaction is:
Zn(s) + 2HC&(aq) — ZnCfo(aq) + H2(g)
The apparatus used is illustrated below.
Cotton wool plug -—————>
Dilute hydrochloric acid Gas bubbles
Zinc granules
Balance
5.1. Define the term reaction rate. (2)
5.2 What is the function of the cotton plug? (1)
A summary of the conditions used in EXPERIMENT 1 and 2 is given in the table
below.
EXPERIMENT | MASS be TEMPERATURE STATE OF
(Zn) 3 (°C) DIVISION
(cm*)
x 150 30 Granules
2 x 150 30 Powder
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Physical Sciences/P2 1
MDE/September 2023
NSC
The change in mass of zinc is calculated and recorded in 3-minute intervals
for both experiments. The results obtained are shown in the graph below
(NOT drawn to scale).
Mass of zinc
° Time (minute) . la
5.3. Use the information in the graph to answer the following questions:
5.3.1
5.3.2
Which graph A or B represents EXPERIMENT 2? (1)
Calculate the number of moles of hydrochloric acid that reacted
from t = 3 minutes to t = 12 minutes in the experiment that is
represented by graph A. (4)
5.4 Calculate the initial mass of zinc used if the average rate of formation of
hydrogen gas, in the experiment represented by graph B, is
2,5 x 104 mol-s™. (5)
5.5 A third experiment (EXPERIMENT 3) is carried out by changing only one
conditi
ion in EXPERIMENT 1. Two energy distribution curves for the
reaction in EXPERIMENTS 1 and 3 are shown in the graph below.
Number of
molecules
5.5.1
$5.2
EXPERIMENT 1
a! EXP. ENT 3
Ex
What change was made to the reacti nditions in
EXPERIMENT 1 to obtain the results of EXPERIMENT 3? (1)
Use the collision theory to explain how the change mentioned in
QUESTION 5.5.1 affects the reaction rate. (4)
[18]
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Physical Sciences/P2 12 MDE/September 2023
NSC
QUESTION 6 (Start on a new page.)
A certain amount of sulphur and 0,3 mol oxygen gas are sealed in a container at
340°C. TI action reaches EQUILIBRIUM according to the following balanced
equation
S(s) + O2(g) = SO2(g)
6.1. Define the term chemical equilibrium. (2)
6.2 Howwill each of the following changes affect the yield of SO2(g)?
Write down only INCREASES, DECREASES or REMAINS THE SAME.
6.2.1 More Sulphur is added to the container. (1)
6.2.2 The pressure is increased by decreasing the volume of the
container at constant temperature. (1)
6.3. It is found that the equilibrium constant (Kc) increases when the
temperature is increased. Is the forward reaction EXOTHERMIC or
ENDOTHERMIC? Fully explain the answer. (3)
6.4 How will the addition of a catalyst Influence the equilibrium constant (Kc)
of this reaction? Write down only INCREASES, DECREASES or REMAINS
THE SAME. (1)
6.5 The graph below, not drawn to scale, shows how the amount of S(s) in the
container changes with time at 340 °C.
10,7
Mass (g)
8,1
Time (minutes)
6.5.1 Equilibrium is reached at 340 °C. Calcu the equilibrium
constant, Ke, at this temperature. The volu the container is
500 cm. (9)
6.5.2 Determine the Kc value for the reverse reaction. (2)
[19]
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NSC
QUESTION 7 (Start on a new page.)
7.1. The dissociation constant of some substances is given in the table below:
Name of substance Formula Ka (298 K)
Hydrogen sulphate ion HSO, 1,2 x 102
Ammonium ion NHz 5,6 x 107°
Hydrocyanic acid HCN 4,9 x 10°7°
7.1.1. Write down the NAME or FORMULA of the substance that has the
highest tendency to dissociate. Give a reason for the answer. (2)
7.1.2 Write down the FORMULAE of the conjugate bases of hydrogen
sulphate ion and hydrocyanic acid. (2)
7.2 To determine the percentage purity of a sample of oxalic acid (H2C20s).
The three steps below are followed:
Step 1: A standard solution of sodium hydroxide, NaOH(aq), is prepared
by adding 50 cm? of NaOH(aq) of concentration 0,63 mol-dm® in
950 cmé of water.
Step 2: Animpure sample of oxalic acid solution, H2C2O4(aq), is prepared
by dissolving 0,25 g in 75 cm of water.
Step 3: The H2C2Oa(aq) solution is titrated with the standard NaOH(aq).
During the titration, 40 cm* of the NaOH(aq) is needed to neutralise 50 cm*
of the impure H2C204(aq).
The equation for the reaction is:
2NaOH(aq) + H2C204(aq) + NazC20a(aq) + 2H20(£)
7.2.1 Define the endpoint of a titration. (2)
7.2.2 Calculate the concentration of the standard NaOH solution. (3)
7.2.3 Calculate the percentage purity of the oxalic acid.sample. (6)
7.3 Sodium ethanoate solid, CH3COONa(s), undergoes hy! is in solution.
7.3.1 Define the term hydrolysis. ; (2)
7.3.2 How will the pH of the solution be affected by the hydrolysis of
CHsCOONa(s)? Choose from INCREASES, DECREASES or
REMAINS THE SAME. Use a balanced equation to explain the
answer. (4)
[21]
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Physical Sciences/P2 14 MDE/September 2023
NSC
QUESTION 8 (Start on a new page.)
The reaction between magnesium and copper(Il)nitrate is used to set up an
electroch | cell under standard conditions. A balanced equation of the rection
is given bi
8.1
8.2
8.3
8.4
Mg(s) + Cu(NOs)2(aq) + Mg(NOs)2(aq) + Cu(s)
Write down the
8.1.1 Type of electrochemical cell (1)
8.1.2 Cell notation of this cell (3)
8.1.3 NAME of the reducing agent (1)
8.1.4 Standard conditions for this electrochemical cell (2)
Calculate the initial emf of this cell. (4)
How will the concentration of Mg2* ions be affected when the cell is
functioning? Write down only INCREASES, DECREASES or REMAINS
THE SAME. (1)
This cell is connected to a light bulb. In theory the bulb should light up, but
in practice it does not. Give TWO possible reasons for this observation. (2)
[14]
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NSC
QUESTION 9 (Start on a new page.)
The diagram below shows an electrochemical cell used in the refining of copper.
9.1
9.2
9.3
9.4
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Electrode X Electrode Y
Electrolyte
Define the term electrolyte.
Write down the formula of the cation in the electrolyte of the above
electrochemical cell.
When an electric current passes through the electrolyte the mass of the
electrodes changes.
9.3.1 Does the mass of electrode X increase or decrease?
9.3.2 Write down the relevant half reaction to support the answer in
QUESTION 9.3.1
During the process illustrated by the above cell, a total of 2,259 x 1074
electrons is transferred. Calculate the mass by which the cathode change.
TOTAL
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MDE/September 2023
(2)
(1)
(1)
(2)
(5)
[11]
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Physical Sciences/P2 MDE/September 2023
Nee
DATA FOR PHYSICAL SCIENCES GRADE 12
PAPER 2 (CHEMISTRY)
GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12
VRAESTEL 2 (CHEMIE)
TABLE 1 YSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES
NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE
Avogadro's constant Na 6,023 x 1023 mot
TABLE 2: FORMULAE/TABEL 2: FORMULES
M Ny
ORIOF ¢ = n=
“Vv MV Vin
Ma _ Ca Ve pH = -log(Hs0*]
n, Cc, V,
Kw = [H3O*][OH1] = 1 x 10°4 at/ by 298 K
Eton = Ecatnode — Esnode / Et = Etatoae — Eenode
OR/OF
Fes = ERduction — Eosidaton / Ess: = Enduicle — Eotidasie
OR/OF
° 8 @ _ fe 8
Serr = EO idinnaent EC aieieegarl / Ea = Ei adeaineeel — Ee cameral
Q Q
=— n=—
Copyright reserved Please turn over
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Physical Sciences/P2
Increasing strength of oxidising agents/ Toenemende sterkte van oksideermiddels
Copyright reserved
nse
TABLE 4A: STANDARD REDUCTION POTENSTIALS
TABEL 4A: STANDAARD-REDUKSIEPOTENSIALE
Half-reactions/Halfreaksies E® (Vv)
Fo(g)+2e = 2F- + 2,87
Co*+e = Co* + 1,81
H2O2+ 2H*+2e = 220 E77
MnO;+ 8H*+5e = Mn%*+4H20 + 1,51
Ck(g)+2e = 2Ct + 1,36
Cr,0} +14H*+4e = 2CrP°* +720 + 1,33
O.(g)+4H*+4e == = 2H20 + 1,23
MnO2+ 4H* + 2e == Mn + 2H20 + 1,23
Pttt+2e = Pt + 1,20
Bro(t)+2e = 2Br + 1,07
NO, + 4H* + 3e = NO(g) + 2H20 + 0,96
Hg**+2e = Hog(f) + 0,85
Agt+e = Ag + 0,80
NO,+2H*+e = NOz(g)+H20 + 0,80
Fe*+e = Fe* +0,77
O2(g) + 2H*+2e"° == H202 + 0,68
lo + 2e = 2l + 0,54
Cut+e = Cu + 0,52
SO2+4H*+4e = S+2H20 + 0,45
2H20+O2+4e = 40H + 0,40
Cu%*+2e = Cu + 0,34
SO? +4H*+2e = SOx(g)+2H2O +0,17
Cu*+e = Cut + 0,16
Sn#*#+2e = Sn* +0,15
S+2H*+2e = H2S(g) + 0,14
2H*+2e = Hag) 0,00
Fe*+3e <= Fe — 0,06
Pb?*++2e = Pb - 0,13
Sn%*+2e = Sn -— 0,14
Ni? + 2e = Ni —0,27
Co*%*+2e = Co — 0,28
Cd**+2e = Cd —0,40
Cr++e = Cr -0,41
Fe**+2e = Fe — 0,44
Cr++3e = Cr —0,74
Zn? +2e = Zn — 0,76
2H20 + 2e == Ha(g) + 20H
Cr++2e = Cr
Mn?*+2e = Mn
AGb++3e = Al
Mg?*+2e = Mg
Nat+e = Na
Ca?* + 2e = Ca
Srt+2e = Sr
Ba’%*+2e = Ba
Cst+e = Cs
Ktte = K
Lite = Li
MDE/September 2023
Increasing strength of reducing agents/Toenemende sterkte van reduseermiddels
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Physical Sciences/P2
Increasing strength of oxidising agents/Toenemende sterkte van oksideermiddels
Copyright reserved
Nsc
MDE/September 2023
TABLE 4B: STANDARD REDUCTION POTENSTIALS
TABEL 4B: STANDAARD-REDUKSIEPOTENSIALE
Half-reactions/Halfreaksies E® (Vv)
lite =| Li — 3,05
Kt +e = K - 2,93
Cs*+e 2 Cs - 2,92
Ba**+2e = Ba — 2,90
Srt+2e = Sr — 2,89
Ca*+2e = Ca — 2,87
Nat+e = Na -2,71
Mg?* + 2e = Mg — 2,36
A@M++3e = AL — 1,66
Mn**+2e = Mn 1,18
Cr++2e = Cr - 0,91
2H2O0 +2e = H2(g)+20H — 0,83
Zn?* + 2e = 2Qn — 0,76
Cr++3e = Cr — 0,74
Fe*+2e = Fe — 0,44
Cr++e = Cre ~0,41
Cd**+2e = Cd ~ 0,40
Co*%*+2e = Co -— 0,28
Ni#* + 2e = Ni —0,27
Sn%*+2e = Sn ~ 0,14
Pb**+2e = Pb - 0,13
Fe*+3e = Fe — 0,06
2H*+2e = H2(g) 0,00
S+2H*+2e = HeS(g) + 0,14
Sn +2e = Sn +0,15
Cu*+e = Cut +0,16
SOf +4Ht+2e = SO2(g)+2H20 + 0,17
Cu2*+2e = Cu + 0,34
2H20 + O2 + 4e = 40H +0,40
SO2+4H*+4e = S+2H20 +0,45
Cuv+e = Cu + 0,52
k+2e = 2 + 0,54
O2(g)+ 2H*+2e = H202 + 0,68
Fe*+e = Fe +0,77
NO, +2H*+e = NOz2(g)+H20 + 0,80
Agt+e = Ag + 0,80
Hg?*+2e = Hg(f) + 0,85
NO, +4H*+3e = NO(g)+2H20
Brot)+2e = 2Br
Pi??+2e = Pt
MnOz2+ 4H*+2e = = = Mn? + 2H20
O2(g)+4H*+4e° = = 2H20
Cr0? +14H*+4e° = 2CrP°*+7H20
Chk(g)+2e = 2Ct
MnOz+8H*+5e = Mn? +4H20
H2O2 + 2H* + 2e = 2H20
Co*+e = Co*
Fog) +2e = OF
Increasing strength of reducing agents/Toenemende sterkte van reduseermiddels
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education
MPUMALANGA PROVINCE
REPUBLIC OF SOUTH AFRICA
NATIONAL
SENIOR CERTIFICATE
GRADE 12
PHYSICAL SCIENCES: CHEMISTRY P2
SEPTEMBER 2023
MARKING GUIDELINES
MARKS/PUNTE: 150
This memorandum consists of 12 pages.
Hierdie memorandum bestaan uit 12 bladsye.
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Physical Sciences P2/Fisiese Wetenskappe V2 September 2023
NSC/NSS- Marking Guidelines
QUESTION 1 / VRAAG 1
1.1 Dvv
42; Cvv
1s Dre
14 Bv¥v
1 Ce
15 Dv"
17 Avv
18 Bvv
19 Avv
110 Dever [20]
QUESTION 2 / VRAAG 2
2.1 Organic compounds that consist of hydrogen and carbon only. ¥
Organiese verbindings wat slegs uit waterstof en koolstof bestaan. (1)
2.2.1 2,4-dimethylhex-1-ene/2,4-dimetielheks-1-een
Marking criteria: Nasienkriteria:
e Correct stem i.e. hexene. ¥ e Korrekte stam d.i. hekseen. ¥
e Dimethylv e DimetielY
e IUPAC name completely correct e /UPAC-naam heeltemal korrek
including numbering, sequence, insluitende volgorde,
hyphens and commas. “ koppeltekens en kommas. ¥ (3)
2.2.2 CnHan ¥ (1)
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NSC/NSS- iedleg Guidelines
2.2.3
2.2.4
2.3.1
2.3.2
2.3.3
2.3.4
2.4.1
2.4.2
Bromine (water)/Broom(water)/Br2 “
Aldehyde/Aldehied ¥
Formyl groep/Formielgroep ¥
2-methylv butanal” /2-metielbutanaal
September 2023
Marking criteria / Nasienriglyne
e Seven C atoms in longest chain (only
single bonds between C-atoms /
Sewe C-atome in langste ketting
(slegs enkel bindings tussen C-
atome)v
e Two methyl and one ethyl
substituents/Twee metiel en een etiel-
substituente. ¥
e Whole structure correct / Hele
struktuur korrek ¥
H H oH
v_ | Marking criteria / Nasienriglyne
|
H aa
H H H
e Only functional group correct / Slegs
funksionele groep korrek Vv
e Whole structure correct / Hele struktuur korrek
2-methylv -pentan-2-olv /2-metielpentan-2-ol
Tertiary (alcohol)/Tersiére (alkohol) ¥
The C-atom bonded to the hydroxyl/-O
is bonded to three other C-atoms. v
Die C-atoom wat aan die hidroksiel/-OH gebind is, is aan drie ander C-atome
gebind.
QUESTION 3/ VRAAG 3
3.1
(3)
(1)
(1)
(1)
(2)
(2)
(2)
(2)
[19]
Marking criteria/Nasienriglyne
If any one of the underlined key phrases in the correct cont f
deduct 1 mark/Indien enige van die onderstreepte frases in deHorekte
konteks uitgelaat is, trek 1 punt af.
The temperature at which the solid and liquid phases of a substance are at
equilibrium. vv
Die temperatuur waarby die vaste- en vioeistoffases van 'n stof in ewewig is.
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Physical Sciences P2/Fisiese Wetenskappe V2 4
September 2023
NSC/NSS- Marking Guidelines
3.2.1. Chain length / number of C-atoms / Molecular mass ¥
Kettinglengte / getal C-atome/ molekulére massa (1)
3.2.2 ¢
3.3
Structare:
Compoul und B has a larger surface _area/longer_ chain _length/more_C
atomsilarger molecular mass than_ compound AY
Intermolecular forces:
Intermotecular forces in compound B are stronger than those in compound A.”
Energy
More energy needed to overcome intermolecular forces in compound B than
in compound A. ¥
Struktuur:
Verbinding B het 'n_groter_opperviakte/anger_kettinglengte/meer _C-
atome/groter molekulére massa as verbinding A.
Intermolekulére kragte:
Intermolekulére kragte in_verbinding B is sterker as in verbinding A.
Energie:
Meer energie word benodig om intermolekulére kragte in verbinding B te
oorkom as in verbinding A. (3)
D/Butan-1-ol ¥
D has the highest boiling point/ D het die hoogste kookpunt ¥ (2)
3.4.1
Molecular mass/number of Carbon and Hydrogen atoms/Molekulére
massa/aantal Koolstof en Waterstof atome ¥ (1)
3.4.2 ¢
In C/ butanal/aldehydes: dipole-dipole forces v(in addition to London
forces/dispersion forces/induced dipole forces).
In D/butan-1-ol: Hydrogen bonding. v (in addition to London forces/dispersion
forces/induced dipole forces).
Intermolecular forces in C/butanal are weaker vthan in D/butan-1-ol OR
dipole-dipole forces are weaker than hydrogen bonds OR intermolecular forces
in D/butan-1-ol are stronger than in C/butanal.
More energy needed to overcome/break intermolecular forces in D. ¥
In C/butanal/aldehiede: dipool-dipoolkragte (tesame met Londonkragte/
dispersiekragte/geinduseerde dipoolkragte).
In D/butan-1-ol: | Waterstofbinding. (tesame met Londonkragte/
dispersiekragte/geinduseerde dipoolkragte). P
Intermolekulére kragte in C/butanaal/aldehied is sw
butan-1-ol/alkohol
Intermolekulére kragte in D/butan-1-ol sterker as in C/butahaal OF dipool-
dipoolkragte is swakker as waterstofbindings. oe
Meer energie benodig om intermolekulére kragte te oorkom/breek in D. (4)
[13]
T
ér as in D/
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Physical Sciences P2/Fisiese Wetenskappe V2 September 2023
NSC/NSS- Marking Guidelines
QUESTION 4/ VRAAG 4
4.1.1. Hydrohalogenation/HydrobrominationY
Hidrohalogenasie/Hidrohalogenering/Hidrobrominasie (1)
4.1.2 Hydrogein tion/Hidrogenering/Hidrogenasiev (1)
4.1.3 | (1)
4.2.1. Substitution/HydrolysisY
Substitusie/Hidrolise (1)
4.2.2 Dilute strong base/NaOH/KOHI/LIOHY and mildly heatedv
Verdunde sterk basis/ Na©OH/KOH/LIOH en matig verhit (2)
4.2.3. NaBr/Sodium bromide/NatriumbromiedY (1)
4.3 Pt/Pd/Niv (1)
4.4 Marking criteria/Nasienriglyne
e Correct condensed structural formula for but-1-ene ¥
Korrekte gekondenseerde struktuurformule van but-1-een
e¢ Compound X: Bromine atom on correct carbon” and whole condensed
structural formula correct ~
Verbinding X: Broom atoom op korrekte C-atoom en die hele
gekondenseerde struktuurformule korrek.
CH2CHCH2CHs Y + HBr — CHsCHBrCH2CHsv ¥
NOTE/LET WEL
e Penalise only once for the use of structural formulae or molecular formulae
e Penaliseer slegs een keer vir die gebruik van struktuurformules of molekulére
formule (3)
4.5 Alcohol/Alkohol ¥ (1)
4.6.1 Esterification/Esterifikasie V (1)
4.6.2 Butyl “methanoatev /Butieletanoaat pa
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QUESTION 5/ VRAAG 5
5A Marking criteria/Nasienriglyne
If any ongaaiithe underlined key phrases in the correct context is omitted,
deduct ‘mark. /Indien enige van die onderstreepte frases in die korrekte
konteks‘uitgelaat i is, trek 1 punt af.
aanin
ANY Pe
e The change in concentration v of reactants or products per unit time”
e Change in amount/number of moles/volume/mass of products or reactants
per (unit) time.
e products formed/reactants used
ENIGE EEN
e Die verandering in konsentrasie V van reaktante of produkte per eenheid
tyd.v
e Verandering in hoeveelheid/getal mol/volume/massa van produkte of
reaktanse per (eenheid) tyd.
e Hoeveelheid/getal mol/volume/massa van produkte gevorm/reaktanse gebruik
per (eenheid) tyd.
e Tempo van verandering in konsentrasie/ hoeveelheid mol/getal mol/ volume/
massa. Y (2 of 0) (2)
5.2 To make sure that only the H2(g)/gases escapes./Om seker te maak dat slegs
H2(g)/gasse kan ontsnap. ¥ (1)
5.3.1 Graph/Grafiek B Vv (1)
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NSC/NSS- idle Guidelines
5.3.2 | Marking criteria/Nasienriglyne
e Calculate change in m(Zn) or n(Zn) ¥
Bereken 1 verandering in m(Zn) of n(én)
° [ Vervang 65 g-mot" inn = = v
tio/ Gebruik sxalverheudinge n(Zn)=2n(HC2) v
an er/Finale antwoord (0,2 mol) ¥
OPTION1/OPSIE 1 OPTION 2/0PSIE 2
AZn = 7 — 0,5V” 7
=6,5g n(Zn3,) = = = e57 = = 0,108 mol Zn
m 0,5
N(ZNusea/gebruik) = M n(Zn425) = 65
= = 0,0077 mol Zn
pal Zn An(Zn) = 0,108 — 0,0077v
= 0,1 mol Zn
n(HCl) = 2n(Zn)¥
= 2(0,1) n(HCl) = 2n(Zn)v
= 0,2 molv = 2(0,1)
= 0,2 molv (4)
5.4 Marking criteria/Nasienriglyne
¢ Substitute/Vervang 2,5 x 10* in ave rate/gem. Tempo = a
¢ Substitute/Vervang 12 x 60 (720 s) in ave rate/gem. Tempo = ad
e Use mol ratio/Gebruik molverhouding: n(Zn)=2n(H2)
e Substitute/Vervang 65 g-mol" inn = 7 ¥
e Final answer/Finale antwoord: 10,08 g v
An
ave rate/gem. tempo = ——
At *
: 7
22,510 720-(0"
n = —0,18 mol
f- n, = —0,18
n(Zn) = n(H2) = 0,18 mol ¥
n(Zn) = 0,18 x 65”
=11,79v
5.5.1 Temperature was decreased/ Temperatuur was verlaag ¥
(5)
(1)
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Physical Sciences P2/Fisiese Wetenskappe V2 8
NSC/NSS- Marking Guidelines
5.5.2 e Decrease in temperature decreases the average kinetic energy/molecules
move slower. v
Afname in temperatuur verlaag die gemiddelde kinetiese_energie/molekule
beweeg stadiger.
e Less molécules have enough/sufficient kinetic energy/Less molecules have
Mindér-tolekule het genoeg/voldoende kinetiese energie/Minder molekule
het B-=€..
e Less effective collisions per unit time/second. /Frequency of effective
collisions decreases. V
Meer effektiewe botsings per eenheidtyd/sekonde./Frekwensie van
effektiewe botsings neem toe.
e Reaction rate decreases /Reaksietempo neem afv
QUESTION 6 / VRAAG 6
6.1 When the rate of the forward reaction equals the rate of the reverse reaction. VV
Die tempo van die voorwaartse reaksie is gelyk aan die tempo van die
terugwaartse reaksie.
6.2.1 Reamaine the same / Bly dieselfde Vv
6.2.2 Reamaine the same / Bly dieselfde v
6.3 Endothermic / Endotermies v
e A increase in temperature favour the endothermic reaction Vv
‘n Verhooging in temperatuur bevoordee! die endotermiese reaksie
e The forward reaction was favoured v
Die voorwaartse reaksie is bevoordeel.
e The forward reaction is endothermic /Die voorwaartse reaksie is
endotermies.
6.4 Reamaine the same / Bly dieselfde ¥
6.5.1. Marking criteria / Nasienkriteria:
a. Subsitute 32 in formula n = a v
Vervang 32 in formule n =o
b. Substitute 0,334 in nS(s)initial and 0,253 in nS(s)fnai in table”
Vervang 0,334 in NS(S)aanvankik €N 0,253 in NS(S)fnaai in tabel
Use mol ratio / Gebruik mol verhouding : 1:1:1 ¥
n Equilibrium/ n Ewewig = nReactants / nReaktanteinitiaiegi
nReaktante reacted/ reageer w
n Equilibrium/ n Ewewig = n SOz2 initiavpegin + N SO? reacted re
Divide by the volume (0,5)/ Deel deur die volume (0,5) ¥
Correct Ke expression / Korrekte Ke uitdrukking ¥
Correct substitute into Kc expression / Korrekte invervanging in
K. — uitdrukking ¥
i. Final answer / Finale antwoord (0,37) v
2.9
sa>o
September 2023
(4)
[18]
(2)
(1)
(1)
(3)
(1)
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Physical Sciences P2/Fisiese Wetenskappe V2 9
NSC/NSS- Marking Guidelines
September 2023
m m
n= uM ny = uM
_ 10,7 _ 8,1
~ 32v ~ 32
= 0,3. | = 0,253 mol
parang S(s) O2(g)_| SOca(g)
Initial mol + 0,334 0,3 0
Aanvanklike mol
Change in mol ¥(b)= -0,081 | -0,081 | +0,081 Ratio v(c)
Verandering in mol
Equilibrium mol 0,253 0,219 0,081
Ewewigs mol sil v(d) v(e)
Equilibrium concentration 0,438 | 0,162 | Divided by/deel
Ewewigskonstante deur 0,5 v (f)
_ [SOz]
“i.
= 0.438 "Oe
= 0,36986" (i)
= 0,37 (9)
6.5.2 1
= 0,37
=2,704 Vv (2)
[19]
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Physical Sciences P2/Fisiese Wetenskappe V2 September 2023
NSC/NSS- Marking Guidelines
QUESTION 7 / VRAAG 7
7.1.1. Hydrogen sulphate ion/Waterstofsulfaatioon/HSO, v, Ka value is the highest /
Ka waarde is die hoogstev (2)
7.1.2 (2)
7.2.1. The poifahere the indicator changes colour. vv
Die puntwear die indicator kleur verander. (2)
#22 cVj = CfV5
(0,63)(0,05)v = o(1)v
c; = 0,0315 mol - dm~3v (3)
POSITIVE MARKING FROM QUESTION 7.2.2
7.2.3 | Marking criteria / Nasienkriteria:
a. Use of formula (n = c x v) and (m = n x M)¥
b. Substitute answer in 7.2.2 concentration nnaoH = Cc xX Vv ¥
Vervang antwoord in 7.2.2 as konsentrasie in nnaon = c x V
c. Ratio / Verhouding n(NaOh) : 2: 1”
d. Substitude / Vervang 90 g-mol™ in m(C2H2Oa) =n x MY
e. Divide m(C2H20s) by given mass / Deel m(C2H204) deur gegewe massav
| f. Answer / Antwoord (22,68%)v
n(NaOH) = cV
= (0,0315) (0,04) Y(a)
= 1,26 x 10° mol
n(C2H20,4) = %n(NaOH)
= %4(1,26 x 10°)
= 6,3 x 10~* mol v (c)
= (6,3 x 10°*)(90)v (a)
= 0,0567 g
0,0567
% purity / suiwerheid = 0.25 ¥(e) x 100
= 22,68%Y (f) (6)
7.3.1. Reaction of a salt with water / Reaksie van ‘n sout met water. (2)
7.3.2 Increases / Neem toe v
CHsCOO- + H20 v — OH + CHsCOOH ¥ ~
OH’ ions formed causes the solution to become more alkaline therefore pH
increases/OH- ione wat gevorm word veroorsaak dat oplossing meer alkalies
word en dus die pH laat toeneem. Vv (4)
[21]
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NSC/NSS- Marking Guidelines
QUESTION 8 / VRAAG 8
8.1.1. Galvanic cell / Galvaniese sel ¥ (1)
8.1.2 Mg/ waite ¥ Cu2*/ Cu ¥ (3)
8.1.3 Magnesia] ” (1)
8.1.4 Concentration / Konsentrasie: 1 mol-dm? ”
Temperature / Temperatuur: 25°C Vv (2)
8.2
(4)
8.3 Increases / Neem toe ¥ (1)
8.4 e The light bulb is a resistor. / Gloeilamp is 'n weerstandY
e The potential difference is enough but the current is too small./ Die
potensiaalverskil is genoeg maar die stroom is te klein. V (2)
[14]
QUESTION 9/ VRAAG 9
9.1 Is a substance of which the aqueous solution contains ions / substance that
dissolves in water to give a solution that conducts electricity. vv
‘n Stof waarvan die oplossing ione het / ‘n Stof wat in water oplos om ‘n oplossing
te vorm wat elektriese stroom gelei. (2)
9.2 Curv (1)
9.3.1 Decreases / Afneem (1)
9.3.2 Cu— Cu + 2e vv (2)
9.4 | Marking criteria / Nasienkriteria:
e Use Formula / gebruik formule n = = x
Answer / antwoord n = 3,7525 mol ¥
Use mol ratio / Gebruik mol verhouding - 2e: Cu 2:1V = ans
Substitute 63,5 in formula / Vervang 63,5 in formule n =
Final answer / Finale antwoord (119,13 g) ¥
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September 2023
NSC/NSS- Marking Guidelines
2
= 1,876 mol
m(Cu) = nM
= (1,876)(63,5)¥
= 119,13 gv (5)
[11]
GRAND TOTAL/GROOTTOTAAL [150]
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education
MPUMALANGA PROVINCE
REPUBLIC OF SOUTH AFRICA
ERRATA: PHYSICAL SCIENCES 2023
GRADE 12 PREPAROTARY EXAM PAPER 2
QUESTION
25:3 2-methylv propanal” / 2-metielpropanaal (2)
ONLY AFRIKAANS QUESTION PAPER ERRATA:
4.6.2 Butielv metanoaatY (2)
9.4 N
n=—
‘A
_ 2259 x 10”
~ 6,02 x 10%
= 3752,49 mol V
n(Cu) =
= 1876,246 mol
3752,49 y
2
m(Cu) = nM
= (1876,246)(63,5)”
= 119141,61 gv (5)
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