NATIONAL
SENIOR CERTIFICATE
GRADE 12
ELECTRICAL TECHNOLOGY: POWER SYSTEMS
NOVEMBER 2025
MARKING GUIDELINES
MARKS: 200
These marking guidelines consist of 17 pages.
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Electrical Technology Grade 12 NSC November 2025 Memo (Eng)
Grade 12 Electrical Technology memorandum from the NSC November Exam 2025 (English), 17 pages. Read online or download the free PDF.
Electrical Technology · Grade 12 · NSC November Exam · 2025. Memorandum, 17 pages. Read online or download the PDF.
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- Electrical Technology
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- Memorandum
- Year
- 2025
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- NSC November Exam
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Electrical Technology: Power Systems 2 DBE/November 2025
NSC – Marking Guidelines
INSTRUCTIONS TO THE MARKERS
1. All questions with multiple answers imply that any relevant, acceptable answer
should be considered.
2. Calculations:
2.1 All calculations must show the formulae.
2.2 Substitution of values must be done correctly.
2.3 All answers MUST contain the correct unit to be considered.
2.4 Alternative methods must be considered, provided that the correct
answer is obtained.
2.5 Where an incorrect answer could be carried over to the next step,
the first answer will be deemed incorrect. However, should the
incorrect answer be carried over correctly, the marker has to re-
calculate the values, using the incorrect answer from the first
calculation. If correctly used, the candidate should receive the full
marks for subsequent calculations.
3. This memorandum is only a guide with model answers. Alternative
interpretations must be considered and marked on merit. However, this
principle should be applied consistently throughout the marking session at ALL
marking centres.
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Electrical Technology: Power Systems 3 DBE/November 2025
NSC – Marking Guidelines
QUESTION 1: MULTIPLE-CHOICE QUESTIONS
1.1 B✓ (1)
1.2 B✓ (1)
1.3 C✓ (1)
1.4 C✓ (1)
1.5 D✓ (1)
1.6 B✓ (1)
1.7 B✓ (1)
1.8 A✓ (1)
1.9 B✓ (1)
1.10 C✓ (1)
1.11 B✓ (1)
1.12 D✓ (1)
1.13 C✓ (1)
1.14 C✓ (1)
1.15 D✓ (1)
[15]
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Electrical Technology: Power Systems 4 DBE/November 2025
NSC – Marking Guidelines
QUESTION 2: OCCUPATIONAL HEALTH AND SAFETY
2.1 Any article or combination of articles assembled, arranged or connected which
is used for converting any form of energy ✓ to performing work. ✓
OR
Any article or combination of articles which is used or intended to be used,
whether incidental there to or not, for developing, receiving, storing, containing,
confining, transforming, transmitting, transferring or controlling any form of
energy. (2)
2.2 Do not touch the person with bare hands. ✓
Use a non-conductive material to free the person from the live connection. ✓
Switch off the supply (2)
2.3 The use/misuse of power tools without adhering to safety protocols. ✓
The etching of PC boards without following safety procedures. ✓
Working on a live system without following safety protocol. (2)
2.4 A critical incident is an event that causes grave or severe physical injury to a
person that requires external emergency services. ✓
An accident is an event that may cause injury or damage to property (severe
or not severe). ✓ (2)
2.5 It is an unsafe act, because it creates an unsafe condition ✓ (no guard on the
machine) that is conducted by a person in a manner that may threaten the
safety ✓ of people in the workshop. (2)
[10]
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Electrical Technology: Power Systems 5 DBE/November 2025
NSC – Marking Guidelines
QUESTION 3: RLC CIRCUITS
3.1 3.1.1 Resonant frequency ✓ (1)
3.1.2 Quality factor/Q factor ✓ (1)
3.2 3.2.1 ✓
𝑉𝑇 = √𝑉𝑅 2 + (𝑉𝐿 − 𝑉𝐶 )2
= √202,162 + (226,82 − 140,18)2 ✓
= 219,94 𝑉
✓ (3)
3.2.2 𝑉𝑇
𝐼𝑇 = ✓
𝑍
𝑉𝑇
𝑍=
𝐼𝑇 ✓
219,94
=
3,61
✓
= 60,93 𝛺
(3)
OR
Alternatively calculate R = 56 Ω and XC = 31,83 Ω, then Z = 64,01 Ω
3.2.3 𝑉𝑅 If R is calculated:
𝐶𝑜𝑠𝜃 = ✓ 𝑅
𝑉𝑇 𝐶𝑜𝑠𝜃 =
𝑉𝑅 𝑍
𝜃 = 𝐶𝑜𝑠 −1 ( ) 56
𝑉𝑇 OR 𝜃 = 𝐶𝑜𝑠 −1 ( )
✓ 60,93
202,16
= 𝐶𝑜𝑠 −1 ( ) = 23,21 °
219,94
✓
= 23,20° (3)
NOTE: 𝑉𝐿 − 𝑉𝐶 may also be used.
𝑇𝑎𝑛𝜃 =
𝑉𝑅
3.2.4 1
𝑋𝐶 = ✓
2𝜋𝑓𝐶
At resonance XL=XC, therefore
1
𝐶=
2𝜋𝑓𝑋𝐶
1 ✓
=
2𝜋 × 50 × 62,83
= 50,66 𝜇𝐹 ✓ (3)
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Electrical Technology: Power Systems 6 DBE/November 2025
NSC – Marking Guidelines
3.3
✓
VL = 226,82 V
✓
VT = 219,94 V
(VL - VC)
θ = 23,20º
✓
IT = 3,61 A VR = 202,16 V
✓
VC = 140,14 V
NOTE:
VL and VC are the TWO primary labels thereafter any TWO correct labels.
If VL, VC, VR, VT, θ and (VL-VC) are written without values, marks will be awarded
given there is a distinct difference between the length of the phasors. (4)
3.4 3.4.1 ✓
𝐼𝑇 = √𝐼𝑅 2 + (𝐼𝐿 − 𝐼𝐶 )2
✓
= √0,52 + (0,9 − 0,2)2
✓
= 0,86 𝐴 (3)
3.4.2 𝑉𝑇 ✓
𝑋𝐶 =
𝐼𝐶
✓
50
=
0,2
= 250 𝛺 ✓ (3)
3.5 The circuit is more inductive. ✓ The inductive current IL is greater than the
capacitive current IC. ✓ (2)
3.6 When the frequency increases XC decreases ✓ and XL increases ✓ until they
are both equal ✓ and the circuit will resonate.
When the frequency increases, IC increases and IL decreases until they are
both equal and the circuit will resonate. (3)
3.7 3.7.1 Parallel RLC circuit. ✓ Impedance is maximum ✓ at resonance in a
parallel RLC circuit. (2)
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Electrical Technology: Power Systems 7 DBE/November 2025
NSC – Marking Guidelines
3.7.2 𝑓𝑟 ✓
𝐵𝑊 =
𝑄
∴ 𝐵𝑊 = 𝑓2 − 𝑓1 ✓
7300
(9200 − 5400) = ✓
𝑄
7300
𝑄 =
(9200 − 5400)
✓
= 1,92 (4)
[35]
QUESTION 4: THREE-PHASE AC GENERATION
4.1 • Installations costs are very high. ✓
• Appliances using three phase power supply are very expensive. ✓
• Three-phase power supply voltage is not available everywhere,
• Not suitable for most residential applications. (2)
4.2 A power factor of less than 1 means that the voltage and current waveforms
are not in phase, ✓ reducing the instantaneous product of the two waveforms ✓
(effective power delivered). (2)
4.3 4.3.1 Delta ✓ (1)
4.3.2 400 V ✓ (1)
4.3.3
VBR ✓
✓ Rotation
120⁰ VRY ✓
120⁰
120⁰
✓
VYB
NOTE:
The following labels will be accepted given the sequence is correct:
L1, L2 & L3 , VL1, VL2 & VL3 and R, Y & B
If the rotation label is omitted that mark may be awarded to the 120º. (4)
4.4 4.4.1 𝑉𝐿 = √3𝑉𝑃𝐻 ✓
= √3 × 220 ✓
= 381,05 𝑉
✓ (3)
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Electrical Technology: Power Systems 8 DBE/November 2025
NSC – Marking Guidelines
4.4.2 𝑆 = √3 𝑉𝐿 𝐼𝐿 ✓
𝑆
𝐼𝐿 =
√3 𝑉𝐿
16 000 ✓
=
√3 × 381,05
= 24,24 𝐴 ✓ (3)
4.4.3 𝑃 = √3𝑉𝐿 𝐼𝐿 𝐶𝑜𝑠𝜃 ✓
= √3 × 381,05 × 24,24 × 𝐶𝑜𝑠(29,54) ✓
= 13 918,75 𝑊
✓
= 13,92 𝑘𝑊 (3)
OR
𝑃 = 𝑆𝐶𝑜𝑠𝜃
= 16 000 × 𝐶𝑜𝑠(29,54)
= 13 920,19 𝑊
= 13,92 𝑘𝑊
4.4.4 𝑄 = √3𝑉𝐿 𝐼𝐿 𝑆𝑖𝑛𝜃 ✓
= √3 × 381,05 × 24,24 × 𝑆𝑖𝑛(29,54) ✓
= 7887,68 𝑉𝐴𝑟
✓
= 7,89 𝑘𝑉𝐴𝑟 (3)
OR
𝑄 2 = 𝑆 2 − 𝑃2
𝑄 = √16 0002 − 13 920,192
= 7888,49 𝑉𝐴𝑟
= 7,89 𝑘𝑉𝐴𝑟
4.5 𝑃𝑂𝑈𝑇 ✓
𝜂= × 100
𝑃𝐼𝑁
3 200 ✓
= × 100
3 450
= 92,75% ✓
(3)
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Electrical Technology: Power Systems 9 DBE/November 2025
NSC – Marking Guidelines
4.6 4.6.1 Coil A - Current coil. ✓ (1)
4.6.2 Digital wattmeters:
• Eliminates the need for precise mechanical components ✓
• Reduces the need for calibration ✓
• Can display multiple current, voltage and power readings on one
device
• Are more accurate (eliminate parallax errors)
• Are easier to read than analogue meters (2)
4.6.3 Coil B is the potential coil connected in parallel with the load to
measure voltage. ✓ It is movable with a needle on it and when
connected it will create a magnetic field that interacts with the
magnetic field on the current coil ✓ and moves/deflects to indicate a
reading. (2)
4.7 4.7.1 Higher energy losses ✓
Thicker cables are required ✓
Larger switchgear is required
Higher electricity bills (2)
4.7.2 A power factor meter indicates whether a system is more inductive
or more capacitive. ✓
A power factor meter indicates the ratio of the active/real power to
the apparent power of an electrical system.
To measure power factor. (1)
4.7.3 A load with a low power factor draws more current ✓ than a load with
a high power factor because more apparent power is needed to
supply the same real power. ✓ (2)
[35]
QUESTION 5: THREE-PHASE TRANSFORMERS
5.1 When an alternating voltage is applied to the primary winding, alternating flux
is set up in the core, ✓ which links with the secondary winding and induces an
emf ✓ of the same frequency to the secondary. (2)
5.2 5.2.1 A1 – A3 windings are connected in star configuration. ✓
B1 – B3 windings are connected in delta configuration. ✓ (2)
5.2.2 An iron core is needed in the construction of a transformer to provide
a magnetic field intense enough ✓ to produce the rated voltage ✓ in
the windings with a minimum of exciting current. ✓
OR
To strengthen the magnetic coupling in the process of transferring
power from the primary to the secondary winding. (3)
5.2.3 It is a Core type. ✓
The core is surrounded by the windings. ✓
The core has three limbs (2)
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Electrical Technology: Power Systems 10 DBE/November 2025
NSC – Marking Guidelines
5.2.4 Dry type transformers dissipate heat through a tubular radiator
around which air circulates, ✓ keeping the transformer cool. (1)
5.3 5.3.1 Voltage rating ✓
Current rating
Turns ratio
Power rating
Efficiency (1)
5.3.2 It is used as step-down transformers in distribution systems ✓ where
a four-wire system (neutral) is required.
School, hospital, Industry etc. will be accepted. (1)
5.3.3 The cost of replacing one damaged transformer is less ✓ as
compared to replacing the whole three-phase transformer unit. ✓
If one transformer (one-phase) becomes faulty, the faulty unit can
be removed and replaced without replacing the entire system. (2)
5.4 5.4.1 In delta 𝑉𝐿 = 𝑉𝑃𝐻 ✓
∴ 𝑉𝐿 = 𝑉𝑃𝐻 = 6 600 𝑉 ✓ (2)
5.4.2 𝑉𝐿 = √3𝑉𝑃𝐻(2) ✓
𝑉𝐿
𝑉𝑃𝐻(2) =
√3
380 ✓
=
√3
= 219, 39 𝑉 ✓
(3)
5.4.3 𝑁1 𝑉𝑃𝐻(1) ✓
𝑇𝑅 = =
𝑁2 𝑉𝑃𝐻(2)
6 600 ✓
=
219, 39
= 30,08 ∶ 1
✓
= 30 ∶ 1
(3)
5.4.4 𝑉𝑃𝐻(1) 𝐼𝑃𝐻(2) ✓
=
𝑉𝑃𝐻(2) 𝐼𝑃𝐻(1)
𝑉𝑃𝐻(2) 𝐼𝑃𝐻(2)
𝐼𝑃𝐻(1) =
𝑉𝑃𝐻(1)
219,92 × 900 ✓
=
6 600
= 29, 92 𝐴 ✓ (3)
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Electrical Technology: Power Systems 11 DBE/November 2025
NSC – Marking Guidelines
5.5 𝑃𝑂𝑈𝑇 ✓
𝜂= × 100
𝑃𝑂𝑈𝑇 + 𝑙𝑜𝑠𝑠𝑒𝑠
𝑃𝑂𝑈𝑇
𝑙𝑜𝑠𝑠𝑒𝑠 = − 𝑃𝑂𝑈𝑇
𝜂
4 500 ✓
= − 4 500
0,96
= 187,50 𝑊 ✓
(3)
5.6 A conservator is required to allow for the expansion and contraction ✓ of the oil
during changes of the temperatures with different operating loads ✓ or
changing of the surrounding air temperature. (2)
[30]
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Electrical Technology: Power Systems 12 DBE/November 2025
NSC – Marking Guidelines
QUESTION 6: THREE-PHASE MOTORS AND STARTERS
6.1 Resistance/continuity test of the windings. ✓
Insulation resistance test between windings. ✓
Insulation resistance test between windings and earth. (2)
6.2 The reactive power of a three-phase induction motor is the power used to set
up and maintain the electromagnetic field in the stator, ✓ without doing any real
work. ✓ (2)
6.3 6.3.1 A - Locked rotor torque ✓
Starting/Start-up torque
B - Breakdown torque ✓ (2)
6.3.2 The slip is minimum at no-load speed. ✓ (1)
6.4 6.4.1 60𝑓 ✓
𝑛𝑠 =
𝑝
60 × 50 ✓
=
2
= 1500 𝑟/𝑚𝑖𝑛 ✓ (3)
6.4.2 ns - nr ✓
% Slip = × 100
ns
1 500 - 1 250 ✓
= × 100
1 500 ✓
= 16,67% (3)
6.5 6.5.1 𝐶𝑜𝑠𝜃 = 𝑝𝑓
✓
𝐶𝑜𝑠𝜃 = 0,85
𝜃 = 𝐶𝑜𝑠 −1 (0,85) ✓
= 31,79° ✓ (3)
6.5.2 𝑃 = √3𝑉𝐿 𝐼𝐿 𝐶𝑜𝑠𝜃
✓
𝑃
𝑉𝐿 =
√3𝐼𝐿 𝐶𝑜𝑠𝜃 ✓
4 000
=
√3 × 6,8 × 0,85 ✓
= 399,55 𝑉 (3)
6.5.3 𝑆 = √3 𝑉𝐿 𝐼𝐿 ✓ 𝑃
𝐶𝑜𝑠𝜃 =
✓ 𝑆
= √3 × 399,55 × 6,8
𝑃
OR 𝑆 =
= 4 705,88 𝑉𝐴 ✓ 𝐶𝑜𝑠𝜃
= 4,71 𝑘𝑉𝐴 4 000
𝑆=
0,85
𝑆 = 4,71 𝑘𝑉𝐴
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Electrical Technology: Power Systems 13 DBE/November 2025
NSC – Marking Guidelines
6.5.4 𝑄 = √3𝑉𝐿 𝐼𝐿 𝑆𝑖𝑛𝜃 ✓
= √3 × 399,55 × 6,8 × 𝑆𝑖𝑛(31,79) ✓
= 2479,09 𝑉𝐴𝑅
✓
= 2,48 𝑘𝑉𝐴𝑅
(3)
OR
𝑆 2 = 𝑃2 + 𝑄 2
𝑄 = √𝑆 2 − 𝑃2
= √4705,882 − 40002
= 2478, 97 𝑉𝐴𝑟
= 2,48 𝑘𝑉𝐴𝑟
6.6 6.6.1 MC1N/O ✓
Retain / hold-in contact (1)
6.6.2 OL N/C will open when the current drawn by the motor in the main
circuit exceeds the set value (or when the motor is overloaded). ✓ (1)
6.6.3 One contactor will be used to provide power to the motor for forward
rotation. ✓ The other contactor will be used to swop any of the two
power lines to the motor in order for it to reverse its rotation. ✓ (2)
6.6.4 Interlocking ✓ (1)
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Electrical Technology: Power Systems 14 DBE/November 2025
NSC – Marking Guidelines
6.6.5
L
OL
N/C
STOP
START START
FWD MC1 REV MC2
N/O1 N/O1
MC2 MC1
✓ ✓
N/C N/C
✓ ✓
MC1 MC2
FWD REV
N
(4)
6.6.6 The circuit will not be energized ✓ when any of the start buttons is
pressed. (1)
[35]
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Electrical Technology: Power Systems 15 DBE/November 2025
NSC – Marking Guidelines
QUESTION 7: PROGRAMMABLE LOGIC CONTROLLERS (PLCs)
7.1 7.1.1 A = Input Scan/Read inputs ✓
B = Process scan/Run programme ✓ (2)
7.1.2 The PLC updates the status of all output devices ✓ based on the
results of the program execution. ✓
OR
The PLC finally activates each of the outputs connected to it,
according to the status of the 'output table' stored in memory. (2)
7.2 • A PLC system becomes more economical (cheaper) when compared to
large, bulky relay systems. ✓
• Modifications are less expensive as the program can merely be altered
instead of replacing/adding components in hardwired relay systems. ✓ (2)
7.3 To ensure that:
• There is no incorrect wiring ✓ that could cause short circuits and damage
the PLC unit.
• There are no loose connections ✓ that can cause false triggering or arcing. (2)
7.4 • All processing is done at low voltages and therefore safer. ✓
• The normal operation of a plant can be observed electronically on a monitor
keeping the observer away from dangerous machines. ✓
• All operations are shown on the interface as machines turned on and faulty
contactors can be located without having to fault find on a live system.
• Part of a plant can be switched off digitally for repairs to be done. (2)
7.5 7.5.1 • Markers are used to hold data ✓ in the PLC program.
• They can be switched on or off and control other programs or
output devices. ✓
• They can be used to indicate when a certain stage in a program
is complete.
• They can be used to indicate the start of the timing processors
next event. (2)
7.5.2 • The contactor in a program drives the coil of the relay contact on
the output module. ✓
• It can be programmed to be normally closed or normally open
contacts. ✓
• When a contactor in a program is activated, it is an indication that
a rung is successfully completed. (2)
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Electrical Technology: Power Systems 16 DBE/November 2025
NSC – Marking Guidelines
7.6 7.6.1
A
✓ ✓ OUTPUT ✓
B
OR
A &
B
& OUTPUT
NOTE:
Marks can only be awarded to the labels if the symbol is correct (3)
7.6.2 X =1✓
Y =0✓ (2)
7.7
OL1 ✓ ✓
MC1 ✓
STOP N/C START1
✓
MC1 N/O1
✓ OL2 ✓ ✓
✓
MC1 N/O2 N/C START2 MC2
✓
MC2 N/O
(9)
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Electrical Technology: Power Systems 17 DBE/November 2025
NSC – Marking Guidelines
OL1 MC1
STOP START1
N/C
MC1 N/O
OL2 MC2
MC1 N/O START2
N/C
MC2 N/O
7.8 7.8.1 Improvement of torque ✓ over the same current drawn. ✓ (2)
7.8.2 • Improves energy usage by controlling the power that is fed into
the motor.✓
• Reduce motor wear. ✓
• Better process control, such as speeding up or slowing down a
motor process depending on the type of production and
processes.
• It can convert a fixed-frequency and fixed voltage to a variable
frequency and variable voltage.
• The VSD requires less current to provide the required torque to
a specific load and thus the motor can be under designed with
thinner wires, leading to a cheaper motor and more profit. (2)
7.9 Braking Resistor. ✓ (1)
7.10 • Variable air volume air conditioning system ✓
• Exhaust systems ✓
• Water pumping systems ✓
• Fan systems
• Heating systems
• Battery powered electric cars (3)
7.11 A VSD has a rectifier that changes the three-phase AC supply to DC by using
three pairs of diodes ✓ where each pair of diodes rectifies a phase of the
three-phase supply. ✓ (2)
7.12 Longer ON times during pulse width modulation creates a longer
waveform ✓ which in turn decreases the frequency of the VSD output. ✓ (2)
[40]
TOTAL: 200
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