Physical Sciences Grade 12 P2 Eastern Cape Prelim 2024 Memo

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE/IBANGA 12 SEPTEMBA 2024 PHYSICAL SCIENCES P2 IFIZIKHALI SAYENSIZI P2 MARKING GUIDELINE/UMGAQO WOKUMAKISHA AMANQAKU: 150 This marking guideline consists of 21 pages./Lo mgaqowokumakisha unamaphepha angama 21 Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 2 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) QUESTION 1 /UMBUZO 1 1.1 C  (2) 1.2 C  (2) 1.3 B  (2) 1.4 A  (2) 1.5 B  (2) 1.6 B  (2) 1.7 C  (2) 1.8 A  (2) 1.9 B  (2) 1.10 B  (2) [20] Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 3 QUESTION 2 / UMBUZO 2 2.1 Marking criteria/ Umgaqo woniko manqaku If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Ukuba esinye seziqwengana ezingu ndoqo esinomgca ngaphantsi ngokwe khonteksti eyiyo sishiyiwe, nyiba inqaku libe-1. A bond or an atom or a group of atoms that determine(s) the physical and chemical properties of a group of organic compounds.  Yibhondi okanye i-athom okanye igruphu yee-athomu edithemina iifizikhali nee khemikhali propatizi ze gruphu yee oganikhi khompawundi.  (2) 2.2.1 E  (1) 2.2.2 A  (1) 2.2.3 C  (1) 2.3 EQUAL TO.  Compound E and ethyl methanoate are functional isomers / structural isomers / have the same molecular formula / same number and type of atoms / same number of C, H and O atoms  ILINGANA NO.  Ukhompawundi E no ethyl methanoate baziifunctional isomers/ structural ispmers/ bane molecularfomyula efanayo/bane nani elilingayo netayiphu yee athom/ banenani lee athom zika C,H no O elilinganayo.  (3) 2.4.1 H │ Marking criteria/ Umgaqo woniko H H― C ― H O H manqaku  • Functional group correct  │ │ II │ iFunctional gruphu H ― C ― C ― C ― C ― H . Whole structure correct  │ │ │ Isitraktsha sonke sichanekile H H H (2) 2.4.2 Propanoic acid / Propanoic asidi  (2) 2.4.3 4-methylhex-2-yne / 4-methyl-2-hexyne Marking criteria/ Umgaqo woniko manqaku • Hexyne  • Methyl  (3) • Whole name correct / igama lonke lichanekile Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 4 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) Marking criteria/ Umgaqo woniko manqaku 2.5 H H H • Functional group on 2nd carbon  │ │ │ iFunctional gruphu ikwikhabhoni yesibini H ― C ― C ― C ― H • Whole structure correct  │ │ │ Isitraktsha sonke sichanekile H Cℓ H (2) 2.6 C7H12 + 10 O2 → 7 CO2 + 6 H2O  Bal  NOTES / AMANQAKU • Reactant / Irhiecktenti Products/ iProwduakti  Balancing / ukuBalansisa  (3) [20] QUESTION 3 / UMBUZO 3 3.1.1 Marking criteria/ Umgaqo woniko manqaku If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Ukuba esinye seziqwengana ezingu ndoqo esinomgca ngaphantsi ngokwe khonteksti eyiyo sishiyiwe, nyiba inqaku libe-1 The temperature at which the vapour pressure of a substance / liquid equals the atmospheric pressure  Itempritsha apho ivapour pressure yesabsitensi/ ilikhwidi ilingana ne atmospheric presha. (2) 3.1.2 All Primary alcohols / Zonke iiprayimari alkhoholi  (1) 3.1.3 London forces / dispersion forces/ induced-dipole forces  iiLondon fosi/ iidispersion fosi/ ii- induced-dipole fosi (1) 3.1.4 Pentan-1-ol / 1-pentanol / i-Pentan-1-ol / i-1-pentanol /  (2) 3.2.1 Compound C / propanoic acid  Ukhomawundi C / ipropanoikhi aside (1) 3.2.2 Marking criteria/ Umgaqo woniko manqaku • Type of intermolecular forces in compound A  • Compound B and C have hydrogen bonds  • Compare the number of sites for hydrogen bonding in B and C  • Compare the strength of intermolecular forces  • Compare energy required to overcome the intermolecular forces  • Itayiphu ye intamoletyhula fosi ku khompawundi A • Ukhompawundi B no C bane hydrogen bhondi • Thelekisa inani lee site ze hydrogen bhodi ku B naku C • Thelekisa isitrhithi se-itamoletyhula fosi Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 5 • Thelekisa i=eneji efunekayo ukoyisa ii-intamoletyhula fosi • Compound A/butanone has dipole-dipole forces  (and London forces / dispersion forces/ induced-dipole forces) • Compound B/butan-1-ol and C/propanoic acid has hydrogen bonds (and London forces / dispersion forces/ induced-dipole forces) • Compound B/butan-1-ol has one site for hydrogen bonding and C/propanoic acid has two sites for hydrogen bonding  • Strength of the intermolecular forces increases from compound A / butanone to compound B / butan-1-ol to compound C / propanoic acid  • More energy is needed to overcome the intermolecular forces in compound C / propanoic acid than compounds A/ butanone and B/butan-1-ol  • Ukhompawundi A/ ibutanone unee dipole-dipole fosi (neeLondon forces / needispersion fosi/nee-induced-dipole fosi) • Ukhompawundi B/ ibutan-1-ol no C/ ipropanoic asidi inee hydrogen bhond (neeLondon fosi / iidispersion fosi/ ii-induced-dipole fosi) • UkhompawundiB/ ibutan-1-ol ine site enye yehydrogen bhondingi noC /ipropanoic asidi inee site ezimbini zehydrogen bhondingi • iiStrength se-intermolecular fosi siyanda ukusuka kukhompawundi A / ibutanone ukuya kukhompawundi B / ibutan-1-ol ukuya kukhompawundi C / ipropanoic asidi • i-eneji eninzi iyafuneka ukoyisa ii- intermolecular fosi kukhompawundi C / kwipropanoic asidi kuno khompawundi A/ ibutanone noB/ ibutan-1-ol (5) [12] Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 6 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) QUESTION 4 / UMBUZO 4 4.1.1 UNSATURATED  It contains a double bond between its carbon-carbon atoms in the hydrocarbon chain  I-ANSATSHUREYITHEDI  Inee double bhondi phakathi kwee carbon- carbon athom kwihydrocarbon chain. (2) 4.1.2 Substitution / Hydrolysis of a haloalkane  yiSabsitityushini /y iHydrolysis yeehaloalkane (1) 4.1.3 Elimination / dehydrohalogenation of haloalkanes  yiElimination / yidehydrohalogenation /yidehydrohalogenation yeehaloalkane (1) Marking criteria/ Umgaqo woniko manqaku 4.1.4 H H H H H • Functional group correct  iFunctional gruphu H C C C C C H . Whole structure correct   Isitraktsha sonke sichanekile H Cℓ H H H (2) 4.1.4 Pentan-2-ol / 2-pentanol /iPentan-2-ol / i-2-pentanol  (2) 4.1.6 Dilute strong base / NaOH  and mild heat  iDilute strong base / iNaOH  nemild heat (2) 4.1.7 Positional isomers  iPositional isomers (2) Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 7 4.2 Marking criteria / Umgaqo woniko manqaku Reaction 1: Dehydration reaction and correct chemicals.  Reactants with correct condensed structural formula  Products with correct condensed structural formula  uRhiektshini 1: iDehydration rhiekshini neekhemikhali ezichanekileyo. iiRhiekhenti eziziKhocondenisidi straktshaliral fomyula echanekileyo iiProwdacti eziziKhondenisidi straktshaliral fomyula echanekileyo. Reaction 2: Addition reaction and correct chemicals used.  Reactants with correct condensed structural formula  Products with correct condensed structural formula  uRhiekshini 2: i-Addition rhiekshini nokusetyenziswa kweekhemikhali ezichanekileyo iiRhiekithenti ezizikhondensinisidi straktsharali fomyula iiProwudakti ezizikhondensinisidi straktsharali fomyula Reaction 1 Conc H2SO4 CH3CH2CH2CH2OH  Heat / Hitte CH3CH2CHCH2 + H2O  (correct reaction / korrekte reaksie) Urhiekshini 1: Conc H2SO4 CH3CH2CH2CH2OH  Heat CH3CH2CHCH2 + H2O  (irhiekshini echanekinikileyo) Reaction 2 Pt CH3CH2CHCH2 + H2  CH3CH2CH2CH3  (correct reaction) Heat Urhiekshini 2 Pt CH3CH2CHCH2 + H2  CH3CH2CH2CH3  ( irhiekshini Heat echanekinikileyo) (6) [18] Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 8 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) QUESTION 5 / UMBUZO 4 5.1 Marking criteria/ Umgaqo woniko manqaku If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Ukuba esinye seziqwengana ezingu ndoqo esinomgca ngaphantsi ngokwe khonteksti eyiyo sishiyiwe, nyiba inqaku libe-1. ANY ONE Change in concentration of reactant or product per (unit) time.  Change in amount/number of moles/volume/mass of products or reactants per (unit) time.  Change in amount/number of moles/volume/mass of products formed or reactants used reactants per (unit) time.  NAYIPHI ENYE Uthintsho kwi khonsentreyishini yee prowudakthi/rhiekthenti per (unit) time. Utshintsho kwi amawunti/inumber of molesi/ivoluyumu/imass yee prowudakthi okanye yee rhiekthenti per (unit) time. Utshintsho kwi amawunti/inumber of molesi/ivoluyumu/imass yee prowudakthi ezifonyishiweyo okanye yee rhiekthenti ezisetyenzisiweyo per (unit) time. OR/OF The rate of change in concentration / amount of moles / number of moles / volume / mass.  (2 or 0). Irheyithi yotshintsho kwi khonsentreyishini/ I-amawunti yee mowuli/inumber of molesi/ivoluyumu/imass (2 of 0) (2) 5.2 Marking Criteria for investigative question / Umgaqo woniko manqaku kwi investigative question The independent and dependent variables are stated  I-independent nedependent variables zichaziwe Ask a question about the relationship between the independent and dependent variables  Buza umbuzo ngereleyinshiphu phakathi kwe-independent ne dependent variables What is the effect of the increase / decrease / change of concentration on the reaction rate?  Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 9 Ithini impembelelo yokonyusa/nokunciphisa/utshintsho kwikhonsentreyishini kwi reaction rate? OR / OKANYE What is the relationship between the concentration and reaction rate?  Ithini irhileyishinishiphu phakathi kwekhonsentreyishini ne reaction rate? (2) 5.3.1 HIGHER THAN / NGAPHEZULU KUNO (1) Volume of hydrogen gas (cm3) / Marking criteria / Umgaqo woniko 5.3.2 manqaku • Gradient B of is higher than A  B A IGradient kaB ingaphezulu kune ka A. iVoluyumu ka hydrogen gas • Final volume of curve A and B is the same and is horizontal / iFinal volumyu kakhevu A noB iyafana kwihorizontal  (cm3) NOTE: A or B must be indicated Ignore the labels of the axes. QAPHELA: uA noB mababonakaliswe. Zinanze Time / ixesha iileyibheli ze-axes (2) Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 10 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) 5.4 Marking criteria a) Subst. into rate equation  V b) Subst. 486,62 and 25 000 into in n =  Vm c) Use of mol ratio n (Zn) : n (H2)  d) Subst. 0,02 and 65 into m = nM  e) Final answer  Umgaqo woniko manqaku a) Sabst. Kwi-ikhweyzhini ye rheyithi n  b) Sabst. u486,62 no 25 000 ku "n = " "V" /Vm  c) ukusetyenziswa okwe mol ratio ku n (Zn) : n (H2)  d) Subst. 0,02 and 65 into m = nM  e) Impendulo yokugqibela ΔV rate = Δt V-0 8,39 = (𝑎𝑎)  58 V = 486,62 cm3 V n= Vm 486,62 n= (b)  24000 n(H2) = 0,020 mol n (Zn) = n (H2) = 0,020 (c)  m (Zn) = nM m (Zn) = (0,020)(65) (d)  m (Zn) = 1,30 g (e)  (5) Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 11 5.5 INCREASES / IYNYUKA  (1) 5.6 • At higher temperature the average kinetic energy of the particles is higher  • More particles have enough / sufficient kinetic energy or more particles have kinetic energy equal or higher than the activation energy  • More effective collisions per unit time/ Higher frequency of effective collisions  • Kwitthempritsha ephezulu i-average kinetic energy yeeparticles iyenyuka  • Iiparticles ezinininzi zine-enough / isufficient kinetic energy okanye iiparticles ezinizi zikinetic energy elingana okanye engaphezulu kune activation energy  • ii-effective collisions ezininzi per unit time/ ifrequency ephezulu yee effective collisions. (3) [16] Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 12 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) QUESTION 6 / UMBUZO 6 6.1.1 Marking criteria/ Umgaqo woniko manqaku If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Ukuba esinye seziqwengana ezingu ndoqo esinomgca ngaphantsi ngokwe khonteksti eyiyo sishiyiwe, nyiba inqaku libe-1. When the equilibrium in a closed system is disturbed, the system will re- instate a new equilibrium by favouring the reaction that will oppose/cancel the disturbance.  Xa i-ekhwilibriyam kwiclosed system is disturbediphazanyisiwe, isystem iyal ure-instata i-ekhwilibriyam entsha ngoku feyiva irhiekshinieza ku-opposa/ icancel isiphazamiso. (2) 6.1.2 Forward (reaction).  The equilibrium concentration of B is higher than A.  Fowadi (rhiekishini). i-ekhwelilbriyam khonsentreyishini kaB iphezulu kune ka-A. (2) 6.1.3 INCREASES / IYENYUKA  (1) 6.1.4 NO EFFECT/ AKUKHO MPEMBELELO  (1) 6.1.5 EXOTHERMIC / I-EKZOTHEMIKHI  (1) 6.1.6 • The concentration of A increased / [B] decreased  • (According to Le Chatelier’s principle) an increase in temperature favours the endothermic reaction.  • The reverse reaction was favoured / The equilibrium position shifted towards the left  • I-khonsentreyishini ka A yonyukile / [B] yehlile • (ngoku kaLe Chatelier’s principle) ukonyuka kwethempritsha kufeyiva i- endothemikhi rhiekshini. • irivesi rhiekshini feyiviwe / i- equilibrium position ishiftele ngase kunxele (3) Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 13 6.2 OPTION 1: CONCENTRATION : Marking criteria a) Correct Kc expression with square brackets  b) Substitution of 6,34 x 10-4 into correct kc expression  c) Correct substitution of [Br2] into correct kc expression  d) Use of the correct ratio [Br2] : [Br]  e) Determine initial [Br2]  f) Substitution into c = n/V  g) Final answer  INDLELA 1: IKHONSENTREYISHINI/Umgaqo woniko manqaku a) I-Kc expression echanekileyo enesquare brackets. b) iSabstityushini ka 6,34 x 10-4 kwi kc expression echanekileyo. c) iSabstityushini ka[Br2] ka kc expression echanekileyo. d) Ukusetyenziswa kweratio [Br2] : [Br] echanekileyo. e) Fumana [Br2] yokuqala f) iSabstityushini ku c = n/V g) Impendulo yokugqibela • No Kc expression, correct substitution / akho Kc expression, [Br] 2 iSabstityushini echanekileyo. Kc = (a)  Max / Makz 6/7 [Br2] • Wrong Kc expression / Kc [Br]2 expression engachanekanga. Max. 6,34 x 10-4(b)  = (c)  Makz 3/7 (2,074) [Br] = 0,03626 mol·dm-3 Br2 2 Br Initial conc 2,09213  (e) - Change in conc 0,03626  (d) -0,01813 Utshintsho kwi khons Equilibrium conc. 2,074 0,03626 n V = c 1,05 V = (f)  2,09213 V = 0,50 dm3 (g)  Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 14 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) OPTION 2: CONCENTRATION : Marking criteria a) Determine Δ [Br2]  b) Use of the correct ratio [Br2] : [Br]  c) Correct Kc expression with square brackets  d) Substitution of 6,34 x 10-4 into correct Kc expression  e) Correct substitution of [Br2] and [Br] into correct Kc expression  f) Substitution into c = nV  g) Final answer  INDLELA 2: IKHONSENTREYISHINI/Umgaqo woniko manqaku a) Fumana i-Δ [Br2] b) sebenzisa iratio ka [Br2] : [Br] echanekileyo c) iKc expression enesquare brackets echanekileyo d) iSabstityushini ka6,34 x 10-4 kwiKc expression echanekileyo e) Isabstityushini ka [Br2] echanekileyo no [Br] kwiKc expression echanekileyo f) iSabstityushini kuc = nV g) impendulo yokuggqibela Δ[Br2] = x(0,865/100) = 0,0865x  (a) Br2 2 Br Initial conc x - Change in conc -0,00865x 0,0173x  (b) Utshintsho kwi khons Equilibrium conc. 2,074 0,0173x [Br]2 Kc = (c)  [Br2] (0,0173x)2 6,34 x 10-4 (d)  = (e)  (2,074) x / [Br2]o = 2,096 mol·dm-3 n • No Kc expression, correct V = c substitution / akho Kc expression, iSabstityushini echanekileyo. 1,05 Max / Makz 6/7 V = (f)  2,096 • Wrong Kc expression / Kc expression engachanekanga. Max. V = 0,50 dm3 (g)  Makz 3/7 Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 15 OPTION 3: MOLE CALCULATION : Marking criteria a) Determine Δ mol Br2  b) Use of the correct ratio Br2 : Br  c) Correct Kc expression with square brackets  d) Substitution of 6,34 x 10-4 into correct Kc expression  e) Correct substitution of [Br] and [Br] into correct Kc expression  f) Substitution into c = nV  g) Final answer  INDLELA 3: I-MOLE KHALTYHULEYISHINI: Umgaqo woniko manqaku a) Fumana i-Δmol Br2 b) sebenzisa iratio kaBr2 : Br echanekileyo c) iKc expression enesquare brackets echanekileyo d) iSabstityushini ka6,34 x 10-4 kwiKc expression echanekileyo e) Isabstityushini ka [Br2] echanekileyo no [Br] kwiKc expression echanekileyo f) iSabstityushini kuc = nV g) impendulo yokuggqibela Δn(Br2) = 1,05 x 0,865 / 100 = 0,0090825 mol  (a) Br2 2 Br Initial mol 1,05 - Change in mol -0,0090825 0,0818165  (b) Utshintsho kwi mol Equilibrium mol. 2,074V 0,0818165 Equilibrium conc. Equilibrium khons. 2,074 0,018165 / V [Br]2 Kc = (c)  [Br2] • No Kc expression, correct substitution / akho Kc expression, [Br]2 iSabstityushini echanekileyo. 6,34 x 10-4 (d)  = (e)  (2,074) Max / Makz 6/7 • Wrong Kc expression / Kc [Br]o = 0,03626 mol·dm-3 expression engachanekanga. Max. Makz 3/7 n c = • V 0,018165 0,03626 = (f)  V V = 0,50 dm3 (g)  Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 16 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) OPTION 4: MOLE CALCULATION: Marking criteria a) Correct Kc expression with square brackets  b) Substitution of 6,34 x 10-4 into correct Kc expression  c) Correct substitution of [Br] and [Br] into correct Kc expression  d) Determine change in mol Br  e) Use of the correct ratio [Br2] : [Br]  f) Substitution into ne = ni – Δn for Br2  g) Final answer  INDLELA 4: IMOLE KHALTYHULEYISHINI /Umgaqo woniko manqaku a) I-Kc expression echanekileyo enesquare brackets. b) iSabstityushini ka 6,34 x 10-4 kwi kc expression echanekileyo. c) iSabstityushini ka[Br2] ka kc expression echanekileyo. d) Fumana utshintsho kwimoli zika Br e) Ukusetyenziswa kweratio [Br2] : [Br] echanekileyo f) iSabstityushini ku ne = ni – Δn ku Br2 g) Impendulo yokugqibela • No Kc expression, correct substitution / akho Kc expression, iSabstityushini [Br]2 echanekileyo. Max / Makz Kc = (a)  6/7 [Br2] • Wrong Kc expression / Kc [Br] 2 expression engachanekanga. 6,34 x 10-4 (b)  = (c)  Max. Makz 3/7 (2,074) [Br] = 0,03626 mol·dm-3 Br2 2 Br Initial mol 1,05 - Change in mol -0,01813V  (e) 0,03626V  (d) utshintsho kwimol Equilibrium mol. 2,074V 0,03626V Equilibrium conc. Equilibrium khons. 2,074 0,03626 ne = ni – Δn 2,074V = 1,05 - 0,01813V  (f) V = 0,5 dm3  (g) (7) [17] Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 17 QUESTION 7 / UMBUZO 7 7.1.1 Strong acids ionise completely in water  to produce a high concentration of the hydronium ions / (H3O+)  iiStrong acid ziayonayiza ngokupheleleyo emanzini completely  ukuprodyusa ikhonsentreyishini ephezulu yeehydronium ions / (H3O+) . (2) 7.1.2 It donates two protons/ H+ / Idoneytha iiproton ezimbini / H+ / H+  (1) 7.1.3 H2O  (1) 7.1.4 HSO4 –  (2) 7.1.5 Marking criteria/ Umgaqo woniko manqaku a) Ratio / iRatio [H3O+] : [H2SO4]  b) Formula / iFomyula pH = - log [H3O+]  c) pH value substituted into formula / i-pH value isabstitythwe kwifomyula d) Final answer / impendulo yokugqibela  [H3O+] = 2(0,1)  (a) = 0,2 mol·dm-3 pH = - log[H3O+]  (b) pH = - log (0,2)  (c) pH = 0,70  (d) (4) 7.2.1 OPTION 1/ INDLELA 1 OPTION 2 / INDLELA2 m m c =  n = MV M 1,2 1,2 c =  n = (90)(50x10-3) 90 c = 0,27 mol· dm-3  n = 0,013 mol· dm-3 n c =  V 0,013 c =  50x10-3 c = 0,26 mol· dm-3  (3) Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 18 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) 7.2.2 Positive marking from / IPozitivi Positive marking from / makhingi ukusuka ku 7.2.1 IPozitivi makhingi ukusuka ku Marking criteria / Umgaqo woniko 7.2.1 manqaku Marking criteria / Umgaqo woniko manqaku a) Subst. values of H2C2O4 into / n = cV Sabst. iiveliyu zikaH2C2O4 ku n = a) Subst. values of/ Sabst cV c V iveliyu ka na / nb ku ca Va = b) Using ratio / sebenzisa iratio na b b H2C2O4: NaOH 1:2   nb c) Subst of values of / sabst iveliyu ka b) Subst. values of/ Sabst NaOH ku c = n/V  iveliyu ka caVa into/ ku d) Subst into values / Vervang waardes ca Va na =  van NaOH into/ in c1V1 = c b Vb nb c2V2 c) Subst. values of/ Sabst e) Formula / iFomyula m = cMV  iveliyu in/ka Vb ku ca Va n f) Subst into / sabst m = cMV  = na  c b Vb g) Final answer / impendulo b d) Subst into values/ Sabst yokugqibela  iiveliyu zika NaOH into/ ku c1V1 = c2V2  n (H2C2O4) = cV e) Formula / iFomyula m = cMV  = 0,27 x 25 x 10-3 (a)  f) Subst into/ Sabst m= cMV  = 6,75 x 10-3 mol g) Final answer/ Impendulo okugqibela  n (NaOH) = 2 x 6,75 x 10-3 (b)  caVa na n (NaOH) = 0,0135 mol = cbVb nb n c(NaOH) = (0,27)(25) (b)  1 V = (a)  cb(43,8) (c)  2 0,0135 c(NaOH) = (c)  cb = 0,308 mol·dm-3 43,8 x 10-3 c(NaOH) = 0,308 mol·dm-3 c1V1 = c2V2 c1(25) = (0,308)(100) (d)  c1 = 1,232 mol· dm-3 m = cMV (e)  m = (1,232)(40)(2) (f)  m = 98,56 g (g)  (7) [20] Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 19 QUESTION 8 / UMBUZO 8 8.1 Chemical energy to electrical energy  iChemical energy kwielectrical energy (2) 8.2 Provide path for movement of ions / Bied pad vir beweging van ione Ensures electrical neutrality in the cell / Iprovayida indlela yokuhambahamba kwee-ayoni / iqinisekisa i- electrical neutrality kwiseli (Any one/ Nayiphi enye)  (1) 8.3 Fe3+ + e- → Fe2+  (2) Marking criteria / Umgaqo woniko manqaku • Fe3+ + e - ⇌ Fe2+ ½ • Fe2+ ← Fe3+ + e- 2/2 • Fe2+ ⇌ Fe3+ + e - 0/2 • Fe2+ → Fe3+ + e - 0/2 Ignore if the charge omitted on electron / INanza ukuba itshaji kwignoreer kwi elektroni ishiyiwe. 8.4 Eθcell = Eθcathode/reduction/oxidising agent –Eθanode/oxidation/reducing agent  Marking criteria/ Umgaqo woniko manqaku Eθcell = (0,77)  – ( - 0,13)  • Any other formula using unconventional abbreviation , e.g. / Eθcell = EθOA –Eθ RA followed by the correct Eθcell = 0,90 V  substitution Max ¾ • Nayiphi ifomyula ekusetyenziswe i- unconventional abbreviation , umzl.. / Eθcell = EθOA –Eθ RA ilandelwe (4) yisabstityushininechanekileyo followed by the c Makz ¾ 8.5.1 Increases / Iyanda  (1) 8.5.2 Remains the same / ihlala injalo  (1) 8.5.3Increases / iyanda  (1) 8.6 Zn is a stronger reducing agent than Pb  More energy per unit charge is released for the reaction between Zn and Fe3+ / The reaction between Zn and Fe3+ is more strongly product-favoured / equilibrium position lies further to the right than Pb and Fe3+  i-Zn yireducing agent enamandla kunoPb  I-ieneji eninzi iyakhutshwa per unit charge kwirhiekshini ephakathi koZn no Fe3+ / Irhiekshini ephakathi koZn no Fe3+ iproduct-favoured kakhulu ngamandla / i-equilibrium position ikekelele kakhulu ngase kunene kune kaPb no Fe3+ (2) [14] Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com 20 PHYSICAL SCIENCES P2/IFIZIKHALI SAYENSIZ P2 (EC/SEPTEMBA 2024) QUESTION 9 / UMBUZO 9 9.1 The chemical process in which electrical energy is converted to chemical energy (2 or 0)  yichemical process apho i-electrical energy iguqulelwa kwichemical energy (2 of 0) OR / OKANYE The use of electrical energy to produce a chemical change (2 or 0)  Kuksetyenziswa kwe-electrical energy ukuprodyusa ichemical change (2 of 0) (2) 9.2 Battery/ ibhetri  (1) 9.3 Hydrogen gas / H2  (1) 9.4 2 Cℓ− (aq)+ 2e− → Cℓ2(g)  Ignore phases / Nanza iphase Marking criteria / Umgaqo woniko manqaku 1/2 • 2 Cℓ− (aq) + 2e−⇌ Cℓ2(g) 2/2 • Cℓ2(g) ← 2 Cℓ− (aq)+ 2e− 0/2 • Cℓ2(g) ⇌ 2 Cℓ− (aq)+ 2e− 0/2 • Cℓ2(g) → 2 Cℓ− (aq)+ 2e− Ignore if the charge omitted on electron/ Nanza ukuba itshaji kwi-elektroni ishiyiwe (2) 9.5 Pink / iPinki  . OH−  (2) 9.6.1 Zinc/ iZinc  (1) 9.6 2 Marking criteria / Umgaqo woniko manqaku a) Using ratio / Sebenzisa iratio Cu: e- = 1:2  b) Subst. of values of / Sabst iveliyu ka Cu into / ku m = nM  c) Adding the mass of Cu reduced to initial mass /Ukwengeza imass ka Cu emva kwephuyurifikheyishini.phuryifawa.  d) Final answer / Finale antwoord  n (Cu) = ½ x 1,38 x 10-2 (a)  n (Cu) = 6,9 x 10-3 mol m = nM m = (6,9 x 10-3)(63,5) (b)  m = 0,43815 g m (cathode /katode) = 2 + 0,43815 (c)  (4) Hosted by www.ecexams.co.za.

Downloaded from hlayiso.com (EC/SEPTEMBA 2024) PHYSICAL SCIENCES P1/IFIZIKHALI SAYENSIZI P2 21 m (cathode/katode) = 2,43815 g (d)  [13] TOTAL / ITOTALI: 150 Hosted by www.ecexams.co.za.